PHP - sort an array in order descending

Similar Questions

• Sort groupItems Array using the left coordinate of visible limits?

  Hey all! It's been a while, but I'm back with some more busters of brain for you guys.

  I'm trying to re - work a script that Silly-V wrote to me. The goal is to create a work plan around each group of a document element in the order of the top left corner to the lower right (as if reading a book). (ultimately I would like to add a provision that excludes the possibility of having a work plan contained by another work plan, but it is a luxury that I can try to find later).

  Silly script works very well and does exactly what I need... about 60% of the time. The problem comes when I have an item that contains a clipping mask. Since work plans are created through groupItem.visibleBounds, Illustrator assumes that the invisible work that extends beyond the clipping mask is visible and creating a work plan that is too much.

  His version pushes the visible boundaries of each groupItem in an array, then sorts the visible boundaries of the left coordinate, then pushes this sub-table in another table and at the end, to coordinate kinds berries vertically at the top... However, I'm looking to push the real groupItems in the table instead of just the visible limits. So I would like to sort the groupItems by their visible limits table and then I have the opportunity of either by creating work plans based on their visible limits or (the possibility of) loop to make each groupItem selected = true and using the fitArtboardToSelectedart() command.

  I'm stuck on how to sort the groupItems table based on the visible limits... Here's what I have so far:

  my inclination is to set a variable to the visibleBounds of each groupItem in temp (which seems like it would need a loop), but it's not supposed loop me XIRR...? There is something really big, I'm missing here, but I can't wrap my head around it.

  Thanks for any help!

  function organize(){
    var docRef = app.activeDocument;
    var layer = docRef.layers[0];
    var groups = layer.groupItems;
    var currentRowMarker;
  
    var groupList = []; //array of all groupItems
    var sortedGroupList = []; //array of subarrays sorted by visible bounds
    var temp = []; //temporary array for the current row of groupItems. sort this array from left to right first, then push the entire array into "sortedGroupList"
  
  
    //populate groupList
  
  
    for (g=0; g<groups.length; g++){
         groupList.push(groups[g]);
    }
  
  
    //set currentRowMarker and compare rest of groupList to top coordinate of visible bounds. push true results to temp array.
  
  
    for (t=0; t<groupList.length; t++){
    temp = [];
    currentRowMarker = groupList[t].visibleBounds[1];
    temp.push(groupList[t]);
    groupList.splice(t,1);
  
         for (c=0; c<groupList.length; c++){
              var currentGroup = groupList[c];
              var vB = groupList[c].visibleBounds[1];
                   if (vB + 20 > currentRowMarker && vB - 20 < currentRowMarker){
                        temp.push(currentGroup);
                        groupList.splice(c,1);
                   }
         }
  
    //this is where i'd like to sort the temp array
  
    sortedGroupList.push(temp);
    }
  }
  organize();
  

  Thanks for your help, Vassili.

  I've been unable to get your suggestion to work, does not mean that it was an erroneous suggestion. So I decided to go the more complicated route. I hope that I can learn about why your suggestion did not work for me in a subsequent attempt.

  I am sure that this isn't the most elegant way to perform this task, but it was the only way that makes sense to me. Here's what I ended up with:

  for (s=temp.length; s>0; s--){
    var placeholder = 0;
    var farthestLeft;
    var deleteIndex;
         for (a=0; a		   

• to sort an array of numbers NOT as strings using the. sort()

  Hello

  y at - it a function or a simple way to sort an array of numbers in the order of their values and not as strings? For example, 100 came AFTER 9; (9, 100) (100, 9).

  Thank you.

  Use the ARRAY.numeric parameter.

  (and you can still use a custom for kinds more custom sort function parameter).

• Sorting multiple arrays at different indexes

  I have just another very quick question on tables, this time on the sort of them. I just re-wrote my code to use for correspondence with values of 2 tables and then adding them to the screen.

  However, it seems that my correspondent is far away, it matches the items that are the same index, which is not always the case

  The output for the matches, which should be next to sideis as follows (which is incorrect), so I'll try to find values to levels different index

  Dunlop
  Babolat
  Wilson
  Wilson
  Head
  Dunlop
  Adidas
  head
  Babolat
  Slazenger
  Slazeger
  Prince
  Prince
  Völkl
  Völkl
  Adidas

  I tried to sort the array, but it seems that the table cannot be sorted as I want. I simply wanted to do ascending sort, but change to lowecase wouldn't do what I had to do.

  This is the code, the matchInfo function should do all the work

  package {
       
       import flash.display.*;
       import fl.transitions.*;
       import fl.transitions.easing.*;
       import flash.net.*;
       import flash.events.*;
       import flash.text.*;
       import flash.text.AntiAliasType;
       import bucket_left;
       
       
       public class CustomClass extends MovieClip {
            
            //Position Variable
            private var position:uint;
            
            //XML responsible variables 
            private var xmlLoader:URLLoader;
            private var xmlContainer:XML;
            private var xmlList:XMLList;
            
            //Array specific variables 
            private var rackUSA:Array;
            private var rackOther:Array;
            private var imagesArray:Array;
            
            
            //This is the constructor of the application 
            public function CustomClass() {
                 position = 50;
                 rackUSA = new Array();
                 rackOther = new Array();
                 imagesArray =  new Array();
                 LoadXML();
            }
            
            private function LoadXML() {
                 xmlLoader = new URLLoader();
                 xmlLoader.load(new URLRequest("http://localhost/xml/index.php"));
                 xmlLoader.addEventListener(Event.COMPLETE, populateInfo);
            }
            
            public function populateImages(imgname:String, imgurl:String) {
                 var imageLoader:Loader = new Loader();
                 imgname = imgname.split(".gif").join("");
                 imageLoader.name = imgname;
                 imagesArray.push(imageLoader);
                        imageLoader.load(new URLRequest(imgurl));
            }
            
            public function matchInfo(infoArray:Array, imagesArray:Array) {
                 infoArray.sort();
                 trace(infoArray);
                 for (var c:uint = 0; c < imagesArray.length; c++) {
                      trace(infoArray[c].brand);
                      trace(imagesArray[c].name);
                      if (infoArray[c].brand.toLowerCase() == imagesArray[c].name) {
                           var brand:TextField   = new TextField();
                           var country:TextField = new TextField();
                           var made:TextField    = new TextField();
                           var cost:TextField    = new TextField();
                           var bucket                  = new bucket_left();
                           brand.text   = infoArray[c].brand;
                           country.text = infoArray[c].country;
                           made.text    = infoArray[c].made;
                           cost.text    = infoArray[c].cost;
                           
                           //Align Data
                           bucket.y = position;
                           bucket.x = 100;
                           brand.x = -50;
                           brand.y = -35;
                           country.x  = -45;
                           country.y  = -10; 
                           made.x = -45;
                           made.y = 5;
                           cost.x = 45;
                           cost.y = -10;
                           imagesArray[c].x = -100;
                           imagesArray[c].y = -35;
                           
                           addChildAt(bucket, 0);
                           bucket.addChild(DisplayObject(imagesArray[c]));
                           bucket.addChild(brand);
                           bucket.addChild(country);
                           bucket.addChild(made);
                           bucket.addChild(cost);
                      }
                      position += 150;
                 }
            }
            
            private function populateInfo(event:Event) {
                 
                 //Incoming XML Data
                 xmlContainer = new XML(event.target.data);
                 xmlList = xmlContainer.product;
                 //
                 
                 //Variables to hold the string
                 var brandTxt:String;
                 var country:String;
                 var material:String;
                 var price:String;
                 var image:String;
                 
                 for (var i:uint = 0; i < xmlList.length(); i++) {     
                 if (xmlList.country.text()[i] == "USA") {
                 brandTxt = xmlList.brand.text()[i];
                 country = "product of " + xmlList.country.text()[i];
                 material = "made of " + xmlList.material.text()[i];
                 price = "$" + xmlList.price.text()[i];
                 image = xmlList.image.text()[i];
                 rackUSA.push({brand: brandTxt, country: country, made: material, cost: price, pic: image});
                 } else if (xmlList.country.text()[i] == "Other") {
                 brandTxt = xmlList.brand.text()[i];
                 country = "product of " + xmlList.country.text()[i];
                 material = "made of " + xmlList.material.text()[i];
                 price = "$" + xmlList.price.text()[i];
                 image = xmlList.image.text()[i];
                 rackOther.push({brand: brandTxt, country: country, made: material, cost: price, pic: image});
                 }
                 populateImages(image, "http://localhost/rackets/" + image);
                 }
                 matchInfo(rackUSA.concat(rackOther), imagesArray);
            }
       }
  }
  

  given an element of imagesArray the following function returns the first object in infoArray where the brand property corresponds to the element:

  function infoArrayF(ldr:Loader):Object {}

  for (var i: uint = 0; i<>

  {if (infoArray [i]. Brand.toLowerCase () is LDR. Name)}

  return infoArray [i];

  }

  }

  }

  //

  and you can use this function as follows:

  var obj:Object = infoArrayF (imagesArray [c]);

  If you want just the hint of infoArray returned from infoArrayF, I return instead of infoArray [i]

• The order of the points in a sort pathPoints array

  Well, why would I do that? Well, I have areaText the rectangles that have been created by various means, and index 0 is sometimes high on the left, other times the bottom right. I need to do a lot of resizing, alignment, spacing, sizing. To describe the movement of the top left point of each (or anywhere else), I'm trying to clean up the sequence of points in each table pathPoints objects in order to move the pathPoint [0] .anchor for each rectangle and make sure that the upper left corner moves, not another random corner.

  Then, test only one script, and I came up with the following (don't laugh about how I called the table), which works very well in extendScript:

  var testArray = new Array;

  testArray.push ({xVal: 5,:0}) yVal;})

  testArray.push ({xVal: 0, yVal:-2});

  testArray.push ({xVal: 5, yVal:-2});

  testArray.push ({xVal: 0, yVal:0});})

  function primarySort() { testArray.sort (function (a, b) {return b.yVal - a.yVal});}   }

  function secondarySort() {}

  reorganize the first pair of xVal-based points

  If (Number(testArray[0].xVal) > Number(testArray[1].xVal)) {}

  Sensors = testArray [1];

  testArray.splice (1,1);

  testArray.unshift (moveMe) ;}

  reorganize the second pair of points based on xVal

  If (Number(testArray[2].xVal) < Number(testArray[3].xVal)) {}

  Sensors = testArray [2];

  testArray.splice (2.1);

  testArray.push (moveMe) ;}    }
  

  function printArray() {}

  for (i = 0; i < testArray.length; i ++) {}

  var writeMe is testArray [i].xVal.toString () + ', ' + testArray [i].yVal.toString ();.

  $.writeln (writeMe);  }}

  
  

  primarySort();

  printArray();

  $.writeln ('... ») ;

  secondarySort();

  printArray();

  So then I tried to do the same thing for Illustrator:

  var ObjArr = app.activeDocument.textFrames;

  var objPoints = new Array;

  for (i = 0; i < objArray.length; i ++) {}

  var pathObj = .textPath ObjArr [i];

  objPoints = pathObj.pathPoints;

  XYpairSort() ;}

  function XYpairSort() {}

  writes the current sequence of anchor pathPoint y coordinate x in the console

  for (i = 0; i < objPoints.length; i ++) {}

  writeMe var = objPoints [i] .anchor [0] m:System.NET.SocketAddress.ToString () + ', ' + objPoints [i] .anchor [1] m:System.NET.SocketAddress.ToString () + "," + i;

  $.writeln (writeMe) ;}

  Sort the four points at the top and at the bottom of the pairs

  objPoints.sort (function (a, b) {return b.anchor [1]-a.anchor [1]});

  reorganize the first pair of xVal-based points

  If (Number(objPoints[0].anchor[0]) > Number(objPoints[1].anchor[0])) {}

  Sensors = objPoints [1];

  objPoints.splice (1,1);

  objPoints.unshift (moveMe) ;}

  reorganize the second pair of points based on xVal

  If (Number(objPoints[2].anchor[0]) < Number(objPoints[3].anchor[0])) {}

  Sensors = objPoints [2];

  objPoints.splice (2.1);

  objPoints.push (moveMe) ;}

  writing the new sequence of pathPoint anchor y coordinate x in the console

  for (i = 0; i < objPoints.length; i ++) {}

  writeMe var = objPoints [i] .anchor [0] m:System.NET.SocketAddress.ToString () + ', ' + objPoints [i] .anchor [1] m:System.NET.SocketAddress.ToString () + "," + i;

  $.writeln (writeMe) ;}

  }

  Who raises an error "objPoints.sort is not a function".

  Unlike the single version JS, my script HERE trying to sort all the points of all of the textAreas, which I will fix shortly so it sorts the 4 points for each object. The problem is that the script is not sorting points, but providing a helpful error instead.

  Any ideas? Research on the Internet for this error does not explain why it happens, just in other ways to do the kinds.

  Well, if you did this time to the discussion, the approach I took is completely unnecessary.

  You see, I knew .top, .the .width and .height rectangles properties, and if you changed the width of a textFrame, he would scale the text that it contains:

  var obj = app.activeDocument.textFrames [0] / / guess that's narrower than the 2 inches

  obj. Width = 144; will scale the width of the block and its content also.

  Thus, to avoid the problem of scaling that I had to make sure that the textPaths of what I had selected was the same index order for I can enter each item individually and always take the same point for each textFrame. I was changing the height and width of each textFrame by assigning new XY coordinates at each angle of the trajectory. Good to know how to do this, but not necessary, because the attributes .top, .the, .width and .height are available for the textPath object.

  What I do not know (and do now), is that you can change the path without scaling the content:

  var obj = app.activeDocument.textFrames [0] / / guess that's narrower than the 2 inches

  var objPath = obj.textPath;

  objPath.width = 144;  is not at the scale of the text inside the frame.

• Sort by default album order

  When I select an Album in Photoshop Elements (ss14), he has "Last" as the default sort order. I know that I can change this by selecting 'Order of the Album' in the dropdown menu, but it's rather tedious. Would it not possible to change the sort order by default for the Albums to for example "order of the Album? When I browse through the forum, I have the impression that this problem is as old as PE8.

  Any help would be appreciated.

  Rik

  Van_Epscheuten wrote:

  Hi Michael,

  Thank you very much for your explanation. I don't know, however, that I understand. You claim a sort order is preserved when switching from a thumbnail view (all media) a view of the album. For me, it does not: the sort order on the selection of an album is always "descending", regardless of the previous sort parameters. It hurts you?

  Rik

  You are right...

  Except that if I'm in "ranking album" in an album and if I switch to another album, I'll stay in sorting "album". Several tests will be required...

  P.S. We are talking about the same version of PE? I do not recognize the ability to sort by 'a far more recent everything first, with the more old/new first for every day'.

  I'm on version 14, but this is not new. The option is set in the Edit menu > Preferences > general tab.

  A glance at 6 elements indicates that the option was already there.

• Sort both arrays

  Hi all

  If we are given two berries sorting, X and Y and X has a big enough buffer at the end of stay there.

  How can merge us Y X in a sorted order.

  X = (1,4,7,8)

  Y = (2,5,6)

  output: 1,2,4,5,6,7,8

  Thank you

  Rambeau

  This is a table... so a table is a construction that has a number of elements.

  The presentation of an array is can be done like this:

  SELECT listagg (COLUMN_VALUE, ',') WITHIN GROUP (ORDER BY COLUMN_VALUE)

  IN my_string

  table (z);

  sys.dbms_output.put_line (my_string);

  HTH

• easier way to sort the array of strings 2D?

  I have an array of strings long 2d, and I would like to sort by the value 2. It originated as:

      public static final String names[][] = {
       {"000000", "Black"},
       {"000080", "Navy Blue"},
       {"0000C8", "Dark Blue"},
       {"0000FF", "Blue"},
          {"000741", "Stratos"},
          ...
       {"FFFFF0", "Ivory"},
       {"FFFFFF", "White"}
      };

  As you can see, they are first sorted by hexadecimal values. It is useful for the part of the application.
  
  There are 1 567 entries. I want to the alphabetize the names of color and place them in a widget from the list. I need to retain the values to hexadecimal color associated with name values. All I can think to do something like:
  
  (1) to a temporary array of strings of length 1 - d
  2) fill loop that adds hexadecimal values in the values of name: temp [i] = new String (names [1] + names [i] [0])
  (3) sort [temporary] with built in the sort of Java
  (4) make a permanent new string, [hexValues] array to hexadecimal values
  (5) copy the last 6 characters of each item to [hexValues]
  (6) to truncate the last 6 characters of each element in [temporary]
  (7) create widget with [temporary] list
  
  Is there a more elegant way? What I really want to do is build an array of int 1 d, with the values that represent locations in alphabetical order of the names. However, I see no integrated whole that would make this kind of indirect type.
  
  - - - - - - - - - -
  Second question - can the bottom of each item in a list widget be a different color? Ideally, the list would display in black or white color name and its value of color as the background. Specifically, I am trying to build the list produced by the JavaScript here:
  
  * http://chir.ag/projects/name-that-color/
  
  and add it to my Java interactive color wheel:
  
  * http://r0k.us/graphics/SIHwheel.html
  
  - - - - - - - - - -
  BTW, I've converted its name this Javascript (ntc.js) color to a native Java class. It is freely distributable, and I have the host here:
  
  * http://r0k.us/source/ntc.java
  
  -Rich
  
  Published by: RichF October 7, 2010 19:04
  Stupid forum software; I don't see what he did go italic the new Word.

  People forget that a 2D array is essentially a table 1 d of paintings.

  colorNames.add(new colorName(ntc.names[1], ntc.names[0]));
  

  The above code attempts to pass arrays as parameters to your Builder, but your Builder expects a String object.

• How to sort the names in order albhabetical in Windows Mail on some recipients?

  Original title: Windows Mail

  Re my Windows Mail, the "Select recipients" list sorts e-mail addresses in alphabetical order rather than alphabetical order the real names, how can I change this?

  Hi sarahsdrive,

  Try these steps and check the result.
  a. in the Contacts folder: change the display «Détails»
  b. right-click on the 'Name' column header, click on "First name", then click on 'Last Name'
  c. click on "Last Name" to sort by this order, or click on the title "First Name" to sort by this order.
  d. in a window to create a message: click on:
  e. click the column 'Name' position... it cycles through 4 different kinds
  f. in Contact properties, click on the arrow pointing downwards at the end of the full name box

  Change Windows Mail send settings

  Visit our Microsoft answers feedback Forum and let us know what you think.

• Office sort by name DOES NOT WORK! By selecting once must rank in alphabetical order (you know A TO Z!) Selecting again should sort in reverse alphabetical order - PERIOD!

  (1) right click Desktop Windows7 containing more than 3 Articles. (I suggest 15 items like a bed of arbitrary "test bench" - tests with 3 items on the desktop will produce any desired results)  Otherwise, I take it your troubleshooting skills 'Null '.  It should be easy to place 15 shortcuts with DIFFERENT characters of departure on your Windows 7 Desktop - there are 26 characters to choose from in the English alphabet.

  (2) choose "sort by name".

  (3) try to understand new interpretation of what Microsoft of 'Alphabetical order' means!

  I jumped through all the "hoops" that Microsoft requires to submit this issue, as all other users here.  I have faithfully install all blessed Windows updates.  Yet, there is no solution.  This issue causes me to serioulsly are wary of what makes Windows 7 to correctly reflect my intelligence to others by running other applications developed by Microsoft.  I am running Windows 7 Professional, and the Virtual Machine XP always knows her alphabet!  Should I buy Windows 7 Ultimate for "Enjoy" the function of sorting in alphabetical order?    REALLY!  It is a legitimate problem - GET the number of POSITIONS!  After having examined them, if Microsoft still believes that there are really that many stupid people here, then fine.  Just fix it in the next update of Windows 7, and all of us, "stupid" people will at least "happy fools!

  Sorts the elements of the bureau in the following order:

  (1) Windows stuff, like the Recycle Bin

  (2) Public\Desktop

  (3) %user%\Desktop

  Or as midi510 above, just move the Public\Desktop in %user%\Desktop - but I think you'd have to do for all users (if more than one account)

  Wouldn't be nice if MS never listened to their customers?

• Photoshop cs6 - how do I sort by date/time order

  Dear Forum

  This is my first question/post... I hope someone can help me? You seem like an easy question, but struggling to achieve this goal.

  I have 2 cameras and shooting RAW images, cameras were developed at the same time but have numbers of unique images, I import them into iphoto11.  I am wanting to edit the images combined in Photoshop cs6 sorted in order not image number order of time.  However, when I make them slide into Photoshop photo tabs are in the picture reference number.  How I either re - sort in Photoshop by chronological order or drag/import so that they are in chronological order?

  Any help really appreciated.

  Thank you

  Do you in Bridge.

  Opening bridge and navigate to the folder that contains the files

  Make a right click any image and select sort

  

• Built-in sort with Arrays.sort

  I have multidimensional array that contains a number as new arr int [10] [10] and that you want to sort according to the last column. Arrays.sort is a simple way to do it, but what happens if I don't want a real movement elements occur by Arrays.sort (arr [] []). Frankly, I'm interested in winning positions but not to grant the lines. Can I pass it arrange step because not interested in changing the original table? For the moment, I sort the table with Arrays.sort then index of table row and I fixed the position number pair. For example arr [0] has rank 1, arr [1] has the rank of 2 etc. If sorted according to the last column.
  
  Published by: totalnewby on May 23, 2011 22:51

  totalnewby wrote:
  I just need to know where the items would be positioned if they have been sorted. I made copy of the table at the moment and my program is successful, even if it takes a lot of time and additional memory to perform the copy because this table has billions lines in reality. If you can suggest less time-consuming solution do let me know.

  This is my standard example of how to do this sort of indirect.

   public static void main(String[] args) throws Exception
      {
          final Words words = new Words("/usr/share/dict/words");
          final List data = new ArrayList();
          for (int i = 0; i < 10000; i++)
          {
              String[] row = new String[10];
              for (int j = 0; j < row.length; j++)
              {
                  row[j] = words.getRandomWord();
              }
              data.add(row);
          }
  
          final Integer[] indirectIndex = new Integer[data.size()];
          for (int i = 0; i < indirectIndex.length; i++)
          {
              indirectIndex[i] = i;
          }
  
          final Comparator indexComparator = new Comparator()
          {
              @Override
              public int compare(Integer left, Integer right)
              {
                  int result = 0;
                  for (int i = 0; result == 0 && i < data.get(left).length; i++)
                  {
                      result = data.get(left).compareTo(data.get(right)[i]);}return result;}};
  
  Arrays.sort(indirectIndex, indexComparator);
  
  for (int i = 0; i < 100; i++){System.out.println(indirectIndex[i] + "\t" + Arrays.toString(data.get(indirectIndex[i])));}}
  
  You just need to create a Comparator for sorting the index array that uses the last entry in each row of real data array when comparing a row rather than all the row entries as I have done. 
  

• Smart Array P440ar: ProLiant DL380 g9 &amp; controller Smart Array boot order

  Work on a server of gen9 ProLiant DL380 (SFF) with an of P440ar (version 3.00) at location 0 (embedded RAID) and a controller (version 2.52) P840 to location 1. I have the P440ar connected to the risers on the front of the system, and I'm starting off the P840 6.5 RHEL. If no hard drive is attached to the P440ar, it works, but if all the disks are connected to the P440ar, the boot device is not found. I tried to change the order of boot in RSBU controller, but the P440ar was the ONLY listed controller. I didn't even have an option to change the P840.

  Am I allowed to configure the system in this way?

  After fighting with it for several days, I deleted the system P840 and started with just the P440ar. Then I added the P840 in the system and restarting, the system automatically added the P840 to startup controller command list. Works fine now.

• Windows 2010 Live Mail loses attachments and sent box, Windows Live 2010 cannot sort by COLUMN by order alphabetical-how to to back to the old Windows Live Mail

  After Windows 7, computer portable 64-bit Windows Live Mail update to version 2010 in fall 2010, some attachments fail to my computer.  I can see them at the opening of mail on the work of the Windows XP computer, use comcast web mail, so I don't know the attachments exist.  When I get home and open it with Windows Live Mail, the message through (comcast), and the attachment is missing.  Can I go back to an older version of Windows Live Mail because I have attachments on the same computer.  Second problem: in letters, I can't sort messages sent by COLUMN.  They always sort by DATE, even if I want to sort by TO.  This isn't a problem in the IN box.

  Hello Carol_1234,

  There is a forum for Windows Live products. They have experts who specialize in Windows Live and will be better able to answer your questions.

  Click here for a link to the Windows Live Help Forum. Then click on mail.
  http://windowslivehelp.com/

  Thank you

  Marilyn

• GPO sorting FlexField array elements is possible?

  Hi all.

  I have a table, this table contains more than one column, one of them is FlexField, which contain 7 columns.  Case in common, I put the column real SortAllowed property and it will work, but it does not work with FlexField. How can I fix this (if itn is possible)?

  I don't have a lot of time.

  Nice day.

  p.s Flex field has property Type: Descriprive.

  Hi Alex,

  Because Oracle does not sort on DFF, you can check if you need the FDF itself values (in function of the importance is the requirement of sorting). A solution could be to capture the columns in FACT as of the independent columns of the database in the custom table and allow to sort. But this way you'd lose the flexitbities provided by DFF.

  Concerning