Primary key in 11g - known problem 6894412 problem

Similar Questions

• ADF: addition of the JSF error message: another user has modified the line containing oracle.jbo.Key [185 primary key].

  When you call the function DB. The function performs its operation, but shows an exception. In JDev 11.1.2.3

  And there is not another user. I'm testing alone.

  ADF: addition of the JSF error message: another user has modified the line containing oracle.jbo.Key [185 primary key].

  oracle.jbo.RowInconsistentException: Houston-25014: another user has modified the line containing oracle.jbo.Key [185 primary key].

  The problem is that the function db has a commit and my code also. However the db function called once in a case.

  Thanks a lot for your help.

• Oracle 11g: problem with disable primary key

  Hello
  I have this problem:
  
  I performed "EXECUTE IMMEDIATE"ALTER TABLE your table of KEY PRIMARY DISABLE";"
  
  This operation returns an error
  but when I did 'insert into table... ". »... Oracle returned ora-0001.
  
  The operations are in the same stored procedure, so in the same session.
  
  Database: Oracle 11.2.0.2
  
  How is that possible?
  All solutions?
  
  Thanks in advance.
  
  Best regards.
  Alessandro Zenoni

  Try to add 'DROP INDEX' to your disable command.

  not tested

  alter table xy disable primary key drop index
  

• Problem by setting the primary key: relaxation Assigned primary key in the sequence.

  I have a table and a trigger for insert/update on the table. Trigger I get the game of the primary key of a sequence. I tested unit by inserting records in the table. It works very well. Kets primary key the next sequence number.
  
  I use this table as an entity in my adf application. The primary key attribute is set to "DBSequence". But when inserted I do not receive the following sequence for the primary key. Instead it is inserting the temporary number - ve that assigns the adf.
  
  I use JDeveloper 11 g.
  
  
  Can someone tell me what could be the problem?

  Your trigger should be something like:

  create or replace TRIGGER "SID_ASSIGN"
   before INSERT
   ON MY_TABLE
   FOR EACH ROW
  
  BEGIN
  
  if :new.SID is null or :new.SID < 0 then
     SELECT MASTER_SID_SEQUENCE.nextval into :new.SID from dual ;
  end if;
  END;
  

  You can refer to the guide of Dev of 11g for more details on this...

  Julian

• Engineering problems the surrogate with Unique key primary key

  SDDM 3.3.0.747 with 2 problems (at least so far).  I hope that the problem comes from this recruit SDDM and I forgot a setting. PROBLEM 1 I don't want to start a religious debate on substitution vs natural keys but I'm having a problem correctly both the logic model of engineering.  I'm a rookie when it comes to SDDM but have many years of experience with the Designer. By default, only I wish I had a natural UID (UK) and a surrogate mother based on a primary key UID (PK) which is used for foreign keys.  The problem I have with engineering is I can successfully engineer the substitute PK, engineer of the FK with the PK, but cannot get the unique key to contain surrogate keys in the child table.  If I check the identification property in relationships, the PK columns and the UK are included in the child PK and the United Kingdom contains no columns. The installation program, I've defined two reference entities, PROBABILITY and GRAVITY with unique keys natural defined.  I also have a child entity RISK_ASSESMENT with links to entities of the PROBABILITY and SEVERITY and both have the "use surrogate keys:": check box selected.  The unique key of the entity RISK_ASSESMENT includes links to PROBILITY and GRAVITY.  None of the entities have a PK or replacement of the defined keys and they all have the checkbox "Create a surrogate key" checked.  In addition the following preferences are defined: Data Modeling/model/logic NO checked - use and the first Unique key as primary key value NOT checked - name - Keep under the name of the from attribute Checked - entity carrier to create controlled key - use surrogate PROBLEM 2 key relationship when the foreign key columns are engineered I want names have a prefix 'FK_"but they don't.  Models are defined as follows: Data Modeler/assignment of Standard/Templates Foreign Key name: FK_ {children} {parent} foreign key column: engineer FK_ {Ref column} relational model/General checked Options - translation name Marcus Bacon apply

  Once more, I designed without removing anything and still no FK to the United Kingdom of the child.

  There is a synchronization problem in DM 4.0 EA1. This will be fixed for the production version.

  Philippe

• Potential problems for tables without primary keys and unique keys

  GoldenGate 11.2.1.0.3/Solaris 10
  DB: Oracle for Oracle (Source and target is 11.2.0.3)
  Topology: unidirectional
  
  
  In our one-way configuration GG, little of the tables being replicated is not a primary key or a Unique key.
  
  Last week when we have implemented GG for the test, we received warnings for these table below.
  

  GGSCI > add trandata WMHS_UD.crtn_dtl
  
  2013-01-12 11:34:33  WARNING OGG-00869  No unique key is defined for table 'CRTN_DTL'. All viable columns will be used to represent the key, but may not guarantee uniqueness.  KEYCOLS may be used to define the key.
  
  Logging of supplemental redo data enabled for table WMHS_UD.crtn_dtl.

  Replication seems to work very well for these tables.
  
  Googling, I think that there may be performance degradation when you replicate tables without PK or the United Kingdom.
  
  But are there other potential problems such as data of a certain kind not replicated to the lack of PK/UK?

  It really depends on the data.

  By default, GG is combining all columns as a virtual primary key but don't no conflict control by default. So when you can be sure that the record you insert into the table is unique, then it will work.
  BUT as soon as you insert the same record, which is already inserted, then you will encounter problems.

  Let me show what happens when you use an initial charge because it makes it easier to describe:
  We start at 10:00 the capture for a table. Now, you insert a record at 10:00 in the tables. When you now start an initial charge to 10.02, then check you have inserted in the database to 10.01 will be repeated two times. During the IPL as the initial charge is made to 10.02 and it includes data of 10.01 AND it will be replicated again through the process of capture/replicate.

• Constraint primary key turn off - turn on problem solution

  Hello
  recently I truncate a table. during the truncation process I face with problem and solve below the track.
  
  SQL > TRUNCATE TABLE USER_STATE;
  TRUNCATE TABLE USER_STATE
  *
  ERROR on line 1:
  ORA-02266: permit to unique/primary keys in table referenced by foreign keys
  
  Then I find the related CONSTRAINT on the table according to the truncate table ORA-02266
  
  
  SQL > ALTER TABLE USER_STATE_PARAMETER disable the CONSTRAINT FK1_USR_SES_ST_PAR;
  
  Modified table.
  
  SQL > ALTER TABLE USER_STATE disable the CONSTRAINT SYS_C0030849;
  
  Modified table.
  
  Then successfully truncate the table as below
  
  SQL > TRUNCATE TABLE USER_STATE;
  
  Table truncated.
  
  then I activate the CONSTRAINT
  
  SQL > ALTER TABLE USER_STATE allow CONSTRAINT SYS_C0030849;
  
  Modified table.
  
  SQL > ALTER TABLE USER_STATE_PARAMETER allow FK1_USR_SES_ST_PAR of CONSTRAINT;
  
  Modified table.
  
  
  -My Question is, after you disable the CONSTRAINT, I did the truncate operation, and then enable the CONSTRAINT. I do who will trust me to do not face any problem in the database of the DML OPERATION? I also found there is no CONSTRAINT to disable in my database.

  >
  I do
  >
  Nope - you would not enable foreign key constraints, if the tables had given them that reference the you truncated.

  So if the constraints are enabled and valid, you will have no problem.

  You can (and should) always test certain simple dml to confirm there is no problem.

• Primary key cause problem in the meantime Partition Exchange

  DB: 11.2.0.2
  OPERATING SYSTEM: AIX 6.1
  
  I get the problem when exchanging data with range partitioned table. I have a partitioned table of interval and a regular intermediate table with data to be uploaded.
  Here are the steps that I did.
  

  SQL> CREATE TABLE DEMO_INTERVAL_DATA_LOAD (
                  ROLL_NUM        NUMBER(10),
                  CLASS_ID        NUMBER(2),
                  ADMISSION_DATE  DATE,
                  TOTAL_FEE       NUMBER(4),
                  COURSE_ID       NUMBER(4))
                  PARTITION BY RANGE (ADMISSION_DATE)
                  INTERVAL (NUMTOYMINTERVAL(3,'MONTH'))
                  ( PARTITION QUAT_1_2012 VALUES LESS THAN (TO_DATE('01-APR-2012','DD-MON-YYYY')),
                   PARTITION QUAT_2_2012 VALUES LESS THAN (TO_DATE('01-JUL-2012','DD-MON-YYYY')),
                   PARTITION QUAT_3_2012 VALUES LESS THAN (TO_DATE('01-OCT-2012','DD-MON-YYYY')),
                   PARTITION QUAT_4_2012 VALUES LESS THAN (TO_DATE('01-JAN-2013','DD-MON-YYYY')));
  
  Table created.
  
  SQL> ALTER TABLE DEMO_INTERVAL_DATA_LOAD ADD CONSTRAINT IDX_DEMO_ROLL PRIMARY KEY (ROLL_NUM);
  
  Table altered.
  
  SQL> SELECT TABLE_OWNER,
             TABLE_NAME,
             COMPOSITE,
             PARTITION_NAME,
         PARTITION_POSITION,
            TABLESPACE_NAME,
         LAST_ANALYZED
  FROM DBA_TAB_PARTITIONS
      WHERE TABLE_OWNER='SCOTT'
     AND TABLE_NAME='DEMO_INTERVAL_DATA_LOAD'
     ORDER BY PARTITION_POSITION;
  
  TABLE_OWNER                    TABLE_NAME                     COM PARTITION_NAME                 PARTITION_POSITION TABLESPACE_NAME                LAST_ANAL
  ------------------------------ ------------------------------ --- ------------------------------ ------------------ ------------------------------ ---------
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_1_2012                                     1 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_2_2012                                     2 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_3_2012                                     3 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_4_2012                                     4 USERS
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD VALUES (10,1,'12-MAR-2012',1000,90);
  
  1 row created.
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD VALUES (11,5,'01-JUN-2012',5000,80);
  
  1 row created.
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD VALUES (12,9,'12-SEP-2012',4000,20);
  
  1 row created.
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD VALUES (13,7,'29-DEC-2012',7000,10);
  
  1 row created.
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD VALUES (14,8,'21-JAN-2013',2000,50); ---- This row will create a new interval partition in table.
  
  1 row created.
  
  SQL> commit;
  
  SQL> SELECT TABLE_OWNER,
          TABLE_NAME,
          COMPOSITE,
          PARTITION_NAME,
          PARTITION_POSITION,
          TABLESPACE_NAME,
          LAST_ANALYZED
    FROM DBA_TAB_PARTITIONS
       WHERE TABLE_OWNER='SCOTT'
     AND TABLE_NAME='DEMO_INTERVAL_DATA_LOAD'
     ORDER BY PARTITION_POSITION;
  
  TABLE_OWNER                    TABLE_NAME                     COM PARTITION_NAME                 PARTITION_POSITION TABLESPACE_NAME                LAST_ANAL
  ------------------------------ ------------------------------ --- ------------------------------ ------------------ ------------------------------ ---------
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_1_2012                                     1 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_2_2012                                     2 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_3_2012                                     3 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_4_2012                                     4 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  SYS_P98                                         5 USERS   
  
  SYS_P98 partition is added to table automatically.
  
  SQL> CREATE TABLE DEMO_INTERVAL_DATA_LOAD_Y (
                  ROLL_NUM        NUMBER(10),
                  CLASS_ID        NUMBER(2),
                  ADMISSION_DATE  DATE,
                  TOTAL_FEE       NUMBER(4),
                  COURSE_ID       NUMBER(4)); 
  
  Table created.
  
  SQL> INSERT INTO DEMO_INTERVAL_DATA_LOAD_Y VALUES (30,3,'21-MAY-2013',2000,12);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  
  Since, i need a partition in DEMO_INTERVAL_DATA_LOAD table, which can be used in partition exchange, so i create a new partition as below:
  
  
  SQL> LOCK TABLE DEMO_INTERVAL_DATA_LOAD PARTITION FOR (TO_DATE('01-APR-2013','DD-MON-YYYY')) IN SHARE MODE;
  
  Table(s) Locked.
  
  SQL> SELECT TABLE_OWNER,
             TABLE_NAME,
             COMPOSITE,
             PARTITION_NAME,
             PARTITION_POSITION,
             TABLESPACE_NAME,
             LAST_ANALYZED
  FROM DBA_TAB_PARTITIONS
      WHERE TABLE_OWNER='SCOTT'
     AND TABLE_NAME='DEMO_INTERVAL_DATA_LOAD'
     ORDER BY PARTITION_POSITION;
  
  TABLE_OWNER                    TABLE_NAME                     COM PARTITION_NAME                 PARTITION_POSITION TABLESPACE_NAME                LAST_ANAL
  ------------------------------ ------------------------------ --- ------------------------------ ------------------ ------------------------------ ---------
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_1_2012                                     1 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_2_2012                                     2 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_3_2012                                     3 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  QUAT_4_2012                                     4 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  SYS_P98                                         5 USERS
  SCOTT                          DEMO_INTERVAL_DATA_LOAD        NO  SYS_P102                                        6 USERS
  
  SQL> ALTER TABLE DEMO_INTERVAL_DATA_LOAD
  EXCHANGE PARTITION SYS_P102
  WITH TABLE DEMO_INTERVAL_DATA_LOAD_Y
  INCLUDING INDEXES
  WITH VALIDATION;
  ALTER TABLE DEMO_INTERVAL_DATA_LOAD
  *
  ERROR at line 1:
  ORA-14097: column type or size mismatch in ALTER TABLE EXCHANGE PARTITION

  Now, if I turn off and drop the primary key constraint, it works without any problem.
  

  SQL> alter table DEMO_INTERVAL_DATA_LOAD disable constraint IDX_DEMO_ROLL;
  
  Table altered.
  
  SQL> alter table DEMO_INTERVAL_DATA_LOAD drop constraint IDX_DEMO_ROLL;
  
  Table altered.
  
  SQL> ALTER TABLE DEMO_INTERVAL_DATA_LOAD
  EXCHANGE PARTITION SYS_P102
  WITH TABLE DEMO_INTERVAL_DATA_LOAD_Y
  INCLUDING INDEXES
  WITH VALIDATION; 
  
  Table altered.
  
  SQL> select * from DEMO_INTERVAL_DATA_LOAD partition (SYS_P102);
  
    ROLL_NUM   CLASS_ID ADMISSION  TOTAL_FEE  COURSE_ID
  ---------- ---------- --------- ---------- ----------
          30          3 21-MAY-13       2000         12
  
  SQL> select * from DEMO_INTERVAL_DATA_LOAD_Y;
  
  no rows selected

  Please suggest.

  First of all, thanks for posting the code that allows us to reproduce your test. It is essential for such problems.

  Because the primary key is global you will not be able to use

  INCLUDING INDEXES
  WITH VALIDATION;
  

  And you need to add the primary key to the temporary table

   ALTER TABLE DEMO_INTERVAL_DATA_LOAD_Y ADD CONSTRAINT IDX_DEMO_ROLL_Y PRIMARY KEY (ROLL_NUM);
  

  The Exchange will work. You must rebuild the primary key after the Exchange.

• Primary key problem.

  Dear all,
  
  I have a table of database with a field called "SrNo" as the primary key.
  I'm the doDml() substitution in the implementation of the entity class that I call a storedprocedure for insert/update.
  
  I dragged the VO of the table to the form to create a form of the ADF.
  The problem is that the update works well, but when I try to insert it gives me mandatory error on "Srno" and recording is not inserted. How do I fix the problem, because the user is not supposed to enter the primary key.
  I also tried to change the property validation of the attributes of the entity but its readonly.
  
  
  -Thank you

  Hello

  Set the type to 'SrNo"to DBSequenze when you create the ID via a DB-Trigger/Sequenze...
  or false 'Required' to 'SrNo"in the area of occurrence.

• Problem with the primary key and indexes

  Hi all
  
  I'm looking a mess on one of our main tables.
  One of the developers here added an index on 3 columns in the table, thinking that it would speed up (not noticing that it had not a PK).
  
  Subsequently another developer has noticed there do not have a primary on key. So they added a touch of primry on the single column.
  
  The problem is that now the index created on 3 columns is bein used as the primary key index. As when the primary key is created a new index was not created.
  
  Is there anyway to get rid of this index/change it correct?
  
  This table is related to many many other tables, so when we tried to remove the index we could not due to the primary key and foreign key violations with other tables.
  
  Thanks in advance

  Oracle, as you found, is quite capable to use a column enformce multi index a single column primary key, as long as the pk column is the leader in the index. This should not cause performance issues for a search of PK and if the three indexed columns are often selected only may benefit from these types of queries.

  The only way to change that now, would be to drop all CF, drop and add the PK constraint and then add all the FK constraints. A long time and potentially dangerous (if you miss to add back of the FKs) endeavour. Certainly not worth the risk in my opinion.

  John

• Performance problem on the SQL query that does not use the primary key index

  Hello!
  
  I have some performance issues on a single SQL query (Oracle 10 g).
  I could solve the problem by using the INDEX indicator, but I would like to know WHY this is happening.
  
  * Tables *.
  create table jobs)
  ID number (5) not null,
  name varchar2 (100),
  primary key constraint Job_PK (id)
  )
  /
  -Record count: 298
  
  create table Comp)
  integer ID not null,
  name varchar2 (100),
  primary key constraint Comp_PK (id)
  )
  /
  -Record count: 193
  
  -Relation m: n
  create table JobComp)
  integer ID not null,
  id_job integer not null,
  id_comp integer not null,
  primary key constraint JobComp_PK (id),
  unique key constraint JobComp_UK (id_job, id_comp),
  Constraint JobComp_FK_Job foreign key (id_job) refers to Job (id),
  Constraint JobComp_FK_Comp foreign key (id_comp) makes reference Comp (id)
  )
  /
  create index JobComp_IX_Comp on JobComp (Cod_Comp)
  /
  create index JobComp_IX_Job on JobComp (Cod_Job)
  /
  -Record count: 6431
  
  * Ask *.
  
  When I run this query, the execution plan shows the index using (JobComp_PK and JobComp_IX_Comp).
  No problem.
  
  Select JobComp.*
  of JobComp
  Join jobs
  on Job.id = JobComp.id_job
  where JobComp.id_comp = 134
  /
  -runs in 0.20 sec
  
  But when I add the field 'name' of the work table the plan uses full access table to the table of work
  
  Select JobComp.*, Job.name
  of JobComp
  Join jobs
  on Job.id = JobComp.id_job
  where JobComp.id_comp = 134
  /
  -runs in the 2.70 dry
  
  With the help of the index
  
  Select / * + INDEX (Job Job_PK) * /.
  JobComp.*, Job.name
  of JobComp
  Join jobs
  on Job.id = JobComp.id_job
  where JobComp.id_comp = 134
  /
  -runs in 0.20 sec
  
  * Doubt *.
  
  This behavior is correct?
  
  PS. : I tried to recalculate the statistics, but nothing changes:
  
  analyze the job calculation table statistics.
  /
  change the statistical calculation of index Job_PK reconstruction;
  /
  Start
  dbms_utility.analyze_schema (sys_context ('userenv', 'current_schema'), 'CALCULATE');
  end;
  /
  
  [of]
  Gustavo Ehrhardt

  Gus.EHR wrote:
  Hello.
  I'm sorry for the plan unformatted.
  The execution time of the querys "without field name' and 'with the field name with suspicion" are equal.
  He has no problem caching, because I get the plans of the sequence different from the querys and repeated the performance. The result is always the same.

  I don't think that there is no problem with oracle crossing LOOP IMBRIQUEE to the HASH JOIN when you include the field name and this should be the expected behavior. But it seems that your WORKING table has a degree of parallelism set against what is causing the query to run in parallel (as JOB table is now available with full table scan, instead of indexed access earlier). It could be that the parallel execution is contributor to extra Runtime.
  (a) do you know why the degree of parallelism on the WORK table has been defined? Do you need it?

  You can see if the following query provides a better response time?

  select /*+ NOPARALLEL(JOB) */ JobComp.*, Job.Name
    from JobComp
    join Job
      on Job.id = JobComp.id_job
   where JobComp.id_comp = 134
  

• Primary key several columns with Date - parameter problem

  All,
  I'm having a problem where I can not find the answer to. I looked upstairs and down nothing helps. Help, please.
  
  The issue is that I have a table that has a primary key of several columns and a column is a date, and the other is a string. I have a simple search and I want a picture update of the results table that users can click on and go to another page to update this record. The question is when I launch an appeal based on the updated image, I also want to define the settings based on the record that I have selected. So I put the string parameter and that works very well. The problem is with the date. When I put the setting date this market but he chops off the coast of the timestamp. Later when I try to access this setting "("dateParameter") pageContext.getParameter"; that it will bring a date as December 15, 2008 but I need the whole date and time stamp (i.e., December 15, 2008 10:20:33) to properly identify the record.
  
  Help, please!
  
  Thank you
  Colby J

  Hello

  because each parameter go into url as a format string, so you will never get the full date with timestamp setting, the solution would be to

  1.) set a fire on the photo update action, give his name to the event as "update."

  (2.) by clicking Update photograph fires this event.

  (3.) processFormrequest in the controller method

  OAApplicationModule am = pageContext.getApplicationModule (webBean);

  If ("update".equals (pageContext.getParameter ("event")))
  {
  This will give you the select line when you click Update

  String rowReference = pageContext.getParameter (OAWebBeanConstants.EVENT_SOURCE_ROW_REFERENCE);
  Line VORowImpl = (EmployeeSummaryVORowImpl) am.findRowByRef (rowReference);
  Timestamp sdateVal = (String) row.getAttribute ("Date value");

  This will transfer the values to the next page
  pageContext.putTransactionTransientValue ("transferdvalue", sdateVal);

  }

  and in the next page, you can get the value as follows

  timestamp getDateVal = pageContext.getTransactionTransientValue ("transferdvalue" l);

  hope this will solve your problem, please let me know if you face any problem

  thanx
  Pratap

• Problems with the primary key of the query string

  Moving from asp to php, to work with David Power's book: The Essential Guide to Dreamweaver CS4 with CSS, AJAX, and PHP.  Recycling of my brain, so starting from scratch in the learning process.

  Everything was going perfectly until I tried to add the primary key of a record in a query string.  I compared my code with the example code for the book, and everything matches.  When previewing the page in my browser and hover over the link which must pass the main code on the next page, the query string does not appear correctly.  It shows user_id = but no figure shows, as it is supposed to.  www.webpage.com/update_user.php?user_id=

  Here is my code: (Please note, <>have been removed, as I was unable to find a way view the code in the correct way here (copy/paste was doesn't work do not, nor insert syntax))

  ? PHP {?}

  ? PHP echo $row_listUser ['family_name'];? PHP echo $row_listUser ["FirstName"];?

  ? PHP echo $row_listUser ['username'];?       ? PHP echo $row_listUser ["admin_priv"];?

  a href = "update_user.php? user_id =? php echo $row_listUser ['user_id'];?" "Edit / has

  a href = "delete_user.php? user_id =? php echo $row_listUser ['user_id'];?" ' Delete / has

  ? PHP} while ($row_listUser = mysql_fetch_assoc ($listUser));?

  Any ideas that could help me understand why this part does not in particular would be greatly appreciated.  Writing to the database worked perfectly, I see that there are numbers in the database as user_id, and it is defined as my primary key in the configuration database.  Such a simple process that is causing me headaches!

  Thank you

  You have the code to request a copy in your folder:

  $query_listUser = 'SELECT user_id, username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  $totalRows_listUser = mysql_num_rows ($listUser);

  $query_listUser = 'SELECT username, first_name, family_name, admin_priv from users ORDER BY family_name ASC';

  $listUser = mysql_query ($query_listUser, $connSCFDIR) or die (mysql_error ());

  $row_listUser = mysql_fetch_assoc ($listUser);

  The $listUser table will contain the results of the second query, which does not include the field user_id. delete the redundant code.

• Problem with the primary key

  Hi all
  I have a table with the same data repeat 2 times. I mean that the lines are depating twice. so now, I create a primary key for the table. He throws me an error saying voilation key primary. I'll give you the clear script.
  
  create table employee)
  ID VARCHAR2 (4 BYTE) NOT NULL,
  First name VARCHAR2 (10 BYTE),
  VARCHAR2 (10 BYTE) last_name,
  START_DATE DATE,
  End_date DATE,
  Number (8.2) of salary.
  City VARCHAR2 (10 BYTE),
  Description VARCHAR2 (15 BYTE)
  )
  
  
  insert into employee values ('01', 'Jason', 'Martin', to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto', 'Program');
  insert into employee values ('02', "Alison", "Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver', 'Tester');
  insert into employee values ('03', 'James', 'Smith', to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver', 'Tester');
  insert into employee values ('04', 'Celia', 'Rice', to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, "Vancouver", "Manager");
  insert into employee values ('05', 'Robert', 'Black', to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver', 'Tester');
  insert into employee values ('07', 'David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78, 'New York', 'Manager');
  insert into employee values ('06', 'Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78, 'New York', 'Tester');
  insert into employee values ('08', 'James', 'Cat', to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78, 'Vancouver', 'Tester')
  insert into employee values ('07', 'David', 'Larry', to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78, 'New York', 'Manager');
  insert into employee values ('06', 'Linda', 'Green', to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78, 'New York', 'Tester');
  
  
  The table is now with 10 columns
  
  ID FIRST_NAME LAST_NAME START_DAT END_DATE SALARY CITY DESCRIPTION
  ---- ---------- ---------- --------- --------- ---------- ---------- ---------------
  Jason Martin 25 July 96 01 25 July 06 1234.56 Toronto programmer
  02 Alison Mathews 21 March 76 February 21, 86 6661.78 Vancouver Tester
  03 James Smith December 12, 78 March 15, 90 6544.78 Vancouver Tester
  04 Celia rice 24 October 82 21 April 99 2344.78 Vancouver Manager
  Robert Black 05 January 15, 84 8 August 98 2334.78 Vancouver Tester
  Linda Green 06 July 30, 87 January 4, 96 4322.78 tester of New York
  Manager of New York 07 David Larry 31 December 90 February 12, 98 7897.78
  08 James Cat 17-AUG-96 April 15 02 1232.78 ester of Vancouver
  
  
  Create a primary key for the table
  
  "Employee to ALTER TABLE PRIMARY KEY (ID, First_Name, Last_Name, start_date, end_date,
  Salary, city, Description); »
  
  I get error voilation primary key
  
  IS IT POSSIBLE TO CREATE THE KEY PRIMARY ON THE TABLE WITH ON THE DELETION OF THE DATA?
  Is IT POSSIBLE CREATING PRIMARY KEY USING 'GROUP BY' FUNCTION or OTHER FUNCTIONS?
  
  Published by: user11872870 on September 23, 2010 17:41

  Primary key columns cannot contain NULL values. If you tried to create a primary key constraint, you will get an error like this:

  ERROR at line 1:
  ORA-01449: column contains NULL values: cannot alter to NOT NULL
  

  However, you can add a unique constraint by doing something like the following:

  ALTER TABLE test ADD CONSTRAINT test_unq UNIQUE (column1, column2);
  

  I still wonder why you take the approach you take. I have a vague feeling that're missing us the key pieces of information to recommend the correct solution.

• updated primary key of the problem 10 gr 2 (10.1.2.0.1)

  Primary key can be updated... How to protect

  iloveoracle wrote:
  Primary key can be updated...

  Yes - longer updating does not violate constraint primary key

  How to protect

  Trigger.