Partitioning of a table in the production

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  Hi all
  
  I want to delete all partitions on all the tables in a schema having the number of lines equal to zero.
  
  I use the queries below to get a solution.
  
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  Select count (*) in the table table_name partition (nom_partition).
  
  Edited by: 887563 October 17, 2011 13:39

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  from dba_tab_partitions
  where table_owner = 'MY_SCHEMA'
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    v_statement varchar2(500);
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  Hi all
  
  I have a table partitioned, called temp1_list_cmpgn_hist_dtl, and it is partitioned by month (campaign_start_date).
  
  I tried, queries
  TRUNCATE TABLE temp1_list_cmpgn_hist_dtl PARTITION t_list_cmpgn_201006
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  03291 00000 - "invalid truncate option - missing keyword STORAGE"
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  I tried the query,
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  THX,
  Rod.

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  Also, I'll try to find the nom_partition for the 'temp1_list_cmpgn_hist_dtl' table, but it shows not all partitions, although there are partitions.
  I tried the query,
  SELECT Nom_partition from user_tab_partitions WHERE table_name = 'temp1_list_cmpgn_hist_dtl '.

  All the names of objects in the Oracle database, by default, are stored in uppercase letters, so make sure the upper case of the table name.

  John

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• Partitioning of an existing Table using the EXCHANGE PARTITION

  Hi all

  I have one unpartitioned table I partitioned by Exchange, this table has several indexes and constraints (primary and foreign).

  ALTER TABLE notpart_table ADD (
      CONSTRAINT PK_KCESPITI PRIMARY KEY (K_CESP, TIPORD)
          USING INDEX TABLESPACE TBLS_CONTA,
      CONSTRAINT FK_KCONTO_CE FOREIGN KEY (K_CONTO) REFERENCES xxxx (K_CONTO));
  
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  after Create a partitioned Table Destination

  notpart_table2, I created the same constraints and indexes defined in notpart_table

  
  

  When I run

  
  

  ALTER TABLE notpart_table2
    EXCHANGE PARTITION PART_notpart_table2
    WITH TABLE notpart_table
    WITHOUT VALIDATION
    UPDATE GLOBAL INDEXES;
  
  
  
  

  I get: ora-02266

  Why?

  Thanks in advance for any help

  
  

  Post edited by: vigilant Rosario

  It is not exactly what you have. Very probably not partitioned table, you are partitioning is the parent to another table table:

  SQL > create table tbl1 (id number)
  2.

  Table created.

  SQL > alter table tbl1
  2 Add the constraint tbl1_pk
  3 primary key
  4.

  Modified table.

  SQL > create table tbl2 (id number)
  2.

  Table created.

  SQL > alter table tbl2
  2 Add the constraint tbl1_fk1
  3 foreign key
  4 references tbl1
  5.

  Modified table.

  SQL > insert into tbl1 values (1)
  2.

  1 line of creation.

  SQL > insert into tbl2 values (1)
  2.

  1 line of creation.

  SQL > create table tbl1_part (id number)
  2 partition by range (id)
  3 (partition p1 values less than (1000000))
  4.

  Table created.

  SQL >
  SQL > alter table tbl1_part
  Exchange 2 partition p1
  3 with table tbl1
  4 without validation
  5 update global indexes
  6.
  with table tbl1
  *
  ERROR at line 3:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys

  SQL >

  If so, of the foreign key and recreate it pointing to the partitioned table as parent after finished partitioning the table.

  SY.

• Move the data from partition to partition of MAX table?

  11 GR 2, RHEL, 64-bit

  Guys,

  Is there a way to MOVE data to a specific partition on MAX in a partitioned table?

  While I can drop this specific partition and recreate it later, but I want the data to be resident in the MAX score until I recreate this specific partition.

  Pls suggest me?

  Thank you

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  Depends on the way in which the partitions are defined (the partition limit values), each partition will allow only certain values must be stored.

  Logically, the lines that are in partition 'A' cannot return to the partition'm ' because the limit / list of values for the two partitions is different.

  You can move the lines of a fictitious table / temp, but probably not to another partition until and unless MERGE you partitions (in which case the original partition doesn't exist).

  Hemant K Collette

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• A slower loading into partitioned table as the non partitioned table - why?

  Hello
  
  Using oracle 11.2.0.3.
  
  Have a large fact table and do some comparative tests on the loading of large amounts of data histroical (several hundred GB) in fact range partitioned to date table.
  
  Although I understand if use exhange partition loading may be faster to load a partitioned table, trying to figure out why a standard sql insert takes 3 x long to load a table partitioned compared to an identical table but not partitioned. Identical EVERYHING in terms of columsn and the sql that the insert and second partitioned sql execution to
  ensure caching with no impact.
  
  Local partitioned table a partitioned bitmap index as compared to the non-partitioned table that has standardnon-partioned bitmap indexes.
  
  Any ideas/thoughts?
  
  Thank you

  One would expect that the queries that cannot no partition pruning may be slowed down, Yes.

  An easy way to see this is to imagine that you have a partitioned local index b-tree and a query that needs to scan all partitions of the index to find a handful of lines that interest you (of course, this is not likely to be exactly what you see probably but we hope informative of the source of the problem). Let's say that each partition of the index has a height of 3, so for each partition, Oracle has read 3 blocks to reach the correct terminal node. So to analyze each of the N index partitions, you need block index 3 * N bed. If the index is not partitioned, perhaps the height of the index would go up to 4 or 5 If, in that case not partitioned, you must read 4 or 5 blocks. If you have hundreds or thousands of partitions, it can easily be hundreds of times more work to analyze all the index partitions individual he would to analyze one unpartitioned index.

  Partitioning is not a magical option "go faster". It is a compromise - you optimize certain operations (such as those that can partition pruning) at the expense of operations that do not partition size.

  Justin