How add us partition on an existing table?

Similar Questions

• Cannot add the partition to an existing table.

  Hello

  I don't add the partition to an existing table that is not partitioned, get the error as a type of data not valid, then I'm not find syntax errors.

  ALTER TABLE MESSAGEX_XCHANGE

  ADD THE PARTITION OF RANGE (LAST_MODIFY_TIMESTAMP)

  (

  PARTITION old_data VALUES LESS THAN (To_TIMESTAMP('27/02/2014','DD/MM/YYYY')),

  You see for VALUES LESS THAN (To_TIMESTAMP('28/02/2014','DD/MM/YYYY')) of the PARTITION

  );

  Error report:

  SQL error: ORA-00902: invalid data type

  1. 00000 - "invalid data type".

  * Cause:

  * Action:

  Thank you

  Manon...

  You get this error because your edit statement has an invalid syntax. In addition, you cannot partition a table that is not already configured for partitioning!

  You have to physically re-create the partitioned table in order to add new partitions to it.

• How to add the new column in existing table to our desired location?

  How to add the new column in existing table to our desired location?

  For example, I have to add the new column 'course' before the salary column in the emp table.

  I think the best way is to add the column at the end of the table and create a new view with the order of the columns...

  Another option...

  places the data into a temporary table and recreate the table with the correct order of the columns, and then insert data to the table from the temporary table

  Refer

  Add column (from table) in the desired position

  Example:

  CREATE TABLE temp_my_user LIKE)

  SELECT * FROM password);

  DROP TABLE password;

  (Password) CREATE TABLE

  userID NUMBER

  , first name VARCAHR2 (25)

  , middleInitial VARCHAR2 (1)

  (, name VARCHAR2 (25));

  INSERT INTO password (userID, firstName, lastName)

  (SELECT username

  first name

  lastName

  OF temp_my_user);

  DROP TABLE temp_user;

• How can I add data file to an existing table on Oracle RAC ASM with no OMF? Thank you!

  How can I add data file to an existing table on Oracle RAC ASM with no OMF? Thank you!

  Hello

  So I guess you have some files in ASM, see your first existing file structure

  Select file_name

  from dba_data_files;

  and to add to an existing table, the example below (even if you're better sticking with OMFs!)-is that what you are looking for?

  SQL > create tablespace TEST1

  2 datafile '+ DATA' size 1 M;

  Created tablespace.

  SQL > select file_name in dba_data_files;

  FILE_NAME

  --------------------------------------------------------------------------------

  +Data/orcl2/datafile/users.259.859820983

  +Data/orcl2/datafile/undotbs1.258.859820983

  +Data/orcl2/datafile/SYSAUX.257.859820983

  +Data/orcl2/datafile/system.256.859820981

  +Data/orcl2/datafile/example.269.859821049

  +Data/orcl2/datafile/Test1.271.859843053

  6 selected lines.

  SQL > alter tablespace TEST1

  2 Add datafile ' + DATA / mynewfile01.dbf ' size 2 m;

  Tablespace altered.

  SQL > select file_name in dba_data_files;

  FILE_NAME

  --------------------------------------------------------------------------------

  +Data/orcl2/datafile/users.259.859820983

  +Data/orcl2/datafile/undotbs1.258.859820983

  +Data/orcl2/datafile/SYSAUX.257.859820983

  +Data/orcl2/datafile/system.256.859820981

  +Data/orcl2/datafile/example.269.859821049

  +Data/orcl2/datafile/Test1.271.859843053

  + DATA / mynewfile01.dbf

  Thank you

• Add the sequence to an existing table

  How can I add a sequence to an existing table in a new field called the User_Id? I use Oracle SQL Developer 3.0.04 version, and it provides an option to create a sequence that I did, called Log_Seq. So, I need to put this sequence in the Final_Log table under a column named User_Id. I'm stuck at this part. I'd appreciate any help I can get!

  Hello
  what you can do is to add a trigger on the table that make it work for you.

  For example:
  http://www.razorsql.com/features/oracle_add_sequence_trigger.html

  concerning
  Peter

• Add the cluster to an existing table in oracle

  Is it possible to add the cluster of an existing table? For example...

  I have a table:

  CREATE TABLE table_name)

  t_id number PRIMARY KEY,

  t_name varchar2 (50));

  Cluster:

  CLUSTER to CREATE my_cluster

  (c_id NUMBER) SIZE 100;

  Y at - it a command such as: ALTER TABLE t_name add CLUSTER my_cluster (t_id); or something like that?

  Because I want to table to look like this:

  CREATE TABLE table_name)

  t_id number PRIMARY KEY,

  t_name varchar2 (50))

  My_cluster (t_id) CLUSTER;

  And drop all the tables isn't really what I want to do.

  Thank you

  No,

  It is the reverse:

  A table can be stored as a segment of memory (the common way) or in a cluster.

  Will not be part of the table "in the cluster", but other parts outside.

  Please create a new table in the cluster and insert your data here.

  Sorry,

  Martin

• I can add a column to an existing table with the data.

  Hello
  
  I'm working on
  The Version of database: Oracle 9i
  
  I can add a column to an existing table that already has data with below given command.
  
  ALTER TABLE table_name
  ADD the definition of the column_name column;
  
  Kind regards
  John

  Add to that:

  If your new column is NOT "null", you need the task in 3 steps:

  1. Add the column without a NOT NULL constraint
  2. the default value of the new column added.
  3. Add the NOT NULL constraint in the new column.

  concerning
  AJ

• Partitioning of an existing Table.

  Hi exports.

  We have a table that is not partitioned in our production DB. Now we have to this partition table. Please suggest a solution how can we partition this table as this table is the primary table in the application.

  Kind regards...

  ASIT K. reducing

  AsitK.Mohanty wrote:

  Hi exports.

  We have a table that is not partitioned in our production DB. Now we have to this partition table. Please suggest a solution how can we partition this table as this table is the primary table in the application.

  Kind regards...

  ASIT K. reducing

  The easiest way is to simply create a new table and INSERT the data into the it from the old table. You will need a window of failure for the operation. After the new table is filled you can rebuild the constraints and indexes, rename/move the original table and rename the new table to the old name.

  You can also export the table data and import it into a new partitioned table.

  The short answer is: ALL of the data needs to be moved to new segments. IF the existing data are old and ready to be archived then now is the time to do it. Simply move only the data in the new table.

• Partitioning of an existing Table using the EXCHANGE PARTITION

  Hi all

  I have one unpartitioned table I partitioned by Exchange, this table has several indexes and constraints (primary and foreign).

  ALTER TABLE notpart_table ADD (
      CONSTRAINT PK_KCESPITI PRIMARY KEY (K_CESP, TIPORD)
          USING INDEX TABLESPACE TBLS_CONTA,
      CONSTRAINT FK_KCONTO_CE FOREIGN KEY (K_CONTO) REFERENCES xxxx (K_CONTO));
  
  CREATE INDEX IX_NFATTURA_CE ON notpart_tab (ANNO_FATTURA, K_REGISTRO, K_REGFA, TIPORD)
      TABLESPACE TBLS_CONTA;
  
  
  
  
  

  after Create a partitioned Table Destination

  notpart_table2, I created the same constraints and indexes defined in notpart_table

  
  

  When I run

  
  

  ALTER TABLE notpart_table2
    EXCHANGE PARTITION PART_notpart_table2
    WITH TABLE notpart_table
    WITHOUT VALIDATION
    UPDATE GLOBAL INDEXES;
  
  
  
  

  I get: ora-02266

  Why?

  Thanks in advance for any help

  
  

  Post edited by: vigilant Rosario

  It is not exactly what you have. Very probably not partitioned table, you are partitioning is the parent to another table table:

  SQL > create table tbl1 (id number)
  2.

  Table created.

  SQL > alter table tbl1
  2 Add the constraint tbl1_pk
  3 primary key
  4.

  Modified table.

  SQL > create table tbl2 (id number)
  2.

  Table created.

  SQL > alter table tbl2
  2 Add the constraint tbl1_fk1
  3 foreign key
  4 references tbl1
  5.

  Modified table.

  SQL > insert into tbl1 values (1)
  2.

  1 line of creation.

  SQL > insert into tbl2 values (1)
  2.

  1 line of creation.

  SQL > create table tbl1_part (id number)
  2 partition by range (id)
  3 (partition p1 values less than (1000000))
  4.

  Table created.

  SQL >
  SQL > alter table tbl1_part
  Exchange 2 partition p1
  3 with table tbl1
  4 without validation
  5 update global indexes
  6.
  with table tbl1
  *
  ERROR at line 3:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys

  SQL >

  If so, of the foreign key and recreate it pointing to the partitioned table as parent after finished partitioning the table.

  SY.

• Add the column to an existing table-based user-defined type

  Hello guys,.
  I am compiling my function that returns a type defined by the user based on an existing table. Throughout the process of initialization so my query returns an additional column - SCORE (1). Here is my package:
  
  create or replace
  PACKAGE STAFF_AGENCY_PKG AS
  
  TYPE TYPE_SEEKER_TABLE IS TABLE OF THE DRAW. SEEKER % ROWTYPE;
  FUNCTION GET_SEEKERS (IN_KEYWORD IN VARCHAR2)
  TYPE_SEEKER_TABLE RETURN PIPELINE;
  
  END STAFF_AGENCY_PKG;
  -------
  
  create or replace
  STAFF_AGENCY_PKG PACKAGE BODY
  AS
  
  FUNCTION GET_SEEKERS (IN_KEYWORD IN VARCHAR2)
  TYPE_SEEKER_TABLE RETURN PIPELINE
  IS
  R_TBL TYPE_SEEKER_TABLE; -to return
  BEGIN
  FOR R IN)
  SELECT Seeker.SEEKER_ID,
  Seeker.FIRSTNAME,
  Seeker.LASTNAME,
  Seeker.NATIONALITY,
  Seeker.ISELIGIBLE,
  Seeker.BIRTHDATE,
  Seeker.ISRECIEVEEMAILS,
  Seeker.HIGHESTDEGREE,
  Seeker.ETHNICITY,
  Seeker.GENDER,
  Seeker.ISDISABILITY,
  Seeker.DISABILITY,
  Seeker.CV,
  Seeker.PASSWORD,
  Seeker.PREFFERED_CITY,
  SEEKER. E-mail
  SEEKER. JOB_PREFERENCES_ID,
  SCORE (1)
  THE APPLICANT Seeker
  WHERE CONTAINS (CV, ' < query >)
  < textquery lang 'grammar' = 'context' = > ' |
  GET_RELATED_CATEGORIES (IN_KEYWORD) |
  ' < / textquery >
  < score datatype = "INTEGER" / >
  (< / query > ', 1) > 0
  )
  LOOP
  PIPE ROW (R); -Error (38,10): PLS-00382: expression is of the wrong type
  END LOOP;
  RETURN;
  
  END GET_SEEKERS;
  END STAFF_AGENCY_PKG;
  
  How do I change my user type to be sufficient?
  
  Oracle version 11.2.0.1.0
  Thanks in advance!

  >
  How do I change my user type to be sufficient?
  >
  You will need to create two new TYPEs. The one who has all the columns of the draw. The REQUESTOR table and the new column SCORE, then a TYPE which is an array of the first type.

  See example 12-22 using a Pipelined Table function for a Transformation in the PL/SQl language reference

  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28370/tuning.htm#i53120

  Here's the first part

  -- Define the ref cursor types and function
  CREATE OR REPLACE PACKAGE refcur_pkg IS
    TYPE refcur_t IS REF CURSOR RETURN employees%ROWTYPE;
    TYPE outrec_typ IS RECORD (
      var_num    NUMBER(6),
      var_char1  VARCHAR2(30),
      var_char2  VARCHAR2(30));
    TYPE outrecset IS TABLE OF outrec_typ;
   FUNCTION f_trans(p refcur_t)
        RETURN outrecset PIPELINED;
  END refcur_pkg;
  /
  
  CREATE OR REPLACE PACKAGE BODY refcur_pkg IS
    FUNCTION f_trans(p refcur_t)
     RETURN outrecset PIPELINED IS
      out_rec outrec_typ;
      in_rec  p%ROWTYPE;
    BEGIN
  

  Change

    TYPE outrec_typ IS RECORD (
      var_num    NUMBER(6),
      var_char1  VARCHAR2(30),
      var_char2  VARCHAR2(30));
    TYPE outrecset IS TABLE OF outrec_typ;
  

  to include all the columns you need. Unfortunately, you have to manually list all the columns in the draw. The REQUESTOR table. If you think you need this same structure in other places you must create them as SQL types instead of PL/SQL types.

  This example should be enough to show you how to modify your code to do something similar.

• Type logic Partition of an existing table

  Dear all,
  
  My database is 10gr 2 and Linux is the operating system.
  
  One of my table in the production database is huge and contains lots of data. Table is growing daily. There are many queries that users run on this table and the selection criteria is normally the date of entry of the registration, it's an Entrty_Date field with the date data type.
  
  I want a partition logical on this table in such a way, the table name remains the same, and data are logically partitioned.
  
  As if the Entry_Date is from 2005, a partition is made on criteria:
  
  
  2005-2006
  2006-2007
  .
  .

  2011

  . at the request of the user for records having entry date > 2011... the query is made only this piece of the table, which makes the fast query.
  
  I hope that I am able to make you understand my problem. If its possible in Oracle please let me know the name of the method and I'll RND on this one. And I have to do it on an existing table that contains a lot of data.
  
  Thank you
  Imran

  Hello

  You can do this
  http://www.Oracle-base.com/articles/Misc/PartitioningAnExistingTable.php
  I suggest go fill through the myths of have from before backward Oracle documentation and to understand and then to proceed
  http://download.Oracle.com/docs/CD/B10501_01/AppDev.920/a96612/d_redefi.htm

  -Pavan Kumar N

• Windows Media Player-how add audio files to the existing selection

  Editing of existing playlist in Player 12 - great pain

  In previous versions of media player, I could drag a song to a windows explore Panel directly in a playlist. so adding media was a nod to a playlist. Now, you must open it in the game Panel, add media, and you MUST CREATE a NEW NAME FOR THE list of READING which is ABSURD! In other words you can not change the playlist, click SAVE, and the playlist that you work is registered. You should always create a NEW name. What I do is add a '1' to the old name, create the NEW name, and then I have to go back and remove the old list. Once again. It is ridiculously heavy. Can Microsoft fix this? Everyone is significant pain is?

  Original name? If you change an unregistered playlist, then it doesn't have a name yet. It is quite normal that you must enter a name when you click on save the list for the first time. The next time you save, you will not have to enter a name more (because then it's not playlist not registered).

• Partition on existing Tables

  Hello
  
  I want to archive a database due to too much data into DB everymonth, so I have to delete the records from the previous month, which is about 4 million.
  
  Can someone give me idea to delete records as soon as possible. My opinion is to create the partition on the table and drop the partition once he becomes older.
  But if I want to introduce the partition then I have to create a partition in an existing table. So please give me the best way to introduce the partition of the existing table.
  
  It would really help that may suggest meanings.
  
  Thank you
  
  Spengler

  Here is an example

  CREATE TABLE my_table (
    id           NUMBER,
    description  VARCHAR2(50),
    create_date date
  )PARTITION BY RANGE (create_date)
  (PARTITION id_id0 VALUES LESS THAN (TO_DATE('26/08/2009', 'DD/MM/YYYY')) TABLESPACE users,
   PARTITION id_id1 VALUES LESS THAN (TO_DATE('27/08/2009', 'DD/MM/YYYY')) TABLESPACE users,
   PARTITION id_id2 VALUES LESS THAN (TO_DATE('28/08/2009', 'DD/MM/YYYY')) TABLESPACE users,
   PARTITION id_id3 VALUES LESS THAN (TO_DATE('29/08/2009', 'DD/MM/YYYY')) TABLESPACE users,
  PARTITION id_id4 VALUES LESS THAN (TO_DATE('30/08/2009', 'DD/MM/YYYY')) TABLESPACE users,
  PARTITION id_max  VALUES LESS THAN  (MAXVALUE) TABLESPACE users);
  

  -Insert the sample data

   INSERT INTO my_table  VALUES (0, 'ZERO',sysdate);
  INSERT INTO my_table  VALUES (1, 'One',sysdate+1);
  INSERT INTO my_table  VALUES (2, 'Two',sysdate+2);
  INSERT INTO my_table  VALUES (3, 'Three',sysdate+3);
  INSERT INTO my_table  VALUES (4, 'Four',sysdate+4);
  COMMIT;
  

  -You can run these queries to check the output.

  select * from my_table;
  select * from my_table partition(id_id0);
  select * from my_table partition(id_id1);
  select * from my_table partition(id_id2);
  select * from my_table partition(id_id3);
  select * from my_table partition(id_id4);
  select * from my_table partition(id_max);
  

  -Split partition

  ALTER TABLE my_table SPLIT PARTITION id_max AT (TO_DATE('01/09/2009', 'DD/MM/YYYY'))
  INTO (PARTITION id_id5 TABLESPACE users,PARTITION id_max TABLESPACE users);
  

  -Insert data into the new partition

  INSERT INTO my_table  VALUES (5, 'FIVE',sysdate+5);
  commit;
  

  -check

  select * from my_table partition(id_id5);
  

• Need to create the Partition in the history table

  Hello

  I have an audit table that stores the data for the last 8 years in it and the customer wants to retain the data for the last 8 years. Now as adding data to this table is increasing, there is a delay in execution of report which are acquired by querying on this table.

  Basically, they go a from date and to date. Then these date are compared with two columns of dates in the table. The condition of the query will be as below

  TRUNC (NVL (DATE1, DATE2)) > = TRUNC (TO_DATE (?, ' dd/mm/yyyy ""))

  AND TRUNC (NVL (DATE1, DATE2)) < = TRUNC (TO_DATE (?, ' dd/mm/yyyy ""))

  Users can query for any date range.

  I am thinking of creating a Partition of the range on this table for each month during the 8 years of data. Please suggest on the question of whether I should use partition interval range to make it more effective. And would also create an Index on this partition for the above two day columns.

  12 (months) SO * 8 (years) = 98 would be created partitions. This will not overload the schema of database/Tablespace? Y at - it another effective way to set the table.

  Please suggest and let me know for any clarification.

  There are 2 approaches (but not limited to 2) to create the Partition on an existing table:

  Note: There is no ALTER TABLE statement to convert a heap table to a partitioned table.

  1. create a temporary Partitioned table with the same types of data in the column. Take a dump of the original table (HEAP) export and import the dump into the newly created partitioned intermediate table. After checking the data file the original and rename the interim even as the original table.

  2 using the package Oracle DBMS_REDEFINITION automates the steps above from said (not exactly the same steps, however) and its done online - which means there is no required downtime, the original table may undergo DML operations during this process of redefinition. View partitioning of a table online with DBMS_REDEFINITION | Oracle instructor

  According to my understanding if let us know as a partition interval then in April if there is an inserted record then it will create a new partition for the month of April will be of value less than 30 April 2014 "and all other documents created in April will pass under it"

  Yes, it's a feature of 11g, which Oracle manages adding partitions as needed. In earlier versions DBA can add partitions manually from time to time. Reference www.gavinsoorma.com/2009/09/11g-interval-partitioning/

  Here the reason for check the sent_out_datetime NVL will be NULL for few records, so in this case we want to get the records for dates of mapping them to received_datetime

  In addition, try to replace the NVL with COALESCE and test it. This would help improve performance.

• How to add the primary key for the table with the existing data?

  The table is already busy data. There was no primary key before, so for each column, there are some duplicate values.
  
  I want to add a new column, which should be of the integer data type and can automatically incremented, from 001. I tried with Oracle SQL Developer, but it says "ORA-01758: table must be empty to add mandatory (NOT NULL) column. How can I do? Thank you!

  Hello

  Look for the [ALTER TABLE | http://download.oracle.com/docs/cd/B28359_01/server.111/b28286/statements_3001.htm#sthref4803] command to find out how to add a column (step (1)) and a (step (3)) constraint to an existing table.

  For the step (2):

  CREATE SEQUENCE  employee_id_seq
  START WITH  1
  ;
  
  UPDATE  employee
  SET     id  = employee_id_seq.NEXTVAL;
  

  When you create a sequence, START WITH 1 is the default value, so that the line is not really necessary above... I've included just to show how you could start with any number you have chosen.