Problem with LEFT OUTER JOIN

Hello

I am in charge of the migration of a SQL Server 2000 database to Oracle 11 g, under what I also migrate some predefined queries, that my client has. However I can't seem to get the syntax right and it keeps failing. Could you please help me? Thank you.

Query:

SELECT *,(select r.recsolins from gx.repara r where r.percod=c.percod and r.concod=c.concod and r.rectpo='I' and r.recsts='F' and r.grppercod=10 and r.recnro=(select max(t.recnro) from gx.repara t where t.percod=c.percod and t.concod=c.concod and t.rectpo='I' andt.recsts='F' ) ) as NROID
FROM gx.CONABO c, gx.abonad a  
LEFT OUTER JOIN gx.CALLES y ON  y.dptocod=10 and y.ciucod=524 and y.CALCOD=A.AboCalEsq1, 
LEFT OUTER JOIN gx.CALLES Z ON  z.dptocod=10 and z.ciucod=524 and z.CALCOD=A.AboCalEsq2 
,gx.calles x WHERE c.PERCOD in (10,60) and CONSTSHAB in ('C','D','P')
and a.percod=c.percod and a.abocod=c.abocod and
x.dptocod=10 and x.ciucod=524
and x.calcod=abocal
order by c.percod,c.concod;

The fields are correct, but I get not found when expected in FROM clause.

Published by: n on June 5, 2012 13:47

Tags: Database

Similar Questions

Problem format (LEFT OUTER JOIN)?

THE addresses of Mutiple of return as a single record + current addresses

>
Hi all

I have to back student addresses home and dormitory under a single registration.

He had to go something like this:

LAST_NAME     FIRST_NAME     ADDY_TYPE   ADDRESS             ZIP
Smith                John             HOME         123 Awesome St     10003
Smith               John               DORM         Oak Quad             10013

In this format the desired:

LAST_NAME  FIRST_NAME     ADDY_TYPE  ADDRESS         ZIP        ADDY_TYPE     ADDRESS     ZIP
Smith            John      HOME        123 Awesome St  10003   DORM            Oak Quad     10013

You also need to get their last addresses by date.
The database hold records of all students have places moving from dorm to dorm
and some permanent residence ("HOME") has changed as well.
To return only a DORM address and only a HOME address
for each student.

I'm looking at possibly a function BOX to put on a line/record and RANK BY() or DENSE_RANK to determine the last addresses.

Hope I'm making some sense and as always very grateful for any help. Thank you.
>

The correct code provided by Frank Kulash here:

WITH    got_rnum     AS
(
     SELECT     last_name
     ,     first_name
     ,     addy_type
     ,     address
     ,     zip
     ,     ROW_NUMBER () OVER ( PARTITION BY  last_name
                               ,                    first_name
                         ,             addy_type
                         ORDER BY        addy_date     DESC     NULLS LAST
                       ) AS rnum
     FROM    table_x
--     WHERE     ...          -- Any filtering goes here
)
SELECT    last_name
,       first_name
,       MIN (CASE WHEN addy_type = 'HOME' THEN address END)     AS home_address
,       MIN (CASE WHEN addy_type = 'HOME' THEN zip     END)     AS home_zip
,       MIN (CASE WHEN addy_type = 'DORM' THEN address END)     AS dorm_address
,       MIN (CASE WHEN addy_type = 'DORM' THEN zip     END)     AS dorm_zip
FROM       got_rnum
WHERE       rnum     = 1
GROUP BY  last_name
,            first_name
;

I need to add a 'NATION' field, located on another table for the addresses of welcome for foreign students.
I made a LEFT OUTER JOIN with the table of the NATION and the release came out like this:

LAST_NAME  FIRST_NAME     ADDY_TYPE  ADDRESS   ZIP      NATION    ADDY_TYPE       ADDRESS     ZIP
Smith            John      HOME        Rue Henry M1V 4F4  CANADA      null              null             null
Smith            John      null        null      null     null        DORM               Oak Quad     10013

My desired output would be like this:

LAST_NAME  FIRST_NAME     ADDY_TYPE  ADDRESS   ZIP      NATION    ADDY_TYPE       ADDRESS     ZIP
Smith            John      HOME        Rue Henry M1V 4F4  CANADA    DORM              Oak Quad     10013

Maybe it's something I'm not right. What is the way I'm joining tables?

As always very grateful for your contributions. Thank you.

Give a glance to your group by, you group on the nation, but it has two values (NULL and CANADA). Try this way:

WITH    got_rnum     AS
(
     SELECT     STUINFO_id
  , STUINFO_last_name
     ,     STUINFO_first_name
     ,     ADDRESSLIST_atyp_code
     ,     ADDRESSLIST_street_line1
  , ADDRESSLIST_street_line2
  , ADDRESSLIST_city
  , ADDRESSLIST_stat_code
     ,     ADDRESSLIST_zip

, ADDRESSLIST_natn_code
, NATION_nation
     ,     ROW_NUMBER () OVER ( PARTITION BY  STUINFO_last_name
                               ,                    STUINFO_first_name
                         ,                         ADDRESSLIST_atyp_code

                         ORDER BY        ADDRESSLIST_from_date     DESC     NULLS LAST
                       ) AS rnum
     FROM STUINFO JOIN CLASSROSTER ON STUINFO_pidm = CLASSROSTER_pidm JOIN ADDRESSLIST ON ADDRESSLIST_pidm = STUINFO_pidm LEFT OUTER JOIN NATION ON ADDRESSLIST_NATN_CODE =NATION_CODE
-- The WHERE part determines if the student is currently enrolled in a class
-- ADDRESSLIST_to_date is the last date the student will be living in that residence
WHERE ADDRESSLIST_atyp_code IN ('PR', 'CA') and  STUINFO_change_ind IS NULL and STUINFO_last_name !='Registrar'
and CLASSROSTER_term_code='200909' and CLASSROSTER_PTRM_CODE IN ('D', 'D1', 'D2') and CLASSROSTER_CAMP_CODE='1'

and (ADDRESSLIST_to_date is NULL OR ADDRESSLIST_TO_DATE > SYSDATE)
)
SELECT    STUINFO_id
,   STUINFO_last_name
,       STUINFO_first_name
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'PR' THEN ADDRESSLIST_STREET_LINE1  END)     AS PR_ADDRESSLIST_STREET_LINE1
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'PR' THEN ADDRESSLIST_STREET_LINE2  END)     AS PR_ADDRESSLIST_STREET_LINE2
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'PR' THEN ADDRESSLIST_city     END)     AS PR_ADDRESSLIST_city
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'PR' THEN ADDRESSLIST_stat_code     END)     AS PR_ADDRESSLIST_stat_code
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'PR' THEN ADDRESSLIST_zip     END)     AS PR_ADDRESSLIST_zip
,       MIN (CASE WHEN ADDRESSLIST_natn_code IS  NULL THEN ADDRESSLIST_natn_code     END)     AS PR_ADDRESSLIST_natn_code
, MIN(NATION_nation) NATION_nation
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'CA' THEN ADDRESSLIST_STREET_LINE1  END)     AS CA_ADDRESSLIST_STREET_LINE1
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'CA' THEN ADDRESSLIST_STREET_LINE2  END)     AS CA_ADDRESSLIST_STREET_LINE2
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'CA' THEN ADDRESSLIST_city     END)     AS CA_ADDRESSLIST_city
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'CA' THEN ADDRESSLIST_stat_code     END)     AS CA_ADDRESSLIST_stat_code
,       MIN (CASE WHEN ADDRESSLIST_atyp_code = 'CA' THEN ADDRESSLIST_zip     END)     AS CA_ADDRESSLIST_zip

FROM       got_rnum
WHERE       rnum     = 1
GROUP BY  STUINFO_last_name
,            STUINFO_first_name
,         STUINFO_id
ORDER BY STUINFO_last_name;

Max

Problem with ANSI OUTER JOIN

Hi all

I have issues with the help of ANSI LEFT JOIN compared to Oracle (+). Below test I did the same thing.

      create table emp (emp_id number(10), emp_name varchar2(50));
      create table courses (course_id number(10), emp_id number(10), course_name varchar2(50));
      
      INSERT INTO EMP values(1,'A');
      INSERT INTO EMP values(2,'B');
      INSERT INTO EMP values(3,'C');

      INSERT INTO COURSES values(1,1,'ORACLE');
      INSERT INTO COURSES values(2,1,'JAVA');
      INSERT INTO COURSES values(3,3,'C#');

      --*Query 1
      SELECT a.*, b.*
      FROM EMP a  LEFT JOIN COURSES b 
      ON a.emp_id = b.emp_id
      AND a.emp_name = 'A'

      --*Query 2      
      SELECT a.*, b.* 
      FROM EMP a, COURSES b 
      where a.emp_id = b.emp_id(+)
      and a.emp_name = 'A'

Here Query1 return all records of 4 same records regardless of emp_name = 'A' where as Query2 returns 2 records of ep_name = 'A' which is correct.

Is this correct? I'm confused if you use the standard ANSI OUTER JOINS or not.

I am using Oracle 11g

Thank you.

Change your AND WHERE, in the style of ANSI, select:

SELECT a.*, b.*
FROM EMP a  LEFT JOIN COURSES b
ON a.emp_id = b.emp_id
WHERE a.emp_name = 'A'

Filters in the clause are those who use the (+) in the Oracle syntax.
Filters WITHOUT (+) in the Oracle syntax should be in the WHERE clause using the ANSI syntax.

Published by: Kim Berg Hansen on September 23, 2011 08:03

Problem with XMLTABLE and LEFT OUTER JOIN

Hi all.

I have a problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns the correct result, but in 10g it doesn't, it is illustrated as a INNER JOIN.

SELECT * FROM v$version;

Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
PL/SQL Release 11.2.0.1.0 - Production
"CORE     11.2.0.1.0     Production"
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production

--test for 11g

CREATE TABLE XML_TEST(
     ID NUMBER(2,0),
     XML XMLTYPE
);

INSERT INTO XML_TEST
VALUES
(
     1,
     XMLTYPE
     ('
          <msg>
               <data>
                    <fields>
                         <id>g1</id>
                         <dat>data1</dat>
                    </fields>
               </data>
          </msg>
     ')
);

INSERT INTO XML_TEST
VALUES
(
     2,
     XMLTYPE
     ('
          <msg>
               <data>
                    <fields>
                         <id>g2</id>
                         <dat>data2</dat>
                    </fields>
               </data>
          </msg>
     ')
);

INSERT INTO XML_TEST
VALUES
(
     3,
     XMLTYPE
     ('
          <msg>
               <data>
                    <fields>
                         <id>g3</id>
                         <dat>data3</dat>
                    </fields>
                    <fields>
                         <id>g4</id>
                         <dat>data4</dat>
                    </fields>
                    <fields>
                         <dat>data5</dat>
                    </fields>
               </data>
          </msg>
     ')
);

SELECT
     t.id,
     x.dat,
     y.seqno,
     y.id_real
FROM
     xml_test t,
     XMLTABLE
     (
          '/msg/data/fields'
          passing t.xml
          columns
               dat VARCHAR2(10) path 'dat',
               id XMLTYPE path 'id'
     )x LEFT OUTER JOIN
     XMLTABLE
     (
          'id'
          passing x.id
          columns
               seqno FOR ORDINALITY,
               id_real VARCHAR2(30) PATH '.'
     )y ON 1=1
;

ID     DAT     SEQNO     ID_REAL
--     -----     -----     -------
1     data1     1     g1
2     data2     1     g2
3     data3     1     g3
3     data4     1     g4
3     data5

This is all nice, now the problem:

Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
PL/SQL Release 10.2.0.1.0 - Production
"CORE     10.2.0.1.0     Production"
TNS for HPUX: Version 10.2.0.1.0 - Production
NLSRTL Version 10.2.0.1.0 - Production

--exactly the same environment as 11g (tables and rows)
SELECT
     t.id,
     x.dat,
     y.seqno,
     y.id_real
FROM
     xml_test t,
     XMLTABLE
     (
          '/msg/data/fields'
          passing t.xml
          columns
               dat VARCHAR2(10) path 'dat',
               id XMLTYPE path 'id'
     )x LEFT OUTER JOIN
     XMLTABLE
     (
          'id'
          passing x.id
          columns
               seqno FOR ORDINALITY,
               id_real VARCHAR2(30) PATH '.'
     )y ON 1=1
;

ID     DAT     SEQNO     ID_REAL
--     -----     -----     -------
1     data1     1     g1
2     data2     1     g2
3     data3     1     g3
3     data4     1     g4

As you can see in 10g that I don't have the last row, it seems that Oracle 10 g does not recognize the LEFT OUTER JOIN.

Is this a bug?, Metalink says that sometimes we can have an ORA-0600, but in this case there is no error results returned, just incorrect.

Help, please.

Kind regards.

What about try the original Oracle method for outer joins? Using (+) without the extra space

XMLTABLE(...COLUMNS ... id XMLTYPE PATH ... ) x,
XMLTABLE(... PASSING x.id ...) (+) y

Left Outer Join with sum

Dear elders,

Firstly, sorry if my question is considered to be 'very novice' but I have this problem of confusion.

Can I use the left outer join with summary?
For example:

Work table

JobCode      JobGroupCode      
111A         1100              
112B         1100               
113C         1100
121A         1200
333F         3300

Table No.

JobGroupCode    ParentCode
1100            1000
1200            1000
1300            1000
3300            3000

Activity table

Jobcode      Mandays
111A         5
112B         7
113C         3

I want to choose with this result

Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
111A           1100                 1000                      5
112B           1100                 1000                      7               
113C           1100                 1000                      3
121A           1200                 1000                      0
333F           3300                 3000                      0

All I did was:

select j.jobcode, j.jobgroupcode, jg.parentcode, sum(a.mandays)
  from job j
 inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
  left join activity a on j.jobcode = a.jobcode
 group by j.jobcode, j.jobgroupcode, jg.parentcode

and I got was only jobcode activity table, not exactly what I want to get all the work table jobcode. Could you please tell me, where I was wrong?

result

Job.JobCode    Job.JobGroupCode     JobGroup.Parentcode       Mandays
111A           1100                 1000                      5
112B           1100                 1000                      7               
113C           1100                 1000                      3

Thank you very much.

Published by: user11197113 on May 25, 2009 03:31

Published by: user11197113 on May 25, 2009 03:32

Hello (and welcome!).

Edit

OK, try this:

select j.jobcode, j.jobgroupcode, jg.parentcode, NVL(sum(a.mandays),0)
  from job j
 inner join jobgroup jg on j.jobgroupcode = jg.jobgroupcode
  left join activity a on j.jobcode = a.jobcode
 group by j.jobcode, j.jobgroupcode, jg.parentcode

That will give you this:

JOBC JOBG PARE SUM(A.MANDAYS)
---- ---- ---- --------------
111A 1100 1000              5
112B 1100 1000              7
113C 1100 1000              3
121A 1200 1000              0
333F 3300 3000              0

These are real results of your test data.

Why left outer join with a table gives me more lines?

Hi gurus,
I can see "view_a" and a table 'table_a '.
view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.
However, I'm more than 100 lines. Is it still possible?
Also even to analyze these situations, how can I move forward?
Because it is very high volumn of sight and takes longer to run.
Select count (*) view_a, view_b
where view_a.col1 = view_b.col1 (+)
and view_a.col2 = view_b.col2 (+);
Thank you

I can see "view_a" and a table 'table_a '.

view_a a county of 100 lines. Now, when I left outer join that discovers with a 'table_a', I expect all 100 lines.

However, I'm more than 100 lines. Is it still possible?

Also even to analyze these situations, how can I move forward?

Because it is very high volumn of sight and takes longer to run.

Select count (*) view_a, view_b

where view_a.col1 = view_b.col1 (+)

and view_a.col2 = view_b.col2 (+);

Which is not necessarily related to the use of an outer join.

Just join of two tables in general will give you more rows of one table has.

Scott DEPT table contains ONE row for deptno = 10

The EMP table has THREE rows of deptno = 10

The number of rows you plan if you join two tables using an equi-join?

Three - what is MORE lines the DEPT table has for deptno = 10

Select * from Department where deptno = 10

DEPTNO, DNAME, LOC
10, ACCOUNTING, NEW YORK

Select * from emp where deptno = 10

MGR, EMPLOYMENT ENAME, EMPNO, HIREDATE, SAL, COMM, DEPTNO
7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

Select dept.*, emp.*
Department, emp
where dept.deptno = 10
and dept.deptno = emp.deptno

DEPTNO, DNAME, LOC, EMPNO, ENAME, JOB, MGR, HIREDATE, SAL, COMM, DEPTNO_1
10, ACCOUNTING, NEW YORK, 7782, CLARK, MANAGER, 7839, 6/9/1981,2450, 10
10, ACCOUNTING, NEW YORK, 7839, KING, PRESIDENT, 17 NOVEMBER 00, 10
10, ACCOUNTING, NEW YORK, 7934, MILLER, CLERK, 7782, 23 JANUARY 00: 10

So if these are the lines ONLY in the table EMP and DEPT the query would give you THREE lines despite the DEPT table only ONE line.

No do you expect? You get ALL the child rows that belong to the parent company. Otherwise, how could it possibly work?

The OUTER join includes lines where the parent row exists but there is NO child line as others have shown.

Outer joins

Outer join extends the result of a simple join. Outer join returns all rows that satisfy the join condition and also returns some or all rows in a table for which no line of the other meet the join condition.

Get more lines to exist in one of the paintings is a basic necessity. It usually has NOTHING to with the question of whether you have an outside to join or not.

See the section on the JOINTS in the Oracle documentation

http://docs.Oracle.com/CD/B28359_01/server.111/b28286/queries006.htm

Using Left Outer Join with reference
I have three tables.
Table 1: BOOK_DETAILS
Fields: BOOK_ID, BOOK_NAME

Table 2: BOOK_ISSUE_RECORD
Fields: BOOK_ID, USER_NAME

Table 3: BOOK_AUTHOR
Fields: BOOK_ID, AUTHOR_NAME

I must link table 1 and table 2 with a left outer join, because even if the book is not the questions to anyone, his name should come.
I have once again display the name of the author of books for each book.
I am able to create a query with the left outer join between table 1 and table 2. However, I am not able to give a reference to Table 3.
Can someone help me with this please.

Concerning
Hawker
```
select  d.book_name,
        a.book_author,
        i.user_name
  from       book_details d
        join
             book_author a
          on (d.book_id = a.book_id)
        left join
             book_issue_recors i
          on (d.book_id = i.book_id)
/
```
SY.

LEFT OUTER JOIN, trigger after QUERY problem
Hello

Guide to please the following

I wrote under query in QUERY after a BLOCK of TABULAR DATA, not as a single text element, called INVENTORY_ITEM

Select c.cat |' '|| s.SubCat |' '|| L1.lvl1 POINT IN: DATABLOCK. INVENTORY_ITEM
of itemcat c
LEFT OUTER JOIN itemsubcat s on (c.catid = s.catid)
LEFT OUTER JOIN lvl1 l1 on (s.subcatid = l1.subcatid)

When I compile the module an error is generated

«* ' Met the 'LEFT' symbol when waiting for one of the following values for the group with intersect less order start union where connect '.» *

Top query works fine with ORACLE SQL DEVELOPER.

Any solution please.

Kind regards
Difference

Modeling of the left outer join

Hello world
I'm tender hand to you guys for a modeling help
I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model
Fact and the client are joined through CUST_ID
FACT and DATE are joined through DATE_ID
CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS
If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.
Application under
Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
Of
F FACT
JOIN THE
CUSTOMER C
ON C.CUST_ID = F.CUST_ID
JOIN THE
DIM_DATE D
ON F.DATE_ID = D.DATE_ID
LEFT OUTER JOIN
CUST_ADDRESS CA
ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_ID
Thanks in advance

When I add the CUSTOMER and in FACT LTS CUST_ADDRESS

Stop it!

Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?

You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.

So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?

No problem...

Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.

In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.

Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.

Give it a try at that.

But do not add these tables in the LTS, they are logical dimensions.

Left Outer Join help...

Hello world
I'm still trying to learn the SQL, and I can not specifically with the left outer join. I normally join tables using equijoin, but I don't get the right data set returns, and designed with the help of a left or right outer join would solve the problem...
Here is my SQL that works properly with 1 left outer join. I build the slow query in the SQL following, you will see where I see the error. I don't expect you to understand the data and the columns, I'm trying to join, I think the problems I encounter are related to syntax, and I hope that you can find where are my syntax errors.
Select
s.Name as "Pseudonym,"
SV.view_name as "name of the view.
s_view. Name
Of
s s_screen,
s_screen_view sv
outer join left s_view
WE (sv.view_name = s_view.name)
where
SV.screen_id = ' 1-866 A - 1X3LU' and
s.ROW_ID = sv.screen_id and
s.repository_id = ' 866 A-1-1"and
s_view.repository_id = ' A-1-1 866 ";
Here is the SQL code where I encounter the following error...
Error:
ORA-00904: "SV". "" View_name ": invalid identifier
00904, 00000 - '% s: invalid identifier '.
* Cause:
* Action:
Error on line: column 14: 7
Problematic SQL:
Select
s.Name as "Pseudonym,"
SV.view_name as "name of the view.
s_view. Name,
s_applet. Name as Applet
-b.SID like "name of the cmdlet.
Of
s s_screen,
s_screen_view sv,
wti s_view_wtmpl_it
outer join left s_view
WE (sv.view_name = s_view.name)
outer join left s_applet
WE (wti.name = s_applet.name)
where
SV.screen_id = ' 1-866 A - 1X3LU' and
s.ROW_ID = sv.screen_id and
s.repository_id = ' 866 A-1-1"and
s_view.repository_id = ' A-1-1 866 ";
Thanks in advance for your help.
Chris

> ORA-00904: "S_VIEW_WEB_TMPL." "" ROW_ID ": invalid identifier

I don't see this table in your FROM clause.

LEFT OUTER JOIN SYNTAX?
Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production 64-bit
With partitioning, OLAP, Data Mining and Real Application Testing options

When I run:
SELECT ACCF. SPECIMEN_ID as ACC_ID,
ACCF. PREFIX,
ACCF. SPECIMEN_NBR as ACC_NBR,
RP. PHYSICIAN_ID as REFPHY_BUS_KEY,
ACCF. SIGNOUTLOC,
THE. Location_id as LAB_BUS_KEY,
ACCF. COLLDATE as ACC_SPCMN_COLL_DT_ID,
ACCF. ACDATE as ACC_CREATED_DT_ID,
ACCF. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
ACCF. SODATE as ACC_SIGNOUT_DT_ID
OF ACC_FACT_WS ACCF.
REFPHY_WS RP,
THE LAB_WS
WHERE ACCF. BLINK = RP. PHYSICIAN_ID
AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
AND ACCF. PREFIX = A '
AND ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID

It works fine, but I really have an outer join on LAB_WS.
When I run with an outer join, I get:
SQL > SELECT ACCF. SPECIMEN_ID as ACC_ID,
2 ACCF. PREFIX,
3 ACCF. SPECIMEN_NBR as ACC_NBR,
4. PR PHYSICIAN_ID as REFPHY_BUS_KEY,
5 ACCF. SIGNOUTLOC,
6. THE. Location_id as LAB_BUS_KEY,
ACCF 7. COLLDATE as ACC_SPCMN_COLL_DT_ID,
ACCF 8. ACDATE as ACC_CREATED_DT_ID,
ACCF 9. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
ACCF 10. SODATE as ACC_SIGNOUT_DT_ID
11 ACC_FACT_WS ACCF,
12 REFPHY_WS RP
13 LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
14. WHERE ACCF. BLINK = RP. PHYSICIAN_ID
15 AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
16 AND ACCF. PREFIX = A ';
LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
*
ERROR on line 13:
ORA-00904: "ACCF. "" SIGNOUTLOC ": invalid identifier

The previous query shows ACCF. SIGNOUTLOC is not the problem.
What is the problem and how to fix it?
Note: the syntax of the old outer join is not an option. The query will be finally 9 outer joins.

Thank you
Jon Jacobs
Hello

You are mixing syntax to join Oracle with ANSI, which is sometimes delicate.
Best is to use a unique syntax, for example ANSI:
```
...
FROM ACC_FACT_WS ACCF
     JOIN REFPHY_WS RP ON ACCF.CLIN = RP.PHYSICIAN_ID
     LEFT OUTER JOIN LAB_WS LA on ACCF.SIGNOUTLOC = LA.LOCATION_ID
WHERE ACCF.ACDATE > to_date('2010-06-17','YYYY-MM-DD')
AND ACCF.PREFIX = 'D'
```

doubt left outer join

Hi all
I use under version
Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E,.
DEPT 5 D
6. WHERE = E.DEPTNO D.DEPTNO (+);
ENAME, DEPTNO LOC
---------- ------ -------------
DALLAS SMITH 20
ALLEN 30 CHICAGO
WARD 30 CHICAGO
20 DALLAS JONES
MARTIN 30 CHICAGO
BLAKE 30 CHICAGO
CLARK 10 NEW YORK
SCOTT 20 DALLAS
THE 10 NEW YORK KING
TURNER 30 CHICAGO
20 DALLAS ADAMS
JAMES 30 CHICAGO
FORD 20 DALLAS
MILLER 10 NEW YORK
40 BOSTON
15 selected lines
-----------------------------------------------------------------------------------------------------------------------------
SQL > SELECT E.ENAME,.
2 D.DEPTNO,
3 D.LOC
4. TO EMP E
5 LEFT OUTER JOIN
D 6 DEPT
7. THE E.DEPTNO = D.DEPTNO;
ENAME, DEPTNO LOC
---------- ------ -------------
MILLER 10 NEW YORK
THE 10 NEW YORK KING
CLARK 10 NEW YORK
FORD 20 DALLAS
20 DALLAS ADAMS
SCOTT 20 DALLAS
20 DALLAS JONES
DALLAS SMITH 20
JAMES 30 CHICAGO
TURNER 30 CHICAGO
BLAKE 30 CHICAGO
MARTIN 30 CHICAGO
WARD 30 CHICAGO
ALLEN 30 CHICAGO
14 selected lines
My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.
but the results are different.
For the first query null is coming for unmatched records in the dept table
but in the second query, it does not come
Thank you

Hello

2947022 wrote:

Hi all

I use under version

Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0

SQL > SELECT E.ENAME,.

2 D.DEPTNO,

3 D.LOC

4. TO EMP E,.

DEPT 5 D

6. WHERE = E.DEPTNO D.DEPTNO (+);

ENAME, DEPTNO LOC

---------- ------ -------------

DALLAS SMITH 20

ALLEN 30 CHICAGO

WARD 30 CHICAGO

20 DALLAS JONES

MARTIN 30 CHICAGO

BLAKE 30 CHICAGO

CLARK 10 NEW YORK

SCOTT 20 DALLAS

THE 10 NEW YORK KING

TURNER 30 CHICAGO

20 DALLAS ADAMS

JAMES 30 CHICAGO

FORD 20 DALLAS

MILLER 10 NEW YORK

40 BOSTON

15 selected lines

-----------------------------------------------------------------------------------------------------------------------------

SQL > SELECT E.ENAME,.

2 D.DEPTNO,

3 D.LOC

4. TO EMP E

5 LEFT OUTER JOIN

D 6 DEPT

7. THE E.DEPTNO = D.DEPTNO;

ENAME, DEPTNO LOC

---------- ------ -------------

MILLER 10 NEW YORK

THE 10 NEW YORK KING

CLARK 10 NEW YORK

FORD 20 DALLAS

20 DALLAS ADAMS

SCOTT 20 DALLAS

20 DALLAS JONES

DALLAS SMITH 20

JAMES 30 CHICAGO

TURNER 30 CHICAGO

BLAKE 30 CHICAGO

MARTIN 30 CHICAGO

WARD 30 CHICAGO

ALLEN 30 CHICAGO

14 selected lines

My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.

but the results are different.

For the first query null is coming for unmatched records in the dept table

but in the second query, it does not come

Thank you

In fact, these requests are not the same.

The first is to find all the lines of the Department, with the corresponding lines of PGE (when there are). This is equivalent to «FROM dept LEFT OUTER JOIN emp...» ».

The second is to find all the rows in the emp of the lines of the Department (when there are any). This is equivalent to «...» WHERE e.deptno = d.deptno (+).

Bad result in a left outer join in 12.1.0.2

Hallo,
We discovered a strange behaviour in a query. The query provides values in a column of outer join where there is no corresponding value in the table is attached to the outside.
When you expand this request by the "ORDER BY" then this query gives the correct result.
Example:
SQL > desc tb_a
Name                                Null?    Typ
-------------------------------------------- ----------------------------
ID NOT NULL NUMBER (19)
SQL > desc tb_b
Name                                Null?    Typ
-------------------------------------------- ----------------------------
CLOSED NOT NULL NUMBER (1)
ID NOT NULL NUMBER (19)
CCS_APPLICATION@icw01> select * from tb_a where id in (4148,4141,4195);
ID
----------
4148
4141
4195
CCS_APPLICATION@icw01> select * from tb_b where id in (4148,4141,4195);
INTERNAL ID
---------- ----------
4148 0
CCS_APPLICATION@icw01> SELECT
2      b.id                            AS b_id,
3      a.id                            AS a_id,
4 b.closed AS b_closed
5
6 tb_a a
7 LEFT OUTER JOIN tb_b b ON a.id = b.id
8 WHERE a.id IN (4148, 4195, 4141)
9 ORDER BY ASC a.id
10;
B_ID ALLOCATION A_ID B_CLOSED
---------- ---------- ----------
4141
4148 4148 0
4195
CCS_APPLICATION@icw01> SELECT
2      b.id                            AS b_id,
3      a.id                            AS a_id,
4 b.closed AS b_closed
5
6 tb_a a
7 LEFT OUTER JOIN tb_b b ON a.id = b.id
8 WHERE a.id IN (4148, 4195, 4141)
9 - ORDER BY ASC a.id
10;
B_ID ALLOCATION A_ID B_CLOSED
---------- ---------- ----------
4148 4148 0
4141 4141
4195 4195
instance parameter:
VALUE OF TYPE NAME
------------------------------------ ----------- ------------------------------
compatible string 12.1.0.2.0
optimizer_features_enable string 12.1.0.2
After ""alter system set optimizer_features_enable = ' 11.2.0.4 ';" the query provides the correct result in both cases (ordered and unordered).
Now the final question: is this a bug?

1480970 wrote:

Hallo! Yes, I searched the Support of Oracle. I found some similar entries, but not an exact match. To fix some issues

with 12.1.0.2.

There is another interesting clue when look you on the execution plan:

Note

-----

-the dynamic statistics used: dynamic sampling (level = 2)

- This is an adaptation plan

We have disabled (= FALSE) optimizer_adaptive_features and the query provides the correct values.

This could be a solution for us.

Looks like a pretty tight match for bug 18430870, even if it affects the two 12.1.0.1 and 12.1.0.2, which contradicts the Martin trial against 12.1.0.1.

The description of the bug mentions disabling "_projection_pushdown" (set to false) should also be a viable solution, perhaps if you want to give that a try and see if it is a different bug or not.

There are also a number of one-time fixes already available for download, maybe your version / platform is already covered, if the bug applies.

Randolf

Left Outer Join DR.

Hi Experts,
I have a requirement that says - see the chart for the past 10 days, regardless the presence data table in fact.
Lets consider an example - Time_dim product, are my dimension tables, Purchase_Order is my fact table.
I did it for external Purchase_Order in left RPD with TIME_DIM and inner join with the PRODUCT table. and execution of query of exit-
Select T.Date, P.item, count (distinct PO.order_no)
TIME_DIM t, PRODUCT P, PURCHASE_ORDER PO
where T.date_key = PO.date_key
and P.item = in. agenda
and P.item = 'laptop ';
The query generated by OBIEE left outer join, but when the condition P.item = "Notebook" included in the query, and if there are no orders for this product in one of the date, that date will not come in the result set.
the query to be generated by the OBIEE is-

Select T.Date, PO.item, count (distinct PO.order_no)
TIME_DIM t,.
(SELECT P.ITEM, IN. ORDER_NO
PRODUCT P, PO PURCHASE_ORDER
WHERE P.item = in. agenda
and P.item = 'Laptop') IN.
WHERE T.date_key = PO.date_key (+);
How to design the RPD to achieve this. All pray to advise on this. Thanks in advance.
Thank you
Chantal

Hello

You are on 11.1.1.7?

I would say that your condition can be made without using external and maintenance of product and the standard between the FACT dimension, time inner join join.

If you enable your property analysis OBIEE "Include Null values" will automatically return all the elements of time and product matching your filter (so you'll need to add a filter on 'Date' to limit it to the last 10 days or you will have a unique day of your time dimension).

If you filter then on "Laptop", even if there is not a single value in order for "Laptop" in the last 10 days, he will be there on the screen.

Easy, clean and you keep your inner join between the facts and Dimensions.

Take a look at this example, I just did on SampleApp 406:

Selection of 12 months (year 2010) and a customer (id = 89) and income. The model has only an inner join. I activate the option "Include Null values" and here is the result.

A line with cells only empty because there is not a single revenue for customer 89 in 2010. This is exactly your condition.

Honestly, do not touch your model using the outer join, you will have more side effects than benefits. Every single scan will do the outer join and you'll have a lot of data 'empty' return of the DB (more large data set containing just the null values) and probably you need the outer join in 15 to 25% of your analysis.

Keep things simple, it will be faster and easier to maintain.

3 left outer join tables

Hi all
I have 3 tables A, B, C
Create table a (varchar2 (100)) of the currency;
insert into a values (GBp);
insert into a values (GBP);
insert into a values (GBX);
Create table B (varchar2 (100) currency, number);
insert into B values (GBP, 61.1);
Create a table (minor_currency varchar2 (100), major_currency varchar2 (100));
insert into values of C (GBp, GBP);
insert into values of C (GBX, GBP);
I need to get the rate table B by linking the A with the currency as a condition of joining. (left outer join)
For currencies which are not in table B, table should be attached with C minor currency-based
and get the major_currency and join with table B
Ex:
something like this:
Select B.rate from A, B, C
WHERE (A.currency = B.currency or (A.currency = C.minor_currency and B.currency = C.major_currency)
O/P: for GBp and GBX currency, I need to get the rate as 61.1 in table B, but B currency is GBP. So I need to get the major_currecny for GBp, GBX table C and join with the table B
Thank you
Sasi

Hi all

Thanks for your time. Its done

Problem with LEFT OUTER JOIN

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