Why this text does not work well?

Hi guys,.

I am having trouble with this text.

http://www.pixentral.com/show.php?picture=1y1N3lL5KPRBejo9GlPhEdkpl4KDQe

It's in a column and the text block ends with the word 'amorosa '. I don't know why in the text the word "looking" will move to the next line and can only be inserted after that «nostalgia DEL...» "line of text even if ups with the end of the image apparently large enough to hold.

http://www.pixentral.com/show.php?picture=1nu94bPp66d7lumber8SBjn6eI7Z1

Maybe there is a better way to work with tabs, avoiding the list and so forth, but so far I have not understand it... so I work with the tools I know.

Thanks for any info!

See you soon,.

SEBS

Most importantly, you should do in this file is to remove all the keystrokes unnecessary (circled in red on my picture).

You only need a paragraph return after caida, a tab after Coccoz, a tab after Catalanand without tab in the 'second paragraph' text (such as after del), and you do not need a line break after amorosa.

After you have removed all the junk, set a tab on the left for the "second column and take note of its position." Suppose that you assign the p180 tab. To do the hanging indent, set the left indent p180 and first line indent to-p180 (i.e. negative 180 points). In this way, all text will be in the "second column", except the first line of the paragraph, which in this case are the names that make up your "first column". When you are ready to start with a new name, it's when you need a normal declaration.

Tags: InDesign

Similar Questions

  • Why this scriipt does not work with Firefox? < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

    Please tell me why this script does not work with Firefox. It works with Safari. Here is the page that includes the script: www.lionsgatehoa.org/newslettertest.html. Thank you. Tom Engleman

    Here's the script in my html document:

    < embed src = "News2008Fall.pdf" width = '615' height = '3200' > < / embed > "

    Edit: removed # phone

    Works for me on Linux.

    Your system details list does not display the Adobe Reader plugin, so you'll have to (re) install this program.

    See:

  • Why this SQL does not work?

    The following code does not work when I try to delete rows from a table of test. The test table has no unique or primary key on it and is defined as test (identification number). Can you explain to me why it doesn't work?


    delete from test a where a.rowid in (select b.rowid from test b where b.id = a.id and b.rowid != a.rowid);




    When I run the subquery (selection) with replacement of the actual values of a.rowid and the table queried a.id (IE.select b.rid from test2 b where b.id = 1 and b.rid != 'XXX'

    ), the subquery returns exactly as expected (that is to say, it gives the rowid is different from that which went from subquery). And as although I know the internal subquery must return the result for each row of the table in the outside circle delete statement, and only after that should execute the delete statement. For example, for the first row of the table in the external suppression, the delete statement must send the ID of the first row in the internal subquery and then wait the result which should return. And then runs the delete statement, in which case the subquery must return the rowid is different from that which went from subquery (ie.

    b.rowid != a.rowid

    ). Am I wrong? What is the error in this statement.


    P.S. The sql is also not working if we replace remove it with the update or select

    in this case, the subquery must return the rowid is different from that which went from subquery (IE.

    b.rowid != a.rowid

    ). Am I wrong? What is the error in this statement.

    You are right that this subquery should return other than past rowid thr. But you used the IN clause as well as below:

    where a.rowid in

    What States remove the line if rowid returned by the subquery contains the identifier for the row whose ID was passed. As the inner query is to return another rowid, therefore, no row is deleted.

    To remove duplicate lines, try the query (Replace tablename/columns with your) below:

    DELETE FROM emp A

    WHERE A.ROWID > ALL (SELECT B.ROWID

    PEM'S B

    WHERE A.empno = B.empno);

  • Why Internet explorer does not work well, stop working, do not dowlown and the printer too

    When I use the Microsoft Office word 2003 stop working. I can't use the printer because it says I don't have enough right. Internet explorer stop working when I want to use. When I said work stoppage, because stop (the word screen "not responding") and for seconds, I have to wait this back and start to work so slow.  I also have a lot of problems with the dates.

    Please can you check my computer and advise me how I can solve these problems.
    Thanks for your help
    Alicia of Bazo

    Hello AliciaD'Bazo,.

    Thank you for your message.  How long these problems last?  If all of these symptoms have occurred recently, you can perform a System Restore to a point when your computer was functioning as designed.

    If a system restore does not resolve the problem, I think that you would be better served download and run the malicious software removal tool.

    After you run the tool, you will find that your computer is or is not infected with a virus or a virus.  At the same it is, please post on the forum Vista Security steps to return your PC to a usable state.

    Another way to ensure that your computer is 100% clean is to perform a new installation.  Don't forget that a new installation will delete all your data and the current settings.  You would need to save everything that is important before you perform a clean installation.

    We can't wait to hear back on your part.

    See you soon

  • Why this mixture does not work?

    I work in CS4 on Mac. I want to do a 10 pastel colors color wheel. I had planned to use ten spokes - each scratched a color - and then mix together them. I did it before with success with other colors, I got the idea for this Web site: http://colorburned.com/create-a-color-picker-icon-in-illustrator/

    However, it does not for the moment. Here are my photos before and after.

    before.jpgAfter.jpg

    Any ideas on the reasons that a segment is so shredded? I tried to increase the width of each RADIUS of 1 pt to 4pt, but it did not help.

    You need to duplicate the higher-level object and place it under the entire stack.

    In this example, the strokes begin with yellow (the bottom) and eventually green (at the top of the stack).

    Select the green path, Edit > copy, edit > paste in front, object > Arrange > put in the background... and then create the mix.

    You need to start and stop of the same color in the same place for the entire circle mix properly.

  • Why this code does not work, its simple!

    Hello

    I know the myVISITORinfoFormdomain name, say, the name is myTextField25, but I do not know its full path! but, I want to make gray and read-only, so I put the code below (I put the cursor on the node 'myVISITORinfoForm' and selected the DocReady event)

    var c = xfa.resolveNode("myTextField5").fillColor = '192,192,192. "
    var d = xfa.resolveNode("myTextField26").fillColor = '192,192,192. "
    var e = xfa.resolveNode("myTextField25").access = "readOnly";
    var f = xfa.resolveNode("myTextField26").access = "readOnly";

    I also tried another field of myTextField26, I also kept the same code in the FormReady events initialization... but has not worked!

    myTextField25 and myTextField26 are positioned on the 3rd page of the mySubForm12 subform.

    Pls let me know wht miss me?

    Thank you

    Hello

    If you want to make each field read only and gray, so why not script directly in each of the two textfields?

    It's the two fields docReady event:

    this.fillColor = "192,192,192";
    this.access = "readOnly";
    

    You can only do this if the fields are not null (for example when the form is returned to you). In this case you would wrap the script in an if statement:

    if (this.rawValue === null)
    {
         this.fillColor = "192,192,192";
         this.access = "readOnly";
    }
    

    I don't think the way you declare variables and setting properties on one line will work. Also, the use of the xfa.resolveNode is not effective.

    Hope that helps,

    Niall

  • Why this code does not work in dreamweaver?

    <! DOCTYPE HTML >

    < html >

    < head >

    < style type = "text/css" >

    {body

    Width: 100%;

    height: 100%;

    margin: 0px;

    padding: 0px;

    }

    < / style >

    < / head >

    < body >

    < img src = "images/last.png" alt = "left" style ="width: 100%; "/ >

    < / body >

    < / html >

    When I put it in the tab code Dreamweaver html blank document page, it does not seem to load. Any suggestions?

    Are you sure that the image is in the folder named "images" last.png? Are you sure the image is to use the right color RGB and CMYK not the space.

    There's nothing wrong with the code that I can see. What happens if you try just text:

    Hello

  • Puzzled why this code does not work... (Update record) ASP/VB - please help.

    What I'm trying to do is to check two values of database and if they are what I said I want the code to run (record code update). Here's what I have:

    < % if (rsSoftwareRequests.Fields.Item("Approved"). Value) = "Yes" AND rsSoftwareRequests.Fields.Item ("EmailSent"). Value) = "False" then % >
    < %
    If (CStr (Request ("MM_update")) = "form1") then
    If (not MM_abortEdit) then
    'perform the update
    Dim MM_editCmd

    Set MM_editCmd = Server.CreateObject ("ADODB.Command")
    MM_editCmd.ActiveConnection = MM_Intranet_New_STRING
    MM_editCmd.CommandText = "UPDATE SoftwareRequest SET EmailSent."
    =?, ApprovedByUserName =? WHERE ID =? »
    MM_editCmd.prepared = true
    MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param1",
    1, 50, 202 Request.Form ("EmailSent")) ' adVarWChar
    MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param2",
    202, 1, 255, Request.Form ("ApprovedByUserName")) ' adVarWChar
    MM_editCmd.parameters.Append MM_editCmd.CreateParameter ("param3",
    5, 1, -1, MM_IIF (Request.Form ("MM_recordId"),
    Request.Form ("MM_recordId"), null)) ' adDouble
    MM_editCmd.execute
    MM_editCmd.ActiveConnection.close


    ' add the query string to the redirect URL
    Dim MM_editRedirectUrl
    MM_editRedirectUrl = "software_hardware1.asp".
    If (Request.QueryString <>"") then
    If (InStr (1, MM_editRedirectUrl, "?", vbTextCompare in) = 0) then
    MM_editRedirectUrl = MM_editRedirectUrl & "?" &
    Request.QueryString
    On the other
    MM_editRedirectUrl = MM_editRedirectUrl & "" &
    Request.QueryString
    End If
    End If
    Response.Redirect (MM_editRedirectUrl)
    End If
    End If
    % >
    < % end If % >


    The recordset is set above the statement 'IF '... I put these values in the HTML body to see if it is pulling them correctly and yet it is the code under the IF statement is not pull out... I don't understand?


    Any help would be appreciated. Thank you!

    I think that is the oder of your orders, I did a quick page to test and it works fine, I left the sql insert at the top of the page where DW put and I think all his money form if SO, was the order in my page like this:

    Insert code - report
    RS for the values-

    <%If (rsSoftwareRequests.Fields.Item("Approved").Value) = "Yes" AND rsSoftwareRequests.Fields.Item("EmailSent").Value) = "False" Then%>


    FORM code right after IF THEN exposed


    <% end if %>

    Notice the document.form1.submit () is inside the IF THEN statement so it will trigger if the FI THEN returns true and that is not the value of the onLoad of the body, it should work, I left the record insertion code where DW puts but try it inside the fi can. NOTE: If the user has JS disabled the page will not work, but there are risks to everything!

  • Why this introduction does not work?

    < html >
    < head >
    < style type = "text/css" >
    H1 {make-size: 300%; do-family: "Comic Sans MS"; color: 66FFFF; text-align: center ;}}
    H2 {font-size: 150%; do-family: "Comic Sans MS"; color: fd0202; text-align: left ;}}
    p {color: #EEEEEE; make-weight: lighter; text-align: left ;}}

    < / style >
    < body style = "" background-color: #151a1d; ">"
    < / head >
    < body >

    < h2 > 13,700,000,000 BC. (From OUR UNIVERSE FROM HUBBLE TELESCOPE DATA 1990 CALCULATED) < h2 / >

    < h2 > 4,567,000,000 BC (BEGINNING OF HADEAN EON) < h2 / >

    < p > name derived from Hades, the Greek God of the underworld name and referring
    to the devilishly hot, partially melted Earth surface and frequent collisions with other bodies of the solar system during this period. Geologist Preston Cloud defined
    In 1972 as the run-up to the oldest rocks known on Earth. Massive star exploded and produced the large cloud of gas and dust that came together like melted
    of the masses and became our solar system consisting of a Sun and planets. Our Sun was only 70% as bright as today ' hui. < p / >

    IT WORKED YESTERDAY WITH SOME RED TEXT BUT NOW SHOWS UP AS BLACK ON BLACK BACKGROUND H2 TEXT.  WHAT I AM DOING WRONG?

    You still have a duplicatetag...

    ... also, your end tags are formatted incorrectly. You currently have

    and

    instead of and

    . You can also change one of your

    affects a

    defined as indicated in your css.

    Check out the rest of the tags at the end of your page as well, I still don't see an end

    or both.

  • That means 1e9 and why this query does not work?

    What does 1e9? Someone has links to documentation on this oracle? And why I get this error?
    SQL> select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER';
    select segment_name,(bytes/1e9) AS size from dba_segments where segment_name='MSG_MASTER'
                                       *
    ERROR at line 1:
    ORA-00923: FROM keyword not found where expected

    SIZE is a keyword - so if you want the name of the column size then use 'SIZE' else give it a different name

    Try dividing by other exponentials, then you'll see how: 1e0 1e1 (div 1), (div by 10), 1e2 :-) etc

    Mette

    Published by: mettemusens on 2009-05-12 16:02

  • I have no idea why this 1130 does not work.

    Hello, everyone!

    I work in an elementary school in Detroit. We bought an access point Cisco 1130 for use on our local network. The problem is that our wireless laptops do not receive its signal.

    Here are the details.

    1. I connected the access point to our network and it turned.

    2. I used IPSU to find the IP address.

    3. I used Internet Explorer to connect to the access point.

    4. I gave you a fixed IP address on our field.

    5. I also entered the SSID and the WEP key.

    Everything seems good. The circular led on top of the access point is green. Unfortunately, Windows XP cannot 'see' the network signal.

    Is there someone who could help me get this thing working?

    Thank you very much

    -Ed

    All new 1130 AP come from the factory with the disabled radios. As you have seen, you need to enable them manually. I'm glad you have all this work!

  • Why this example does not work

    I couldn't run this example vi, he told me that sub vi is missing.

    How can I run this vi.  I have LABVIEW 8.5

    Atef

    Hello

    Cannot open under VI LV8.5 cause cause of too old version of VI. It is possible to open in LV7.1.  Here should work now. I mass compile of 7.1 to 8.5 by 8.0.

    But I think that there is an app for old VI can open in LV up to 8.5. Maybe someone will give link.

    Concerning

  • Why this Spry does not work?

    as a simple test case, I created a new VBScript/ASP file and in it, I created a form with a text field, a Spry confirm the text field and another field of text for a field of blur. When I smack F12 for a race "fields do not match' get an immediate error before getting even a single character. Below the source code. What's wrong?

    ==================================

    "< %@LANGUAGE="VBSCRIPT "CODEPAGE ="65001"% >

    < ! DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional / / IN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd" > ""

    " < html xmlns =" http://www.w3.org/1999/xhtml ">

    < head >

    < meta http-equiv = "Content-Type" content = text/html"; charset = utf-8 "/ >"

    < title > Untitled Document < /title >

    "< script src="/SpryAssets/SpryValidationConfirm.js "type =" text/javascript"> < / script >

    "< link href="/SpryAssets/SpryValidationConfirm.css "rel ="stylesheet"type =" text/css"/ >

    < / head >

    < body >

    < p > < / p >

    < form id = "form1" name = "form1" method = "post" action = "" >

    PWD1 < label for "pwd1" = > < / label >

    < input type = "text" name = "pwd1" id = "pwd1" / >

    < span id = "spryconfirm1" >

    < label for = "pwd2" > pwd2 < / label >

    < input type = "text" name = "pwd2" id = "pwd2" / >

    < span class = "confirmInvalidMsg" > the values don't match. </span > < / span >

    blur of < label for = "blur" > < / label >

    < input type = "text" name = "blur" id = "fuzzy" / >

    < / make >

    < p > < / p >

    < script type = "text/javascript" >

    var spryconfirm1 = new Spry.Widget.ValidationConfirm ("spryconfirm1", "pwd1", {isRequired:false, validateOn:["blur"]});})

    < /script >

    < / body >

    < / html >

    ==============================

    If the path to the support files are false. You may have noticed that I have linked files in the repository of Adobe.

    GRAMPS

  • Why this query does not work on the CF when it works fine on MYSQL?

    Subject says it all. I can run it through console mysql and get the result that I need, but when I place it inside a cfquery that he will not treat.

    SET @saldo = 20000;
    SELECT
    IF (Co.transtipo=0,@saldo:[email protected],@saldo:=@saldo+t.transmonto),
    @saldo: = @saldo - t.transmonto.
    t.TransID,
    t.cuentaid,
    t.operacionid,
    t.fechatrans,
    t.voucher,
    t.cheque,
    t.transtitular,
    t.transmonto,
    t.transdetalle,
    t.modificado,
    Co.transtipo,
    Co.Operacion
    OF cuentastrans t
    LEFT JOIN cuentasoperacion co ON t.operacionid = co.operacionid
    WHERE the t.cuentaid = 7
    ORDER BY t.fechatrans ASC

    Fixed, coldfusion must be labeled with 'AS' of the expressions in the opposite case he used to index the column.

  • My screen touch iphone 5 does not work well when charging. Please someone help me

    Members of the apple, Hello

    When I'm using my iphone and he is in charge the touchscreen does not work well

    Why apple made this feature on ios?

    Try

    http://support.Apple.com/en-us/HT201559

Maybe you are looking for