Outline around the selected items of OCD

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• Get rid of the black borders around the selected items?

  My granddaughter of thirteen months was interested in my keyboard and now each selected item has a black frame to highlight... and there is a small sign at the bottom left of the screen showing what I typed just, by providing the keystrokes, etc..

  What is and how to turn everything off?

  Thank you!

  ED in Brooklyn

  System preferences/accessibility/voice off - turn off the power. Command - F5 works also.

• Appearance of the selected item

  Overall, I like the appearance of the Explorer of Windows Vista.  However, when an item is selected, the color of the selected item is so light that it is (for me) almost not visible.  I can change the classic theme, but really prefer to make just the darker outline.  How would I go to do this?

  Hello

  Panel Setup/Customize/Windows color and appearance of the control, use the slider to increase the intensity. There is no additional controls beyond that for aero colors. Good luck, Rick Rogers, aka "Crazy" - Microsoft MVP http://mvp.support.microsoft.com Windows help - www.rickrogers.org

• Grey outline around the objects when exporting to Photoshop

  Hello

  I have a strange issue when exporting with a simple badge that I'm working on Illustrator to Photoshop.

  Everything seems well within the Illustrator, but when I select my creation and copy and paste into Photoshop, then as a "dynamic object" or "pixels", I get a strange gray outline around the objects that should be hidden.

  I use the latest versions of Illustrator and Photoshop 2015 CC and their installation on Mac OSX El Capitan v. 10.11.3

  Edit: I noticed that the compression of the screenshots, it is difficult to see, but it should be very obvious if you download AI and try it yourself.

  I link to the file: http://bit.ly/1QhIi6i

  Best regards

  Rasmus

  

  

  

  

  I think that the problem is more on the side of Photoshop.

  Rasterize the objects in Illustrator; no visible lines.

  Pixelation in Photoshop; the Ant-aliasing artifacts.

  It is easy to reproduce: put a couple of black oval overlaid. Use Pathfinder > divide

  Now you have perfectly fitting distinct forms.

  Copy and paste into Photoshop; lines.

  Rasterize them (or use the pixelation effect) in Illustrator, copy and paste it into Photoshop. no lines.

• Cant' import images of Photos because "it is not enough free space on the volume of your library to import the selected items.

  Hey guys,.

  So I tried to import some ~ 8 GB of photos on my mac, but the Photos app gives me the following message: "there isn't enough free space on the volume of your library to import the selected items. It is estimated that you need at least X.XX GB of additional free space. »

  Where X.XX represents the amount of GB it says that I need but it changes everytime that I reopen the application to attempt an import.

  My mac has currently 44.4 GB so I don't know why this issue is coming.

  Any help would be great!

  Thanks in advance,

  Andres

  Where is your library?  If it's on an external HD and how the drive is formatted?

  Have you tried to repair the library according to this document from Apple: library of your repair?

  What version of PHotos do you use?

  

• To access the selected items in a ListBox control

  In LabVIEW 2010, I have a ListBox control. How can I get a list of the objects that the user selected in the ListBox?

  I don't see any method, property or event that would provide this information.

  Thank you.

  The value of the ListBox are the indexes of the selected items.

  If you allow the user to select "0 or more' items, the data type will change in a table."

  To get the names of the selected items (I guess that is what you want), you should India property 'element names.

  Tone

• How to detect when the selected item ObjectListField changed?

  I expanded the ObjectListField to implement a scroller of marquee style iPod for long lines of text that will disappear from the screen. So far, I have everything works well, and it works as I expect... when it fires.

  I'm having a problem to find a way to make reliable activate. It doesn't seem to be any method I can substitute or any earpiece I can use that fires when the current list item is changed. I first tried setSelectedIndex substitution. That worked sometimes, because apparently the OS is not call setSelectedIndex when he wants to change the item selected, it does something else.

  Then I tried the substitution of navigationMovement and manually call the code to start the timer, but that no longer works (I was the substitution of method navigationMovement of the ListField, maybe I should have done the Manager instead?). But anyway this approach does work for the version of the storm of my application because the storm never calls navigationMovement.

  Then I tried to use a fieldChangeListener, but apparently who don't get fired for the selection.

  Finally in despiration I tried substitution of drawListRow, only qualifying when index equals the selectedRow. But my code of scroll calls invalidate, so of course it just causes a loop infinite drawListRow, slow down the device and not even starting the scroll, because whenever the timer is started, it cancels the old one.

  Anyone have any ideas on what I can do here? Thank you.

  Good end I could not fieldChangeNotify to the fire, no matter which I overrided, even with the first setting the listener. It only seems fair to shoot during the selection change event. One thing to note, I use an objectlistfield, not an ObjectChoiceField... maybe you are thinking as well to another area?

  Thanks for the help anyway, in the end I was able to get the desired effect by modifying the code slightly to reuse the same animation timer rather than create a new one when the selected item changes. The timer is started in the constructor of the ListField. Works very well.

• get the values of the selected items to RichSelectManyChoice

  Hi all

  I have a RichSelectManyChoice

  When the user clicks on the "submit" button I want to get the values of the selected items...

  
  

  ----------------------------------------------------------page.jspx-----------------------------------------------------------------------------

  <? XML version = "1.0" encoding = "UTF - 8"? >

  " < = xmlns:jsp jsp:root ' http://Java.Sun.com/JSP/page "version ="2.1"xmlns:f =" " http://Java.Sun.com/JSF/core "

  ' xmlns:af = ' http://xmlns.Oracle.com/ADF/faces/rich "> "

  < jsp:directive.page contentType = text/html"; Charset = UTF - 8 "/ >

  < f: view >

  < af:document title = "untitled1.jspx" id = "d1" > "

  < af:messages id = "m1" / >

  < af:form id = "f1" >

  < af:panelGridLayout id = "pgl1" >

  < af:gridRow height = "100%" id = "gr1" >

  < af:gridCell width = '100% ' halign = "stretch" valign = "stretch" id = "gc1" >

  <! - content - >

  < af:selectManyChoice value = "#{bindings." CountriesView1.inputValue}.

  label = "#{bindings." CountriesView1.label}"id ="smc1.

  valuePassThru Binding = "#{suspect." Country}"="true">

  < f: selectItems value = "#{bindings." CountriesView1.items}"id ="si1"/ >

  < f: validator binding = "#{bindings." CountriesView1.validator} "/ >"

  < / af:selectManyChoice >

  < / af:gridCell >

  < / af:gridRow >

  < / af:panelGridLayout >

  < text af:button = "Button 1" id = "b1" action = "#{suspect.valide}" / >

  < / af:form >

  < / af:document >

  < / f: view >

  < / jsp:root >

  ---------------------------------------------------------------------------------------------------------------------------------------

  --------------------------------------------------------------------suspect.java-------------------------------------------------------------------

  package test.view;

  import com.sun.org.apache.xpath.internal.operations.String;

  Import oracle.adf.view.rich.component.rich.input.RichSelectManyChoice;

  public class suspect {}

  RichSelectManyChoice campaign private;

  String string = null;

  public suspect() {}

  ????????????????????????????????????????

  }

  public void valide() {}

  }

  {} public void setCountry (RichSelectManyChoice country)

  This.Country = country;

  }

  public RichSelectManyChoice {} getCountry()

  back country;

  }

  }

  ---------------------------------------------------------------------------------------------------------------------------------------------------------
  

  
  

  Anyone has an idea please?

  Hello

  You can use

  JUCtrlListBinding listBindings = (JUCtrlListBinding) getBindings () .get ("CountriesView1");

  Object [] str = listBindings.getSelectedValues ();

  for (int i = 0; i)< str.length;="" i++)="">

  System.out.println (STR [i]);

  }

  in this loop, you will get all the values of selectManyChoice, for details see Ashish Awasthi (Jdev/ADF) Blog: using the selection Multiple (component selectManyListbox & selectManyCheckbox) in ADF

  hope it helps

• The ghost as a white outline around the text at the beginning of the appearance.

  When I superimpose a title (with a black font) at the beginning of a clip and apply a bland cross both default to fade in, I see a ghost as a white outline around the text at the beginning of the appearance. Happened to the CS6.

  [title published by mod]

  Place a fade on top a dissolution can cause unexpected results for the balance.

  A suggestion for a better (more reliable) way to fade in multiple layers - especially when these layers are compositing - is to place a Black video clip (you can generate a new element function) on a layer above several clips you want to fade in or out and then just melted this black clip to fade in the lower layers , or fade the back clip to Dim lower layers.

  Not having dissolved individual on each track also makes it easier to adjust the fade in and out, as you only need to adjust the length of the transition from one dissolve applied to your black clip.

  MtD

• How to change the background color of selection of the selected item in the drop-down box of choice?

  How to change the background color of selection of the selected item in the drop-down box of choice?

  By default, the selection background color like 'blue', but if I want it to be "yellow" for example, how should I do?

  Thank you

  The id is applied by (I think) the skin of the ChoiceBox class. You don't need to define.

  You must apply the css in an external style sheet. You can apply the external style sheet to any parent of the box of your choice, or on-site (the most usual way to do it).

  Example:

  import java.util.ArrayList;
  import java.util.List;
  
  import javafx.application.Application;
  import javafx.scene.Scene;
  import javafx.scene.control.ChoiceBox;
  import javafx.scene.layout.VBox;
  import javafx.stage.Stage;
  
  public class ChoiceBoxTest extends Application {
  
    @Override
    public void start(Stage primaryStage) throws Exception {
      primaryStage.setTitle("Example 2");
  
      final ChoiceBox choiceBox = new ChoiceBox<>();
  
      List tempResult = new ArrayList();
      for (int i = 0; i < 10; i++) {
        tempResult.add("Item " + i);
      }
      choiceBox.getItems().setAll(tempResult);
  
      VBox root = new VBox();
      root.getChildren().add(choiceBox);
      final Scene scene = new Scene(root, 300, 250);
      scene.getStylesheets().add("choiceBox.css");
      primaryStage.setScene(scene);
      primaryStage.show();
    }
  
    public static void main(String[] args) {
      launch(args);
    }
  
  }
  

  choiceBox.css:

  @CHARSET "UTF-8";
  #choice-box-menu-item:focused  {
   -fx-background-color: yellow ;
  }
  #choice-box-menu-item .label {
   -fx-text-fill: black ;
  }
  

  Post edited by: James_D

• Download the work plan of the selected item

  I have the script where I select objects on the artboard multiple, but I can't seem to get advice art activates the selected item. Is this possible?

  each work plan is a text element and I that they in the same position on each of their own work plans they are already a. now it fits them all to a work plan. Here's what I have so far

  doc = app.activeDocument;
  for(i = 0; i < selection.length; i++){
      var firstItemPosition = doc.selection[0].position;
      doc.selection[i].position = firstItemPosition;
      var activeArtboardIndex = doc.artboards.getActiveArtboardIndex();
      alert(activeArtboardIndex);
   }
  

  .. .or with a "brute force" approach

  // return each selected item's artboard index
  // carlos canto 09/28/2013
  // http://forums.adobe.com/message/5721205?tstart=0#5721205
  
  var idoc = app.activeDocument;
  app.userInteractionLevel = UserInteractionLevel.DONTDISPLAYALERTS;
  var selec = idoc.selection;
  
  var sel = [];
  for(i = 0; i < selec.length; i++)
      sel.push(selec[i]);
  
  for(j = 0; j < sel.length; j++) {
      idoc.selection = null;
      alert('selection ' + j + objectArboardIindex (sel[j]));
  }
  
  for(j = 0; j < sel.length; j++)
      sel[j].selected = true;
  
  app.userInteractionLevel = UserInteractionLevel.DISPLAYALERTS; 
  
  function objectArboardIindex (obj) {
      var idoc = app.activeDocument;
      for(i=0; i		   

• Determine the index of the selected items in a ListBox?

  Hello

  I can't find a simple/direct method to determine the index of the selected item in a list box.

  I feel I'm missing something, but I can't seem to figure out who (if any) returns an index number if you use it with the recall of .onChange for a ListBox control.

  The following code implements that I need, but is not particularly efficient or elegant and can get confused if you introduce multiple lists to check.

  Any suggestions to reproduce this behavior, even with the best code would be appreciated.

  Thank you!

  var RES = ' palette {text: 'Example-list' properties: {resizable: true}-} ".

  NLP: Panel {orientation: 'row', preferredSize: [400 600]------}

  list1: ListBox {preferredSize: [400 550], properties: {multiselect: true, numberOfColumns:2, showHeaders:true, columnTitles: ["list 1", "item 0"]}}, \

  }}"

  var win = new Window (res)

  Win.Show)

  for (i = 0; i < 10; i ++) {}

  var line = win.pnl.list1.add ("point", "Same entry")

  row.subItems [0] .text = ' paragraph '+ i}.

  Win.PNL.List1.OnChange = function() {}

  var tempArray = new Array()

  for (i = 0; i < win.pnl.list1.items.length; i ++) {}

  If (win.pnl.list1.items [i] .selected == true) {tempArray.push (i)}

  }

  selectedRow = win.pnl.list1.items var [tempArray [0]] .text

  var selectedRowSubitem = win.pnl.list1.items [tempArray [0]] .subItems [0]

  Alert ("selection:" + tempArray + "\n posted content:" + selectedRow + "\t" + selectedRowSubitem)

  }

  .. .in the same time, that should be enough

  win.pnl.list1.onChange = function() {
       alert(this.selection.index); // for this to work set, multiselect:false
  }
  

  I guess you already tried and the result is 'undefined', the reason is that you have this property

  multiselect:true
  

  in this case, the selection returns an array

  this.selection[0].index;
  

  I'd give you the first selected item, even if you only have a single element selected, for all selected items to loop through all the elements in the selection table.

  not sure if the wonderful guide Peter explains this (explained in the Guide to the tools), but you should read it too, he has tons of info.

• Get an AIArtHandle for all the selected items in the doc

  I'm doing what someone does in this other thread about the export in PNG.

  reference: http://forums.Adobe.com/thread/320685

  We have several layers (some off and locked).

  I would like to pass all the selected items to the Action of Image Optimization as a group rather than optimize each.  I use AIMatchingArt Suite to retrieve items selected, but it points to an array of AIArtHandles... any ideas?

  That's how I ended up doing and it works.  (In addition to the other code which has been referenced in the original post).

  I don't know if it would work better with an ArtSet, but it works.  Perhaps, if the images I'm flattening were somewhat more complicated, I would run in the duplication you mentioned.

  result = sAIActionManager-> PlayActionEvent (kAISelectAllAction, kDialogOff, NULL);

  result = sAIMatchingArt-> GetSelectedArt (store, & County);

  If {(result)

  Store = NULL;

  Count = 0;

  } else {}

  result = sAILayer-> InsertLayer (NULL, kPlaceAboveAll, & newLayer);

  If (newLayer &! result)

  {

  sAILayer-> SetLayerVisible (newLayer, true); See the layer

  sAILayer-> SetLayerIsTemplate (newLayer, false); Mark as NOT a model layer get exported

  sAILayer-> SetLayerEditable (newLayer, true);

  result = sAIArt-> NewArt (kGroupArt, kPlaceAboveAll, Nile, &group);)

  for (index = 0; (result == kNoErr) & (index< count="" );="" index++="" )="">

  Art AIArtHandle = (* store) [index];

  Copy of AIArtHandle;

  Add the art group

  result = sAIArt-> DuplicateArt (kPlaceInsideOnBottom, group, ©);)

  }

  }

  }

• Retain the selected items on the right side of the shuttle in cascade

  Hello
  
  I'm under Apex 4.0.2 and have a cascading shuttle point so that a user can filter the left side of the shuttle using the text field.
  
  However when filter it - the shuttle seems to lose the items already selected on the right side.
  
  How can I change the element of the shuttle so that the user can always see the selected items, and the filter only works the unselected points (left side)?
  
  Thank you
  Keith

  Hi Keith,

  I don't have a blog, so there is no post. However, this is what I did:

  1 set the P298_FILTER element to 'Submit when you press enter' and added a branch to the page that redirected to the same page

  2. make the following settings for the P298_SHUTTLE element:

  Cascading LOV Parent article (s): P298_FILTER
  Page items to submit: P298_SHUTTLE
  List of values definition:

  SELECT ENAME d, EMPNO r
  FROM EMP
  WHERE UPPER(ENAME) LIKE UPPER(:P298_FILTER) || '%'
  OR '%' || :P298_SHUTTLE || '%' LIKE '%:' || EMPNO || ':%'
  ORDER BY UPPER(ENAME)
  

  and that is it really. The WHERE clause filters the record based on a filter match or a match with the existing items from the shuttle

  Andy

• How to read the value of the selected item in the DropDownList control?

  Hello

  The DropDownList component has a selectedItem property is supposed to return a ListBase.

  But what I want is just the 'chain' which is supposed to be the selected item in the DropDownList control.

  How to read this value?

  Thank you

  -Malena

  You are misreading the documentation. ListBase.selectedItem returns an object. This item comes directly from your data provider, so you just have to go up or go for any property you need.