OBIEE and SQL

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  Hi all

  Please find test data and results as XML and SQL output.

  Version : Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

  create table emp_xml (empno number, emp_name varchar2 (100), by e-mail to varchar2 (100));

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  -----------------------

  EMPNO EMP_NAME EMAIL DEPTNO

  DAVID 100 [email protected] 10

  DAVID 100 [email protected] 20

  DAVID 100 [email protected] 30

  ROBERT 101 [email protected] 10

  ROBERT 101 [email protected] 20

  ROBERT 101 [email protected] 30

  ROBERT 101 [email protected] 40

  ROBERT 101 [email protected] 50

  DANIEL 102 [email protected] 10

  Results in XML

  -----------------------

  < USERS_DETAILS >

  < USER >

  < EMPNO > 100 < / EMPNO >

  DAVID < NAME > < / NAME >

  < EMAIL > [email protected] < / EMAIL >

  < ASSIGNED_DEPT >

  < DEPT > 10 < / DEPT >

  < DEPT > 20 < / DEPT >

  < DEPT > 30 < / DEPT >

  < / ASSIGNED_DEPT >

  < / USER >

  < USER >

  101/EMPNO < EMPNO > >

  ROBERT < NAME > < / NAME >

  < EMAIL > [email protected] < / EMAIL >

  < ASSIGNED_DEPT >

  < DEPT > 10 < / DEPT >

  < DEPT > 20 < / DEPT >

  < DEPT > 30 < / DEPT >

  < DEPT > 40 < / DEPT >

  < DEPT > 50 < / DEPT >

  < / ASSIGNED_DEPT >

  < / USER >

  < USER >

  < > 102 EMPNO < / EMPNO >

  DANIEL < NAME > < / NAME >

  < EMAIL > [email protected] < / EMAIL >

  < ASSIGNED_DEPT >

  < DEPT > 10 < / DEPT >

  < / ASSIGNED_DEPT >

  < / USER >

  < / USERS_DETAILS >

  Thank you

  Rambeau

  SQL>   select e.empno
    2         , e.emp_name
    3         , e.email
    4         , regexp_substr(d.dept_list, '[^,]+', 1, level) deptno
    5      from emp_xml e
    6      join emp_dept_xml d
    7        on e.empno = d.empno
    8   connect
    9        by level <= length(d.dept_list) - length(replace(dept_list, ','))
   10       and prior e.empno = e.empno
   11       and prior dbms_random.value() is not null;
  
       EMPNO EMP_NAME             EMAIL                DEPTNO
  ---------- -------------------- -------------------- --------------------
         100 DAVID                [email protected]      10
         100 DAVID                [email protected]      20
         100 DAVID                [email protected]      30
         101 ROBERT               [email protected]     40
         101 ROBERT               [email protected]     20
         101 ROBERT               [email protected]     10
         101 ROBERT               [email protected]     30
         101 ROBERT               [email protected]     50
         102 DANIEL               [email protected]     10
  
  9 rows selected.
  
  SQL> select xmlelement
    2         (
    3              "USERS_DETAILS"
    4            , xmlagg(xmlelement
    5              (
    6                  "USER"
    7                , xmlelement("EMPNO", empno)
    8                , xmlelement("NAME", emp_name)
    9                , xmlelement("ASSIGNED_DEPT", xmlagg(xmlelement("DEPT", deptno)))
   10              ))
   11         ).extract('*') xml_output
   12    from (
   13            select e.empno
   14                 , e.emp_name
   15                 , e.email
   16                 , regexp_substr(d.dept_list, '[^,]+', 1, level) deptno
   17              from emp_xml e
   18              join emp_dept_xml d
   19                on e.empno = d.empno
   20           connect
   21                by level <= length(d.dept_list) - length(replace(dept_list, ','))
   22               and prior e.empno = e.empno
   23               and prior dbms_random.value() is not null
   24         )
   25   group
   26      by empno
   27       , emp_name;
  
  XML_OUTPUT
  --------------------------------------------------------------------------------
  
    
      100
      DAVID
      
        10
        20
        30
      
    
    
      101
      ROBERT
      
        40
        50
        30
        20
        10
      
    
    
      102
      DANIEL
      
        10
      
    
  
  
  SQL>
  

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