problem with join of two tables

Hi, consider the following data

WITH data AS
(
  SELECT 123 cid, 'aaa' isi, 'kkk' sud, 'ttt' ri FROM dual UNION ALL 
  SELECT 222 cid, 'bbb' isi, 'gggg' sud, 'hhh' ri FROM dual

) ,
data2 AS 
(
  SELECT 'aaa' isi, 'yyy' sud, 'ooo' ri FROM dual UNION ALL 
  SELECT 'qqq' isi, 'ggg' sud, 'ooo' ri FROM dual UNION ALL 
  SELECT 'uuu' isi, 'ppp' sud, 'ttt' ri FROM dual UNION ALL
   SELECT 'ppp' isi, 'mmm' sud, 'nnn' ri FROM dual 


)

what I want to do, is to join data2 with data by isi, ri or southern id table and produce this output.

 cid  txt
 ===  ====
 123  aaa
 222  ggg
 123  ttt

It's how I got the above output:
first try to join isi in database2 with isi in "features" and discover if line matches. If this is the case, display the cid of the data table and the use of the value to match.
e.g. in the first line of table data2, we can see that isi = aaa matches line an isi data table. If the output displays 123 and value aaa.

If the rank table two of the Data2 isi = qqq. When join them with the data table, we find not all isi with qqq. in this case, it must join with column of South. We can see that South = ggg data2 games
the second line in the table of output so will bee 222 and value ggg.

now, take a look at the third row in Database2. ISI = uuu is not found in the data table when join them. then try to join to the South. South = ttt is also not found in any row of the data table. so join with ri. We
can see that ri = ttt data2 matches with ri = ttt in the table of data online 1. Therefore, we display the value.

can someone help me write a sql query that joins these two tables by isi. If no line found then join South, if no found rows then join in ri? Thank you

Hello

elmasduro wrote:
Hi Frank, data2.sud = 'Gay' (4 characters) assume to be South = "ggg". by mistake, I type extra g.

I have another question about the request. What happens if I want to bring rows of data.2 even if they do not exist in the data table for the entire column was join?
for example, I want to show this:
cid  txt
===  ====
123  aaa
222  ggg
123  ttt
ppp  --row from data2
the columns of the last row of data.2 does not match any column in the data table. in this case, I want to make but cid will be null. I tried outer join on your request, but it looks like I can not clause or with outer join
SELECT     d1.cid
,     CASE
          WHEN  d1.isi = d2.isi  THEN  d2.isi
          WHEN  d1.sud = d2.sud  THEN  d2.sud
                                        ELSE  d2.ri
     END     AS txt
FROM data     d1
JOIN     data2     d2  ON     d1.is(+)i     = d2.isi
              OR     d1.sud(+)     = d2.sud
              OR     d1.ri(+)     = d2.ri
;
How can I re - write the query for this case? Thanks again for your help

Here is the outer join syntax:

SELECT     d1.cid
,     CASE
          WHEN  d1.isi = d2.isi  THEN  d2.isi
          WHEN  d1.sud = d2.sud  THEN  d2.sud
          WHEN  d1.ri  = d2.ri   THEN  d2.ri
                                        ELSE  d2.isi
     END     AS txt
FROM          data2     d2
LEFT OUTER JOIN     data     d1  ON     d1.isi     = d2.isi
                       OR     d1.sud     = d2.sud
                       OR     d1.ri     = d2.ri
;

The + sign for outer joins only works with the old join syntax, non-ANSI. Do not try to mix the two different ways to do joins.

Not to mention that the outer join, don't forget to change the CASE expression, to include the new possibility of any columns 3 join matching.

Tags: Database

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declare
l_start_file_name varchar2(50) := 'liab_report_summary_p008_c';
l_end_file_name varchar2(50)   := '_english.rep';
l_file_name varchar2(100);
l_sql varchar(32767);
refresh_cdc varchar2(10) := '00540';

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          ' (                                                   '||
          '  draw_number       varchar2(50),                    '||
          '  total_winners_amt number,                          '||
          '  paid_today_amt    number,                          '||
          '  total_paid_amt    number,                          '||
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          '       (                                             '||
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 ' ( draw_number             , '||
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rollback;
l_sql :='drop table LOTO_LIABILITY_REPORT_temp';
execute immediate l_sql;
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 '       LOTO_LIABILITY_REPORT_temp a                                     ,'||
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Table A has 4,000,000 entries and table B has 700,000 entries.

I have a join of two tables with a numeric column as join criteria.

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So I instead of
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When I use the join in a select query, it works.

But when I use the join as inline in an update statement I get the error ORA-01779.

When I remove the '+ 0' the update statement works. (The column is unique in table B).

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http://Apex.Oracle.com/i/index.html
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PW: app_1000
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  - Event: After refresh
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```
//at page load and after each region refresh:
//each: check all checkboxes and set readonly on ename accordingly
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$("td[headers='CHECKBOX'] input[type='checkbox']:visible")
.each(function(){checkReadonly(this);})
.click(function(){checkReadonly(this);});
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Page > function and global variables declaration

function checkReadonly(pCheck){
   var lCheck = $(pCheck);
   lCheck.closest("tr")
   .find("td[headers='ENAME'] input:visible").each(function(){
      $(this).prop("readonly", lCheck.prop("checked"));
   });
};

Page > CSS Inline

td[headers='ENAME'] input{
background-color: red;
}
td[headers='ENAME'] input[readonly]{
background-color: lightgrey;
}

CSS works so much better for this than the application of style through js...

Form 2 tab: copied to Page 13 and made my changes here:_

OnChange on ENAME. This removed. No idea why you would need this.
OnClick on CHECKBOX. Removed what I hate these attributes. Replaced by a dynamic action.
Dynamic action: identical to page 12, just modified trigger area
Changed input to TEXTAREA when it is required:

Page > function and global variables declaration

function checkReadonly(pCheck){
   var lCheck = $(pCheck);
   lCheck.closest("tr")
   .find("td[headers='ENAME'] textarea:visible").each(function(){
      $(this).prop("readonly", lCheck.prop("checked"));
   });
};

Page > CSS Inline

td[headers='ENAME'] textarea{
background-color: red;
}
td[headers='ENAME'] textarea[readonly]{
background-color: lightgrey;
}

The f_set_counter function, I changed a bit: there are 2 straps too, put a semicolon at the end of each line.
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-changed $x (node) .innerHTML to $(node) .text)
I know: it worked. I like this better. OCD? :/

function f_set_counter(pThis,pLength,pMaxLength,pReset)
{
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Published by: Tom on February 15, 2013 12:48
Made a mistake in the case of dynamic action :->, click after refresh!

Problem with joining several tables

Hello PL/SQL gurus and experts.

I use Oracle Database 11 g Enterprise Edition Release 11.2.0.1.0 - 64-bit Production version
I followed two tables

Student-

drop table TT3;
create table TT3(FeesCntlr,CommCntlr,LatePayCntlr,Name,Age) as select
1,11,21,'Mike',25 from dual union all select
2,12,22,'Clark',26 from dual union all select
1,11,21,'Mike',27 from dual union all select
4,17,27,'Ussan',28 from dual union all select
5,13,21,'Linda',29 from dual union all select
6,14,24,'Obrek',35 from dual union all select
7,15,25,'Batty',45 from dual union all select
8,16,26,'Nicky',38 from dual union all select
1,11,21,'Mike',25 from dual union all select
2,12,22,'Clark',26 from dual union all select
1,11,21,'Mike',27 from dual union all select
4,17,27,'Ussan',28 from dual union all select
5,13,21,'Linda',29 from dual union all select
6,14,24,'Obrek',35 from dual union all select
7,15,25,'Batty',45 from dual union all select
8,16,26,'Nicky',38 from dual ;

Fees-

drop table TT4;
create table TT4(FeesCntlr,CommCntlr,LatePayCntlr,Fees,Commission,Latepayment) as select
1,11,21,25000,4456,223 from dual union all select
2,12,22,356000,3321,0 from dual union all select
1,11,21,456000,223,33 from dual union all select
4,17,27,32890,0,0 from dual union all select
5,13,21,0,778,223 from dual union all select
6,14,24,332567,222,0 from dual union all select
7,15,25,228990,22,0 from dual union all select
8,16,26,0,0,2234 from dual union all select
1,11,21,22345,0,0 from dual union all select
2,12,22,2222789,2,33 from dual union all select
1,11,21,334567,0,0 from dual union all select
4,17,27,9987250,2,33 from dual union all select
5,13,21,2227890,0,0 from dual union all select
6,14,24,2278231,0,3345 from dual union all select
7,15,25,223456,2,0 from dual union all select
8,16,26,223890,0,0 from dual ;

I am looking forward to the fees, commissions and surcharges output for each student and by using the following SQL code.

select t3.Name,t3.age,t4.Fees
from tt3 t3, tt4 t4
where t3.FeesCntlr=t4.FeesCntlr
union
select t3.Name,t3.age,t4.Commission
from tt3 t3, tt4 t4
where t3.CommCntlr=t4.CommCntlr
union
select t3.Name,t3.age,t4.Latepayment
from tt3 t3, tt4 t4
where t3.LatePayCntlr=t4.LatePayCntlr

but it gives me not the correct result and showing a lot of entries and display only the "Expenses" column then only I'm looking for the output to be -

Name     Age     Fees          Commission     Laypayment
Mike     25     837912          4679          256
Clark     26     2578789          3323          33
Ussan     36     10020140     2          33
Linda     38     2227890          778          223
Obrek     38     2610798          222          3345
Batty     32     452446          24          0
Nicky     23     223890          0          2234

Kindly help me with this. Thank you in advance for your time and effort.

Hello

I see your table TT3 has duplicated lines. A reason for this?

Rather than run a separate, I created it without duplicated lines:

create table TT3(FeesCntlr,CommCntlr,LatePayCntlr,Name,Age) as select
1,11,21,'Mike',25 from dual union all select
2,12,22,'Clark',26 from dual union all select
4,17,27,'Ussan',28 from dual union all select
5,13,21,'Linda',29 from dual union all select
6,14,24,'Obrek',35 from dual union all select
7,15,25,'Batty',45 from dual union all select
8,16,26,'Nicky',38 from dual;

create table TT4(FeesCntlr,CommCntlr,LatePayCntlr,Fees,Commission,Latepayment) as select
1,11,21,25000,4456,223 from dual union all select
2,12,22,356000,3321,0 from dual union all select
1,11,21,456000,223,33 from dual union all select
4,17,27,32890,0,0 from dual union all select
5,13,21,0,778,223 from dual union all select
6,14,24,332567,222,0 from dual union all select
7,15,25,228990,22,0 from dual union all select
8,16,26,0,0,2234 from dual union all select
1,11,21,22345,0,0 from dual union all select
2,12,22,2222789,2,33 from dual union all select
1,11,21,334567,0,0 from dual union all select
4,17,27,9987250,2,33 from dual union all select
5,13,21,2227890,0,0 from dual union all select
6,14,24,2278231,0,3345 from dual union all select
7,15,25,223456,2,0 from dual union all select
8,16,26,223890,0,0 from dual ;

  SELECT t3.name, t3.age, SUM (t4.fees) fees, SUM (t4.commission) commission
       , SUM (t4.latepayment) latepayment
    FROM tt3 t3, tt4 t4
   WHERE     t3.feescntlr = t4.feescntlr
         AND t3.commcntlr = t4.commcntlr
         AND t3.latepaycntlr = t4.latepaycntlr
GROUP BY t3.name, t3.age;

Output:
NAME         AGE       FEES COMMISSION LATEPAYMENT
----- ---------- ---------- ---------- -----------
Mike          25     837912       4679         256
Ussan         28   10020140          2          33
Linda         29    2227890        778         223
Clark         26    2578789       3323          33
Obrek         35    2610798        222        3345
Nicky         38     223890          0        2234
Batty         45     452446         24           0

Kind regards.
Al

Published by: Alberto Faenza on November 6, 2012 12:40

help the join of two tables

Hello

I need your help in the script below:

I have two tables.

My "table1" table contains the data below:

Code:

Name, Value
------------
12 A, 1
12 B, 1
12 C, 1

Table2 contains the following data:

Code:

value, result
------------
1.12
1.24
1.56
1 423
1.32
1, 3

I need to join based on a field value.

My result is:

Code:

NAME, VALUE, RESULT
-------------------------
12 A, 1, 12
12 B, 1: 24
12 C, 1, 56
12d, 1, 423
12TH, 1, 32
12F, 1, 3

Based on the number of records in the second table, it must add A to Z at the end of the name field. The number of records exceeds no more than 26. How can we achieve this?

_________________

Thank you
Pocard

OK, now you give other useful information - that there always will be combinations of amounts in table2 to match values in table1. (It is difficult to help when you say the specs one both :-))

But it is not easy, because the code should really try to consider all combinations and then 'choose the right' - it's easy for us humans, but not easy to code in the programming logic.
I made an attempt:

SQL> set linesize 120
SQL> with table1 as (
  2     select 'A1' name, 123 id, 150 value from dual union all
  3     select 'A2' name, 123 id, 200 value from dual union all
  4     select 'A3' name, 123 id, 300 value from dual
  5  ), table2 as (
  6     select 123 id, 100 value from dual union all
  7     select 123 id, 100 value from dual union all
  8     select 123 id, 50  value from dual union all
  9     select 123 id, 100 value from dual union all
 10     select 123 id, 100 value from dual union all
 11     select 123 id, 100 value from dual union all
 12     select 123 id, 100 value from dual
 13  )
 14  --
 15  -- End of test data
 16  --
 17  select
 18  t1.id, t1.name, t1.value, t2.value,
 19  t1.rn, t1.minval, t1.maxval,
 20  t2.rn, t2.sumval
 21  from (
 22     select
 23     tab1.*,
 24     nvl(sum(tab1.value) over (
 25        partition by tab1.id
 26        order by tab1.rn
 27        rows between unbounded preceding and 1 preceding
 28     ),0) minval,
 29     sum(tab1.value) over (
 30        partition by tab1.id
 31        order by tab1.rn
 32        rows between unbounded preceding and current row
 33     ) maxval
 34     from (
 35        select
 36        table1.*,
 37        row_number() over (
 38           partition by table1.id
 39           order by table1.value desc
 40        ) rn
 41        from table1
 42     ) tab1
 43  ) t1
 44  join (
 45     select
 46     tab2.*,
 47     sum(tab2.value) over (
 48        partition by tab2.id
 49        order by tab2.rn
 50     ) sumval
 51     from (
 52        select
 53        table2.*,
 54        row_number() over (
 55           partition by table2.id
 56           order by table2.value desc
 57        ) rn
 58        from table2
 59     ) tab2
 60  ) t2
 61  on (t2.id = t1.id)
 62  where t2.sumval > t1.minval
 63  and t2.sumval <= t1.maxval
 64  order by
 65  t1.id,
 66  t1.rn,
 67  t2.rn
 68  ;

        ID NA      VALUE      VALUE         RN     MINVAL     MAXVAL         RN     SUMVAL
---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ----------
       123 A3        300        100          1          0        300          1        100
       123 A3        300        100          1          0        300          2        200
       123 A3        300        100          1          0        300          3        300
       123 A2        200        100          2        300        500          4        400
       123 A2        200        100          2        300        500          5        500
       123 A1        150        100          3        500        650          6        600
       123 A1        150         50          3        500        650          7        650

7 rows selected.

It doesn't seem to work for your sample data, but it is much too simple a rule at work in general. My "rule" is simply of sorts data according to the value descending and adding up to what 'enough' of values have been added.

Consider this example of data instead of this:

SQL> with table1 as (
  2     select 'A1' name, 1 id, 100 value from dual union all
  3     select 'A2' name, 1 id, 200 value from dual union all
  4     select 'A3' name, 1 id, 300 value from dual union all
  5     select 'B1' name, 2 id, 100 value from dual union all
  6     select 'B2' name, 2 id, 200 value from dual
  7  ), table2 as (
  8     select 1 id, 25  value from dual union all
  9     select 1 id, 75  value from dual union all
 10     select 1 id, 50  value from dual union all
 11     select 1 id, 50  value from dual union all
 12     select 1 id, 175 value from dual union all
 13     select 1 id, 225 value from dual union all
 14     select 2 id, 25  value from dual union all
 15     select 2 id, 50  value from dual union all
 16     select 2 id, 75  value from dual union all
 17     select 2 id, 100 value from dual union all
 18     select 2 id, 50  value from dual
 19  )
 20  --
 21  -- End of test data
 22  --
 23  select
 24  t1.id, t1.name, t1.value, t2.value,
 25  t1.rn, t1.minval, t1.maxval,
 26  t2.rn, t2.sumval
 27  from (
 28     select
 29     tab1.*,
 30     nvl(sum(tab1.value) over (
 31        partition by tab1.id
 32        order by tab1.rn
 33        rows between unbounded preceding and 1 preceding
 34     ),0) minval,
 35     sum(tab1.value) over (
 36        partition by tab1.id
 37        order by tab1.rn
 38        rows between unbounded preceding and current row
 39     ) maxval
 40     from (
 41        select
 42        table1.*,
 43        row_number() over (
 44           partition by table1.id
 45           order by table1.value desc
 46        ) rn
 47        from table1
 48     ) tab1
 49  ) t1
 50  join (
 51     select
 52     tab2.*,
 53     sum(tab2.value) over (
 54        partition by tab2.id
 55        order by tab2.rn
 56     ) sumval
 57     from (
 58        select
 59        table2.*,
 60        row_number() over (
 61           partition by table2.id
 62           order by table2.value desc
 63        ) rn
 64        from table2
 65     ) tab2
 66  ) t2
 67  on (t2.id = t1.id)
 68  where t2.sumval > t1.minval
 69  and t2.sumval <= t1.maxval
 70  order by
 71  t1.id,
 72  t1.rn,
 73  t2.rn
 74  ;

        ID NA      VALUE      VALUE         RN     MINVAL     MAXVAL         RN     SUMVAL
---------- -- ---------- ---------- ---------- ---------- ---------- ---------- ----------
         1 A3        300        225          1          0        300          1        225
         1 A2        200        175          2        300        500          2        400
         1 A2        200         75          2        300        500          3        475
         1 A1        100         50          3        500        600          4        525
         1 A1        100         50          3        500        600          5        575
         1 A1        100         25          3        500        600          6        600
         2 B2        200        100          1          0        200          1        100
         2 B2        200         75          1          0        200          2        175
         2 B1        100         50          2        200        300          3        225
         2 B1        100         50          2        200        300          4        275
         2 B1        100         25          2        200        300          5        300

11 rows selected.

In this data set simple ranking by value won't work - it should have been A3: (225,75), A2: (175,25) and A1: (50.50).

I can't really think of a reasonably easy way to do this in SQL only. Maybe using the clause TYPE would be possible, but not negligible. It is possible, it would be easier to solve this problem in PL/SQL in iterating through a few tables and intelligently to try different combinations, rather than creating all combinations in a huge piece of brute force SQL.

I'm sorry, Pandeesh, but I can't think a solution easily.
I might be able to do something, if I fiddled with the problem for a few days, but that would be beyond the scope of this forum. It would be a consultation of employment rather than a little help from the forum :-)

Please, help me to join of two tables?

Hello..
I'm using oracle 11g.
I have two tables with below description
1.esb_v_study_personnel
study_code_alias varchar2,
Site_ID number,
role_at_site_level_desc varchar2
2 esb_v_study_site
study_code_alias varchar2
Site_ID
I'm counting the role_at_site_level_desc where it is'Monitor' or 'primary monitor'
So I wrote the following query
Select study_code_alias, site_id,.
no_of_study_monitors (role_at_site_lvl_desc)
esb_v_study_site_personnel
study_code_alias IN & arg_trial_code
role_at_site_lvl_desc in ()"Monitor" "Main screen"()
Group of study_code_alias, study_site_id
order by study_site_id
using the above, I'm getting lines of 1617.
but I want to map the resultant site_id
esb_v_study_site with lines of 1647. If I want to get all the site_id in esb_v_study_site table mapping to above query.
Can you guide me on this point.
I tried with a left outer join, but still iam getting lines of 1617.
Select study_code_alias,
no_of_study_monitors (role_at_site_lvl_desc)
esb_v_study_site_personnel
study_code_alias IN & arg_trial_code
role_at_site_lvl_desc in ()"Monitor" "Main screen"()
Group of study_code_alias, study_site_id
order of study_site_id) a
LEFT OUTER JOIN
ON a.trial_no = d.trial_no et a.study_site_id = d.study_site_id
où d.study_code_alias in & arg_trial_code
Group by d.study_code_alias, d.study_site_id, a.no_of_study_monitors
order by d.study_site_id
Please help me on this?

I'm not quite sure, because your query seems to us of small missing pieces. He was probably down during some copy & paste on this forum.

I guess the reason is that the left join is performed after the group where the count on the column does not count NULL values that might be created by the outer join.

Maybe you can start with the following query and give us the results and tell us if it is always wrong and what the outcome would be expected.

example (not tested the syntax)
```
select  d.study_code_alias
    ,d.site_id
   , count(a.role_at_site_lvl_desc) no_of_study_monitors
   , count(distinct a.role_at_site_lvl_desc) no2
   , count(*) no3
from esb_v_study_site d
left join esb_v_study_site_personnel a on a.trial_no=d.trial_no and a.study_site_id=d.study_site_id and a.role_at_site_lvl_desc in ('Field Monitor','Primary Monitor')
where d.study_code_alias IN (&arg_trial_code)
group by d.study_code_alias,d.study_site_id
order by d.study_site_id;
```
BTW: If you read the FAQ in the upper right corner, here, he said how well sql zip code search.

Problems with automatic expansion into table cells

I have problems with a table in my form in LiveCycle Designer. In the document below, "Field 1", I enter text and the cell remains the same size, with the additional text indicated by a '+' at the bottom right. This is the format I want.
However, when I enter more than one line of text in the indicated "lines problem" in the file, the cell automatically expands to fit the text. It's something I want to happen... I would like to the "problem of the lines" to show the same format that "Field 1" in the document and the cell containing the same size of the user required to click on the '+' to display additional information. ". The problem is, the disorder of cells expanded the rest of the form when I put additional information in, and I want to keep the cells in a table evenly the same size.
Thanks for your help! The file is here:
https://Acrobat.com/#d=tdu1W9Xp3PgGXcGLMLwo8A
Windows 7, Acrobat X Pro 10.0.0, LC 9.0.0.2

If you insist on past this road, you can click on the cell you want to order and on the Layout tab, uncheck develop it to adapt to the checkbox in the height box.

Paul

Join of two tables

Hi all
I have two tables - TableA and TableB
I need all these records in TableA that have no matching records in TableB based on Key1, Key2, and Key3 and process them further.
Can someone help pls?

Hello 954475

Try this:

SELECT A.*

FROM TableA A

WHERE DOES NOT EXIST (SELECT 1

FROM TableB B

WHERE A.Key1 = B.Key1

AND A.Key2 = B.Key2

AND A.Key3 = B.Key3

)

;

I hope that helps!

Problems with slices in FW / tables in DW

I created a template page in FW. I made the slices and exported. When to use it in DW to template use, I have problems with some parts of the page skin. I have a top, a navagation on the left and a main content area. When you change the main content area, it puts the gaps in the left navigation, break to the top of the page.

Can anyone help? PLEASE, I BEG YOU.
Thanks for the tips, I'll try that.

Select the problem with joined tables

Hello everyone I have the following query

SELECT 
    OBJEKTI.OBJEKAT_ID OBJEKAT_ID, 
    OBJEKTI.ADRESA ADRESA, 
    OBJEKTI.POVRSINA POVRSINA, 
    OBJEKTI.BROJ_IZVRSILACA BROJ_IZVRSILACA, 
    OPREMLJENOSTI.OPREMLJENOST_ID OPREMLJENOST_ID, 
    OPREMLJENOSTI.PULT PULT, 
    OPREMLJENOSTI.REKLAMA REKLAMA, 
    OPREMLJENOSTI.MOKRI_CVOR MOKRI_CVOR, 
    OPREMLJENOSTI.WC_ZA_IGRACE WC_ZA_IGRACE, 
    OPREMLJENOSTI.WC_ZA_OSOBLJE WC_ZA_OSOBLJE, 
    OPREMLJENOSTI.VENTILATOR VENTILATOR, 
    OPREMLJENOSTI.OSVJETLJENJE OSVJETLJENJE, 
    OPREMLJENOSTI.VRSTA_BROJILA VRSTA_BROJILA, 
    OPREMLJENOSTI.ELEKTRO_INSTALACIJE ELEKTRO_INSTALACIJE, 
    OPREMLJENOSTI.VODO_INSTALACIJE VODO_INSTALACIJE, 
    OPREMLJENOSTI.TELEFONSKE_INSTALACIJE TELEFONSKE_INSTALACIJE, 
    OPREMLJENOSTI.GRIJANJE_ID GRIJANJE_ID, 
    OPREMLJENOSTI.POD_ID POD_ID, 
    OPREMLJENOSTI.PROZORI_VRATA_ID PROZORI_VRATA_ID, 
    OPREMLJENOSTI.OBJEKAT_ID OBJEKAT_ID1, 
    TEHNICKE_OPREMLJENOSTI.TEH_OPR_ID TEH_OPR_ID, 
    TEHNICKE_OPREMLJENOSTI.ONLINE_KLADIONICA ONLINE_KLADIONICA, 
    TEHNICKE_OPREMLJENOSTI.PANO PANO, 
    TEHNICKE_OPREMLJENOSTI.NOSACI NOSACI, 
    TEHNICKE_OPREMLJENOSTI.TV_LCD TV_LCD, 
    TEHNICKE_OPREMLJENOSTI.TV_TELETEXT TV_TELETEXT, 
    TEHNICKE_OPREMLJENOSTI.APARATI_IGRE APARATI_IGRE, 
    TEHNICKE_OPREMLJENOSTI.EVONA EVONA, 
    TEHNICKE_OPREMLJENOSTI.NOVOMATIC NOVOMATIC, 
    TEHNICKE_OPREMLJENOSTI.RULET RULET, 
    TEHNICKE_OPREMLJENOSTI.BILIJAR BILIJAR, 
    TEHNICKE_OPREMLJENOSTI.KLIMA KLIMA, 
    TEHNICKE_OPREMLJENOSTI.OBJEKAT_ID OBJEKAT_ID2, 
    PONUDE.PONUDA_ID PONUDA_ID, 
    PONUDE.ONLINE_TERMINAL ONLINE_TERMINAL, 
    PONUDE.SRECKE SRECKE, 
    PONUDE.ONLINE_KLADIONICA ONLINE_KLADIONICA1, 
    PONUDE.APARATI_IGRE APARATI_IGRE1, 
    PONUDE.RULET RULET1, 
    PONUDE.BILIJAR BILIJAR1, 
    PONUDE.OBJEKAT_ID OBJEKAT_ID3 
FROM 
    OBJEKTI, 
    OPREMLJENOSTI, 
    TEHNICKE_OPREMLJENOSTI, 
    PONUDE 
WHERE 
(PONUDE.OBJEKAT_ID=OBJEKTI.OBJEKAT_ID AND TEHNICKE_OPREMLJENOSTI.OBJEKAT_ID=OPREMLJENOSTI.OBJEKAT_ID) OR (OPREMLJENOSTI.OBJEKAT_ID=OBJEKTI.OBJEKAT_ID AND TEHNICKE_OPREMLJENOSTI.OBJEKAT_ID=OPREMLJENOSTI.OBJEKAT_ID)
 ORDER BY OBJEKTI.OBJEKAT_ID

The problem I have is any WHERE clause I use I have double values that makes no sense. I checked in the tables and I not all double values. Each Opremljenost has 1 objekat (there are 2 rows of each with its own Objekat) and this applies to 2 other tables (PONUDE and TEHNICKE OPREMLJENOSTI), but for some reason any that they double values. If I run it without a where clause at all clause, I get a repetition of values itself up to 4 times. Does anyone have an idea what's wrong with my request?

Well, if all relationships are to 1-1 (1-0), then try this (the names of table/column, but you get what I mean bad):

select OBJ.*, OPR.*, TEH.*, PON.* -- I know you can't do this, but you get what I mean.
from OBJ,OPR,TEH,PON
where OBJ.object = OPR.object (+)
  and OBJ.object = TEH.object (+)
  and OBJ.object = PON.object (+)
/

its supposed to be a 1 to 1 relationship, but it is not.

In this case the remedy is very simple: create a UNIQUE constraint on the column of the OBJECT in OPR, TEH and PON...

I have a problem with a CS6 dynamic table creation

I have 2 tables, 1 of them is caled 'user', the other a "cars" they are inked with a foreign key in the table of cars there is a column called UserID and takes the value of "user", so my question is I tried to make it dynamic table when the user is connected to display its cars that have his Userid on them only unfortunetly when I do this I get a blank table with nothing in it anyone can help me solve this problem. This is the code I use:
<? php require_once('Connections/MyConnection.php');? >
<? PHP
initialize the session
If (! isset {})
session_start();
}
* Log out the current user. **
$logoutAction = $_SERVER ['PHP_SELF']. » ? doLogout = true;
If ((isset & & ($_SERVER ['QUERY_STRING']! = "")) {})
$logoutAction. = '& '. htmlentities($_SERVER['QUERY_STRING']);
}
{If ((isset($_GET['doLogout'])) & & ($ {_GET ['doLogout'] == "true"))}
to completely disconnect a visitor, you must delete the session varialbles
$_SESSION ['MM_Username'] = NULL;
$_SESSION ['MM_UserGroup'] = NULL;
$_SESSION ['PrevUrl'] = NULL;
unset($_SESSION['MM_Username']);
unset($_SESSION['MM_UserGroup']);
unset($_SESSION['PrevUrl']);
$logoutGoTo = "/ cars/LogOut.php";
If {($logoutGoTo)
Header ("Location: $logoutGoTo");
"exit";
}
}
? >
<? PHP
If (! isset {})
session_start();
}
$MM_authorizedUsers = '1', 2;
$MM_donotCheckaccess = "false";
Restrict access to Page: grant or deny access to this page
Function isAuthorized ($strUsers, $UserGroup, $strGroups, $UserName) {}
For safety, first assuming that the visitor is NOT allowed.
$isValid = false;
When a visitor is connected to this site, the MM_Username of Session variable value equal to their username.
So, we know that a user is NOT logged if this Session variable is empty.
If (! empty ($UserName)) {}
In addition to being connected, you can restrict access to only certain users based on a created ID when they connect.
Analyze the channels in the tables.
$arrUsers = explode (",", $strUsers);
$arrGroups = explode (",", $strGroups);
If (in_array ($UserName, $arrUsers)) {}
$isValid = true;
}
Or, you can restrict access to only certain users based on their user name.
If (in_array ($UserGroup, $arrGroups)) {}
$isValid = true;
}
If (($strUsers == "") & & false) {}
$isValid = true;
}
}
return $isValid;
}
$MM_restrictGoTo = "/ cars/Home.php";
If (!) {(((isset($_SESSION['MM_Username']))) & & (isAuthorized ("", $MM_authorizedUsers, $_SESSION ['MM_Username'], {$_SESSION ['MM_UserGroup']})))}
$MM_qsChar = ';?
$MM_referrer = $_SERVER ['PHP_SELF'];
If (strpos ($MM_restrictGoTo, "?")) $MM_qsChar = "&";
If (isset($_SERVER['QUERY_STRING']) & & strlen($_SERVER['QUERY_STRING']) > 0)
$MM_referrer. = « ? ». $_SERVER ['QUERY_STRING'];
$MM_restrictGoTo = $MM_restrictGoTo. $MM_qsChar. "accesscheck =". UrlEncode ($MM_referrer);
Header ("Location:".) $MM_restrictGoTo);
"exit";
}
? >
<? PHP
If (! function_exists ("GetSQLValueString")) {}
function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
If (via PHP_VERSION < 6) {}
$theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;
}
$theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);
Switch ($theType) {}
case 'text ':
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "long":
case "int":
$theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';
break;
case "double":
$theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';
break;
case "date":
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "set":
$theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;
break;
}
Return $theValue;
}
}
If (! function_exists ("GetSQLValueString")) {}
function GetSQLValueString ($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "")
{
If (via PHP_VERSION < 6) {}
$theValue = get_magic_quotes_gpc()? stripslashes ($TheValue): $theValue;
}
$theValue = function_exists ("mysql_real_escape_string")? mysql_real_escape_string ($TheValue): mysql_escape_string ($theValue);
Switch ($theType) {}
case 'text ':
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "long":
case "int":
$theValue = ($theValue! = "")? intval ($TheValue): 'NULL ';
break;
case "double":
$theValue = ($theValue! = "")? doubleVal ($TheValue): 'NULL ';
break;
case "date":
$theValue = ($theValue! = "")? « " ». $theValue. "" "": "NULL";
break;
case "set":
$theValue = ($theValue! = "")? $theDefinedValue: $theNotDefinedValue;
break;
}
Return $theValue;
}
}
$maxRows_cars = 10;
$pageNum_cars = 0;
If (isset($_GET['pageNum_cars'])) {}
$pageNum_cars = $_GET ['pageNum_cars'];
}
$startRow_cars = $pageNum_cars * $maxRows_cars;
$colname_cars = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_cars = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_cars = sprintf ("" SELECT * FROM cars WHERE UserID = %s ", GetSQLValueString ($colname_cars,"int")");
$query_limit_cars = sprintf ("%s LIMIT %d, %d", $query_cars, $startRow_cars, $maxRows_cars);
$cars = mysql_query ($query_limit_cars, $MyConnection) or die (mysql_error ());
$row_cars = mysql_fetch_assoc ($cars);
If (isset($_GET['totalRows_cars'])) {}
$totalRows_cars = $_GET ['totalRows_cars'];
} else {}
$all_cars = mysql_query ($query_cars);
$totalRows_cars = mysql_num_rows ($all_cars);
}
$totalPages_cars = ceil($totalRows_cars/$maxRows_cars)-1;
$colname_user = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_user = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_user = sprintf ("SELECT * FROM 'user' WHERE Email = %s", GetSQLValueString ($colname_user, "text") ");
$user = mysql_query ($query_user, $MyConnection) or die (mysql_error ());
$row_user = mysql_fetch_assoc ($user);
$totalRows_user = mysql_num_rows ($user);
$colname_user = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_user = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_user = sprintf ("SELECT FirstName, LastName FROM 'user' WHERE Email = %s", GetSQLValueString ($colname_user, "text") ");
$user = mysql_query ($query_user, $MyConnection) or die (mysql_error ());
$row_user = mysql_fetch_assoc ($user);
$colname_User = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_User = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_User = sprintf ("SELECT * FROM 'user' WHERE Email = %s", GetSQLValueString ($colname_User, "text") ");
$User = mysql_query ($query_User, $MyConnection) or die (mysql_error ());
$row_User = mysql_fetch_assoc ($User);
$colname_User = "-1";
If (isset($_GET['MM_Username'])) {}
$colname_User = $_GET ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_User = sprintf ("SELECT * FROM 'user' WHERE Email = %s", GetSQLValueString ($colname_User, "text") ");
$User = mysql_query ($query_User, $MyConnection) or die (mysql_error ());
$row_User = mysql_fetch_assoc ($User);
$colname_User = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_User = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_User = sprintf ("SELECT * FROM 'user' WHERE Email = %s", GetSQLValueString ($colname_User, "text") ");
$User = mysql_query ($query_User, $MyConnection) or die (mysql_error ());
$row_User = mysql_fetch_assoc ($User);
$colname_User = "-1";
If (isset($_SESSION['MM_Username'])) {}
$colname_User = $_SESSION ['MM_Username"];
}
@mysql_select_db ($database_MyConnection, $MyConnection);
$query_User = sprintf ("SELECT * FROM 'user' WHERE UserID = %s", GetSQLValueString ($colname_User, "int") ");
$User = mysql_query ($query_User, $MyConnection) or die (mysql_error ());
$row_User = mysql_fetch_assoc ($User);
? >
< ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""
" < html xmlns =" http://www.w3.org/1999/xhtml ">
< head >
< link href = "CSS/Layout.css" rel = "stylesheet" type = "text/css" / > "
< link href = "CSS/Menu.css" rel = "stylesheet" type = "text/css" / > "
"< link href="/Cars/CSS/VerticalMenu.css "rel ="stylesheet"type =" text/css"/ >
< meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"
< title > Untitled Document < /title >
< / head >
< body >
< div id = 'Holder' >
< div id = "Header" >
< div id = "HeaderContentRight" >
< table width = "0" border = "0" align = "right" >
< b >
< td > logged in as: <? PHP echo $row_user ["FirstName"];? > <? PHP echo $row_user ['name'];? > < table >
< td > < a href = "<?" PHP echo $logoutAction? > "> sign out < /a > < table >"
< /tr >
< /table >
< / div >
< / div >
< div id = "NavBar" >
< nav >
< ul >
"< li > < a href="/Cars/HomeAccount.php "> home < /a > < /li >
< /ul >
< / nav >
< / div >
< div id = "Content" >
< div id = "PageHeading" >
Welcome < h1 >, <? PHP echo $row_user ["FirstName"];? > <? PHP echo $row_user ['name'];? >! < / h1 >
< / div >
< div id = "ContentLeft" >
Control Panel < h6 > < / h6 >
< p > < / p >
< ul id = "MyMainMenu" >
< li > < a href="/Cars/Account.php" > account < /a > < /li > ".
< li > < a href="/Cars/UpdateAccount.php" > update account < /a > < /li > ".
< li > < a href="/Cars/CarManagment.php" > car management < /a > < /li > ".
< /ul >
< / div >
< div id = "ContentRight" >
< table border = "1" align = "center" >
< b >
CarBrand < td > < table >
CarModel < td > < table >
YearOfProduction < td > < table >
< /tr >
<? PHP {? >}
< b >
< td > <? PHP echo $row_cars ["CarBrand'];? > < table >
< td > <? PHP echo $row_cars ["CarModel'];? > < table >
< td > <? PHP echo $row_cars ["YearOfProduction"];? > < table >
< /tr >
<? PHP} while ($row_cars = mysql_fetch_assoc ($cars));? >
< /table >
< / div >
< / div >
< div id = "Footer" > < / div >
< / div >
< / body >
< / html >
<? PHP
mysql_free_result ($CARS);
mysql_free_result ($User);
? >
Thank you for your time!

Nowhere on this page I see that you have found the "UserID" variable that is used to query the database of cars everywhere.

You must get that table "user" when a successful connection occurred.

Go to your login page and find the code which queries the database (it will look something like the below, your request will be slightly different)

$LoginRS__query = sprintf ("SELECT username, password loginUsers WHERE username = %s AND password is %s",

MAKE SURE YOU add to THE QUERY "UserID" (see below.) This is the column of your 'user' table and the foreign key record unique identifier in your table 'cars')

$LoginRS__query = sprintf ("SELECT UserID, username, password AND password loginUsers WHERE username = %s is %s",

Then, find the lines of code below:

$LoginRS = mysql_query ($LoginRS__query, $MyConnection) or die (mysql_error ());

$loginFoundUser = mysql_num_rows ($LoginRS);

Include these two lines of code directly after the above code:

$row = mysql_fetch_assoc ($LoginRS);

$UserID = $row ['UserID']

Can find these lines of code:

If {($loginFoundUser)

$loginStrGroup = "";

Declare two session variables and assign them

$_SESSION ['MM_Username"] = $loginUsername;

$_SESSION ["MM_UserGroup"] = $loginStrGroup;

Add this line of code directly after the above code:

$_SESSION ['username'] = $UserID;

Now, go to the login page of success (whatever you call that)

Find the code at the top of the page below:

If (! isset {})

session_start();

}

Add the line of code below:

If (! isset {})

session_start();

$userID = $_SESSION ['username'];

}

Look for the query:

@mysql_select_db ($database_MyConnection, $MyConnection);

$query_cars = sprintf ("" SELECT * FROM cars WHERE UserID = %s ", GetSQLValueString ($colname_cars,"int")");

$query_limit_cars = sprintf ("%s LIMIT %d, %d", $query_cars, $startRow_cars, $maxRows_cars);

$cars = mysql_query ($query_limit_cars, $MyConnection) or die (mysql_error ());

$row_cars = mysql_fetch_assoc ($cars);

and replace with:

@mysql_select_db ($database_MyConnection, $MyConnection);

$query_query_cars = "SELECT * FROM cars WHERE userID ="$userID "";

$query_cars = mysql_query ($query_query_cars, $MyConnection) or die (mysql_error ());

$row_query_cars = mysql_fetch_assoc ($query_cars);

$totalRows_query_cars = mysql_num_rows ($query_cars);

Now, you can pass the details of the car associated with the user ID in the 'user' table and a foreign key in the table "cars."

You probably want to use a / while loop to get all the information from the database. With a DW repeat region behavior.

problem with join of two tables

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