order by clause union in date column
Hi gems... good evening...Oracle version: 11.2.0.2 EL6 Linux server
I have a query as below:
Select col1, col2, col3 col4
tab1, tab2, tab3
where the conditions
Union
Select col1, col2, col3 col4
tab1, tab2, tab3
where the conditions
Union
Select col1, col2, col3 col4
tab1, tab2, tab3
where the conditions;
Now the col4 is a date column, and I need to order by on that entire result sets. I know that I can do (order of col4) (order by 4) or at the end of all of the query.
But the problem is that the output is coming to Mon-dd-yyyy (i.e. 31-Dec-2012).
I want each output in the format dd/mm/yyyy, so I need to use the function to_char.
But in this case, I can't use the order by clause, because in this case it's get organized by character IE by 1,2,3,4,5 like that.
How can I solve my problem... Please help... Thanks in advance.
Published by: gogol on 3 November 2012 08:05
Maybe - when you order by date column, she did it with a date internal representation so on exit you can use any date format you think appropriate
select distinct
col1,col2,col3,col4
from (select col1,col2,col3,col4
from tab1,tab2,tab3
where conditions_1
or conditions_2
or conditions_3
)
Concerning
Etbin
Tags: Database
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What's the point of having several columns in the ORDER BY clause?
DB version: 10 gr 2
When you use the ORDER BY clause, the lines are always sorted by the first column in the ORDER BY clause. So, what's the point of having several columns in the ORDER BY clause (I always see this in production codes)?
For the below SQLs' schema SCOTT, result sets are always classified according to the first column ename. When I added use asc and desc of employment, does not change the result set.
SQL> select * from emp order by ename; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected. SQL> select * from emp order by ename, job; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected. SQL> select * from emp order by ename, job desc; EMPNO ENAME JOB MGR HIREDATE SAL COMM DEPTNO ---------- ---------- --------- ---------- --------- ---------- ---------- ---------- 7876 ADAMS CLERK 7788 23-MAY-87 1100 20 7499 ALLEN SALESMAN 7698 20-FEB-81 1600 300 30 7698 BLAKE MANAGER 7839 01-MAY-81 2850 30 7782 CLARK MANAGER 7839 09-JUN-81 2450 20 7902 FORD ANALYST 7566 03-DEC-81 3000 20 7900 JAMES CLERK 7698 03-DEC-81 950 30 7566 JONES MANAGER 7839 02-APR-81 2975 20 7839 KING PRESIDENT 17-NOV-81 5000 20 7654 MARTIN SALESMAN 7698 28-SEP-81 1250 1400 30 7934 MILLER CLERK 7782 23-JAN-82 1300 20 7788 SCOTT ANALYST 7566 19-APR-87 3000 20 7369 SMITH CLERK 7902 17-DEC-80 800 20 7844 TURNER SALESMAN 7698 08-SEP-81 1500 0 30 7521 WARD SALESMAN 7698 22-FEB-81 1250 500 30 14 rows selected.Search in this example, you will see the difference
SQL> create table test_order (name varchar2(10), surname varchar2(10), age number); Table created. SQL> insert into test_order values('Kamran','Agayev',26); 1 row created. SQL> insert into test_order values('Kamran','Taghiyev',26); 1 row created. SQL> insert into test_order values('John','Kevin',23); 1 row created. SQL> select * from test_order; NAME SURNAME AGE ---------- ---------- ---------- Kamran Agayev 26 Kamran Taghiyev 26 John Kevin 23 SQL> select * from test_order 2 order by age; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Agayev 26 Kamran Taghiyev 26 SQL> select * from test_order 2 order by age asc, surname desc; NAME SURNAME AGE ---------- ---------- ---------- John Kevin 23 Kamran Taghiyev 26 Kamran Agayev 26 SQL>When in the second query, I sorted out only for age, you saw it there two 26 years old Keita, there was first Agayev, then Taghiyev. But if I want to get the family names in descending order when there are two very old person, then I will add the second column in the order by clause
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Kamran Agayev a. (10g OCP)
http://kamranagayev.WordPress.com -
order of varchar and digital data
Hello
I use the apex of oracle 10g 3.2
I am using an sql query in a region. I want to make sure he by setting col.parameter column is varchar2 (1000).
The values can be of a character or the format of number of characters.
as
format ABC or def - 1
Now, I want to use the order by clause in there.
But when I have data like
ABC-1, abc-2 11 - abc
His comes as
ABC-1
ABC-11
ABC-2
instead of abc - 1
ABC-2
ABC-11
the query is
Select distinct
p.Parameter Test
of T_RESULTS t, M_PARAMETERS p where p.parameter_id = t.parameter_id and
t.service_registration_id =: P43_SERVICE_REGISTRATION_ID
order to decode (instr(p.parameter,'-'), 0, p.parameter, to_number (substr (p.parameter, instr(p.parameter,'-') + 1)))
So, what should I do?
Thank youHello
with t as (select 'abc-1' col1 from dual union all select 'abc-11' col1 from dual union all select 'abc-2' col1 from dual) select col1 from t order by case instr(col1,'-') when 0 then col1 else substr(col1,1,instr(col1,'-')-1) end, case instr(col1,'-') when 0 then 0 else to_number(substr(col1,instr(col1,'-')+1)) endThe first element will sort the alphanumeric characters, the other numbers if they exist.
Herald tiomela
htendam.WordPress.com -
How to remove the Order By clause
How can I get rid of the Order By clause in the underlying SQL query? I created a simple hierarchy, but when I use the hierarchy in the analysis and then come down, the results show multiple occurrences of each child. For some reason, I was able to reduce the number of occurrences of each child by adding a saved filter.
I was expecting this:
Instead, I got this:
The generated physical query looks like this:
SET VARIABLE QUERY_SRC_CD = "report"; SELECT s_0, s_1, s_2, s_3, s_4 s_5, (FROM s_6)
SELECT
s_0 0,.
CAST (NULL AS VARCHAR s_1 (1)).
"Registration - College". «Dimensions of the inscription '.» "' Exercise ' s_2,.
'All the colleges' s_3,.
IDOF ("registration - College". «Hierarchies of the inscription '.» "College". ". ("' S_4 all Colleges").
MOUNT s_5 (NULL AS DOUBLE),
"Registration - College". "" Counties of schooling. "" Full-time student "s_6
"REGISTRATION - College".
UNION ALL
SELECT
1 s_0
"Registration - College". «Dimensions of the inscription '.» "" Name of College "s_1,.
"Registration - College". «Dimensions of the inscription '.» "' Exercise ' s_2,.
'All the colleges' s_3,.
IDOF ("registration - College". «Hierarchies of the inscription '.» "College". ". ("' S_4 all Colleges").
IDOF ("registration - College". «Hierarchies of the inscription '.» "College". ". ("' S_5 College ').
"Registration - College". "" Counties of schooling. "" Full-time student "s_6
"REGISTRATION - College".
WHERE
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) djm ORDER OF 1, 3 ASC NULLS LAST, 4 ASC NULLS FIRST, 5 ASC NULLS FIRST, 2 ASC NULLS FIRST, NULLS FIRST CSA 6
EXTRACT FIRST 10000000 LINES ONLY
HI mbengue,.
Check the report you are running any column presentation sorted in the user interface (in which case the order by clause will creep into generated sqls Physics). Also, I think that its worth it to check the settings of the hierarchy you have configured and if the installation program for the calculation of the measured column (number of students in this case), has been done correctly.
Kind regards
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Hello
I want to know what it means when I use the "order by" clause with more than one column in both cases (sort order, it's the same, and when the sort order is different), for example
What should happen when I do this
1 Select * from table
order by 1, 2; -both are a CSA
2 - Select * from table
order by 1 asc, desc 2;
in both cases if it sorts the column with the first column without worrying, it is asc or desc, order another column order, because he should get
related data in the first column, then another sort column does nothing?
Am I wrong?
Thank you
SQL > select * from t by col1, col2 CSA CSA;
COL1 COL2
-------------------- --------------------
1 1
1 2
1 3
2 1
2 2
SQL > select * from t by CSA col1, col2 desc;
COL1 COL2
-------------------- --------------------
1 3
1 2
1 1
2 2
2 1
-
Cannot wrap a select with order by clause in a file.
TOGETHER SET TERMOUT OFF FEEDBACK OFF PAGESIZE 0 400 LINESIZE ECHO OFF OFF POSITION
coil & 1;
Select "EMPID, EMP_NAME, REGION, FROM, TO, MONTH, ACTIVITY_TYPE, PROJECT_PIN, MILESTONE_NAME, PRACTICE_ID, RESOURCE_CATEGORY, HOURS, COMMENT, percent ALLOCATION, INVOICE_TO, the STATE of the double"
Union of all the
select empid,resource_name,region,week_of,(week_of+7),core_month,bill_rate,project_name,project_type,milestone_name,practice_id,resource_category,total_hours_submitted,project_type,"%ALLOCATION",invoice_to,status from master_emp_allocation order by week_of;
spool off;
"exit";
/
the above block gives result below
select empid,resource_name,region,week_of,(week_of+7),core_month,bill_rate,project_name,project_type,milestone_name,practice_id,resource_category,total_hours_submitted,project_type,"%ALLOCATION",invoice_to,status from master_emp_allocation order by week_of
*
ERROR at line 3:
ORA-00904: "WEEK_OF": invalid identifier
---------------------------------------------------------------------------
Without the order by clause it wraps the file passed as an argument.
check
Combining the UNION AGENDA and BY
Columns in the ORDER BY list must be a subset of the columns in the selection list on the left side of the union.
All the columns in the ORDER BY list should be sorted in ascending order, and they must be a prefix in the order of the columns in the target of the left side of the UNION list.
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ORDER BY clause with an expression
As the column of names and table name is valid, what happening internally when the query is executed?
SQL > SELECT STU_ID, STU_NAME FROM to STUDENT BY 2 + 3, STU_ID;
What I discovered, was that the lines get sorted by ascending order of STU_ID. It is obvious that he does not know the expression 2 + 3, so my doubts are:
(a) is he adding a pseudo-column to the table with 2 + 3 get discounted at 5?
Select (b) if there is a 5th column among students of the table and specify us it in the select statement of the list (5 column names) then why not consider as 5 and sort the data according to that?
(c) it is true that, any expression that we write is getting evaluated to null? Then - what is ORDER BY NULL refers to any order and if the Analyzer search name column or next position (if specified)?
(d) If neither of the two, so what is the reason of ignorance?Hello
Welcome to the forum!
987236 wrote:
As the column of names and table name is valid, what happening internally when the query is executed?SQL > SELECT STU_ID, STU_NAME FROM TO STUDENT BY 2 + 3, STU_ID;
What I discovered, was that the lines get sorted by ascending order of STU_ID. It is obvious that he does not know the expression 2 + 3, so my doubts are:
b is a pseudo-column adding to the table with 2 + 3 get discounted at 5
There is no column pseduo involved. (Pseudo-colonnes are something that Oracle provides to you, without requiring you to specify what you want. Include ROWID and LEVEL pseudo-colonnes. In this example, 2 + 3 is an Expression . Like the pseudo-colonnes, expressions can usually appear in the ORDER BY clause, even if they are not actually stored in the table.)
It is the first sort by the NUMBER 5 (= 2 + 3), not the 5th column. Since the NUMBER 5 has the same value on every row, every row relates to the forefront. The result of sorting by any constant is the same; the results are the same that besides as exrpression in the ORDER BY clause. This is the clause ORDER BY, that you have published is equivalent toORDER BY 2 + 3 , 'foo' , SYSDATE , NULL , stu_idand this is also equivalent to
ORDER BY stu_idNone of the expressions except stu_id vary from one line to the other, then none of them affect sorting.
Select (b) if there is a 5th column among students of the table and specify us it in the select statement of the list (5 column names) then why not consider as 5 and sort the data according to that?
As Solomon replied only literal numbers are taken to refer to a column. 5 is a literal number, then
ORDER BY 5means "Sort by the 5th column", but 2 + 3 is not a literal (that is an expression that happens to include a couple of literals), so
ORDER BY 2 + 3does not refer to the 5th colunmn.
(c) it is true that, any expression that we write is getting evaluated to null? Then - what is ORDER BY NULL refers to any order and if the Analyzer search name column or next position (if specified)?
No, when you way "ORDER BY x", the rows with values of x which come first, followed by the lines with higher values of x. lines having the same value of x will be together, in no particular order with respect to the other (unless there is an expression of failure later in the clause ORDER BY.
This is exactly what happens when you say "ORDER BY NULL". NULL has the same value (in fact, the same lack of any value) on all lines, so all rows have the same value of x, and they will appear in no particular order.(d) If neither of the two, so what is the reason of ignorance?
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sys_context and order by clause
Hi all
IM using Oracle 11 g R2.
Is it somehow possible to use the context variable (to store the column name) in the ORDER BY clause? My ultimate goal is to build by Order at run time, without using the concatenation.
for example, I created context as my_ctx for some pkg and its variable as v_ctx with a value defined as 'TABLE_NAME '.
So it is possible to use it as
Select * from all_tables
sys_context order ('my_ctx', 'v_ctx');
If not, does perform a work around?
Thank you
VivekHi, Vivek,
Vivek says:
Hi allIM using Oracle 11 g R2.
Is it somehow possible to use the context variable (to store the column name) in the ORDER BY clause? My ultimate goal is to build by Order at run time, without using the concatenation.
Of course, you can use SYS_CONTEXT in an ORDER BY clause, but it is unclear what you are trying to do, so I don't know if SYS_CONTEXT will help you.
for example, I created context as my_ctx for some pkg and its variable as v_ctx with a value defined as 'TABLE_NAME '.
So it is possible to use it asSelect * from all_tables
sys_context order ('my_ctx', 'v_ctx');If not, does perform a work around?
Post a full test script Hat people can run to recreate the problem and test their ideas. Show the output you want from the parameters a data you give.
Consider using a CASE expression in the ORDER BY clause. You can use SYS_CONTEXT in the expression BOX, if you wish.
-
Hai all,
I have problem with order by clause,
My query is
"Select number from table1 order number CSA.
and the output as
1
10
12
13
15
17
19
2
20
21
22
.
........
But if we give the order that it should display below the only good?
1
2
10
12
13
15
17
19
20
21
22 ........
Help me please why it is not displayed as she. and how to make the statement to display as in the second case. Thanks in advance.
Kind regards
UrajaIn your table, the column is VARCHAR2 data type.
It is a string, even if it is to store numeric values, it will get condemn as strings
Try the below
select your_column from table1 order by to_number(your_column) ascPublished by: JAC on November 19, 2012 16:35
-
Need help with order by clause row_number() Fn
Desired outputwith t as ( select 123 id, 'brwr' lstatus from dual union all select 123 id, 'ca' lstatus from dual union all select 123 id, 'fac' lstatus from dual union all select 345 id, 'ca' lstatus from dual union all select 345 id, 'brwr' lstatus from dual union all select 567 id, 'brwr' lstatus from dual union all select 789 id, 'brwr' lstatus from dual union all select 1011 id, 'fac' lstatus from dual union all select 1011 id, 'xyz' lstatus from dual )select id,lstatus,row_number() over(partition by id order by lstatus)rw from t;
That is, my first priority is to 'ca', then 'College '.id lstatus rn 123 brwr 3 123 ca 1 123 fac 2 345 ca 1 345 brwr 2 567 brwr 1 789 brwr 1 1011 fac 1 1011 xyz 2
I am aware that this can be done through the use of CASE within the order by clause
but could not find the logic of the apt.
Please help me.A solution just for data given to samples...
with t as ( select 123 id, 'brwr' lstatus from dual union all select 123 id, 'ca' lstatus from dual union all select 123 id, 'fac' lstatus from dual union all select 345 id, 'ca' lstatus from dual union all select 345 id, 'brwr' lstatus from dual union all select 567 id, 'brwr' lstatus from dual union all select 789 id, 'brwr' lstatus from dual union all select 1011 id, 'fac' lstatus from dual union all select 1011 id, 'xyz' lstatus from dual )select id,lstatus,row_number() over(partition by id order by (case when lstatus <> 'brwr' THEN UPPER(lstatus) else lstatus end)) rw from t;Basically, it shows how to use the CASE statement. You can change based on your actual data.
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Arun -
ORDER BY clause or HAVING clause... ERROR
Hi, I request what error throws please find the solution for the application to go without danger...
Select C.src_cd,
D.src_nm,
Count (*) supp_clm_count,
(CASE WHEN A.clm_ttladjamt > 0 then A.clm_ttladjamt to another A.clm_ttlreqamt END) as the amount
Of IWOWNER. WC_clm, a.
IWOWNER. WC_clm_srvc B,.
LOVELY. WC_SRC C.
LOVELY. WC_SRC_lang D
where A.clm_id = B.clm_id
and A.rcv_loc_id = C.src_id
and C.src_id = D.src_id
and TRANSLATE (A.clm_rqst_type_cd) = "SUPPLIERCLAIM".
and TRANSLATE (A.clm_typ_cd) in ('GUARANTEE', 'PRE-DELIVERY')
and DATE (A.clm_create_dt) between January 1, 2000 "and on January 1, 2010"
C.src_cd group, D.src_nm
ERROR:
-------
SQLSTATE: 42803, SQLERRMC: CLM_TTLADJAMT
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With oracle, you can try this query.
Salim cordially.
/* Formatted on 2009/07/22 10:10 (Formatter Plus v4.8.8) */ SELECT DISTINCT c.src_cd, d.src_nm, COUNT (1) OVER (PARTITION BY c.src_cd, d.src_nm) supp_clm_count, (CASE WHEN a.clm_ttladjamt > 0 THEN a.clm_ttladjamt ELSE a.clm_ttlreqamt END ) AS amount FROM iwowner.wc_clm a, iwowner.wc_clm_srvc b, showner.wc_src c, showner.wc_src_lang d WHERE a.clm_id = b.clm_id AND a.rcv_loc_id = c.src_id AND c.src_id = d.src_id AND a.clm_rqst_type_cd = 'SUPPLIERCLAIM' AND a.clm_typ_cd IN ('WARRANTY', 'PRE-DELIVERY') AND a.clm_create_dt BETWEEN TO_DATE ('01/01/2000', 'dd/mm/yyyy') AND TO_DATE ('01/01/2010', 'dd/mm/yyyy') -
Break the order of substitution of my ORDER BY clause
Hi Experts,
I've created a report in Oracle 6i where I receive the ORDER BY clause at run time. And in the datamodel application, I use a lexical to tell parameter, column selected in the parameter order.
The problem facing me, during execution, the ORDER BY clause is ignored by the report, and takes the column mentioned with the order break property as "Crescent" sort by this column.
I'm not able to set the order property of break None for all columns, as Builder's mistake out asking me to have at least one column Asc or Desc value!
Anyone know this problem before? Is there anyway to get rid of this and use the report by columns in the ORDER BY clause.
Please note: I tried an explicit BY < columnname > ORDER in the query data model, but again the report uses the value of the mentioned pause command and sorts by that column.
Appreciate your help on the same.
Thank you!Hello
There is a simple rule, how it works. For each query, you have one or more groups (hierarchical) in the data model. For the lowest group ORDER BY is selected for sorting and for groups, not be the lowest group, the ORDER of ROMPRÉ is chosen (and vice versa ignored).
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Rainer -
Level data column as a level line with headers
Hello
I want to ouput as follows. Please help me.
Table:
A B C D
-- ---- ---- ---
1 65 SRI TESTO/p:
Value of the variable
A 1
SRI B
C TEST
D 65
Thanks in advance.
Kind regards
Amandine
Hello
As said previously it is not a good idea to store numers as strings, but if you do you can use the below:
WITH T AS
(
Select
1A
, "SRI" B
, 'TEST' C
65DOf
DOUBLE
)
SELECT
COLUMN-NAME
VAL
Of
T UNPIVOT (VAL FOR COL_NAME (B, C))
UNION ALL
SELECT
COLUMN-NAME
TO_CHAR (VAL)
Of
T UNPIVOT (VAL FOR COLUMN IN (A, D))
ORDER BY
COLUMN-NAME
;Kind regards
Peter
-
Number data type used on a date column
Hi Forum,
I have a table with one column defined as number type.
This column contains the date information and has an index defined on it.
When I issue a select statement on this table based on this column for over 5 years of data, the query takes a long time.
Select count (*) in x if date = 20070411
The query takes a long time.
such a situation is causing a problem when the where clause on a date, but the field filters is defined has a number type.
All the columns in this table are defined as non-unique, but the date column seems to be more selective.
Just curious to know if this type of data can have any impact IE do not provide the correct information to the optimizer etc.?
Thanks for any help or advice
Hello
user3206995 wrote:
Hi Forum,
I have a table with one column defined as number type.
This column contains the date information and has an index defined on it.
When I issue a select statement on this table based on this column for over 5 years of data, the query takes a long time.
Select count (*) in x if date = 20070411
The query takes a long time.
such a situation is causing a problem when the where clause on a date, but the field filters is defined has a number type.
Yes; You can count on having a lot of different problems, if you are storing information on dates in NUMBER of columns. The columns DATE to the date information.
DATE is also a keyword from Oracle, so it's a very bad name of a column. Use a column name as entry_date or date_column instead of just date.
All the columns in this table are defined as non-unique, but the date column seems to be more selective.
If
date_column = 20070411
is the only requirement, and it is slow, then it seems that you do not have an index on date_column, and you need to create a.
For all performance issues, see the FAQ forum:
Re: 3. how to improve the performance of my query? / My query is slow.
Just curious to know if this type of data can have any impact IE do not provide the correct information to the optimizer etc.?
It doesn't look like this problem is caused by using the wrong type of data. Many others will, however.
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