Open all URLS in the browser

Similar Questions

• Open a URL in the browser via Photoshop

  Is this possible? I don't have a clickable link for the user or anything, I just need the script to open a URL in the default browser users. How would I go to do this?

  function openURL (url) {}

  FName = "shortcut.url"; var

  var shortcut = new file (Folder.temp + ' /' + fname);

  shortcut. Open ('w');

  shortcut.writeln ('[InternetShortcut]');

  shortcut.writeln ("URL =" + url);

  shortcut.writeln ();

  shortcut. Close();

  shortcut. Execute();

  shortcut. Remove();

  };

• Why you put "Open a new tab" on the right side of the browser, when you close a tab on the left and you type a new URL in the browser on the left?

  I changed my computer from XP to Windows 7 and migrated my FF browsers. But... now the tabs at the top of the page are all right (they were upper-front left - where I loved her)

  The most important is the "open a new tab" + - is on the right. But that is not sensible. Why you put "Open a new tab" on the extreme right of the browser, when you close a tab on the left and you type a new URL in the browser on the left?

  How can I put my "open a new tab" immediately to the right of 'Close tab' - as if it was before?

  Please advise?

  Try clicking on "Restore default settings" in the palette to customize to reset the toolbar customization.

  • Firefox '3-bar' menu button > customize
  • View > toolbars > customize
  • https://support.Mozilla.org/KB/customize-Firefox-controls-buttons-and-toolbars

  You can attach a screenshot?

  • http://en.Wikipedia.org/wiki/screenshot
  • https://support.Mozilla.org/KB/how-do-i-create-screenshot-my-problem
  • Use a type of compressed as PNG or JPG image to save the screenshot
  • Make sure you do not exceed the maximum size of 1 MB

• How to open a link in the browser when clicking on Image?

  I created a clickable image. Now, I want to open a link in the browser when clicking on Image.

  How to get there?

  Call Browser.getDefaultSession () .displayPage (String url)

• Launch the application from a url in the browser for BlackBerry?

  I'm developing an application where I will launch a url in the browser where I run my application.

  Suppose if I click google.com , and then press enter, it will launch my app. For this, I tried with the HttpFilterRegistry API.

  For reference, I use the HTTPFilterDemo application. But currently while launching the application, I get the NullPointerException .

  I wrote the code below I have the openFilter method:

    public Connection openFilter( String name, int mode, boolean timeouts ) throws IOException
      {
          Logger.out("Protocol", "it is inside the openFilter method");
          _url = name.substring(2);
          _requestHeaders = new HttpHeaders();
          _responseHeaders = new HttpHeaders();
          _responseHeaders.setProperty(HttpProtocolConstants.HEADER_CONTENT_TYPE, "text/html");
  
          // Attempt to parse for the file name
          int slashIndex = name.indexOf('/', 2);
     if (_resultData == null)
          {
  
  final int modHandle = CodeModuleManager.getModuleHandle("AppLaunchBrowser");
                      Logger.out("Protocol", "here is the module handle:::" +modHandle);
                      final ApplicationDescriptor[] apDes = CodeModuleManager.getApplicationDescriptors(modHandle);
  //                  final String[] arguments = new String[1];
                      final ApplicationDescriptor appDescriptor = new ApplicationDescriptor(apDes[0], new String[]{});
                      Logger.out("Protocol", "here is the app descriptor:::" +appDescriptor);
                      try {
                          final int appCode = ApplicationManager.getApplicationManager().runApplication(appDescriptor, true);
                          Logger.out("Protocol", "here is the app code:::" +appCode);
                      } catch (ApplicationManagerException e) {
                          // TODO Auto-generated catch block
                          e.printStackTrace();
                      }
       }
          return this;
      }
  

  And I am creating alternative entry point in the application class and using as below:

  public class AppLaunch extends UiApplication{
      public static void main(String args[])
      {
          Logger.out("AppLaunch", args+"length of the arguments::::" +args.length);
          if((args != null) && (args.length > 0) && (args[0].equals("background")))
          {
              Logger.out("AppLaunch", "in the alternate entry point");
  //          Logger.out("AppLaunch", args+"length of the arguments::::" +args.length);
              HttpFilterRegistry.registerFilter("www.google.co.in", "com.innominds.ca", false);
  
          }
          else
          {
              Logger.out("AppLaunch", "Inside the Applaunch");
              AppLaunch theApp = new AppLaunch();
              theApp.requestForeground();
              Logger.out("AppLaunch", "created the app launch object");
              theApp.enterEventDispatcher();
  //          Logger.out("AppLaunch", "in the alternate entry point");
  //          HttpFilterRegistry.registerFilter("www.google.co.in", "com.innominds.ca", false);
          }
      }
  
      public AppLaunch()
      {
          checkPermissions();
          showTestScreen();
      }
  
       /**
       * This method showcases the ability to check the current permissions for
       * the application. If the permissions are insufficient, the user will be
       * prompted to increase the level of permissions. You may want to restrict
       * permissions for the ApplicationPermissionsDemo.cod module beforehand in
       * order to demonstrate this sample effectively. This can be done in
       * Options/Advanced Options/Applications/(menu)Modules.Highlight
       * 'ApplicationPermissionsDemo' in the Modules list and select 'Edit
       * Permissions' from the menu.
       */
      private void checkPermissions()
      {
  
          ApplicationPermissionsManager apm = ApplicationPermissionsManager.getInstance();
          ApplicationPermissions original = apm.getApplicationPermissions();
  
          if(original.getPermission(ApplicationPermissions.PERMISSION_BROWSER_FILTER) == ApplicationPermissions.VALUE_ALLOW)
          {
              // All of the necessary permissions are currently available
              return;
          }
  
          ApplicationPermissions permRequest = new ApplicationPermissions();
          permRequest.addPermission(ApplicationPermissions.PERMISSION_BROWSER_FILTER);
  
          boolean acceptance = ApplicationPermissionsManager.getInstance().invokePermissionsRequest(permRequest);
  
          if(acceptance)
          {
              // User has accepted all of the permissions
              return;
          }
          else
          {
  
          }
      }
  
      /**
       * Shows the test screen to allow the user to exercise the application
       * permissions capabilities.
       */
      private void showTestScreen()
      {
          UiApplication.getUiApplication().pushScreen(new AppLaunchScreen());
      }
  }
  

  can someone please help... Sorry for the almost total code display...

  I was finally able to solve this problem. NPE is to come in other methods of recall because I'm implementation of the FilterBaseInterface.

• get the URL of the browser

  Is it possible to get the URL of the browser? I have seen an application that gets it and check.

  I searched all the related browser api but unsuccessful.

  You can add your own item to the browser application menu. The current URL is sent to your application when selected by the user.

  See ApplicationMenuItem and ApplicationMenuItemRepository in the javadocs.

• How to open a link in the browser of the phone

  I tried to find out how to open links in the browser of the phone, but I'm getting a few surprising opion (StackOverflow) :

  It is not the answer, when you want to continue using PhoneGap Build, but I solved the problem by creating a development environment for Cordova (PhoneGap) on my machine and compile the application locally. In Cordoba 2.5.0 window.open('http://www.myurl.nl', '_system'); works perfectly, it will open the link in the system browser. So my advice is to stop using PhoneGap Build and start compiling your application locally.

  I don't know if there is already a good solution that works for all platforms and if I use the Phonegap also supported well build service.

  You ask the Forum of phonegap, but it seems a matter of generation phonegap, the phonegap right build forum is https://forums.adobe.com/community/phonegap/build

  This response seems old, you must use cordova-plugin-inappbrowser to open external links in the browser of the phone

  Install it by adding this line in the config.xml file

  and open the phone's browser with

  cordova.InAppBrowser.open('http://www.myurl.nl','_system');,

• Open Enterprise Manager using the browser on Oracle Linux

  I installed Oracle 10 g Release 2 on Oracle Enterprise (version of Enterprise Linux AS 4 (October 7 update)).
  
  I started the listener and enterprise manager using emctl start dbconsole command successfully.
  
  As I am new to linux, I don't know how to open the url EM Linux.
  
  What browser should I use (exact version that is compatible with the version of Enterprise Linux AS 4 (October update 7).) How do I install the browser and open enterprise manager using the browser.
  I don't even know if any browser is installed during the installation of linux. How can I check if any browser installed or not?

  No one can guess what you have installed or how you have configured your system or the installation of Oracle. The default browser for Oracle Linux 4 is Konqueror, which is not compatible with the MS Oracle dbconsole.

  You might want to try the following:

  Open a Terminal command prompt (System Applications/tools) and enter the following command:

  
  
  su - root
  
  cd /etc/yum.repos.d
  
  wget http://public-yum.oracle.com/public-yum-el4.repo
  
  yum -y install firefox
  
  

  To open a Firefox browser window, open the Web icon in the Menu, next to the Actions or the Applications/Internet or type firefox in an X 11 terminal window.

  The default URL for the dbconsole EM is:

  http://hostname_or_ip:5500 / em

• White screen on Windows Vista Start-cannot open all programs, even the Task Manager

  Original title: white screen on startup of Windows Vista

  Hello

  I tried tirelessly fix my Sony Vaio computer that is running Windows Vista. After that I entered my password by logging into my account, the screen charge nothing; It is empty. I'm unable to open all programs, even the Task Manager.

  I AM able to start safe mode. I tried MSCONFIG, removing all the programs of cleaning, power off start up programs, but nothing seems to work. Can anyone help? Thank you.

  Hello

  See if that helps you.

  Do a Safe Mode system restore to before the problem started.

  http://bertk.MVPs.org/html/restoresysv.html

  @@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@

  If it doesn't, try a startup repair and / or a system restore using a DVD of Vista from Microsoft

  Manufacturers recovery disks normally do not have Service Options; they are normally a relocation to the factory only settings option.

  Here is the guide to repair Options using a Vista DVD from Microsoft.

  If a friend or a work acquantance of yours has one, you can borrow and use it for repairs.

  http://www.bleepingcomputer.com/tutorials/repair-Windows-with-Windows-Startup-Repair/

  Table of contents

  1. Overview of Windows Vista repair options
  2. How to perform an automatic repair of Windows Vista using Startup Repair
  3. Advanced Tools Overview
  4. Conclusion

  If you do not or can not borrow a Microsoft DVD there is a download of a file ISO of Vista Startup Repair available that you can put on a Bootable floppy to make the above startup repair and that the method is recommended by a large number of posters in these Forums.

  Unfortunately, you have to buy it.

  Here is a link to it:

  http://NeoSmart.net/blog/2011/Windows-Recovery-discs-updated-reinstated/

  See you soon.

• Failed to open all files with the extension .exe in Vista Business SP2. Dialog box appears and asks which program to use. Seems to have lost the info file assoc after virus removal.

  Failed to open all files with the extension .exe in Vista Business SP2.  Dialog box appears and asks which program to use.  Seems to have lost the info file assoc after virus removal.  Any suggestions?

  Hello

  Try the methods provided below and check if the problem persists.

  Method 1:

  Try the fix it or follow the manual for troubleshooting to solve the problem.

  When you run an .exe on a Windows XP, Windows Vista or Windows 7 computer file, the file can start another program

  http://support.Microsoft.com/kb/950505

  Note:

  The link above contains steps that tell you how to modify the registry. However, serious problems can occur if you modify the registry incorrectly. Therefore, make sure that you proceed with caution. For added protection, back up the registry before you edit it. Then you can restore the registry if a problem occurs. For more information about how to back up and restore the registry, click on the number below to view the article in the Microsoft Knowledge Base:

  How to back up and restore the registry in Windows

  http://support.Microsoft.com/kb/322756

  Method 2:

  Download and run Microsoft Safety Scanner and check if the problem is caused by a Virus/Malware.

  Microsoft safety scanner

  http://www.Microsoft.com/security/scanner/en-us/default.aspx

• How can I customize the thumbnail that is displayed next to the URL in the browser?

  The use of MUSE to create my site, how can I customize the thumbnail that is displayed next to the URL in the browser?  Also, how can I customize the thumbnail image that appears during the incorporation of the site link in things like Facebook?

  Automatic thumbnails are used... I do not understand how they are drawn and how do I customize Muse.

  The thumbnail is the brown box here:

  

  The thumbnail is the white box here:

  

  Hello

  You can do this by adding Og tags for Facebook share and favicon.

  To apply a favicon in Muse, please go to file > Site Properties > Content and apply the favicon.

  

  Adding images to Facebook Share, please see a similar thread below.

  When I share the link to my site on Facebook or other social media, the preview image is empty, there is nothing there anyway to solve this problem?

  Kind regards

  Vivek

• URL of the browser Newsletter

  We sent a newsletter without the {tag_viewinbrowser} tag. Can be determined with the benefit of hindsight, the URL to the browser representation?

  Hello Gerhard,

  At the moment there is no way to determine the URL of the page in question, it is automatically generated when the newsletter is sent.

• How can I copy and paste the URL into the browser?

  How can I copy and paste the URL into the browser?

  Hey laquettak2368033,

  It is enough to select the URL by dragging your mouse over it & then use the keys Ctrl + C to copy & then paste it using Ctrl + V keys.

  Kind regards

  Nicos

• Get the URL from the browser form

  Dear,
  I'm certain forms of 10gr 2, I would get the URL of the browser inside my shape. How could I do something like that?
  
  Thanks in advance.

  With PJC bean is also possible...

  http://peterv6i.blogspot.com/2012/04/reading-applet-parameters-in-Oracle.html

  or

  package in2.client;
  
  import java.io.PrintStream;
  import java.net.InetAddress;
  import oracle.forms.handler.IHandler;
  import oracle.forms.properties.ID;
  import oracle.forms.ui.VBean;
  
  public class ClientInfo extends VBean
  {
    private static final ID CLIENT_IP = ID.registerProperty("CLIENT_IP");
    private static final ID CLIENT_NAME = ID.registerProperty("CLIENT_NAME");
    private static final ID CLIENT_OS = ID.registerProperty("CLIENT_OS");
    private static final ID CLIENT_USER = ID.registerProperty("CLIENT_USER");
    private static final ID HOST_URL = ID.registerProperty("HOST_URL");
  
    private IHandler mHandler;
    private String hostAddress = "";
    private String hostName = "";
    private String hostOs = "";
    private String hostUser = "";
    private String hostURL = "";
  
    public ClientInfo()
    {
      try
      {
  
        System.out.println("+----------------------+");
        System.out.println("+  ClientInfro PJC     +");
        System.out.println("+  Peter Valencic      +");
        System.out.println("+----------------------+\n"); 
  
        this.hostAddress = InetAddress.getLocalHost().getHostAddress();
        this.hostName    = InetAddress.getLocalHost().getHostName();
        this.hostOs      = System.getProperty("os.name");
        this.hostUser    = System.getProperty("user.name");
  
        System.out.println("Host   adress: " + this.hostAddress);
        System.out.println("Host     name: " + this.hostAddress);
        System.out.println("Host op. syst: " + this.hostOs);
        System.out.println("Host username: " + this.hostUser);
        System.out.println("+----------------------+\n");
      }
      catch (Exception e)
      {
        System.out.println("Init error: " + e.toString());
      }
    }
  
    public void init(IHandler handler)
    {
      super.init(handler);
      this.mHandler = handler;
  
    }
  
    public Object getProperty(ID pid)
    {
      if (pid == CLIENT_IP) {
        System.out.println("Client IP: " + this.hostAddress);
  
        return "" + this.hostAddress;
      }
  
      if (pid == CLIENT_NAME) {
        System.out.println("Client Name: " + this.hostName);
  
        return "" + this.hostName;
      }
  
      if (pid == CLIENT_OS) {
        System.out.println("Client os: " + this.hostOs);
  
        return "" + this.hostOs;
      }
  
      if (pid == CLIENT_USER) {
        System.out.println("Clientuser: " + this.hostUser);
  
        return "" + this.hostUser;
      }
  
      if (pid == HOST_URL) {
        hostURL = this.mHandler.getApplet().getDocumentBase();
        System.out.println("Host Url: " + this.hostURL);
        return "" + this.hostURL;
      }
  
      return super.getProperty(pid);
    }
  }
  

• 403 Forbidden error of execution of the procedures of the URL of the browser stored

  I am currently trying to run a simple stored procedure (ea.hello_world, where "ea" is the pattern and "hello_world" is the name of the procedure) a URL from the browser, but am getting a 403 Forbidden - error message "you don't have permission to access /pls/apex/ea.hello_world on this server. I use APEX 3.2 with Oracle 11 g and mod_plsql and gave the steps of apex_public_user. Any thoughts on what I am doing wrong?
  
  Here is the process I have used so far:
  
  Create the "Hello_World" procedure in the "EA: schema
  
  create or replace
  procedure hello_world
  is
  Start
  HTP. Print ("'Hello World!");
  end;
  
  I then successfully granted to run the apex_public_user procedure:
  
  Grant execute on ea.hello_world to apex_public_user;
  
  Then, I tried to call the stored procedure from the browser using the following syntax:
  
  http:// < Server >: < port > / pls/apex/< schema >. < Procedure & gt;
  
  I also experimented with the use of a public synonym and the configuration of the wwv_flow_epg_include_mod_local, but I do not think that the function s relevant since I'm using mod_plsql and not the embedded pl/sql gateway.

  Hello

  If you have below the line in dads.conf, then wwv_flow_epg_include_mod_local sets

  PlsqlRequestValidationFunction wwv_flow_epg_include_modules.authorize
  

  Try:
  Create public synonym

  CREATE PUBLIC SYNONYM hello_world FOR ea.hello_world;
  

  Grant privilege to execute procedure to the public

  GRANT execute on hello_world to public;
  

  Then change the APEX_030200.wwv_flow_epg_include_mod_local function

  CREATE OR REPLACE FUNCTION
  APEX_030200.wwv_flow_epg_include_mod_local(
      PROCEDURE_NAME IN VARCHAR2)
  RETURN BOOLEAN
  IS
  BEGIN  
  
      IF UPPER(procedure_name) IN (
            UPPER('hello_world'))
     THEN
          RETURN TRUE;
      ELSE
          RETURN FALSE;
      END IF;
  END;
  /
  

  Then try
  http://:/pls/apex/hello_world

  If you can now run your procedure in URL, you can then low and e.g. grant execute procedure to the user of DAD.

  Kind regards
  Jari

  http://dbswh.webhop.NET/dbswh/f?p=blog:Home:0

  Published by: jarola on December 6, 2011 16:20

  Published by: jarola on December 6, 2011 16:24

  typo in the name of the function