Similar Questions

• Puzzled why this code does not work... (Update record) ASP/VB - please help.

  What I'm trying to do is to check two values of database and if they are what I said I want the code to run (record code update). Here's what I have:
  
  < % if (rsSoftwareRequests.Fields.Item("Approved"). Value) = "Yes" AND rsSoftwareRequests.Fields.Item ("EmailSent"). Value) = "False" then % >
  < %
  If (CStr (Request ("MM_update")) = "form1") then
  If (not MM_abortEdit) then
  'perform the update
  Dim MM_editCmd
  
  Set MM_editCmd = Server.CreateObject ("ADODB.Command")
  MM_editCmd.ActiveConnection = MM_Intranet_New_STRING
  MM_editCmd.CommandText = "UPDATE SoftwareRequest SET EmailSent."
  =?, ApprovedByUserName =? WHERE ID =? »
  MM_editCmd.prepared = true
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param1",
  1, 50, 202 Request.Form ("EmailSent")) ' adVarWChar
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param2",
  202, 1, 255, Request.Form ("ApprovedByUserName")) ' adVarWChar
  MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param3",
  5, 1, -1, MM_IIF (Request.Form ("MM_recordId"),
  Request.Form ("MM_recordId"), null)) ' adDouble
  MM_editCmd.execute
  MM_editCmd.ActiveConnection.close
  
  
  ' add the query string to the redirect URL
  Dim MM_editRedirectUrl
  MM_editRedirectUrl = "software_hardware1.asp".
  If (Request.QueryString <>"") then
  If (InStr (1, MM_editRedirectUrl, "?", vbTextCompare in) = 0) then
  MM_editRedirectUrl = MM_editRedirectUrl & "?" &
  Request.QueryString
  On the other
  MM_editRedirectUrl = MM_editRedirectUrl & "" &
  Request.QueryString
  End If
  End If
  Response.Redirect (MM_editRedirectUrl)
  End If
  End If
  % >
  < % end If % >
  
  
  The recordset is set above the statement 'IF '... I put these values in the HTML body to see if it is pulling them correctly and yet it is the code under the IF statement is not pull out... I don't understand?
  
  
  Any help would be appreciated. Thank you!
  

  I think that is the oder of your orders, I did a quick page to test and it works fine, I left the sql insert at the top of the page where DW put and I think all his money form if SO, was the order in my page like this:

  Insert code - report
  RS for the values-

  <%If (rsSoftwareRequests.Fields.Item("Approved").Value) = "Yes" AND rsSoftwareRequests.Fields.Item("EmailSent").Value) = "False" Then%>
  

  
  FORM code right after IF THEN exposed
  
  
  
  <% end if %>

  Notice the document.form1.submit () is inside the IF THEN statement so it will trigger if the FI THEN returns true and that is not the value of the onLoad of the body, it should work, I left the record insertion code where DW puts but try it inside the fi can. NOTE: If the user has JS disabled the page will not work, but there are risks to everything!

• Why this code does not work in dreamweaver?

  <! DOCTYPE HTML >

  < html >

  < head >

  < style type = "text/css" >

  {body

  Width: 100%;

  height: 100%;

  margin: 0px;

  padding: 0px;

  }

  < / style >

  < / head >

  < body >

  < img src = "images/last.png" alt = "left" style ="width: 100%; "/ >

  < / body >

  < / html >

  When I put it in the tab code Dreamweaver html blank document page, it does not seem to load. Any suggestions?

  Are you sure that the image is in the folder named "images" last.png? Are you sure the image is to use the right color RGB and CMYK not the space.

  There's nothing wrong with the code that I can see. What happens if you try just text:

  Hello

• Why this scriipt does not work with Firefox? &lt; embed src = "News2008Fall.pdf" width = '615' height = '3200' &gt; &lt; / embed &gt; "

  Please tell me why this script does not work with Firefox. It works with Safari. Here is the page that includes the script: www.lionsgatehoa.org/newslettertest.html. Thank you. Tom Engleman

  Here's the script in my html document:

  < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

  Edit: removed # phone

  Works for me on Linux.
  
  Your system details list does not display the Adobe Reader plugin, so you'll have to (re) install this program.

  See:

  • https://support.Mozilla.org/KB/using+the+Adobe+Reader+plugin+with+Firefox
  • http://KB.mozillazine.org/Adobe_Reader
  • http://get.Adobe.com/reader/otherversions/

• Why this SQL does not work?

  The following code does not work when I try to delete rows from a table of test. The test table has no unique or primary key on it and is defined as test (identification number). Can you explain to me why it doesn't work?
  

  
  

  delete from test a where a.rowid in (select b.rowid from test b where b.id = a.id and b.rowid != a.rowid);

  
  

  
  

  
  

  When I run the subquery (selection) with replacement of the actual values of a.rowid and the table queried a.id (IE.select b.rid from test2 b where b.id = 1 and b.rid != 'XXX'

  ), the subquery returns exactly as expected (that is to say, it gives the rowid is different from that which went from subquery). And as although I know the internal subquery must return the result for each row of the table in the outside circle delete statement, and only after that should execute the delete statement. For example, for the first row of the table in the external suppression, the delete statement must send the ID of the first row in the internal subquery and then wait the result which should return. And then runs the delete statement, in which case the subquery must return the rowid is different from that which went from subquery (ie.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.
  
  

  
  

  P.S. The sql is also not working if we replace remove it with the update or select
  

  in this case, the subquery must return the rowid is different from that which went from subquery (IE.

  b.rowid != a.rowid

  ). Am I wrong? What is the error in this statement.

  You are right that this subquery should return other than past rowid thr. But you used the IN clause as well as below:

  where a.rowid in

  What States remove the line if rowid returned by the subquery contains the identifier for the row whose ID was passed. As the inner query is to return another rowid, therefore, no row is deleted.

  To remove duplicate lines, try the query (Replace tablename/columns with your) below:

  DELETE FROM emp A

  WHERE A.ROWID > ALL (SELECT B.ROWID

  PEM'S B

  WHERE A.empno = B.empno);

• Why this text does not work well?

  Hi guys,.

  I am having trouble with this text.

  http://www.pixentral.com/show.php?picture=1y1N3lL5KPRBejo9GlPhEdkpl4KDQe

  It's in a column and the text block ends with the word 'amorosa '. I don't know why in the text the word "looking" will move to the next line and can only be inserted after that «nostalgia DEL...» "line of text even if ups with the end of the image apparently large enough to hold.

  http://www.pixentral.com/show.php?picture=1nu94bPp66d7lumber8SBjn6eI7Z1

  Maybe there is a better way to work with tabs, avoiding the list and so forth, but so far I have not understand it... so I work with the tools I know.

  Thanks for any info!

  See you soon,.

  SEBS

  Most importantly, you should do in this file is to remove all the keystrokes unnecessary (circled in red on my picture).

  

  You only need a paragraph return after caida, a tab after Coccoz, a tab after Catalanand without tab in the 'second paragraph' text (such as after del), and you do not need a line break after amorosa.

  After you have removed all the junk, set a tab on the left for the "second column and take note of its position." Suppose that you assign the p180 tab. To do the hanging indent, set the left indent p180 and first line indent to-p180 (i.e. negative 180 points). In this way, all text will be in the "second column", except the first line of the paragraph, which in this case are the names that make up your "first column". When you are ready to start with a new name, it's when you need a normal declaration.

• I have no idea why this 1130 does not work.

  Hello, everyone!

  I work in an elementary school in Detroit. We bought an access point Cisco 1130 for use on our local network. The problem is that our wireless laptops do not receive its signal.

  Here are the details.

  1. I connected the access point to our network and it turned.

  2. I used IPSU to find the IP address.

  3. I used Internet Explorer to connect to the access point.

  4. I gave you a fixed IP address on our field.

  5. I also entered the SSID and the WEP key.

  Everything seems good. The circular led on top of the access point is green. Unfortunately, Windows XP cannot 'see' the network signal.

  Is there someone who could help me get this thing working?

  Thank you very much

  -Ed

  All new 1130 AP come from the factory with the disabled radios. As you have seen, you need to enable them manually. I'm glad you have all this work!

• Why this mixture does not work?

  I work in CS4 on Mac. I want to do a 10 pastel colors color wheel. I had planned to use ten spokes - each scratched a color - and then mix together them. I did it before with success with other colors, I got the idea for this Web site: http://colorburned.com/create-a-color-picker-icon-in-illustrator/

  However, it does not for the moment. Here are my photos before and after.

  

  Any ideas on the reasons that a segment is so shredded? I tried to increase the width of each RADIUS of 1 pt to 4pt, but it did not help.

  You need to duplicate the higher-level object and place it under the entire stack.

  

  In this example, the strokes begin with yellow (the bottom) and eventually green (at the top of the stack).

  Select the green path, Edit > copy, edit > paste in front, object > Arrange > put in the background... and then create the mix.

  You need to start and stop of the same color in the same place for the entire circle mix properly.

• Why my Code does not work?

  I'm doing so if a user selects an option button in a group of 2 (choice1 & lendemain2) the formula in the field "Total" changes.

  This is the javascript in the field 'Total '.

  //////////////////////////////////////////////////////////////////////////////

  If (document. Group1 ('Choice1'). Checked)

  {

  Event.Value = (this.getField("WSAtotal").value + this.getField("SAandAdd").value);

  }

  
  

  Another yew (document. Group1(Choice2'). Checked)

  {

  Event.Value = (this.getField("NSAtotal").value + this.getField("SAandAdd").value);

  }

  //////////////////////////////////////////////////////////////////////////////

  P.S. I don't know anything about javascript so I have just been Frankensteining this code from around the web.

  All first if you have radio buttons that should be in a group of exclusion, to give them the same field name but the export values.

  Radio buttons are fields, you must first access the domain object before testing the value of the field.

  var oGroup = this.getField ('Group'); get the field object for the radio buttons named "group".

  debugging help.

  Console.Show ();

  Console.clear();

  Console.println ("Group field has a value of"+ oGroup.value ");

  end debugging help;

  Event.Value = ""; clear the value of the event;

  If (oGroup.value == "Choice1") {}

  the group object is "choice1."

  Event.Value = (this.getField("WSAtotal").value + this.getField("SAandAdd").value);

  }

  If (oGroup.value == "Lendemain2") {}

  the group object's value is "Lendemain2";

  Event.Value = (this.getField("NSAtotal").value + this.getField("SAandAdd").value);

  }

• That means 1e9 and why this query does not work?

  What does 1e9? Someone has links to documentation on this oracle? And why I get this error?
  

  SQL> select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER';
  select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER'
                                     *
  ERROR at line 1:
  ORA-00923: FROM keyword not found where expected

  SIZE is a keyword - so if you want the name of the column size then use 'SIZE' else give it a different name

  Try dividing by other exponentials, then you'll see how: 1e0 1e1 (div 1), (div by 10), 1e2 :-) etc

  Mette

  Published by: mettemusens on 2009-05-12 16:02

• Why this introduction does not work?

  < html >
  < head >
  < style type = "text/css" >
  H1 {make-size: 300%; do-family: "Comic Sans MS"; color: 66FFFF; text-align: center ;}}
  H2 {font-size: 150%; do-family: "Comic Sans MS"; color: fd0202; text-align: left ;}}
  p {color: #EEEEEE; make-weight: lighter; text-align: left ;}}

  < / style >
  < body style = "" background-color: #151a1d; ">"
  < / head >
  < body >

  < h2 > 13,700,000,000 BC. (From OUR UNIVERSE FROM HUBBLE TELESCOPE DATA 1990 CALCULATED) < h2 / >

  < h2 > 4,567,000,000 BC (BEGINNING OF HADEAN EON) < h2 / >

  < p > name derived from Hades, the Greek God of the underworld name and referring
  to the devilishly hot, partially melted Earth surface and frequent collisions with other bodies of the solar system during this period. Geologist Preston Cloud defined
  In 1972 as the run-up to the oldest rocks known on Earth. Massive star exploded and produced the large cloud of gas and dust that came together like melted
  of the masses and became our solar system consisting of a Sun and planets. Our Sun was only 70% as bright as today ' hui. < p / >

  IT WORKED YESTERDAY WITH SOME RED TEXT BUT NOW SHOWS UP AS BLACK ON BLACK BACKGROUND H2 TEXT.  WHAT I AM DOING WRONG?

  You still have a duplicatetag...

  ... also, your end tags are formatted incorrectly. You currently have

  and

  instead of and

  . You can also change one of your

  affects a

  defined as indicated in your css.

  Check out the rest of the tags at the end of your page as well, I still don't see an end

  or both.

• Why this Spry does not work?

  as a simple test case, I created a new VBScript/ASP file and in it, I created a form with a text field, a Spry confirm the text field and another field of text for a field of blur. When I smack F12 for a race "fields do not match' get an immediate error before getting even a single character. Below the source code. What's wrong?

  ==================================

  "< %@LANGUAGE="VBSCRIPT "CODEPAGE ="65001"% >

  < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

  " < html xmlns =" http://www.w3.org/1999/xhtml ">

  < head >

  < meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"

  < title > Untitled Document < /title >

  "< script src="/SpryAssets/SpryValidationConfirm.js "type =" text/javascript"> < / script >

  "< link href="/SpryAssets/SpryValidationConfirm.css "rel ="stylesheet"type =" text/css"/ >

  < / head >

  < body >

  < p > < / p >

  < form id = "form1" name = "form1" method = "post" action = "" >

  PWD1 < label for "pwd1" = > < / label >

  < input type = "text" name = "pwd1" id = "pwd1" / >

  < span id = "spryconfirm1" >

  < label for = "pwd2" > pwd2 < / label >

  < input type = "text" name = "pwd2" id = "pwd2" / >

  < span class = "confirmInvalidMsg" > the values don't match. </span > < / span >

  blur of < label for = "blur" > < / label >

  < input type = "text" name = "blur" id = "fuzzy" / >

  < / make >

  < p > < / p >

  < script type = "text/javascript" >

  var spryconfirm1 = new Spry.Widget.ValidationConfirm ("spryconfirm1", "pwd1", {isRequired:false, validateOn:["blur"]});})

  < /script >

  < / body >

  < / html >

  ==============================

  If the path to the support files are false. You may have noticed that I have linked files in the repository of Adobe.

  GRAMPS

• Why this example does not work

  I couldn't run this example vi, he told me that sub vi is missing.

  How can I run this vi.  I have LABVIEW 8.5

  Atef

  Hello

  Cannot open under VI LV8.5 cause cause of too old version of VI. It is possible to open in LV7.1.  Here should work now. I mass compile of 7.1 to 8.5 by 8.0.

  But I think that there is an app for old VI can open in LV up to 8.5. Maybe someone will give link.

  Concerning

• Why this query does not work on the CF when it works fine on MYSQL?

  Subject says it all. I can run it through console mysql and get the result that I need, but when I place it inside a cfquery that he will not treat.
  
  SET @saldo = 20000;
  SELECT
  IF (Co.transtipo=0,@saldo:[email protected],@saldo:=@saldo+t.transmonto),
  @saldo: = @saldo - t.transmonto.
  t.TransID,
  t.cuentaid,
  t.operacionid,
  t.fechatrans,
  t.voucher,
  t.cheque,
  t.transtitular,
  t.transmonto,
  t.transdetalle,
  t.modificado,
  Co.transtipo,
  Co.Operacion
  OF cuentastrans t
  LEFT JOIN cuentasoperacion co ON t.operacionid = co.operacionid
  WHERE the t.cuentaid = 7
  ORDER BY t.fechatrans ASC

  Fixed, coldfusion must be labeled with 'AS' of the expressions in the opposite case he used to index the column.

• This device does not work properly because Windows cannot load the drivers required for this device. (Code 31)

  Original title: this device does not work properly because Windows cannot load the drivers required for this device. (Code 31) in graphics AMD - 8151 HyperTransport (MC) AGP3.0 Tunnel

  This device does not work properly because Windows cannot load the drivers required for this device. (Code 31) in the graphics AMD - 8151 HyperTransport (MC) AGP3.0 Tunnel, what do I do to fix this help please.

  Jake

  Hey Jake,

  Follow these methods.

  Method 1: Follow these steps:

  (a) restart your computer if you have not already done so. There is always the possibility that the error Code 31 that you see was caused by a temporary problem with Device Manager. If so, a simple reboot can solve the Code 31.

  (b) have you install a device or a change in the Device Manager, just as the Code 31 error appeared? If so, it is very possible that the modification caused the Code 31 error.

  (c) cancel the change if you can restart the computer and then check again the error Code 31. Depending on the changes, some solutions may include:

  Remove or reconfigure newly installed unit.

  Restore a version prior to updating the driver.

  Use system restore to undo the Device Manager recent related changes.

  http://Windows.Microsoft.com/en-us/Windows-Vista/system-restore-frequently-asked-questions

  (d) to remove the registry values filters upper and lower. A common cause of errors in Code 31 is the corruption of two registry values in the class of the CD-ROM/DVD-ROM drive registry key.

  Note: This section, method, or task contains steps that tell you how to modify the registry. However, serious problems can occur if you modify the registry incorrectly. Therefore, make sure that you proceed with caution. For added protection, back up the registry before you edit it. Then you can restore the registry if a problem occurs. For more information about how to back up and restore the registry, click the following link. http://Windows.Microsoft.com/en-us/Windows-Vista/back-up-the-registry

  Method 2: Update the latest graphic drivers.

  Updated a hardware driver that is not working properly

  http://Windows.Microsoft.com/en-us/Windows-Vista/update-a-driver-for-hardware-that-isn ' t-work correctly