Similar Questions

• Why this code does not work, its simple!

  Hello

  I know the myVISITORinfoFormdomain name, say, the name is myTextField25, but I do not know its full path! but, I want to make gray and read-only, so I put the code below (I put the cursor on the node 'myVISITORinfoForm' and selected the DocReady event)

  var c = xfa.resolveNode("myTextField5").fillColor = '192,192,192. "
  var d = xfa.resolveNode("myTextField26").fillColor = '192,192,192. "
  var e = xfa.resolveNode("myTextField25").access = "readOnly";
  var f = xfa.resolveNode("myTextField26").access = "readOnly";

  I also tried another field of myTextField26, I also kept the same code in the FormReady events initialization... but has not worked!

  myTextField25 and myTextField26 are positioned on the 3rd page of the mySubForm12 subform.

  Pls let me know wht miss me?

  Thank you

  Hello

  If you want to make each field read only and gray, so why not script directly in each of the two textfields?

  It's the two fields docReady event:

  this.fillColor = "192,192,192";
  this.access = "readOnly";
  

  You can only do this if the fields are not null (for example when the form is returned to you). In this case you would wrap the script in an if statement:

  if (this.rawValue === null)
  {
       this.fillColor = "192,192,192";
       this.access = "readOnly";
  }
  

  I don't think the way you declare variables and setting properties on one line will work. Also, the use of the xfa.resolveNode is not effective.

  Hope that helps,

  Niall

• Why this code does not work in dreamweaver?

  <! DOCTYPE HTML >

  < html >

  < head >

  < style type = "text/css" >

  {body

  Width: 100%;

  height: 100%;

  margin: 0px;

  padding: 0px;

  }

  < / style >

  < / head >

  < body >

  < img src = "images/last.png" alt = "left" style ="width: 100%; "/ >

  < / body >

  < / html >

  When I put it in the tab code Dreamweaver html blank document page, it does not seem to load. Any suggestions?

  Are you sure that the image is in the folder named "images" last.png? Are you sure the image is to use the right color RGB and CMYK not the space.

  There's nothing wrong with the code that I can see. What happens if you try just text:

  Hello

• Why this scriipt does not work with Firefox? &lt; embed src = "News2008Fall.pdf" width = '615' height = '3200' &gt; &lt; / embed &gt; "

  Please tell me why this script does not work with Firefox. It works with Safari. Here is the page that includes the script: www.lionsgatehoa.org/newslettertest.html. Thank you. Tom Engleman

  Here's the script in my html document:

  < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

  Edit: removed # phone

  Works for me on Linux.
  
  Your system details list does not display the Adobe Reader plugin, so you'll have to (re) install this program.

  See:

  • https://support.Mozilla.org/KB/using+the+Adobe+Reader+plugin+with+Firefox
  • http://KB.mozillazine.org/Adobe_Reader
  • http://get.Adobe.com/reader/otherversions/

• Bought 5 Lightroom online from Best Buy.  When I enter the redemption code, I get an error message indicating "Oops!" This code does not appear to be active.  Please contact the retailer or enter a different code. "I contacted Best Buy; they indicate that

  Bought 5 Lightroom online from Best Buy.  When I enter the redemption code, I get an error message indicating "Oops!" This code does not appear to be active.  Please contact the retailer or enter a different code. "I contacted Best Buy; they indicate that the code has been validated.

  Make sure that you're not confuse common lookalikes (for example, 1 l, or 0 and o).  Then go to their store with your redemption code, sign in to adobe.com using one of their computers store and show them what you're doing to redeem your code.

• I created a Web site and it is actually connected live. My login is working locally, but it does not work online. Could you please help me?

  I created a Web site and it is actually connected live. My login is working locally, but it does not work online. Could you please help me?

  Hi Hervé Joseph,

  Your question is more complex than what is generally answered in the Microsoft Answers forums. Appropriate in the MSDN Internet Explorer development Forums.

  Please post your question in the MSDN Internet Explorer development Forums

• Why this SQL does not work?

  The following code does not work when I try to delete rows from a table of test. The test table has no unique or primary key on it and is defined as test (identification number). Can you explain to me why it doesn't work?
  

  
  

  delete from test a where a.rowid in (select b.rowid from test b where b.id = a.id and b.rowid != a.rowid);

  
  

  
  

  
  

  When I run the subquery (selection) with replacement of the actual values of a.rowid and the table queried a.id (IE.select b.rid from test2 b where b.id = 1 and b.rid != 'XXX'

  ), the subquery returns exactly as expected (that is to say, it gives the rowid is different from that which went from subquery). And as although I know the internal subquery must return the result for each row of the table in the outside circle delete statement, and only after that should execute the delete statement. For example, for the first row of the table in the external suppression, the delete statement must send the ID of the first row in the internal subquery and then wait the result which should return. And then runs the delete statement, in which case the subquery must return the rowid is different from that which went from subquery (ie.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.
  
  

  
  

  P.S. The sql is also not working if we replace remove it with the update or select
  

  in this case, the subquery must return the rowid is different from that which went from subquery (IE.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.

  You are right that this subquery should return other than past rowid thr. But you used the IN clause as well as below:

  where a.rowid in

  What States remove the line if rowid returned by the subquery contains the identifier for the row whose ID was passed. As the inner query is to return another rowid, therefore, no row is deleted.

  To remove duplicate lines, try the query (Replace tablename/columns with your) below:

  DELETE FROM emp A

  WHERE A.ROWID > ALL (SELECT B.ROWID

  PEM'S B

  WHERE A.empno = B.empno);

• Why this mixture does not work?

  I work in CS4 on Mac. I want to do a 10 pastel colors color wheel. I had planned to use ten spokes - each scratched a color - and then mix together them. I did it before with success with other colors, I got the idea for this Web site: http://colorburned.com/create-a-color-picker-icon-in-illustrator/

  However, it does not for the moment. Here are my photos before and after.

  

  Any ideas on the reasons that a segment is so shredded? I tried to increase the width of each RADIUS of 1 pt to 4pt, but it did not help.

  You need to duplicate the higher-level object and place it under the entire stack.

  

  In this example, the strokes begin with yellow (the bottom) and eventually green (at the top of the stack).

  Select the green path, Edit > copy, edit > paste in front, object > Arrange > put in the background... and then create the mix.

  You need to start and stop of the same color in the same place for the entire circle mix properly.

• Why my Code does not work?

  I'm doing so if a user selects an option button in a group of 2 (choice1 & lendemain2) the formula in the field "Total" changes.

  This is the javascript in the field 'Total '.

  //////////////////////////////////////////////////////////////////////////////

  If (document. Group1 ('Choice1'). Checked)

  {

  Event.Value = (this.getField("WSAtotal").value + this.getField("SAandAdd").value);

  }

  
  

  Another yew (document. Group1(Choice2'). Checked)

  {

  Event.Value = (this.getField("NSAtotal").value + this.getField("SAandAdd").value);

  }

  //////////////////////////////////////////////////////////////////////////////

  P.S. I don't know anything about javascript so I have just been Frankensteining this code from around the web.

  All first if you have radio buttons that should be in a group of exclusion, to give them the same field name but the export values.

  Radio buttons are fields, you must first access the domain object before testing the value of the field.

  var oGroup = this.getField ('Group'); get the field object for the radio buttons named "group".

  debugging help.

  Console.Show ();

  Console.clear();

  Console.println ("Group field has a value of"+ oGroup.value ");

  end debugging help;

  Event.Value = ""; clear the value of the event;

  If (oGroup.value == "Choice1") {}

  the group object is "choice1."

  Event.Value = (this.getField("WSAtotal").value + this.getField("SAandAdd").value);

  }

  If (oGroup.value == "Lendemain2") {}

  the group object's value is "Lendemain2";

  Event.Value = (this.getField("NSAtotal").value + this.getField("SAandAdd").value);

  }

• Why this text does not work well?

  Hi guys,.

  I am having trouble with this text.

  http://www.pixentral.com/show.php?picture=1y1N3lL5KPRBejo9GlPhEdkpl4KDQe

  It's in a column and the text block ends with the word 'amorosa '. I don't know why in the text the word "looking" will move to the next line and can only be inserted after that «nostalgia DEL...» "line of text even if ups with the end of the image apparently large enough to hold.

  http://www.pixentral.com/show.php?picture=1nu94bPp66d7lumber8SBjn6eI7Z1

  Maybe there is a better way to work with tabs, avoiding the list and so forth, but so far I have not understand it... so I work with the tools I know.

  Thanks for any info!

  See you soon,.

  SEBS

  Most importantly, you should do in this file is to remove all the keystrokes unnecessary (circled in red on my picture).

  

  You only need a paragraph return after caida, a tab after Coccoz, a tab after Catalanand without tab in the 'second paragraph' text (such as after del), and you do not need a line break after amorosa.

  After you have removed all the junk, set a tab on the left for the "second column and take note of its position." Suppose that you assign the p180 tab. To do the hanging indent, set the left indent p180 and first line indent to-p180 (i.e. negative 180 points). In this way, all text will be in the "second column", except the first line of the paragraph, which in this case are the names that make up your "first column". When you are ready to start with a new name, it's when you need a normal declaration.

• That means 1e9 and why this query does not work?

  What does 1e9? Someone has links to documentation on this oracle? And why I get this error?
  

  SQL> select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER';
  select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER'
                                     *
  ERROR at line 1:
  ORA-00923: FROM keyword not found where expected

  SIZE is a keyword - so if you want the name of the column size then use 'SIZE' else give it a different name

  Try dividing by other exponentials, then you'll see how: 1e0 1e1 (div 1), (div by 10), 1e2 :-) etc

  Mette

  Published by: mettemusens on 2009-05-12 16:02

• I have no idea why this 1130 does not work.

  Hello, everyone!

  I work in an elementary school in Detroit. We bought an access point Cisco 1130 for use on our local network. The problem is that our wireless laptops do not receive its signal.

  Here are the details.

  1. I connected the access point to our network and it turned.

  2. I used IPSU to find the IP address.

  3. I used Internet Explorer to connect to the access point.

  4. I gave you a fixed IP address on our field.

  5. I also entered the SSID and the WEP key.

  Everything seems good. The circular led on top of the access point is green. Unfortunately, Windows XP cannot 'see' the network signal.

  Is there someone who could help me get this thing working?

  Thank you very much

  -Ed

  All new 1130 AP come from the factory with the disabled radios. As you have seen, you need to enable them manually. I'm glad you have all this work!

• Why this introduction does not work?

  < html >
  < head >
  < style type = "text/css" >
  H1 {make-size: 300%; do-family: "Comic Sans MS"; color: 66FFFF; text-align: center ;}}
  H2 {font-size: 150%; do-family: "Comic Sans MS"; color: fd0202; text-align: left ;}}
  p {color: #EEEEEE; make-weight: lighter; text-align: left ;}}

  < / style >
  < body style = "" background-color: #151a1d; ">"
  < / head >
  < body >

  < h2 > 13,700,000,000 BC. (From OUR UNIVERSE FROM HUBBLE TELESCOPE DATA 1990 CALCULATED) < h2 / >

  < h2 > 4,567,000,000 BC (BEGINNING OF HADEAN EON) < h2 / >

  < p > name derived from Hades, the Greek God of the underworld name and referring
  to the devilishly hot, partially melted Earth surface and frequent collisions with other bodies of the solar system during this period. Geologist Preston Cloud defined
  In 1972 as the run-up to the oldest rocks known on Earth. Massive star exploded and produced the large cloud of gas and dust that came together like melted
  of the masses and became our solar system consisting of a Sun and planets. Our Sun was only 70% as bright as today ' hui. < p / >

  IT WORKED YESTERDAY WITH SOME RED TEXT BUT NOW SHOWS UP AS BLACK ON BLACK BACKGROUND H2 TEXT.  WHAT I AM DOING WRONG?

  You still have a duplicatetag...

  ... also, your end tags are formatted incorrectly. You currently have

  and

  instead of and

  . You can also change one of your

  affects a

  defined as indicated in your css.

  Check out the rest of the tags at the end of your page as well, I still don't see an end

  or both.

• Why this example does not work

  I couldn't run this example vi, he told me that sub vi is missing.

  How can I run this vi.  I have LABVIEW 8.5

  Atef

  Hello

  Cannot open under VI LV8.5 cause cause of too old version of VI. It is possible to open in LV7.1.  Here should work now. I mass compile of 7.1 to 8.5 by 8.0.

  But I think that there is an app for old VI can open in LV up to 8.5. Maybe someone will give link.

  Concerning

• Why this Spry does not work?

  as a simple test case, I created a new VBScript/ASP file and in it, I created a form with a text field, a Spry confirm the text field and another field of text for a field of blur. When I smack F12 for a race "fields do not match' get an immediate error before getting even a single character. Below the source code. What's wrong?

  ==================================

  "< %@LANGUAGE="VBSCRIPT "CODEPAGE ="65001"% >

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"

  < title > Untitled Document < /title >

  "< script src="/SpryAssets/SpryValidationConfirm.js "type =" text/javascript"> < / script >

  "< link href="/SpryAssets/SpryValidationConfirm.css "rel ="stylesheet"type =" text/css"/ >

  < / head >

  < body >

  < p > < / p >

  < form id = "form1" name = "form1" method = "post" action = "" >

  PWD1 < label for "pwd1" = > < / label >

  < input type = "text" name = "pwd1" id = "pwd1" / >

  < span id = "spryconfirm1" >

  < label for = "pwd2" > pwd2 < / label >

  < input type = "text" name = "pwd2" id = "pwd2" / >

  < span class = "confirmInvalidMsg" > the values don't match. </span > < / span >

  blur of < label for = "blur" > < / label >

  < input type = "text" name = "blur" id = "fuzzy" / >

  < / make >

  < p > < / p >

  < script type = "text/javascript" >

  var spryconfirm1 = new Spry.Widget.ValidationConfirm ("spryconfirm1", "pwd1", {isRequired:false, validateOn:["blur"]});})

  < /script >

  < / body >

  < / html >

  ==============================

  If the path to the support files are false. You may have noticed that I have linked files in the repository of Adobe.

  GRAMPS