output of Get-store data in the table (datagrid)

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  expdp_schemas_18MAY2013_1.dmp

  expdp_schemas_18MAY2013_2.dmp

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  VI test1.par

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  DIRECTORY = DATA

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  No,

  DataPump cannot retrieve a dumpfile data in a flat file.

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• How to write a simple select query to get the data of the table as an XML.

  How to write a simple select query to get the data of the table as an XML. In the query, I'm just adding items below which i need be there in the XML document
  

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  I need to URL escapes with the UTF-8 code points that we have already achieved using the utl_http package. Please help how to do that without using the utl_http package.

  What is wrong with him?

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• Get the data in the table in the format of number

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  who gave this:

  124

  524

  If something goes wrong in trying to read the table, but what? and how can it be solved.

  I don't know what you're after, but if you want to use the same loop twice, then put it inside another loop... (Note that arrays start at index 0, not 1)

  for (var i = 0; i)<2;>

  for (var teller1 = 0; teller1<16; teller1++)="">
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  Can someone tell me, are there disadvantages, performance problems using default storage in oracle?
  
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• Choose the date of the table

  Hello
  
  It comes to my table
  

  CREATE TABLE TEMP_LEAP
    (
      "DATE_FROM" DATE
    )

  Insertion of the data in it with the procedure which takes 2 parameters of date format:
  

  CREATE OR REPLACE
  PROCEDURE  "T_PROC" (p_dat_from date, p_dat_to date) IS
  BEGIN
  
  
  DECLARE
  
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    st           NUMBER := 0;
  
  BEGIN
  
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  for p in 1 .. day     
             
  loop   
                  
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   commit; 
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  Now lets fill in the data in the table:
  

  execute T_PROC(TO_DATE('01.01.2010','DD.MM.YYYY'),TO_DATE('17.08.2013','DD.MM.YYYY'));

  Data are now filled in the table.
  
  I want to do is do a select statement that will make the following output data:
  

  01.01.2010 - 31.12.2011
  01.01.2012 - 31.12.2012
  01.01.2013 - 17.08.2013

  I want is to get the leap year if there is a. I only need of days in the year, so don't mind the months.
  
  I need to check if there is a leap year in considering the p_dat_from and p_dat_to.
  
  If it isn't then you will get a single record of our instruction select and values will be made of: p_dat_from - p_dat_to.
  
  If there is a leap year in our period we will arrive after statements (example above).
  
  01.01.2010 - 31.12.2011 <-first date is p_dat_from and second is the last day before the leap year
  01.01.2012 - 31.12.2012 <-this is leap year. First date is the beginning of the leap year and the last date is the end of the leap year or p_date_to (if it ends in leap years).
  01.01.2013 - 17.08.2013 <- and this is the period after the leap years.
  
  It is a piece of code that I fell or with up to now:
  

  SELECT
  MIN(date_from),
  MAX(date_from)
  FROM temp_leap
  WHERE remainder(to_number(to_char(date_from,'yyyy')),4) = 0
  union
  
  SELECT 
  
  MIN(date_from) over (partition by to_char(date_from,'yyyy')),
  MAX(date_from) OVER (PARTITION BY to_char(date_from,'yyyy'))
  FROM temp_leap
  WHERE remainder(to_number(to_char(date_from,'yyyy')),4) <> 0
  
  ORDER BY 1,2;

  OK, that's all. I hope that its understandable that I do.
  If you have a questions please ask away.
  
  PS is there anything I need to do. You don't have to bother with the questions "what i February is after before etc." I don't love about it. All the other logic is already fixed all I need is what I wrote above.
  
  Thank you.
  
  Published by: BluShadow on March 14, 2013 08:24
  Fixed barcode labels

  Here's a way...

  SQL> create table temp_leap(date_from DATE)
    2  /
  
  Table created.
  
  SQL>
  SQL> insert into temp_leap
    2  select date '2010-01-01' + rownum - 1
    3  from dual
    4  connect by rownum <= (date '2013-08-17' - date '2010-01-01') + 1
    5  /
  
  1325 rows created.
  
  SQL>
  SQL> commit
    2  /
  
  Commit complete.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  select min(date_from)||' - '||max(date_from)
    2  from
    3        (select date_from
    4              ,sum(leap_yr_switch) over (order by date_from) as leap_yr_switch_cnt
    5        from (
    6              select date_from
    7                    ,case when lag(leap_yr) over (order by date_from) != leap_yr then 1 else 0 end as leap_yr_switch
    8              from (
    9                    select date_from
   10                          ,case when mod(to_number(to_char(date_from,'YYYY')),400) = 0
   11                                 or (    mod(to_number(to_char(date_from,'YYYY')),4) = 0
   12                                     and mod(to_number(to_char(date_from,'YYYY')),100) != 0
   13                                    )
   14                           then 1 else 0 end as leap_yr
   15                    from temp_leap
   16                   )
   17             )
   18       )
   19  group by leap_yr_switch_cnt
   20* order by min(date_from)
  SQL> /
  
  MIN(DATE_FROM)||'-'||MAX(DATE_FROM)
  -------------------------------------------
  01-JAN-2010 00:00:00 - 31-DEC-2011 00:00:00
  01-JAN-2012 00:00:00 - 31-DEC-2012 00:00:00
  01-JAN-2013 00:00:00 - 17-AUG-2013 00:00:00
  

  Published by: BluShadow on March 14, 2013 08:51
  a slight correction in the calculation of the leap year, forgotten 100 years being does not leap.

• How to get a list of the tables more fragmented in Oracle?

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  Hi jerry2134,

  jerry2134 wrote:

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    2  select x.c1, x.c2, x.c3
    3  from example t
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    8               , c2 varchar2(500) path 'Field[@name="participantID"]'
    9               , c3 varchar2(500) path 'Field[@name="participantName"]'
   10       ) x
   11  ;
  
  3 rows inserted
  
  SQL> select * from hasil1;
  
  C1                     C2        C3
  ---------------------- --------- --------------------------------
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
  01234567890aaaaaaa     OD001     EQUITY SECURITIES INDONESIA,PT
   
  

• inserting data into the table

  Hi all
  I use forms [32 bit] Version 6.0.8.24.1 (Production)
  Oracle Database 10g Release 10.2.0.1.0 - Production
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  I heard that there is a different method of insetions
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  Thank you...

  user13329002 wrote:
  Thanks for everyone.
  I have to take the data from the table as e_name, e_code, of the table and insert it into another table with some other values such as
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  in other words, the values for Emp_status, emp_type I have no values in the e_table.so table and enter in e_table I have to hard code it.
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  can someone clear me of the foregoing.

  Thank you...

  Published by: user13329002 on February 15, 2011 20:11

  Yes... You can hardcode the values for Emp_status, emp_type.

  SQL> CREATE TABLE e_emp(emp_code NUMBER(10),emp_status VARCHAR2(1),emp_type VARCHAR2(1));
  
  Table created.
  
  SQL> create table e_table as (select * from e_emp);
  
  Table created.
  
  SQL> INSERT INTO e_table(emp_code) VALUES('1111');
  
  1 row created.
  
  SQL> insert into e_table(emp_code) values('2222');
  
  1 row created.
  
  SQL> select * from e_table;
  
    EMP_CODE E E
  ---------- - -
        1111
        2222
  
  SQL> insert into e_emp(emp_code,emp_status,emp_type) (select emp_code,'0','N' from e_table);
  
  2 rows created.
  
  SQL> select * from e_emp;
  
    EMP_CODE E E
  ---------- - -
        1111 0 N
        2222 0 N
  
  SQL> 
  

  I hope this helps.

  Kind regards
  Claudy