On the issue of the port already in use and multiply the application instance?
I use the message connection to receive sms. When I restart the application, I found the already used port exception. I've been through many posts and believe that BB allows a UNIQUE APPLICATION connecting the port of sms at a time. But the port of sms I know certainly is used only by my candidacy, is somehow wrong to create a second instance of application trying to access this port?
This question confused me a lot of time, to appreciate someone give me a help.
This problem has been resolved.
The two possible solutions for this problem:
1 re - save the connection string for registery push in the start method. but avoid registering a new when enforcement is woken up by sms push, otherwise it won't get the message.
public void startApp() { String[] list = PushRegistry.listConnections( true ); boolean isByPush = (list != null && list.length > 0) ? true : false; if(!isByPush) { PushRegistry.unregisterConnection( connString ); PushRegistry.registerConnection( connString,Test.class.getName(), "*" ); } bbReceiveSmsThread = new BBReceivingSmsThread(connString); bbReceiveSmsThread.start(); } private static class BBReceivingSmsThread extends Thread { private boolean stop = false; private MessageConnection mc; private String connString; public BBReceivingSmsThread(String connString) { this.connString = connString; } public synchronized void stop() throws IOException { stop = true; mc.close(); // Close the connection so the thread returns. } public void run() { try { mc = (MessageConnection)Connector.open(connString); for(;;) { if ( stop ) return; Message message = mc.receive(); String text = null; if( message instanceof TextMessage ) text = ( (TextMessage)message ).getPayloadText(); if( message instanceof BinaryMessage ) text = new String( ( (BinaryMessage)message ).getPayloadData(), "UTF-8" ); if(text != null) { //do your message here } } } catch (Exception e) {} } }
Tags: BlackBerry Developers
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