Please explain this?

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• Please explain this query

  Hi all

  Select col1, col2, col3, col4, col5, col6, count (*), grouping_id (col1, col2), grouping_id(col3,col4), grouping_id (col5, col6) of the Group FLAT_FILE_TEST of grouping sets (col3, col4), ((col1,col2) (col5, col6));

  Separate Grouping_id here is 0 and 3

  0 is for the current group, other grouping_id become 3.

  Someone please explain meaning of 3

  Why returning 3?

  
  

  Thank you

  Elayaperumal S
  

  Hello

  Thanks for posting the sample data.   I get errors on all directions of INSERTION, because the column names aren't the names of columns in the CREATE TABLE statement.

  Don't forget to post the results you want from these data, as well as an explanation of how you can (not necessarily how Oracle will be) the results of these data.

  Maybe you have nothing particular in mind; you're just experimenting GROUPING_ID to see how it works.

  In this case, if I have not answered your question in my first answer, so I understand not what is your question.

  In general terms,.

  GROUPING_ID (x_n,... x_2, x_1, x_0) equals

  (GROUPING (x_n) * POWER (2, n)) +.

  ...

  (GROUPING (x_2) * POWER (2, 2)) +.

  (GROUPING (x_1) * POWER (2, 1)) +.

  (GROUPING (x_0) * POWER (2, 0))

  If you have any questions, please tell what it is.  For example "on lines where gro1 = 7, why is - this 7 and not 4?  Instead of theis... in language SQL manual it says... and you said... so I expect gro1 to 4 because... «,.

  GROUPING_ID is so intimately linked to the GROUPING, then, in your result set, include GROUPING (x), where x is any column that you use as an agrument to GROUPING_ID, for ease of understanding.

• Please explain this issue

  Hello

  I'm prerparing to SCJP.

  I got this question

  What will be the result of the program?

  {public}
  public static throwit Sub)
  {
  System.out.Print ("throwit");
  throw new RuntimeException();
  }
  Public Shared Sub main (String [] args)
  {
  Try
  {
  System.out.Print ("hello");
  throwit();
  }
  catch (Exception)
  {
  System.out.Print ("taken");
  }
  Finally
  {
  System.out.Print ("finally");
  }
  System.out.println ("after");
  }
  }

  A.	Hello throwit caught
  B.	Compilation failure
  C.	Hello throwit RuntimeException captured after
  D.	Hello throwit finally after What is treatment and why. Please explain

  answer would be D.

  car-

  The method main() correctly handles the RuntimeException in the catch block catch finally runs (as it always does), and then the code returns to normal.

  A, B, and C are incorrect based on the logic of the program described above. Don't forget that properly handled exceptions do not cause the program to stop execution.

• Please explain this part of the code

  CREATE OR REPLACE PROCEDURE IS abc123
  -Statements
  v_T_MAP_record T_MAP_map % ROWTYPE;
  
  TYPE t_element_cursor IS REF CURSOR;
  v_T_MAP_cursor t_element_cursor;
  
  number of v_T_MAP_count;
  BEGIN
  DBMS_OUTPUT. ENABLE (1000000);
  v_T_MAP_cursor: = get_T_MAPs (1308); -This will get the record of the cursor
  
  -Open the cursor
  EXTRACTION v_T_MAP_cursor
  IN v_T_MAP_record;
  
  V_T_MAP_cursor % FOUND LOOP
  
  dbms_output.put_line ('uc.use_case_id: ' | v_T_MAP_record.use_case_id);
  
  
  v_T_MAP_count: = v_T_MAP_count + 1;
  
  EXTRACTION v_T_MAP_cursor
  IN v_T_MAP_record;
  
  END LOOP;
  
  -Close the cursor
  CLOSE V_T_MAP_cursor;
  
  EXCEPTION
  While OTHERS THEN
  dbms_output.put_line ('Error' |) TO_CHAR (SQLCODE) | ': ' || SQLERRM);
  END;
  
  I do not understand why we are having 2 game instruction Fetch IN v_T_MAP_record's first before the while loop v_T_MAP_cursor and the other inside the v_T_MAP_cursor. Please explain. If I remove the second instruction fetch inside the loop, it gives me a buffer overflow error.

  It's what he does...

  CREATE OR REPLACE PROCEDURE abc123  IS
      --Variable declarations
      v_T_MAP_record T_MAP_map%ROWTYPE;
  
      TYPE t_element_cursor IS REF CURSOR;
      v_T_MAP_cursor t_element_cursor;
  
      v_T_MAP_count number;
    BEGIN
      DBMS_OUTPUT.ENABLE(1000000);  -- THIS ISN'T REALLY NEEDED
  
      -- This opens the ref cursor, it doesn't fetch anything (assuming get_T_MAPs doesn't fetch itself)
      v_T_MAP_cursor := get_T_MAPs(1308);
  
      -- This fetches the first record from the cursor
      FETCH v_T_MAP_cursor
        INTO v_T_MAP_record;
  
      -- If a record is found we enter a loop
      WHILE v_T_MAP_cursor%FOUND LOOP
        -- output the current record details
        dbms_output.put_line('uc.use_case_id: '||v_T_MAP_record.use_case_id);
        v_T_MAP_count := v_T_MAP_count + 1;
  
        -- fetch the next record
        FETCH v_T_MAP_cursor
          INTO v_T_MAP_record;
        -- loop back to the start of the while loop
      END LOOP;
  
      --Close the cursor
      CLOSE v_T_MAP_cursor;
  
    -- Pointless stupid exception handler
    EXCEPTION
      when OTHERS THEN
        dbms_output.put_line('Error ' || TO_CHAR(SQLCODE) || ': ' || SQLERRM);
    END;
  

  Although this would be a better style:

  CREATE OR REPLACE PROCEDURE abc123  IS
    --Variable declarations
    v_T_MAP_record T_MAP_map%ROWTYPE;
    TYPE t_element_cursor IS REF CURSOR;
    v_T_MAP_cursor t_element_cursor;
    v_T_MAP_count number;
  BEGIN
    -- This opens the ref cursor, it doesn't fetch anything (assuming get_T_MAPs doesn't fetch itself)
    v_T_MAP_cursor := get_T_MAPs(1308);
  
    LOOP
      -- This fetches the first/next record from the cursor
      FETCH v_T_MAP_cursor INTO v_T_MAP_record;
      EXIT WHEN v_T_MAP_cursor%NOTFOUND;
  
      dbms_output.put_line('uc.use_case_id: '||v_T_MAP_record.use_case_id);
      v_T_MAP_count := v_T_MAP_count + 1;
    END LOOP;
  
    --Close the cursor
    CLOSE v_T_MAP_cursor;
  END;
  

  However, I would also change things to use the SYS_REFCURSOR as the need to define your own type from the REF CURSOR was placed back in 9i with the new type built in SYS_REFCURSOR.
  There are probably many other things I would like examine why I'm using ref Cursor in the first place and why I try to write data using dbms_output etc., but hey, we all have start somewhere.

  Published by: BluShadow on 28-Sep-2012 14:28

• Please explain this code

  I take the test and found this code-

  public class Outer
{
   public void someOuterMethod()
  {
   //Line 5
  }
   public class Inner { }
  
   public static void main(String[] argv)
  {
  Outer ot = new Outer();
   //Line 10
  }
}

  The following code fragments inserted, for compiling?

  A. New inner(); On line 5 B. New inner(); On line 10 C. OT again. Inner(); On line 10 D. new Outer.Inner (); On line 10

  Answer is A.

  Why not the answer is B?

  well explained by cardan2

  further explanation

  Option A compile without problem

  Option B gives an error - variable not static cannot be referenced from a static context.

  There is no option package C only ot.

  Option D gives an error - variable not static cannot be referenced from a static context.

  hope you get it

• Can someone please explain this to me

  So yesterday, I made a change in our production database. What we had was a synonym in the S1 schema that pointed to a view of schema S2. We needed to make a change to do some minor data manipulations before we see in S1. So I dropped the synonym and created a view of the same name. All this went well in dev and QA, where we register S1 to do all the tests, but in production, our application connects to the database as S1USER that has select privileges on all tables of S1 and the views. After you have created the user view privileges granted DBA select on view at S1USER, but when I tried to query the table like S1USER I got ORA-01031: insufficient privileges. The DBA has thought that I didn't select privileges on the underlying view in S2, so it has that. Again I got the error of insufficient privileges. He seems to have had the privilege to choose granted by the account DBA was not good enough, he had to be granted by S1. I have never heard something like that. Why don't the DBA grant select to do the job, and select should be granted by the owner of the schema. Someone at - he never encountered this before?

  Even if ADMINISTRATOR privilege, he did on behalf of S1, considered as a DBA user:

  SQL > grant create session to one identified by one;

  Grant succeeded.

  SQL > grant select on mpprod.indv_t to one.

  Grant succeeded.

  SQL > select table_name, constituent
  2 of dba_tab_privs
  3 where dealer = "A";

  TABLE_NAME GRANTOR
  ------------------------------ ------------------------------
  INDV_T MPPROD

  However, nor the role of s/n, not the DBA have with grant on the indv_t table option, the ADMINISTRATOR cannot transmit the (implicit) permissions on the table S2 S1 at S1user.  Only S1 can transmit the implicit permissions to table S2.

  John

• Level - Can Reporting someone please explain this attribute?

  All - I am a newbie on Siebel on demand but creating reports with other tools for years. I recently came across some reports that I inherited that constantly give us bad. These are basic reports that look at the number of calls, meetings, etc. for a given user. What we see is that we used this statement attribute level to filter, but according to the Manager of logging level in it cause problems. Some people cannot see the data, and some receive a massive amount of duplicated data.
  
  When all is said and done, we are looking for a simple list of Manager-rep of counts of these activities. After looking at the value of level reporitng it would look like an indicator of the relative position of the level lower in the reports - to the hierarchy. We will generally filter level = 0 (or maybe 1) reports more but what I want is a way to control based on the user. My requirement is to have the level they can see and retail at a level more low but I don't ' fully understand how that is created or how can I use system variables to determine the level of user control.
  
  Anyone who has the news of background on this page or how I can order a basic report anaylytic in more manageable to show my stuff and subtotals to a level more down which would be greatly appreciated.

  Not sure if I can help with the specific report, but I'll try more of light level Reporting.

  In a report which is flush with the dimension possessed by the user, you can find the Reporting level field. Each user belongs to a reporting hierarchy, derived from the "Reports To" value in their user profile.

  The best way to see it is to create a simple report with the Email of the user level reports and email Manager. This will show you the Manager at each level. You can use this to expose and filter on the complete management hierarchy.

  Level 0 = user. All users have a value of themselves as Manager at level 0.
  Level 1 = reports to-which reports directly to the user.
  Level 2 + = towards the top of the chain...

  You can take a look at some of the predefined reports to see how this can be used to create reports based team, as 'Team Pipeline Analysis', ' team sales analysis of efficiency "and"analysis of the Team activity. You can open all the pre-buiilt reports as well as the starting points.

• SQL: can someone please explain this question?

  Select to_char (-4567, ' 9999 mI') a1, to_char (-4567, '99999pr') n2, to_char (4567, '00099999') double a3

  Select to_char (4567, '9.999EEEE') a1, to_char (4567, '9999V9999') double n2

  --

  Thank you

  You need to consider the Format of number patterns

  http://docs.Oracle.com/database/121/SQLRF/sql_elements004.htm#SQLRF00211

• Please explain this SQL output

    1* SELECT style, window, TO_CHAR(rate, '999,999.99') rate FROM ship_cabins ORDER BY 1,2
  SQL> /
  
  STYLE           WINDOW     RATE
  --------------- ---------- -----------
  Stateroom       None            555.65
  Stateroom       Ocean         5,000.00
  Stateroom       Ocean           500.00
  Suite           None            300.00
  Suite           None             25.00
  Suite           Ocean           333.44
  Suite           Ocean           444.55
  Suite           Ocean           123.78
  Suite           Ocean           666.66
  
  9 rows selected.
  
  SELECT style, window, rate FROM ship_cabins 
  WHERE style= 'Suite' AND NOT window = 'Ocean' OR rate > 500;
  
  SQL> /
  
  STYLE           WINDOW           RATE
  --------------- ---------- ----------
  Suite           None              300
  Stateroom       Ocean            5000
  Suite           None               25
  Stateroom       None           555.65
  Suite           Ocean          666.66

  How can we get the lines with

  rate <= 500 

  ?
  How can we get the lines with

   window = 'Ocean'

  ?
  
  Published by: 957072 on April 4, 2013 04:23

  Hello

  957072 wrote:

  1* SELECT style, window, TO_CHAR(rate, '999,999.99') rate FROM ship_cabins ORDER BY 1,2
  SQL> /
  
  STYLE           WINDOW     RATE
  --------------- ---------- -----------
  Stateroom       None            555.65
  Stateroom       Ocean         5,000.00
  Stateroom       Ocean           500.00
  Suite           None            300.00
  Suite           None             25.00
  Suite           Ocean           333.44
  Suite           Ocean           444.55
  Suite           Ocean           123.78
  Suite           Ocean           666.66
  
  9 rows selected.
  
  SELECT style, window, rate FROM ship_cabins
  WHERE style= 'Suite' AND NOT window = 'Ocean' OR rate > 500;
  
  SQL> /
  
  STYLE           WINDOW           RATE
  --------------- ---------- ----------
  Suite           None              300
  Stateroom       Ocean            5000
  Suite           None               25
  Stateroom       None           555.65
  Suite           Ocean          666.66
  

  OR meanis includes the lines if they meet either the conditon before the OR keyword, or condition that comes after it.

  How can we get the lines with

  rate <= 500 
  

  ?

  These lines meet the other condition: NO window = "Ocean."

  How can we get the lines with

   window = 'Ocean'
  

  ?

  These lines satisfy the condition else: rates > 500

  If you want lines that meet all the criteria, then use AND place where.
  If you want to use both AND and OR in the WHERE clause even, use parentheses to indicate clearly who will be evaluatd forst.
  For example:

  WHERE   (    style      = 'Suite'
       AND   NOT window = 'Ocean'
       )
  OR        rate      > 500
  

• Can you please explain this grace of Scripts

  Cat /oracle/data/XXX/Headcount.txt $HADOOP/other/chrtacct.dim > /oracle/data/XXX/chrt3.txt
  Cat /oracle/data/XXX/invgp5.txt /oracle/data/XXX/Headcount.txt $HADOOP/other/chrtacct.dim > /oracle/data/XXX/chrt2.txt
  Cat $HADOOP/XXX/shc_busform.dim $HADOOP/other/altbfmt.dim > /oracle/data/XXX/bsfrmdim.txt
  Cat /oracle/data/XXX/UDA.txt > /oracle/data/XXX/KUDA.txt
  ##############################################################

  cat is to concatenate the files listed on the left of the ">" symbol and direct the result in the file on the right of the ' > ' symbol (which will be overwritten if it already exists).

  Type "cat man" on your system to learn more about how it works.

• Please explain 1/24/3 600 s

  Can you please explain this SQL I was running with 24/1/3600. What is this way with regard to the last day of the month. Thank you
  

        -- Revenue Recognition date within the previous month 
               AND ob.revenue_recogn_date BETWEEN (LAST_DAY (ADD_MONTHS (TRUNC (SYSDATE), -2)) + 1) 
                                              AND (LAST_DAY (ADD_MONTHS (TRUNC (SYSDATE), -1)) + 1 -1/24/3600)    

  ricard888 wrote:
  What does the logic here in terms of revenue capture.

  As it says in the commentary:

  -Date of recognition of income in the previous month

  It limits the selected lines in the rows where ob.revenue_recogn_date is the last month (e.g.within July if you run today and inside August when you launched it in September).

  SY.

• I have an error in my event viewer: the fault bucket + 45216 0xD1_athr, type the name of the event 0: BlueScreen. Can someone please explain to me how to solve this problem.

  I have an error in my event viewer: the fault bucket + 45216 0xD1_athr, type the name of the event 0: BlueScreen

  Can someone please explain to me how to solve this problem. My computer shuts down whenever I get on the internet. I need some answers please.

  You have a problem with a driver Atheros.

  It could be the network card is bad or the driver is damaged.

  If it is a wireless card, try to connect to the router with an ethernet cable. See if you can get an updated driver from the computer manufacturer's website.

  http://msdn.Microsoft.com/en-us/library/ff560244 (v = VS. 85) .aspx

• Why we cannot create more than one primary key on a table. Why we create several unique key on a table. Please explain if anyone have details of this.

  Why we cannot create more than one primary key on a table. Why we create several unique key on a table. Please explain if anyone have details of this.

  «a primary key has semantic meaning, it is to be immutable (never change of value), unique and not null.»

  a unique constraint is simply "at any time, these values are unique - they can change and they can be null.

  You use a unique when constraint

  (a) you do not already have a primary key for a table can have only one
  (b) you allow NULL values in attributes
  "(c) to allow you to update the values in the attributes.

  https://asktom.Oracle.com/pls/Apex/f?p=100:11:0:P11_QUESTION_ID:5541352100346689891

• I paid to be a member of the Adobe every month, and I just noticed that I can not download a complete version of all creative products only a trial... This was never the case! Can someone explain please why this seems to be a scam?

  Hello world

  For years I had to pay a subscription for Adobe Creative cloud that allowed me to use all Adobe products. Recently, I have noticed that I am only allowed to upoad a trial version of Adobe not a full version which was the case before.

  so I'm not sure what I pay for every month...

  Someone at - it from Adobe can give me an answer to this, because it seems to me that I throw my money out the window.

  Thank you

  Concerning

  Paulina

  Hello

  Please refer to the steps below: -.

  First of all, disconnect, then back into creative cloud, using adobe id to pay for your subscription.

  https://helpx.Adobe.com/creative-cloud/help/sign-in-out-activate-apps.html

  Then, if you launch any product of CC 2015 and the pop up still shows a trial message window, please check this link for the resolution:

  https://helpx.Adobe.com/manage-account-membership/CC-reverts-to-trial.html

• Please explain how to delete a computer IMAC?

  Please explain how to delete documents and files from my office? Why simple Apple does not offer an option to delete above under edit. This totally baffles me? How much easier would it be? I'm not tech savvy so I end up saving multiple copies of the same thing. Please help me, my inability to delete anything on this computer either this Apple drives me crazy and I can't face is no longer with this computer.

  Select them and press the command and DELETE keys, then choose Empty trash from the Finder menu. The menu option to remove is on the file menu.

  (145043)