Problem in createLinearGradientBackground()

I use the following method to set the background color. I have a value R, B and B for the color I want. But how can I convert to 32-bit 0x00RRGGBB.

public static Background createLinearGradientBackground(int colorTopLeft,
                                                        int colorTopRight,
                                                        int colorBottomRight,
                                                        int colorBottomLeft)

How do I convert it?

Your color values will be in the range 0-255.  Convert these to hex then used.  For example, if your Red value 128, while in France is 80, if Green was 16, then it would be 10 in hexadecimal, and if blue was 64, it's 40, so the color value would be 0 X 00801040.  make sense?

Tags: BlackBerry Developers

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