Practice SQL

Hello
m using 12R/win xp...
review of sql en preparation m and I wanted to ask a question...
I used Toad to exercise under the scott schema...
but now I have km I cannot perform any function of DML on it or may b i dnt know abt that...
even with sql cmd... When I connect to the database I can't insert new lines in the scott schema emp table...
m using apps/apps like user login...
thr may comes to sm of rights...
Please guide me on this topic!
thnx in advance!
Kind regards!

Hi Shaaquile,

Your statement is incorrect, look at this,.

INSERT INTO  () VALUES ();

Kind regards
Christian Balz

Tags: Database

Similar Questions

Practical SQL training/exam question

Hello
I am a student at the bases SQL 1z0-051 exam, and examples of questions about the Oracle University site review is the following:
3. review the structure of the EMP table:
EMP
Name                                  Null?                        Type
------------------------------------------------------------------------------------------
EMPNO NOT NULL NUMBER (3)
ENAME                                                               VARCHAR2(25)
SALARY                                                              NUMBER(10,2)
COMM_PCT                                                        NUMBER(4,2)
You want to generate a report which meets the following requirements:
1 shows the names of employees and the commission amounts
2 excludes employees who do not have a commission
3 displays a zero for the employees whose SALARY has no value
You run the following SQL statement:
SQL > SELECT ename, NVL (salary * comm_pct, 0)
WCP
WHERE comm_pct <>NULL;

What is the result?
It generates an error
B it runs successfully but displays no results
C it runs successfully but displays results that meet only the requirements 1 and 3
D it is running successfully and displays results which fulfil all the requirements
The answer provided on the Web site is: B it runs successfully but displays no results
and I don't understand why...

The WHERE clause excludes rows with comm_pct is NULL. So for the function NVL in the SELECT clause, the value of comm_pct will never be NULL, but salary * can * be NULL (there is no NULL constraint on this topic), so for lines where the salary is NULL, salary * comm_pct evaluate to NULL and the function NVL would transform these nulls to 0.

Am I missing something? I realize that for some people on this forum, the answer may be obvious, but I'm learning just for the first level of certification SQL, so for now I still have a lot to discover.

Thanks in advance,
JM

x <> NULL

x = NULL

Neither is never true. NULL is never equal to what whatsoever (including NULL). NULL is also never not equal to what

X IS NOT NULL

X IS NULL

are the right way

http://docs.Oracle.com/CD/B19306_01/server.102/b14200/sql_elements005.htm

best practices of vCenter 4.1 SQL server 2008

I was wondering if there is best practice documentation a SQL server 2008 vCenter 4.1 databases. I am also looking to see if VMware provides a list of best practices SQL database maintenance or if they recommend suite Microsoft Best practice for SQL database maintenance.

This pdf file is still topical

http://www.VMware.com/files/PDF/vc_microsoft_sql_server.PDF

with the KB below, you should have a good plan.

http://KB.VMware.com/kb/1025914

also, I suggest you run the DB instance in simple mode instead of full recovery.

Installation of SQL
Hi all

I'm new to this site and I got to the checkpoint in a week or two. I want to install SQL for queries etc.

I have a MAC Pro system and you want to install SQL on that. There are several links different shows from sites such as SQL server, SQL cluster and so many others and I'm not sure what to install to run SQL queries for the practice.

If any of you know any reliable link to install SQL on my system, please add it to this threat.
Also, any of you can tell what requests should expect in interview?

Harry
If you just want to practice SQL and want to avoid any installation of the software, you can give a try to an APEX free service provided by Oracle Corp.: http://apex.oracle.com/i/index.html

APEX includes SQL Workshop http://download.oracle.com/docs/cd/E17556_01/doc/user.40/e15520/toc.htm#

Which book is good to learn the fundamentals of SQL?
Hello world

I am preparing for the exam-1Z0-051 (Oracle Database 11g: SQL Fundamentals I).

I want to know which of the two works is best for the preparation and covers each topic in great depth.
1 oracle Database 11 g SQL by Jason Price
2 oracle Database 11 g the complete reference by Kevin Loney

I have no prior experience in SQL. Your advice will be appreciated.

Thank you
Deepika

Published by: user12054553 on July 26, 2010 09:21
Hello

Here is a book that got good reviews:
```
Oracle SQL By Example (4th Edition)
Alice Rischert, 2009
Publisher is Prentice-Hall.
ISBN-10: 0137142838
ISBN-13: 978-0137142835
```
Unfortunately, I don't have a copy, so this 'recommendation' is hearsay. It is very well regarded. Personally, I like to learn by example.

The remaining books I mentioned are not specific Oracle (which, depending on your point of view, could be a good thing)

I use the following book to learn SQL:
```
SQL Cookbook
By Anthony Molinaro
Publisher: O'Reilly
Pub Date: December 2005
Print ISBN-10: 0-596-00976-3
Print ISBN-13: 978-0-59-600976-2 
```
I recommend this book with some reservations. In most of the solutions he gives he relies on totally artificial relationships in the data (relying on anything other than forced relationships in the data is a very bad thing to do!). If you study the way I do then, these bad solutions are actually a good thing, reworking poor solutions into something that is worthy of the production is a great exercise. Finally, if you have decided to learn by using this book, you will need to read the Oracle manuals for complete information (good thing to do anyway.)

I also used
```
The Practical SQL Handbook
By Judy S. Bowman, Sandra L. Emerson and Marcy Darnovsky
Publisher: Addison Wesley Publishing
ISBN: 0-201-62623-3
```
I consider this book a very good book. Chapter 2 is probably the best short, concise and lucid explanation I've read about how design and normalize a database, why index, no index on a column and other basic concepts of database design. (I want that most DBAs had read this chapter :(). Information on these topics are presented in a single chapter, however, they do a better job at what other books do hundreds, if not thousand + pages. Their explanation of the SQL language is good, but slow the pace for my taste. However, Chapter 2 alone is worth the price of the book.

Finally, is something I recommend, do not learn only what the test requires. You want to KNOW your stuff. The test is a mere formality, being aware of what they ask, but do not limit your knowledge development in the area defined by the test.

HTH and good luck,

John.

I don't know the size of tablespaces
I make a plsql for insert on transaction 700,000,000.00 program a table has only 5 int column. I'm not a database, I do the program practice sql, forms and report. My tablespace has just 50 m, that's why the plsql gives me an error. I don't know the size of a tablespace again. Can anyone help?
joaquin2 wrote:
Thank you for your help. The table is
create table numbers
(int num1, num2 int, int num3, num4 int, int num5);

The table space is
Numbers of CREATE TABLESPACE
DATAFILE 'C:\calculos\numeros' SIZE 30G AUTOEXTEND ON
MINIMUM 500K
DEFAULT STORAGE (INITIAL 500K NEXT 500K MAXEXTENTS 500 PCTINCREASE 0)
ONLINE
/

Management of the space will be much more effective if you use uniform extensions and specify a reasonable size for autoextend:
```
> CREATE TABLESPACE numeros
 DATAFILE 'C:\calculos\numeros' SIZE 30G AUTOEXTEND ON
 next 1g uniform size 512k
 ONLINE
 /
```
Published by: JohnWatson on January 9, 2013 16:26
I should have added, what is your db_block_size? If the default 8 k, your maximum file size is of 32G.

Help on query: how to produce from columns of ranks?

Hi all
I have a table table1 with below the structure and data

Item     State          Value
A1      MS          100
A1      GOA          3
A1      UP          4
B2      MS          34
B2      GOA          55
B2      PB          3
B2      DL          4
B3      MS          99
B3      TN          1

I have a requirement to query this table and generate the output below

Item      MS     GOA     UP     PB     DL     TN
A1     100      3     4     0     0     0
B2      34     55     0     3     4     0
B3      99      0     0     0     0     1

The problem here is that we can have multiple status codes, so as a result the query should return dynamically the number of columns

Is it possible to produce above output? Any help will be appreciated.

Oracle DB Version - Oracle 8i

Thanks in advance!

Hello

This is called a pivot .
The basic technique is something like:

SELECT     item
,     SUM (CASE WHEN state = 'MS'  THEN value ELSE 0)     AS ms
,     SUM (CASE WHEN state = 'GOA' THEN value ELSE 0)     AS goa
,     SUM (CASE WHEN state = 'UP'  THEN value ELSE 0)     AS up
,     SUM (CASE WHEN state = 'PB'  THEN value ELSE 0)     AS pb
,     SUM (CASE WHEN state = 'DL'  THEN value ELSE 0)     AS dl
,     SUM (CASE WHEN state = 'TN'  THEN value ELSE 0)     AS tn
FROM     table_x
GROUP BY  item;

but this requires you to know indicates how many there are, and what they are, when you write the query.

Since you have not, you must run a preliminary motion that will generate a select like the one above, or at least SUM expressions for variable columns. This is called dynamic SQL code , and a technique to do this is included below. (The example uses COUNT, but any aggregate, including the SUM function, work).

Another possibility is the aggregation of the chain, where instead of individual columns for each State, you have a huge column VARCHAR2, formatted to look like separate columns. The avaiable tools to do this in Oracle 8.1 are quite poor, however, so I think you're better with dynamic SQL.

/*
How to Pivot a Table with a Dynamic Number of Columns

This works in any version of Oracle
The "SELECT ... PIVOT" feature introduced in Oracle 11
is much better for producing XML output.

Say you want to make a cross-tab output of
the scott.emp table.
Each row will represent a department.
There will be a separate column for each job.
Each cell will contain the number of employees in
     a specific department having a specific job.
The exact same solution must work with any number
of departments and columns.
(Within reason: there's no guarantee this will work if you
want 2000 columns.)

Case 0 "Basic Pivot" shows how you might hard-code three
job types, which is exactly what you DON'T want to do.
Case 1 "Dynamic Pivot" shows how get the right results
dynamically, using SQL*Plus.
(This can be easily adapted to PL/SQL or other tools.)

NOTE: Using SQL*Plus file I/O, as in this example, is just
one of many ways to do dynamic SQL.
*/

PROMPT     ==========  0. Basic Pivot  ==========

SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
ORDER BY     deptno
;

PROMPT     ==========  1. Dynamic Pivot  ==========

--     *****  Start of dynamic_pivot.sql  *****

-- Suppress SQL*Plus features that interfere with raw output
SET     FEEDBACK     OFF
SET     PAGESIZE     0

SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql

SELECT     DISTINCT
     ',     COUNT (CASE WHEN job = '''
||     job
||     ''' '     AS txt1
,     'THEN 1 END)     AS '
||     job
||     '_CNT'     AS txt2
FROM     scott.emp
ORDER BY     txt1;

SPOOL     OFF

-- Restore SQL*Plus features suppressed earlier
SET     FEEDBACK     ON
SET     PAGESIZE     50

SPOOL     p:\sql\cookbook\dynamic_pivot.lst

SELECT     deptno
@@dynamic_pivot_subscript
FROM     scott.emp
GROUP BY     deptno
ORDER BY     deptno
;

SPOOL     OFF

--     *****  End of dynamic_pivot.sql  *****

/*
EXPLANATION:
The basic pivot assumes you know the number of distinct jobs,
and the name of each one.  If you do, then writing a pivot query
is simply a matter of writing the correct number of ", COUNT ... AS ..."\
lines, with the name entered in two places on each one.  That is easily
done by a preliminary query, which uses SPOOL to write a sub-script
(called dynamic_pivot_subscript.sql in this example).

The main script invokes this sub-script at the proper point.
In practice, .SQL scripts usually contain one or more complete
statements, but there's nothing that says they have to.
This one contains just a fragment from the middle of a SELECT statement.

Before creating the sub-script, turn off SQL*Plus features that are
designed to help humans read the output (such as headings and
feedback messages like "7 rows selected.", since we do not want these
to appear in the sub-script.
Turn these features on again before running the main query.

*/

pivot table problem

create the table mytable
(
name varchar2 (50).
name varchar2 (50)
)

Insert the table mytable values ('mary', 'john')
Insert the table mytable values ('mary', 'baby')
Insert the table mytable values ('mary', 'lady')
Insert the table mytable values ('sean', 'kate')
Insert the table mytable values ('sean', 'terry')
Insert the table mytable values ('kate', 'tom')
Insert the table mytable values ('kate', 'lary')
.
.
.

my result of the query is

last name first name
Jean-Marie
baby Marie
Lady Mary
Sean kate
Sean Terry
Tom Kate
Kate lary

I want to like this

Mary kate sean

John tom kate
baby terry lary
Lady

It's not all data.
the data are changeable.there are 3 name as name like sean John 2 2 lik kate and it will be 5 name like paul... I want as column name and surname as the data...
Thanks for your help...

Hello

Try this:

WITH     number_rows     AS
(
     SELECT     name
     ,     surname
     ,     ROW_NUMBER () OVER
               (     PARTITION BY     name
                    ORDER BY     surname
               )     AS r_num
     FROM     mytable
)
SELECT     r_num
,     MAX (CASE WHEN name = 'mary'     THEN surname END)     AS mary
,     MAX (CASE WHEN name = 'sean'     THEN surname END)     AS sean
,     MAX (CASE WHEN name = 'kate'     THEN surname END)     AS kate
FROM     number_rows
GROUP BY     r_num
ORDER BY     r_num;

The output is not quite what you asked:

.    R_NUM MARY       SEAN       KATE
---------- ---------- ---------- ----------
         1 baby       kate       lary
         2 jon        terry      tom
         3 lady

You do not have to display r_num: I showed just to make things easier to understand.
If the output should really include "Jean" rather than "jon", or if it should appear above 'baby', rather than below, so please explain.

If the names in columns ("Mary", "sean" and "kate" in your sample data) should be determined at run time, you need dynamic SQL statements to generate a statement like the one above.
The script below shows one way to do this in SQL * more.

/*
How to Pivot a Table with a Dynamic Number of Columns

This works in any version of Oracle
The "SELECT ... PIVOT" feature introduced in Oracle 11
is much better for producing XML output.

Say you want to make a cross-tab output of
the scott.emp table.
Each row will represent a department.
There will be a separate column for each job.
Each cell will contain the number of employees in
     a specific department having a specific job.
The exact same solution must work with any number
of departments and columns.
(Within reason: there's no guarantee this will work if you
want 2000 columns.)

Case 0 "Basic Pivot" shows how you might hard-code three
job types, which is exactly what you DON'T want to do.
Case 1 "Dynamic Pivot" shows how get the right results
dynamically, using SQL*Plus.
(This can be easily adapted to PL/SQL or other tools.)
*/

PROMPT     ==========  0. Basic Pivot  ==========

SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
ORDER BY     deptno
;

PROMPT     ==========  1. Dynamic Pivot  ==========

--     *****  Start of dynamic_pivot.sql  *****

-- Suppress SQL*Plus features that interfere with raw output
SET     FEEDBACK     OFF
SET     PAGESIZE     0

SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql

SELECT     DISTINCT
     ',     COUNT (CASE WHEN job = '''
||     job
||     ''' '     AS txt1
,     'THEN 1 END)     AS '
||     job
||     '_CNT'     AS txt2
FROM     scott.emp
ORDER BY     txt1;

SPOOL     OFF

-- Restore SQL*Plus features suppressed earlier
SET     FEEDBACK     ON
SET     PAGESIZE     50

SPOOL     p:\sql\cookbook\dynamic_pivot.lst

SELECT     deptno
@@dynamic_pivot_subscript
FROM     scott.emp
GROUP BY     deptno
ORDER BY     deptno
;

SPOOL     OFF

--     *****  End of dynamic_pivot.sql  *****

/*
EXPLANATION:
The basic pivot assumes you know the number of distinct jobs,
and the name of each one.  If you do, then writing a pivot query
is simply a matter of writing the correct number of ", COUNT ... AS ..."\
lines, with the name entered in two places on each one.  That is easily
done by a preliminary query, which uses SPOOL to write a sub-script
(called dynamic_pivot_subscript.sql in this example).

The main script invokes this sub-script at the proper point.
In practice, .SQL scripts usually contain one or more complete
statements, but there's nothing that says they have to.
This one contains just a fragment from the middle of a SELECT statement.

Before creating the sub-script, turn off SQL*Plus features that are
designed to help humans read the output (such as headings and
feedback messages like "7 rows selected.", since we do not want these
to appear in the sub-script.
Turn these features on again before running the main query.

*/

Values of Colum as separate columns

I have a table that looks like this:

Company (varchar),
FieldName (varchar)
Valuex (varchar)

Data can look like this:

Company Fieldname valuex
------------- --------------- -----------

John 123 name
MiddleName 123 C
LastName 123 Smith

I would like to write a query that comes out like this:

MiddleName t first name last name company
------------- ------------ ---------------- ------------
Smith John 123 C

It can be? Thanks in advance.

Hello

Column definitions must be hard-coded in the application.
You cannot hardcode anything today and make sure that it reflects accurately data next year.
but you can write soemthing today who, when it is executed next year, will make the hardcode then.
This is called dynamic SQL.
Here's a way to do it in SQL * Plus, with the command of the COIL:

/*
How to Pivot a Table with a Dynamic Number of Columns

For example, you want to make a cross-tab output of
the scott.emp table.
Each row will represent a department.
There will be a separate column for each job.
Each cell will contain the number of employees in
     a specific department having a specific job.
The exact same solution must work with any number
of departments and columns.
(Within reason: there's no guarantee this will work if you
want 2000 columns.)
*/

PROMPT     ==========  0. Basic Pivot  ==========

SELECT     deptno
,     COUNT (CASE WHEN job = 'ANALYST' THEN 1 END)     AS analyst_cnt
,     COUNT (CASE WHEN job = 'CLERK'   THEN 1 END)     AS clerk_cnt
,     COUNT (CASE WHEN job = 'MANAGER' THEN 1 END)     AS manager_cnt
FROM     scott.emp
WHERE     job     IN ('ANALYST', 'CLERK', 'MANAGER')
GROUP BY     deptno
ORDER BY     deptno
;

PROMPT     ==========  1. Dynamic Pivot  ==========

--     *****  Start of dynamic_pivot.sql  *****

-- Suppress SQL*Plus features that interfere with raw output
SET     FEEDBACK     OFF
SET     PAGESIZE     0

SPOOL     p:\sql\cookbook\dynamic_pivot_subscript.sql

SELECT     DISTINCT
     ',     COUNT (CASE WHEN job = '''
||     job
||     ''' '     AS txt1
,     'THEN 1 END)     AS '
||     job
||     '_CNT'     AS txt2
FROM     scott.emp
ORDER BY     txt1;

SPOOL     OFF

-- Restore SQL*Plus features suppressed earlier
SET     FEEDBACK     ON
SET     PAGESIZE     50

SPOOL     p:\sql\cookbook\dynamic_pivot.lst

SELECT     deptno
@@dynamic_pivot_subscript
FROM     scott.emp
GROUP BY     deptno
ORDER BY     deptno
;

SPOOL     OFF

--     *****  End of dynamic_pivot.sql  *****

/*
EXPLANATION:
The basic pivot assumes you know the number of distinct jobs,
and the name of each one.  If you do, then writing a pivot query
is simply a matter of writing the correct number of ", COUNT ... AS ..."\
lines, with the name entered in two places on each one.  That is easily
done by a preliminary query, which uses SPOOL to write a sub-script
(called dynamic_pivot_subscript.sql in this example).

The main script invokes this sub-script at the proper point.
In practice, .SQL scripts usually contain one or more complete
statements, but there's nothing that says they have to.
This one contains just a fragment from the middle of a SELECT statement.

Before creating the sub-script, remember to turn off SQL*Plus features
that are designed to help humans read the output (such as headings and
feedback messages like "7 rows selected.", since we do not want these
to appear in the sub-script.
Remember to turn these features on again before running the main query.

*/

The first HOLD file that it creates, dynaic_pivot_subscript.sql, looks like this

,     COUNT (CASE WHEN job = 'ANALYST'    THEN 1 END)     AS ANALYST_CNT
,     COUNT (CASE WHEN job = 'CLERK'      THEN 1 END)     AS CLERK_CNT
,     COUNT (CASE WHEN job = 'MANAGER'    THEN 1 END)     AS MANAGER_CNT
,     COUNT (CASE WHEN job = 'PRESIDENT'  THEN 1 END)     AS PRESIDENT_CNT
,     COUNT (CASE WHEN job = 'SALESMAN'   THEN 1 END)     AS SALESMAN_CNT

SQL Server 2012 and NUMA - practical implications

Hello
I read up on top of SQL Server and NUMA, with ESXi 5.1 in mind. I read that I should use the same NUMA architecture on hosts - this means in practice, I should use the same type, RAM speed, etc. when my guests? I want to know if my HP servers have the same NUMA architecture, but so far I was not able to find much information about it.
I think just buying identical hardware to make sure that I understand.
Thank you

Hardware identical is certainly a big plus when your guest has related to NUMA optimizations, and your comments and request can take advantage of them. With vNUMA, the optimization level and the benefits provided by the latter depends on the guest, as well as the material, so have the same host NUMA architecture will provide the most benefits. The performance guide (http://www.vmware.com/pdf/Perf_Best_Practices_vSphere5.1.pdf)

has additional details.

-KjB

Best practices for SQL

I started a discussion a few weeks there is movement .vmdks from the supplier of storage to another in regard to and got some great answers. What I didn't ask was if the hard contain databases SQL is there special considerations when you cut storage EMC VNX (pools versus grpoups raid) or when the data store is created in vCenter. I know that this may be more an EMC forum question but maybe someone in the world of VMware has a recommendation or can provide a link to best practices for the VNX. Thank you.
Post edited by: vmroyale to change the case of SQL

Have you seen the document "using EMC VNX with VMware vSphere storage solutions"?

Best practices for vCenter 5.1 with Microsoft SQL Server 2008 R2

I am looking for a best practices or really any documentation on configuring vCenter 5.1 with a SQL Server 2008 R2 database. I see that SQL Server 2008 R2 is supported, but that's all. Any help is appreciated.

Unless you have a huge (and I mean huge) environment, the vCenter database in general is not that big of a deal or go-getter and was apparently not deemed worthy for some secret magic tips because of this.

Standard SQL "best practices" and observe the standard installation documentation when deployment vCenter and you should be good to go.

Some documents on the vCenter more in-depth database are here:

http://www.VMware.com/resources/TechResources/10162

http://www.VMware.com/resources/TechResources/10302

Also, I highly recommend you watch this recording of VMworld:

http://www.YouTube.com/watch?v=5Ly64_ca7-I

SQL Server 2005 STD. best practice for deploying VCenter 4

Hi all
I I know what kind of criteria from database / best practices that I need to create to support VCenter Management Server v4?
I use Windows Server 2003 standard and SQL Server 2005 SP3 Standard edition.
Thank you.
Kind regards
AWT

Maybe this can help you.

MCP, VCP

Where can I practice Pl/sql
Hi, I m OCA administrator track.

I now practice PL/SQL, but I have no idea on the tools of Oracle and development which tool is right for me.
I've heard of

(* 1) PL/SQL developer *.
(* 2) Jdeveloper *.
(* 3) ADF *.

I want to practice on Windows 7. Kindly help
NO, you need not Fusion Middleware at all to develop PL/SQL modules. The PL/SQL code can be stored either in a text file and loaded in SQL Developer, or stored as a package, procedure, or function in the database.

You should really ask this question in a forum DBA or PL/SQL, Oracle Forms uses and needs of PL/SQL, the reverse is not true you don't need Oracle Forms or Weblogic/Fusion Middleware to learn PL/SQL.

What did I say?

If you want to build using SQL and PL/SQL oracle applications , then you need Fusion Middleware.

ESX 3.5 and SQL best practices

I searched for info on best practices when deploying SQL on the virtual computer. We already have a couple of lightweight SQL production servers running 2008 x 64 and SQL 2005. We are looking for migrating databases existing physical servers to a 2008 newly deployed x 64 SQL VM, I was able to find documents of Vmware and turned to the forum and information. This are not the giant databases - of things such as BES, EPolicy and other mundane but necessary databases. Even more to divide readers to separate newspapers, the sys and databases? Any advice would be appreciated.

Take a look on:

Best Practices for SQL Server

http://www.VMware.com/files/PDF/solutions/sql_server_virtual_bp.PDF

http://www.VMware.com/files/PDF/SQLServerWorkloads.PDF

André

Practice SQL

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