Sort groupItems Array using the left coordinate of visible limits?

Hey all! It's been a while, but I'm back with some more busters of brain for you guys.

I'm trying to re - work a script that Silly-V wrote to me. The goal is to create a work plan around each group of a document element in the order of the top left corner to the lower right (as if reading a book). (ultimately I would like to add a provision that excludes the possibility of having a work plan contained by another work plan, but it is a luxury that I can try to find later).

Silly script works very well and does exactly what I need... about 60% of the time. The problem comes when I have an item that contains a clipping mask. Since work plans are created through groupItem.visibleBounds, Illustrator assumes that the invisible work that extends beyond the clipping mask is visible and creating a work plan that is too much.

His version pushes the visible boundaries of each groupItem in an array, then sorts the visible boundaries of the left coordinate, then pushes this sub-table in another table and at the end, to coordinate kinds berries vertically at the top... However, I'm looking to push the real groupItems in the table instead of just the visible limits. So I would like to sort the groupItems by their visible limits table and then I have the opportunity of either by creating work plans based on their visible limits or (the possibility of) loop to make each groupItem selected = true and using the fitArtboardToSelectedart() command.

I'm stuck on how to sort the groupItems table based on the visible limits... Here's what I have so far:

my inclination is to set a variable to the visibleBounds of each groupItem in temp (which seems like it would need a loop), but it's not supposed loop me XIRR...? There is something really big, I'm missing here, but I can't wrap my head around it.

Thanks for any help!

function organize(){
  var docRef = app.activeDocument;
  var layer = docRef.layers[0];
  var groups = layer.groupItems;
  var currentRowMarker;

  var groupList = []; //array of all groupItems
  var sortedGroupList = []; //array of subarrays sorted by visible bounds
  var temp = []; //temporary array for the current row of groupItems. sort this array from left to right first, then push the entire array into "sortedGroupList"


  //populate groupList


  for (g=0; g<groups.length; g++){
       groupList.push(groups[g]);
  }


  //set currentRowMarker and compare rest of groupList to top coordinate of visible bounds. push true results to temp array.


  for (t=0; t<groupList.length; t++){
  temp = [];
  currentRowMarker = groupList[t].visibleBounds[1];
  temp.push(groupList[t]);
  groupList.splice(t,1);

       for (c=0; c<groupList.length; c++){
            var currentGroup = groupList[c];
            var vB = groupList[c].visibleBounds[1];
                 if (vB + 20 > currentRowMarker && vB - 20 < currentRowMarker){
                      temp.push(currentGroup);
                      groupList.splice(c,1);
                 }
       }

  //this is where i'd like to sort the temp array

  sortedGroupList.push(temp);
  }
}
organize();

Thanks for your help, Vassili.

I've been unable to get your suggestion to work, does not mean that it was an erroneous suggestion. So I decided to go the more complicated route. I hope that I can learn about why your suggestion did not work for me in a subsequent attempt.

I am sure that this isn't the most elegant way to perform this task, but it was the only way that makes sense to me. Here's what I ended up with:

for (s=temp.length; s>0; s--){
var placeholder = 0;
var farthestLeft;
var deleteIndex;
for (a=0; a

Tags: Illustrator

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