Partitioning and Clustering of Table

Similar Questions

• issue with tables and clusters

  Hello

  Another issue with the tables and clusters. I have three engines thatI move on XYZ and then measure something. I need to draw on the 3D, the result of the measurement. How to draw real XYZ and not the index of the data table positions? (I can't actully how to build the matrices 2D forX, Y and Z). In the figures, I give an example of what I need.

  Concerning

  You have to break the data out of the cluster and to present them to the graph 3d to a separate bays for X, Y, Z and W where 'W' is your values measured at the locations described by X, Y, Z.

  This thread shows how trace readings in space 3. The following image shows the data that the original author wanted to draw.

  

  Have fun

  Ben

• Conversion table of Partition Non-Partition and vice versa

  Hello
  
  I followed the method of Partition to Partition and vice versa conversion table below. Please suggest is here
  any other altrnative methods available to accomplish the same thing.
  
  Conversion table of partition table partitions. Export data, drop the table, create the table with partitions and
  import data into the same table, now, the data is organized with Partitions.
  
  Conversion table of partition table non-partition. Export data, drop the table, create the table without partitions and
  import data into the same table, now, the data are organized without Partitions.
  
  Thank you.

  Google "oracle Exchange partition".

• Collection of statistics on partitioned and non-partitioned tables

  Hi all
  My DB is 11.1
  
  I find that the collection of statistics on partitioned tables are really slow.
  

  TABLE_NAME                       NUM_ROWS     BLOCKS SAMPLE_SIZE LAST_ANALYZED PARTITIONED COMPRESSION
  ------------------------------ ---------- ---------- ----------- ------------- ----------- -----------
  O_FCT_BP1                        112123170     843140    11212317 8/30/2011 3:5            NO                    DISABLED
  LEON_123456                      112096060     521984    11209606 8/30/2011 4:2           NO                   ENABLED
  O_FCT                           115170000     486556      115170 8/29/2011 6:3            YES         
  
  SQL> SELECT COUNT(*)  FROM user_tab_subpartitions
    2  WHERE table_name =O_FCT'
    3  ;
  
    COUNT(*)
  ----------
         112

  I used the following script:

  BEGIN
    DBMS_STATS.GATHER_TABLE_STATS(ownname          => user,
                                  tabname          => O_FCT',
                                  method_opt       => 'for all columns size auto',
                                  degree           => 4,
                                  estimate_percent =>10,
                                  granularity      => 'ALL',
                                  cascade          => false);
  END;
  /

  It costs 2 minutes for the first two tables to gather statistics respectively, but more than 10 minutes for the partitioned table.
  Time of collection of statistics represents a large part of the time of the whole lot.
  Most of the work of the lot are at full load, which case all partitions and subpartitions will be affected and we cannot collect just specified partitions.
  
  Does anyone have experiences on this subject? Thank you very much.
  
  Best regards
  Leon
  
  Published by: user12064076 on August 30, 2011 01:45

  Hi Leon

  Why don't collect you statistics to the partition level? If your data partitions will not change after a day (score range date for ex), you can simply do to the partition level

  GRANULARITY-online 'SCORE' for partition level and
  GRANULARITY-online 'SUBPARTITION' for subpartition level

  You collect global stats whenever you can not require.

  Published by: user12035575 on August 30, 2011 01:50

• Can we have hash partition and list on 2 columns in the same table. How.

  Can we have hash partition and list on 2 columns in the same table. How.
  
  Work on 10g release 2

  # List-Hash is a valid composite partitioning strategy 11 from g.

• Bootcamp (Win10) has not started after you changed the partition and updated at El Cap.

  I have a MacBook Pro (retina, 15 inches, end of 2013), 2 GHz Intel Core i7 with 8 GB of Ram.

  I had 2 system installed, Win 10 + Yosemite from the windows of beginning and the use of most of the time.

  Yesterday, I ran out of disk space and passed the partition in OS X with disk utility.

  While I changed the partition and I also upgraded to the El Cap.

  After all, I can't start by winning 10 more, although I could see my windows in the startup disk Control Panel.

  I checked some thread here and mess with command autour terminal, but nothing has worked for me.

  Here is the result of diskutil:

  Jerbins-MacBook-Pro: ~ the jerbinyuan list $ diskutil

  / dev/disk0 (internal, physical):

  #: NAME SIZE TYPE IDENTIFIER

  0: GUID_partition_scheme * GB 251,0 disk0

  1: disk0s1 EFI EFI 209.7 MB

  2: Apple_HFS Macintosh HD 70.1 GB disk0s2

  3: disk0s3 Apple_Boot Recovery 650.0 MB HD

  4: Microsoft data base BART 30.0 GB disk0s4

  5: Microsoft database HOMER 150,0 GB disk0s5

  Jerbins-MacBook-Pro: ~ list of cs jerbinyuan$ diskutil

  No logical volume group CoreStorage found

  Jerbins-MacBook-Pro: ~ jerbinyuan$ sudo TPG - vv - r show/dev/disk0

  Password:

  See the TPG: / dev/disk0: mediasize = 251000193024; SectorSize = 512; blocks = 490234752

  See the TPG: / dev/disk0: MBR suspicious to sector 0

  See the TPG: / dev/disk0: Pri GPT to sector 1

  See the TPG: / dev/disk0: GPT Sec at sector 490234751

  start index size summary

  0 1 MBR

  1 1 Pri GPT header

  2 32 table GPT Pri

  34 6

  40 409600 1 part TPG - C12A7328-F81F-11D2-BA4B-00A0C93EC93B

  409640 136992184 2 part TPG - 48465300-0000-11AA-AA11-00306543ECAC

  137401824 1269536 3 part TPG - 426F6F74-0000-11AA-AA11-00306543ECAC

  768 138671360

  138672128 58595328 4 part TPG - EBD0A0A2-B9E5-4433-87C0-68B6B72699C7

  197267456 292966400 5 part TPG - EBD0A0A2-B9E5-4433-87C0-68B6B72699C7

  490233856 863

  490234719 32 table dry GPT

  490234751 1 dry GPT header

  Jerbins-MacBook-Pro: ~ jerbinyuan$ sudo fdisk/dev/disk0

  Disk: geometry / dev/disk0: 30515/255/63 [490234752 sectors]

  Signature: 0xAA55

  From end

  #: cyl hd s - cyl hd s id [Start - size]

  ------------------------------------------------------------------------

  1: EA 1023 254 63 - 1023 254 63 [1-409639] < unknown ID >

  2: AF 1023 254 63 - 1023 254 63 [409640-136992184] HFS +.

  3: AB 1023 254 63 - 1023 254 63 Boot Darwin [137401824-1269536]

  4: 0 b 1023 254 63-1023 254 63 [138672128-58595328] Win95 FAT-32

  Jerbins-MacBook-Pro: ~ jerbinyuan$ sudo dd if = / dev/rdisk0s4 account = 1 2 >/dev/null | hexdump - C

  00000000 2nd eb 58 90 42 53 44 20 20 34 34 00 02 20 20 00 | X.BSD 4.4...  .|

  00000010 02 00 00 00 00 00 00 20 00 f8 ff 00 00 f8 43 08 |... C. |

  18 00 00000020 7th e0 03 37 00 00 00 00 00 00 02 00 00 00 |... ~... 7..........|

  00000030 01 06 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |... |

  00000040 80 00 29 11 14 2f 2 a 42 41 52 54 20 20 20 20 20 |..) ... / * BART |

  00000050 20 20 46 41 54 33 32 20 20 20 31 c0 d0 bc 8F fa |  FAT32. 1... |

  00000060 00 7 c fb 8th d8 e8 00 00 83 19 bb 07 00 fc 5th c6 | | ......^.......|

  00000070 c0 ac 84 74 b4 06 0e cd 10 eb 30 cd 16 cd e4 f5 |... t... 0....|

  00000080 19 0D 0a 4th 6f 6F 2d 73 79 73 74 65 6 d 20 64 69 |... Nonsystem di |

  00000090 73 6B 0D 0 a 50 72 65 73 73 20 61 79 20 6 6 b 65 | SK... Press any ke |

  000000a 0 79 20 74 6f 20 72 65 62 6f 6f 74 0D 0 a 00 00 00 | is reboot... |

  000000b0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |... |

  *

  000001f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 55 aa |... U. |

  00000200

  Jerbins-MacBook-Pro: ~ jerbinyuan$ diskutil info/dev/disk0s5

  Identifier of the instrument: disk0s5

  Device node: / dev/disk0s5

  Set: No.

  Part of the whole: disk0

  Device / media name: BOOTCAMP

  Volume name: HOMER

  Gendarmerie: Yes

  Mount point: / Volumes/HOMER

  Personality of file system: NTFS

  Type (Bundle): ntfs

  Name (Visible to the user): Windows NT (NTFS) file system

  Partition type: Microsoft Basic Data

  Operating system can be installed: No.

  Media type: generic

  Protocol: PCI

  Smart: checked

  Volume UUID: 4EC75B8E-02A8-4B26-B7F3-5EA9D0A47FA9

  Disk / Partition UUID: 776C43C1-7E4C-4997-BDF5-A91FD406DEBD

  Total size: 150.0 GB (149998796800 Bytes) (exactly 292966400 512-Byte-units)

  Amount of free space: 18.5 GB (18479718400 Bytes) (exactly 36093200 512-Byte-units)

  Device block size: 512 bytes

  Allocation block size: 4096 bytes

  Support read-only: No.

  Volume read-only: Yes

  Location of the device: internal

  Removable media: no

  Solid State: Yes

  Thanks for help.

  Please follow the steps described in [help] can not boot Windows (8.1) after partition resizing .

• Missing Mac 8.1 Windows partition and Bootcamp

  So, I have seen very similar messages and followed several forums, but I can't yet figure out what to do next.

  I have 8.1 Windows on my Mac.  I wanted to repartition the Windows partition and make bigger it because I was running low on space, and the Windows partition is what I use it mostly for graduate studies.  About a year ago, I took an easy youtube video and used Mini Wizard Partition re-partition space and it worked perfectly.  I have found the same video and tried to repartition the Windows partition again, but apparently I royally screwed up.

  My BootCamp is not yet visible more in disk utility.  Under the partitions, there is an option called "disk0s4" greyed, but I'm not allowed to do something with it.  I can't verify or repair.  If I go to Applications, BootCamp Assistant is there, but he wants me to start the installation of BootCamp.  It was not an option to restart Windows more, and when I turned on with alt + market, Windows was not an option more.

  I followed this tutorial:

  http://nerdr.com/bootcamp-partition-lost-repairing-Mac-partitions/

  and when I restarted my Mac, restart Windows was an option. So I thought that I fixed it! EVIL.  My screen was black and said: 'Missing Operating System '.

  I downloaded EaseUS Data Recovery Wizard for Mac (because it was another suggestion), and I was able to recover and see the files on the NTFS disk0s4, so I'm quite positive, they have not all been completely erased.  Or at least the part of basic Windows is still there.  I can't recover the drive to anything, because it tells me that I will just be fitness on the same drive, and I honestly don't know how to retrieve these files will help with the side of the partition of things.

  I also used TestDisk and it seemed to find my missing partition, but in the middle of analysing it, it says something like "disk too small."  After further research, I went through and took only the most recent score that seemed to be deleted with NTFS, and when you are trying to do, it would allow me to make a 'logic' partition because he said something in red, as 'bad file.'

  My Mac still works perfectly, but I'm terribly need to recover my windows.  All suggestions are useful!  Thank you!

  Last login: Wed Mar 9 16:30:28 on ttys001

  Anna-Owenss-MacBook-Pro: ~ acowens1$ sudo gdisk/dev/rdisk0; "exit";

  GPT fdisk (gdisk) version 1.0.1

  WARNING: Open with shared lock devices will not have their

  table partition automatically reloaded!

  Scanning partition table:

  MBR: hybrid

  BSD: absent

  APM: absent

  TPG: present

  Found a valid GPT with hybrid MBR; using GPT.

  Command (? for help): p

  Disk/dev/rdisk0: 625142448 sectors, GiB 298,1

  Logical sector size: 512 bytes

  Identifier (GUID) of disc: 0000429B-368F-0000-CB2D-000003440000

  Partition table contains up to 128 entries

  First usable sector is 34, last usable area is 625142414

  The partitions will be aligned with the boundaries of sector 8

  Space free total is 277435021 areas (132,3 GiB)

  Starting number (sector) end (sector), Code name of size

  409639 40 1 200.0 MiB EF00 EFI system partition

  2 409640 268314855 127.7 giB customer AF00

  3 268314856 269584391 619.9 MiB AB00 Recovery HD

  4 547018752 625141759 37.3 giB 0700 BOOTCAMP

  Command (? for help): r

  Recovery/processing command (? for help): o

  Size of the disk is 625142448 areas (298,1 GiB)

  MBR disk identifier: 0x0000711C

  MBR partitions:

  Code of State sector Boot start end sector number

  1 1 547018751 primary 0xEE

  2 * 547018752 625141759 0 x 07 elementary school

  Recovery/processing command (? for help): h

  CAVEAT! Hybrid MBRs are flaky and dangerous! If you decide to not use one,

  Simply press enter at the prompt below and your partition table MBR will be

  be intact.

  Type one to three GPT partition numbers, separated by spaces, to be

  added to the hybrid MBR, in order: 2 3 4

  Partition of EFI GPT (0xEE) place first in the MBR (good for GRUB)? (Y/N): y

  Create entry for the #2 GPT partition (partition MBR #2)

  Enter a hex code MBR (default AF): n

  Set the bootable flag? (Y/N): n

  Create entry for the #3 GPT partition (partition MBR #3)

  Enter a hex code MBR (default AB):

  Set the bootable flag? (Y/N): n

  Create entry for the #4 GPT partition (partition MBR #4)

  Enter a hex code MBR (default 07):

  Set the bootable flag? (Y/N): y

  Recovery/processing command (? for help): o

  Size of the disk is 625142448 areas (298,1 GiB)

  MBR disk identifier: 0x0000711C

  MBR partitions:

  Code of State sector Boot start end sector number

  1 1 409639 primary 0xEE

  2 409640 268314855 primary 0 x 01

  3 268314856 269584391 primary 0xAB

  4 * 547018752 625141759 0 x 07 elementary school

  Recovery/processing command (? for help):

  I followed the suggestions of the post, but I was not allowed to use the option of 3 4 5 or rather 2 3 4 type, because #5 has been "too big or did not exist."  I'm at the point where I should be typing w (write) but I won't enter this command if it is not correct.

• Size of the partition and Index Local

  Hi all

  Database information: 11.2.0.3 64-bit Linux. It is a 3 RAC Cluster node.

  I recently partitioned a Parent and child tables as PARTITION of REFERENCE set. The parent table has been RANGE - partitioned. The first partition is on an integer column and the beaches are 0-1000, 10001-2000, 20001-30000 and so on. The secondary partition is on a date and it is partitioned for each quarter.

  I created a local index as follows (faullt2vehicle, offboard_load_date, record_type, Column_Y).

  Here's an example query I will carry out, where the date is covering 2 secondary partitions

  select  * from gets_tool_Fault t where fault2vehicle                                      = 12195
  and offboard_load_date                                 BETWEEN TO_DATE('2015-04-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
  AND TO_DATE('2015-07-01 00:00:00', 'yyyy-mm-dd hh24:mi:ss')
  AND record_type                                        IN('FLT','STP','HC','EGU','EOAEQP','CEL')
  

  When I generate the plan explain below is the output

  Plan hash value: 2702285198
  
  --------------------------------------------------------------------------------------------------------------------------
  | Id  | Operation                           | Name               | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
  --------------------------------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT                    |                    |   386 | 76428 |   244   (0)| 00:00:03 |       |       |
  |   1 |  PARTITION RANGE SINGLE             |                    |   386 | 76428 |   244   (0)| 00:00:03 |     2 |     2 |
  |   2 |   PARTITION RANGE ITERATOR          |                    |   386 | 76428 |   244   (0)| 00:00:03 |     7 |     8 |
  |   3 |    TABLE ACCESS BY LOCAL INDEX ROWID| GETS_TOOL_FAULT    |   386 | 76428 |   244   (0)| 00:00:03 |    10 |    18 |
  |*  4 |     INDEX RANGE SCAN                | GETS_TOOL_FAULT_C7 |   386 |       |     7   (0)| 00:00:01 |    10 |    18 |
  --------------------------------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     4 - access("FAULT2VEHICLE"=12195 AND "OFFBOARD_LOAD_DATE">=TO_DATE(' 2015-04-01 00:00:00', 'syyyy-mm-dd 
                hh24:mi:ss') AND "OFFBOARD_LOAD_DATE"<=TO_DATE(' 2015-07-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss'))
         filter("RECORD_TYPE"='CEL' OR "RECORD_TYPE"='EGU' OR "RECORD_TYPE"='EOAEQP' OR "RECORD_TYPE"='FLT' OR 
                "RECORD_TYPE"='HC' OR "RECORD_TYPE"='STP')
  
  

  If you observe the optimizer is currently to identify the partition, and then the secondary partition, but what is confusing to me, this is why the restricted PREMISES index scan scans all secondary partitions for a given partition. The partition should be not even as a value from PARTITION RANGE ITERATOR of 7 and 8.

  Interestingly, when I provide a date range which is in single partition the pruning is happening correctly
  
  Plan hash value: 3457799067
  
  --------------------------------------------------------------------------------------------------------------------------
  | Id  | Operation                           | Name               | Rows  | Bytes | Cost (%CPU)| Time     | Pstart| Pstop |
  --------------------------------------------------------------------------------------------------------------------------
  |   0 | SELECT STATEMENT                    |                    |     1 |   197 |     4   (0)| 00:00:01 |       |       |
  |   1 |  PARTITION RANGE SINGLE             |                    |     1 |   197 |     4   (0)| 00:00:01 |     2 |     2 |
  |   2 |   PARTITION RANGE SINGLE            |                    |     1 |   197 |     4   (0)| 00:00:01 |     7 |     7 |
  |*  3 |    TABLE ACCESS BY LOCAL INDEX ROWID| GETS_TOOL_FAULT    |     1 |   197 |     4   (0)| 00:00:01 |    16 |    16 |
  |*  4 |     INDEX RANGE SCAN                | GETS_TOOL_FAULT_N1 |     1 |       |     3   (0)| 00:00:01 |    16 |    16 |
  --------------------------------------------------------------------------------------------------------------------------
  
  Predicate Information (identified by operation id):
  ---------------------------------------------------
  
     3 - filter("RECORD_TYPE"='CEL' OR "RECORD_TYPE"='EGU' OR "RECORD_TYPE"='EOAEQP' OR "RECORD_TYPE"='FLT' OR 
                "RECORD_TYPE"='HC' OR "RECORD_TYPE"='STP')
     4 - access("FAULT2VEHICLE"=12195 AND "OFFBOARD_LOAD_DATE">=TO_DATE(' 2015-04-01 00:00:00', 'syyyy-mm-dd 
                hh24:mi:ss') AND "OFFBOARD_LOAD_DATE"<=TO_DATE(' 2015-06-01 00:00:00', 'syyyy-mm-dd hh24:mi:ss'))
  

  Thank you

  Jayadeep

  1. your index (faullt2vehicle, offboard_load_date, record_type, Column_Y), your query has a predicate based on a beach on the second column in this index, which means that the order of the index that must be examined is dictated by this predicate and each row in the range must be considered (filtered) to check the third predicate.  Basic guideline on the column in the index you are ordering for more effective use: If you have columns where predicates are always equal put these columns at the beginning of the index, the columns where predicates are usually based on a beach go towards the end. You seem to have been misled by reviews 'the prefix local index' stick to your two columns of partitioning at the front of your index - which should NOT be an automatic choice for the local index: see this note ( https://jonathanlewis.wordpress.com/2011/02/28/prefixed/ ) comments that follow and OTN article it is linked to.

  2 since you have two indexes that start the same way (this goes with the local prefix again) you made easy for the optimizer to choose the index (for you) is clearly evil. That's why behind the choice of the optimizer is probably another example of an issue that I spoke a few days ago: Re: Composite index + map selection N1 your index is probably greater than the index of C7, and the order of the entries in the C7 index probably makes the data much more dispersed that it really is (i.e. high clustering_factor).

  Concerning

  Jonathan Lewis

  PS (update):

  If there are many rows for each fault_id, then you must create an index from fault_id with 'compress 1' (or compress N if the first columns of the index N are repetitive).

  When dealing with range partitions do not forget that the high value partition is never reached in the document, do so based in the form "date_col BETWEEN date1 and date2", use the form "date_col > = dateX and date_col»< datey"="" or="" you="" may="" find="" that="" you="" are="" accessing="" one="" more="" partition="" than="" you="" hope="" to,="" and="" in="" some="" cases="" that="" may="" mean="" "multiple"="" (i.e.="" 2)="" when="" you="" were="" expecting="" 1="" (and="" the="" optimizer="" is="" much="" better="" at="" estimating="" costs="" for="" a="" single="">

• Partitioning of an existing Table using the EXCHANGE PARTITION

  Hi all

  I have one unpartitioned table I partitioned by Exchange, this table has several indexes and constraints (primary and foreign).

  ALTER TABLE notpart_table ADD (
      CONSTRAINT PK_KCESPITI PRIMARY KEY (K_CESP, TIPORD)
          USING INDEX TABLESPACE TBLS_CONTA,
      CONSTRAINT FK_KCONTO_CE FOREIGN KEY (K_CONTO) REFERENCES xxxx (K_CONTO));
  
  CREATE INDEX IX_NFATTURA_CE ON notpart_tab (ANNO_FATTURA, K_REGISTRO, K_REGFA, TIPORD)
      TABLESPACE TBLS_CONTA;
  
  
  
  
  

  after Create a partitioned Table Destination

  notpart_table2, I created the same constraints and indexes defined in notpart_table

  
  

  When I run

  
  

  ALTER TABLE notpart_table2
    EXCHANGE PARTITION PART_notpart_table2
    WITH TABLE notpart_table
    WITHOUT VALIDATION
    UPDATE GLOBAL INDEXES;
  
  
  
  

  I get: ora-02266

  Why?

  Thanks in advance for any help

  
  

  Post edited by: vigilant Rosario

  It is not exactly what you have. Very probably not partitioned table, you are partitioning is the parent to another table table:

  SQL > create table tbl1 (id number)
  2.

  Table created.

  SQL > alter table tbl1
  2 Add the constraint tbl1_pk
  3 primary key
  4.

  Modified table.

  SQL > create table tbl2 (id number)
  2.

  Table created.

  SQL > alter table tbl2
  2 Add the constraint tbl1_fk1
  3 foreign key
  4 references tbl1
  5.

  Modified table.

  SQL > insert into tbl1 values (1)
  2.

  1 line of creation.

  SQL > insert into tbl2 values (1)
  2.

  1 line of creation.

  SQL > create table tbl1_part (id number)
  2 partition by range (id)
  3 (partition p1 values less than (1000000))
  4.

  Table created.

  SQL >
  SQL > alter table tbl1_part
  Exchange 2 partition p1
  3 with table tbl1
  4 without validation
  5 update global indexes
  6.
  with table tbl1
  *
  ERROR at line 3:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys

  SQL >

  If so, of the foreign key and recreate it pointing to the partitioned table as parent after finished partitioning the table.

  SY.

• Find the right Partition for swap Partiton when there are PARTITION and SUBPARTITION

  Hi all

  I have a small problem:

  I want to find the right cause of partitions of the partition key.  I have a partition and a Subpartition (sample - table in annex).

  I leave the database to generate the partition (and name), the name is generated. I need to find for the exchange of partition

  the right of Partition has cause of a given value of the partition key (in this case EVOD_PART_DATE and 20141101 value).

  When I try to find the right partiton name, I would use generally not:

  SELECT DISTINCT dbms_rowid.rowid_object(ROWID) data_object_id
     FROM F_CONTRACT_EVENT
     WHERE  EVOD_PART_DATE = TO_DATE ('20141101','YYYYMMDD')
  

  Okay, I get 2 rows, I'm expecting one, but cause the result are the subpartions, I get this:

    SELECT *  FROM ALL_OBJECTS WHERE DATA_OBJECT_ID IN ( 155159,155154);
  

  I see:

  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4292    155159    155159    TABLE SUBPARTITION
  EVO_DM    F_CONTRACT_EVENT    SYS_SUBP4287    155154    155154    TABLE SUBPARTITION
  

  But I don't want the subparts, I want the PARTITON!

  The table:

  CREATE TABLE "EVO_DM"."A0_F_CONTRACT_EVENT" 
     ( "EVOD_DDATE_ID_VALID_FROM" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDATE_ID_VALID_TO" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DTIME_ID_START" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSUST_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCHAN_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DARTI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCAMP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DUSAG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOPSY_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDEVI_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DSHOP_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPLFO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DACCO_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DDECL_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOBJT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DOFFR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCNTR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCURR_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DCONT_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DIVWC_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "DD_SUBSCRIPTION_ID" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "SINGLE_ISSUE" NUMBER(8,0) DEFAULT 0, 
      "SUBSCRIPTION" NUMBER(8,0) DEFAULT 0, 
      "RENEWAL" NUMBER(8,0) DEFAULT 0, 
      "CONVERSION" NUMBER(8,0) DEFAULT 0, 
      "DOWNLOAD" NUMBER(8,0) DEFAULT 0, 
      "UPDATES" NUMBER(8,0) DEFAULT 0, 
      "NET_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "GROSS_VALUE_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "COMMISSION_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "TAX_IN_EUR" NUMBER(10,4) DEFAULT 0 NOT NULL ENABLE, 
      "POSITION_NR" NUMBER(3,0) DEFAULT -1, 
      "DD_ORDER_NR" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "EVOD_SOURCE_CD" VARCHAR2(50 BYTE) DEFAULT '~' NOT NULL ENABLE, 
      "FLAG_STOCK_RELEVANT" NUMBER(1,0) DEFAULT '0' NOT NULL ENABLE, 
      "RENEWAL_NR" NUMBER(3,0) DEFAULT -1, 
      "EVOD_DDATE_ID_SUBSCRIPTION" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
      "EVOD_DPRCG_ID" NUMBER(20,0) DEFAULT -1 NOT NULL ENABLE, 
    
     EVOD_PART_DATE DATE  GENERATED ALWAYS AS ( TRUNC(TO_DATE(TO_CHAR(EVOD_DDATE_ID_VALID_FROM),'YYYYMMDD'),'MM')) VIRTUAL)
  PARTITION BY RANGE(EVOD_PART_DATE)
  interval(NUMTOYMINTERVAL (1,'MONTH'))
  SUBPARTITION BY LIST(EVOD_SOURCE_CD)
  SUBPARTITION TEMPLATE(
  SUBPARTITION "P_ITUNES"  VALUES ('ITUNES') ,
  SUBPARTITION    "P_WSP"  VALUES ('WSP'),
  SUBPARTITION   "P_GOOGLE"  VALUES ('PLAYSTORE'),
  SUBPARTITION   "P_DEFAULT"  VALUES ('~') ,
  SUBPARTITION   "P_AMAZON"  VALUES ('AMAZON_EREADER', 'AMAZON_MANUELL', 'AMAZON_TABLET') ,
  SUBPARTITION    "P_MSD"  VALUES ('MSD')
  )
  (
   PARTITION P01 VALUES LESS THAN (TO_DATE('200310','YYYYMM')) SEGMENT CREATION DEFERRED
  )
  PARALLEL 10  ;
  

  Any ideas?

  Thanks for Berlin

  First of all - the DOF you posted is INVALID - you do not specify a delayed segment creation for partitions. Specify you for the table.

  Also, you must remove the DEFAULT value - 1 for the partitioning column. The value '-1' cannot be converted to a valid date for the virtual partitioning column value.» The default value is useless and will give confusion around the year exception err when the exception should actually provide a NULL value for a column not null.

  The documentation explains how to use the EXCHANGE PARTITION and has the code example

  Maintenance of Partitions

  Exchange a Partition of a partitioned Table interval

  You can exchange of range partitions in a partitioned table interval. However, you must make sure that the partition of the interval was created before that you can swap partition. You can leave the database create the partition in the partition of the interval of locking.

  The following example shows an Exchange partition for the interval_sales table, range-partitioned using the monthly from partitions of 1 January 2004. This example shows how to add data to the table using charge Exchange partition for June 2007. Assume there is only a local index on the interval_sales table and equivalent index have been created on the interval_sales_june_2007 table.

  LOCK TABLE interval_sales  PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  IN SHARE MODE;    ALTER TABLE interval_sales  EXCHANGE PARTITION FOR (TO_DATE('01-JUN-2007','dd-MON-yyyy'))  WITH TABLE interval_sales_jun_2007  INCLUDING INDEXES;
  

  Note the use of the FOR syntax to identify a partition that has been generated by the system. The name of the partition can be used by querying the *_TAB_PARTITIONS view of data dictionary to find the partition system-generated name.

  Given that the last paragraph? That's what showed Solomon.

  NOTE:-special attention to the FIRST paragraph. If you use segment carried OVER creating the partition you want to Exchange could NOT have been created yet.

  Make SURE that you lock the partition as the example shows, or you will get an exception if it has not been created.

  Also - we know NOT what PROBLEM you're trying to solve.

  If you exchange a PARTITION of a table subpartitioned your working table should actually be partitioned using the SAME parttioning as the subparts in the source table:

  See my response in this thread:

  https://forums.Oracle.com/forums/thread.jspa?threadID=2482090&TSTART=30

  In this thread I have provide the code example illustrating how the table should be created and made Exchange.

• Move the data from the partitions again tablespace - direct table filled by ETL

  Hello

  We have a large composite table date-range/hash partitioned table (using time partitioning 11.2.0.3 range)

  1 partition for each month and each such partition 4 under separate partitions.

  We want to move some data from most significant storage but also direct table and inserted in all the days as part of the data warehouse and large table want to ensure

  operations below result in errors in the data loading procedure

  Suppose also should not take long to run lines 40 million or more each month.

  Select *.

  Of user_tab_partitions

  Where table_name = 'CUSTOMER_TRANSACTION '.

  And nom_partition like 'SYS % '.

  1. (1) Alter table retailer_transaction and rename partition < nom_partition > CUST_PART_ < YYYYMM >
  1. (2) tablespace create dedicated for the month of the affected partition
  1. ((3) alter table retailer_transaction move tablespace subpartition < sys... > < partition_tablespace > created in 2) above

  ALTER table retailer_transaction change the default attributes for the partition < CUST_PART < YYYYMM > < tablespace in 2 above > tablespace)

  4 global index which would eventually rebuild afterwards due to the transition if movement makes no valid.

  Several local bitmap indexes that belong to partitions.

  Thoughts?

  Thank you

  I agree in a good store of data, everything should be according to the best practices ETL or guideline. I guess it is a FACT table, because it's big enough. A method that I can share (followed in the real world big DW) is "ELP" IE Partition Exchange loading. You can find the basic architecture of the Internet.

  The basic architecture is as

  The source (in your case partitioned) Table--> (unpartitioned) intermediate Table--> Table possible target (partitioned)--> the cleaning activities (and overtime).

  You can use any ETL tool for this (I won't mention any other reasons).

  Later, you can delete the original table and use that new table as your FACT table, your application will be available all the time. There are drawbacks as most uses of double-spaced, other than normal ETL these work will take certain amount of resources so that other ALS etc. In addition, if you load a few current days during these activities you plan / program accordingly.

  Your demo is also fine, but regular ETL may fail because you rename the partitions (some uses of ETL tool partition name, in case you ever ELP) also unusable global indexes can cause failure (you have local too?).

• How add us partition on an existing table?

  Hi gurus,

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Thank you

  What would be the best way to add a partition to an existing table?

  Is there a simple documentation for example?

  Was it something you were ask in an interview?

  You cannot add a partition to a table unless this table is a partitioned table.

  The table is already partitioned? If so, after the DDL.

  The Oracle documentation has examples of adding partitions to a table that is already partitioned

  Partition management

  Adding Partitions

  This section explains how to manually add partitions of a partitioned table and explains why partitions can be added specifically for partitioned more indexes.

  Adding a Partition to a partitioned Table range

  Use of the ALTER TABLE ... ADD PARTITION statement to add a new partition at the end 'high' (the point after the last existing partition). To add a partition at the beginning or in the middle of a table, use the SPLIT PARTITION clause.

• Need to create the Partition in the history table

  Hello

  I have an audit table that stores the data for the last 8 years in it and the customer wants to retain the data for the last 8 years. Now as adding data to this table is increasing, there is a delay in execution of report which are acquired by querying on this table.

  Basically, they go a from date and to date. Then these date are compared with two columns of dates in the table. The condition of the query will be as below

  TRUNC (NVL (DATE1, DATE2)) > = TRUNC (TO_DATE (?, ' dd/mm/yyyy ""))

  AND TRUNC (NVL (DATE1, DATE2)) < = TRUNC (TO_DATE (?, ' dd/mm/yyyy ""))

  Users can query for any date range.

  I am thinking of creating a Partition of the range on this table for each month during the 8 years of data. Please suggest on the question of whether I should use partition interval range to make it more effective. And would also create an Index on this partition for the above two day columns.

  12 (months) SO * 8 (years) = 98 would be created partitions. This will not overload the schema of database/Tablespace? Y at - it another effective way to set the table.

  Please suggest and let me know for any clarification.

  There are 2 approaches (but not limited to 2) to create the Partition on an existing table:

  Note: There is no ALTER TABLE statement to convert a heap table to a partitioned table.

  1. create a temporary Partitioned table with the same types of data in the column. Take a dump of the original table (HEAP) export and import the dump into the newly created partitioned intermediate table. After checking the data file the original and rename the interim even as the original table.

  2 using the package Oracle DBMS_REDEFINITION automates the steps above from said (not exactly the same steps, however) and its done online - which means there is no required downtime, the original table may undergo DML operations during this process of redefinition. View partitioning of a table online with DBMS_REDEFINITION | Oracle instructor

  According to my understanding if let us know as a partition interval then in April if there is an inserted record then it will create a new partition for the month of April will be of value less than 30 April 2014 "and all other documents created in April will pass under it"

  Yes, it's a feature of 11g, which Oracle manages adding partitions as needed. In earlier versions DBA can add partitions manually from time to time. Reference www.gavinsoorma.com/2009/09/11g-interval-partitioning/

  Here the reason for check the sent_out_datetime NVL will be NULL for few records, so in this case we want to get the records for dates of mapping them to received_datetime

  In addition, try to replace the NVL with COALESCE and test it. This would help improve performance.

• privileges for partitions and see them in object

  Hello
  
  Anyone seen this before? The dw team has an appid with privileges from read/write to a partitioned table.
  
  connected under appid adshX, I am able to choose among stgadm3. TMUTL_FND_POSN partition (p1)
  
  1 * select count (*) in the stgadm3. TMUTL_FND_POSN partition (p1)
  SQL > /.
  COUNT (*)
  --------------------------------------------------------------------------------
  927282
  
  again, logged in as adshX appid, I am able to choose among object, but only the name of the table is returned.
  SQL > select subobject_name, object_name, object_type, owner
  of object where owner = 'STGADM3' AND object_name = "TMUTL_FND_POSN";
  
  OWNER TYPE_OBJET PARAMETER SUBOBJECT_NAME
  --------------- ---------------------- --------------------- ----------------------
  STGADM3 TABLE TMUTL_FND_POSN
  
  If connected as sys or system, the partition table AND are returned from all_objectds.
  OWNER TYPE_OBJET PARAMETER SUBOBJECT_NAME
  --------------- ---------------------- --------------------- ----------------------
  STGADM3 TABLE PARTITION P1 TMUTL_FND_POSN
  STGADM3 TABLE TMUTL_FND_POSN P_MINUS_1 PARTITION
  STGADM3 TABLE TMUTL_FND_POSN
  
  In addition, the ID adshX have access to views dba_ *, but which returns the correct results.
  OWNER TYPE_OBJET PARAMETER SUBOBJECT_NAME
  --------------- ---------------------- --------------------- ----------------------
  STGADM3 TABLE PARTITION P1 TMUTL_FND_POSN
  STGADM3 TABLE TMUTL_FND_POSN P_MINUS_1 PARTITION
  STGADM3 TABLE TMUTL_FND_POSN
  
  My first thought was that some private was missing, but because they can read/write/create tables and partitions with this id, I don't know what other private, they would need so that the information will be displayed.
  
  It is an oracle 10g db.
  
  Thanks, Pete

  >
  My first thought was that some private was missing, but because they can read/write/create tables and partitions with this id, I don't know what other private, they would need so that the information will be displayed.
  >
  You can make it appear by granting the user to SELECT ANY TABLE or DBA, but you may not want to do. Even grant ON the table to the user allows you to hide the information of subpartion.

• Type logic Partition of an existing table

  Dear all,
  
  My database is 10gr 2 and Linux is the operating system.
  
  One of my table in the production database is huge and contains lots of data. Table is growing daily. There are many queries that users run on this table and the selection criteria is normally the date of entry of the registration, it's an Entrty_Date field with the date data type.
  
  I want a partition logical on this table in such a way, the table name remains the same, and data are logically partitioned.
  
  As if the Entry_Date is from 2005, a partition is made on criteria:
  
  
  2005-2006
  2006-2007
  .
  .

  2011

  . at the request of the user for records having entry date > 2011... the query is made only this piece of the table, which makes the fast query.
  
  I hope that I am able to make you understand my problem. If its possible in Oracle please let me know the name of the method and I'll RND on this one. And I have to do it on an existing table that contains a lot of data.
  
  Thank you
  Imran

  Hello

  You can do this
  http://www.Oracle-base.com/articles/Misc/PartitioningAnExistingTable.php
  I suggest go fill through the myths of have from before backward Oracle documentation and to understand and then to proceed
  http://download.Oracle.com/docs/CD/B10501_01/AppDev.920/a96612/d_redefi.htm

  -Pavan Kumar N