Query regarding SQL logs

I'm currently working on database forensics, if I do some manual changes in the database through some sql queries there no entry in the logs to prove...

Can anyone suggest me some tools that can give the desired result. (i.e. pulled the log of all manual queries)

PS I am using SQL Server 2005

Any help would be appreciated

Thank you.

Hello

Your question is beyond the scope of this community.

Please repost your question in the SQL Server TechNet Forums.

https://social.technet.Microsoft.com/forums/SQLServer/en-us/home?category=SQLServer

See you soon.

Tags: Windows

Similar Questions

How export (unload) result of the query without running query on sql developer
Hello

I want to know how export (unload) result of the query without running query on sql developer.

I know this way.
1. execution of query
2. click on "Download" on the results tab
http://i.stack.imgur.com/CQ4Qb.jpg

Is he available unload a query result before the race?
No, but you can do this ask the developer SQL change however, for other users can vote and add weight to the possible future implementation.

Kind regards
K.

I have some problem in my query to sql server. If I press f5 to run it opens to record dialogue area nd do not run (I don't get successful... orders etc). Please help me

I have some problem in my query to sql server. If I press f5 to run it opens to record dialogue area nd do not run (I don't get successful... orders etc). Please help me

Hello

SQL Server is not supported in these forums. I suggest that you ask your question again in one of the forums dedicated to Microsoft for him here:

http://social.technet.microsoft.com/Forums/en-us/category/sqlserver .

Thank you. :)

Error message when I run delete the query in SQL Server 2008.

Error message when I run delete the query in SQL Server 2008 SP3.

Error message:

MSG 0, level 11, State 0, line 0
A serious error occurred on the current command. The results, if any, should be discarded.

I never got any problem since 5 years.

Please let me know what is the cause of the problem.

You can get a response better/faster if repost you your question in the instances of SQL Server dedicated from Microsoft here:

http://social.technet.microsoft.com/Forums/en-us/category/sqlserver .

Thank you. :)

(I'm sorry, but I can't move this thread for you because the two forums are working on separate platforms)

the variable name of database query to SQL Server using the Oracle database link
Hi all

I have an ApEx 4.1 application running on x 64 (11.2.0.1) 11g on Windows Server 2008 x 64, and I have a few points of data integration with SQL (2005 and 2008) server that I need to create. I have configured the database with dg4odbc link and it works perfectly... I can run queries on the SQL Server database without any problem using the database link.

However, there is a scenario where the SQL Server database name is dynamic, and I need to generate on the fly in a PL/SQL block and then use it in a query dynamic SQL (all this in the ApEx). It of wherever I meet problems... when I asked the default database that is based on the ODBC connection and I don't have to specify the name of the database, no problem. But when I need access to one of the several other databases by default, I received the error "invalid table.

It works well:* (note that 'fv' is the name of my database link)

v_query1: = "select 'Release Date' from dbo." Schedules@FV where dbo. Annexes. "" SchedID "=: calendar";
EXECUTE IMMEDIATE v_query1 in rel_date using the grid.

I then take this rel_date variable, convert a varchar2 (rel_date_char), then use it as the name of the database in the following query...

_ It returns an error(error ORA-00903: invalid table name)

v_query2: = "select"PARTNO": rel_date_char.dbo.ProdDetails@fv where 'SchedID' =: calendar and"UnitID"=: unit"
and 'MasterKey' =: master and "ParentKey" =: parent';

EXECUTE IMMEDIATE v_query2 in part_number using planning, master, parent unit;

I also tried using all of the following conditions without result:

"select"PARTNO"of" | : rel_date_char | '.dbo. ProdDetails@fv where 'SchedID '...
"select"PARTNO"of" | rel_date_char | '.dbo. ProdDetails@fv where 'SchedID '...
"select"PARTNO"of" | @rel_date_char | '.dbo. ProdDetails@fv where 'SchedID '...
"select"PARTNO"in @rel_date_char.dbo.ProdDetails @fv where 'SchedID'..."

Is it possible to do it in PL/SQL?

Thanks for any help!
-Ian C.

Published by: 946532 on July 15, 2012 19:45
Just did a test using passthrough:

SQL > set serveroutput on
SQL > declare
2 val varchar2 (100);
3 c whole;
4 whole nr;
5. start
c: 6 = dbms_hs_passthrough.open_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3;
7 dbms_hs_passthrough.parse@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, "select count (*) from EMP");
8 LOOP
9 nr: = DBMS_Hs_Passthrough.fetch_row@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
10 output when nr = 0;
11 dbms_hs_passthrough.get_value@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, 1, val);
12 dbms_output.put_line (val);
13 end of loop;
14 dbms_hs_passthrough.close_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
15 end;
16.
24576

PL/SQL procedure successfully completed.

SQL > declare
2 val varchar2 (100);
3 c whole;
4 whole nr;
5. start
c: 6 = dbms_hs_passthrough.open_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3;
7 dbms_hs_passthrough.parse@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, ' select count (*) from dbo.) EMP');
8 LOOP
9 nr: = DBMS_Hs_Passthrough.fetch_row@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
10 output when nr = 0;
11 dbms_hs_passthrough.get_value@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, 1, val);
12 dbms_output.put_line (val);
13 end of loop;
14 dbms_hs_passthrough.close_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
15 end;
16.
24576

PL/SQL procedure successfully completed.

So all 3 ways work for me.

Published by: kgronau on July 23, 2012 10:08

Now, using the variables to make the selection:

SQL > declare
2 val varchar2 (100);
3 c whole;
4 whole nr;
5 tabname varchar2 (20): = 'EMP ';
6 ownr varchar2 (20): = "dbo."
7 dbname varchar2 (20): = "door";
Start 8
c: 9 = dbms_hs_passthrough.open_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3;
10 dbms_hs_passthrough.parse@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, ' SELECT count (*) FROM ': dbname: '.) ' || ownr | '.'|| tabname | ") ;
11 LOOP
12 nr: = DBMS_Hs_Passthrough.fetch_row@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
13 when the exit nr = 0;
14 dbms_hs_passthrough.get_value@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c, 1, val);
15 dbms_output.put_line (val);
16 end loop;
17 dbms_hs_passthrough.close_cursor@FREETDS_DG4ODBC_EMGTW_11_2_0_3 (c);
18 end;
19.
24576

PL/SQL procedure successfully completed.

=> instead of executing the statement using the "execute Immediate" we use the PASTHROUGH package to pass the statement to SQL Server.

Published by: kgronau on July 23, 2012 10:10

11g - how do I enable sql logging
Hi, experts,
I can't find how to activate the SQL logging (in nqquery.log)

How to configure?
Hi user,

You can do this with the administration tool. Open the administration tool, and then open your repository in online mode. Go to the manage--> identity. Double-click the user that you want to be able to see queries and the level 2 loggin increse.

I hope this helps.

J. -.

A query regarding the creation of shared objects.

Hello
I have a query regarding the creation of shared objects.
I saw an example where the author is creatining Shared Object as shown
below:

SharedObj = null;
sharedObj = SharedObject.getLocal ("myTasks");
and there is nothing related to the word "myTasks" anywhere in the Application.
Can someone please let me know what this word "myTasks" mean here?
Thanks in advance.

Hello

With a shared object, it will create one if it does not exist, then "myTasks" becomes the name of the shared object or if it exists it will load all the objects that are in the shared object.

Here is a simple example that uses the sharedobjects to store the connection information.

http://gumbo.flashhub.NET/login/

David

Different output for the same query in SQL Server and Oracle
I have two tables table1 and table2

-table1 has two columns c1 int and varchar c2. There are no constraints added in it. It contains data as shown below

C1 c2
-------------------
d 6
5 d
102 g
6%
f 103
5.
501 j
1 g
601 n
2 m

-table2 has only a single column c1 int. There is no added in constraints. It contains data as shown below

C1
----
6
1
4
3
2

now when I run below, given the query in sql server and oracle it gives me different results

Select *.
FROM table1
table2 on table2.c1 = table1.c1 inner join (SELECT ROW_NUMBER() (any ORDER by ASC c1) AS c1 from table2)

output of SQL server
------------------------
C1 c2 c1
--------------------------------
1 g 1
2 m 2
3 h 3
4 g 4
5 d 5

release of Oracle
----------------------
C1 C2 C1
---------------------------------
5 d 5
4 g 4
3 h 3
1 g 1
2 m 2

If you notice the first column in the two outputs. It is sorted in sql server and no oracle.

Why he behaves differently in oracle? Is there a way I can fix this problem in oracle?

Thank you
Jigs
It is NOT a behavior "differently" in Oracle; you did not specify just an order that you expect of your results, so you'll get output in what order the fantasies of the database showing (ie. no guaranteed order). It is an artifact of the way the database chooses to collect the data and databases (or same sets of data within the same database) can and will most likely behave differently.

Same SQL Server will not be guaranteed to always get your data in an orderly manner if you exclude the order by clause, even if you think that there always display the data in an orderly manner.

Your solution is to add an order by clause, in the TWO databases, to force the order of the data output.

How to know the execution time of query in sql plus
Hello

I want to know the duration of execution of query in sql more accompanied by statistics

I say time is set on;
Set autotrace on;
Select * view where usr_id = "abcd";

If the result is 300 lines it scrolls up until all the rows are retrieved and finally gives me the run time in 40 seconds, or 1 minute... (it is after all records scrolls)

but when I run it in Toad he gives 350 milli seconds...

I want to see the execution time in sql how to proceed

client and database server 11g is g 10

concerning
REDA
In sqlplus you can do set autotrace traces to suppress the display of the selected lines.

John

How to convert the hierarchical query of SQL Server (CTE) to Oracle?
How to convert the hierarchical query of SQL Server (CTE) to Oracle?

WITH cte (col1, col2) AS
(
SELECT col1, col2
FROM dbo. [tb1]
WHERE col1 = 12
UNION ALL
SELECT c.col1, c.col2
FROM dbo. [tb1] AS c INNER JOIN cte AS p ON c.col2 = p.col1
)
DELETE one
FROM dbo. [tb1] AS an INNER JOIN b cte
ON a.col1 = b.col1
Hello
Something like this maybe:
```
DELETE FROM dbo.tb1 a
 WHERE EXISTS (
  SELECT 1
    FROM dbo.tb1 b
  WHERE a.co11 = b.col1
      AND a.col2 = b.col2
   START WITH b.col1 = 12
  CONNECT BY b.col2 = PRIOR b.col1)
```
Although you need to do here is to check that CONNECT it BY SELECT, returns records you wait first, then the DELETION should work too.

Cannot query a view in PL/SQL package but it can query in SQL * more

Hello
Logged on as a user, I can query the table DBA_SEGMENTS, but I can't question via a slider or select from a PL/SQL package.
I get the following error message:
LINE/COL ERROR
-------- -----------------------------------------------------------------
28/4 PL/SQL: statement ignored
33/5 PL/SQL: ORA-00942: table or view does not exist
28 select
29 count(*)
30 in
31 n
32 of
33 dba_segments;

Can someone explain to me what is the missing privilege that I need?
Thank you in advance.
Kind regards.

It seems that you have granted to dba_segments by role.

To use this object in pl/sql or sp, you need directly.

Ask your dba to grant:

SQL > grant select on dba_segments to your_user;

Mustafa DOGANAY

http://Doganay.WordPress.com

SQL log file grows to limit, but it can be narrowed and used space is listed as 1%.

Hello.
3 guests ESXi 5.1.0 1463097 in a cluster.
MS SQL 2008 R2 server (SQL Server 10.50.2500) on a Standard VM MS Windows 2008 R2 server.
VIM_SQLEXP instance name
Name of the comic: VIM_VCDB.
Recovery mode: Simple
DB 1 MB, unrestricted growth. Current database size: 3887MB
Log growth of 10%, limited to 4 GB maximum size after shrink this morning BUT 2MB
Every morning the logfile has run nearly full but the VMware VirtualCenter Server service runs and I can start the vSphere Client. I know not if I do not shrink the log, the service will stop later today or tomorrow.
I studied and followed
Determine where growth occurs in the VMware vCenter Server (1028356) database.
SQL Server recovery mode affect the Transaction log space required (1001046)
Troubleshooting of transaction logs on a Microsoft SQL database server (1003980)
but I do not see any table more than many. I see that VPX_EVENT has increased about 28 MB at night, but nothing else seems alarming.
Any ideas what it could be?
Best regards
Peter Lageri Rasch
Denmark

Hello

Some time ago I had a similar situation as you.

I recommend you to check this carefully, it might be useful:

Troubleshooting when the vcenter db transaction log is full (MS SQL server 2005 express)

Best regards

Pablo

Query in sql server from Oracle 9.2
Hello

How can I connect and run the query to Oracle without using other products (DG4MSQL, etc)?

using 9.2.08
Hello
I say it is 'free' because Dg4ODBC is included in your license of RDBMS and simply provide a third party ODBC driver.
See this note-

Gateway and connectivity generic licensing considerations (Doc ID 232482.1)

You must install and configure in an ORACLE_HOME on a machine somewhere then you can use the links in the database to connect to and select databases non-Oracle.
Take a look at these notes depending on the platform that you plan to use-

How DG4ODBC Setup on Linux x 86 32 bit (Doc ID 466228.1)
How to set up DG4ODBC on 64 bit OS Unix (Linux, Solaris, AIX, HP - UX Itanium) to connect to Oracle databases Post Install (Doc ID 561033.1)
How the installer DG4ODBC (gateway for ODBC Oracle database) on Windows 32 bits (Doc ID 466225.1)
How the installer DG4ODBC (gateway for ODBC Oracle database) on 64-bit Windows operating systems (Doc ID 1266572.1)

As I said in my previous update if SQL * Server is your non-Oracle database then a stand-alone installation on Windows is the best option in order to use the Microsoft ODBC driver, although there is now a Linux x 86-64 bit available MS ODBC.

Please read carefully the notes that I called because they should have the information you need.

Kind regards
Mike

query regarding link by
I have the following table, named student: -.

NAME
--------------------
one
b
c
d

Now, I stumbled upon a clause connect by but I can't understand how it works. I know this has something to do with the treelike structures. But when I issued the following query:
Select * student connect you prior name > name;
-the following report was produced: -.

NAME
--------------------
one
b
one
c
one
b
one
d
one
b
one

NAME
--------------------
c
one
b
one

15 selected lines.

I really don't understand how it works. Help, please.
Thanks in advance

Published by: user11930797 on April 27, 2010 05:02

Published by: user11930797 on April 27, 2010 05:03

Published by: user11930797 on April 27, 2010 05:04
Maybe it help if you choose the level and the full path, like this:
```
SQL> with student as
  2  ( select 'a' name from dual union all
  3    select 'b' from dual union all
  4    select 'c' from dual union all
  5    select 'd' from dual
  6  )
  7   select name
  8        , level
  9        , sys_connect_by_path(name,' --> ') scbp
 10     from student
 11  connect by prior name > name
 12  /

N      LEVEL SCBP
- ---------- --------------------------------------------------
a          1  --> a
b          1  --> b
a          2  --> b --> a
c          1  --> c
a          2  --> c --> a
b          2  --> c --> b
a          3  --> c --> b --> a
d          1  --> d
a          2  --> d --> a
b          2  --> d --> b
a          3  --> d --> b --> a
c          2  --> d --> c
a          3  --> d --> c --> a
b          3  --> d --> c --> b
a          4  --> d --> c --> b --> a

15 rows selected.
```
Now, it shows that you generate 4 trees. One for each record, because there is no clause "begins by" specified. And then the tree is constructed using the clause "previous name > name", hence this exit.

I hope this helps.

Kind regards
Rob.

In Oracle XE limitations regarding SQL

Hi all,

Is that there is no limitation in queries SQL Oracle XE?

Because I run a SQL query in Oracle Standard Edition which is clothed with results while I'm not able to run the same query against the Oracle XE with the same table structure and data.

In Oracle XE, it runs the error as ERROR at line 31:
ORA-00904: "EMP". "" EMPLOYEE_CODE ": invalid identifier

My query is

SELECT "EMP". "" EMPLOYEE_CODE, "
"EMP". "" NAME, "
"EMP". "' BIRTH_DATE ',.
"EMP". "" FH_NAME, "
"EMP". "" JOINING_DATE, "
"EMP". "" DESIGNATION. "
"EMP". "" PAN_NO, "
"DEPT". "" DESCRIPTION. "
"EMP". "" DIVISION_CODE, "
"DIV". "" DESCRIPTION. "
"LOC". "" DESCRIPTION. "
"EMP". "" PF_NO, "
"EMP". "" ESI_NO, "
"EMP". "" CURRENT_STATUS, "
"L"." CL_BALANCE,"
"L"." EL_BALANCE,"
"L"." ML_BALANCE,"
"A"." ATTENDED_DAYS,"
"A"." PUBLIC_HOLIDAYS,"
"A"." WEEKLY_HOLIDAYS,"
(SELECT SUM (CASE WHEN "LEAVE". "" LEAVE_CODE "="CL"AND"EXIT".". CASUAL_LEAVE END OF LEAVE_DAYS") LEAVE WHERE PERIOD = 88 AND EMPLOYEE_CODE = EMP. EMPLOYEE_CODE) AS CASUAL_LEAVE,
(SELECT SUM (CASE WHEN "LEAVE". "" LEAVE_CODE "= 'EL' AND 'EXIT'." EARNED_LEAVE END OF LEAVE_DAYS") LEAVE WHERE PERIOD = 88 AND EMPLOYEE_CODE = EMP. EMPLOYEE_CODE) AS EARNED_LEAVE,
"SICK_LEAVE,"
"ON_DUTY,"
"ESI_LEAVE,"
(SELECT SUM (CASE WHEN "LEAVE". "" LEAVE_CODE "="LP"AND THEN"EXIT".". LOSS_OF_PAY_DAYS END OF LEAVE_DAYS") LEAVE WHERE PERIOD = 88 AND EMPLOYEE_CODE = EMP. EMPLOYEE_CODE) AS LOSS_OF_PAY_DAYS,
'PAID_DAYS', 'DIV '. "" ADDRESS2 "| " '||" """DIV"."" ADDRESS3"AS THE ADDRESS,
(SELECT PLATE OF)
SELECT A.EMPLOYEE_CODE, SUM (A.AMOUNT) AS AMOUNT OF PAYROLL A, B PAY_ELEMENT
WHERE A.PAY_ELEMENT_CODE = B.PAY_ELEMENT_CODE AND
A.PERIOD = 88 AND A.EMPLOYEE_CODE = EMP. EMPLOYEE_CODE AND B.PAY_ELEMENT_TYPE = 'E'
AND B.PAY_ELEMENT_CODE NOT IN ('FC')
A.EMPLOYEE_CODE GROUP
UNION
SELECT A.EMPLOYEE_CODE, AMOUNT OF FOOD_COUPON A, PAY_ELEMENT B
WHERE EMPLOYEE_CODE = EMP. EMPLOYEE_CODE
AND B.PAY_ELEMENT_CODE = A.PAY_ELEMENT_CODE
AND B.PAY_ELEMENT_TYPE = 'E'
AND PERIOD = 88) D
WHERE EMPLOYEE_CODE = EMP. EMPLOYEE_CODE) AS REMUNERATION.
(SELECT PLATE OF)
SELECT A.EMPLOYEE_CODE, SUM (A.AMOUNT) AS AMOUNT OF PAYROLL A, B PAY_ELEMENT
WHERE A.PAY_ELEMENT_CODE = B.PAY_ELEMENT_CODE AND
A.PERIOD = 88 AND A.EMPLOYEE_CODE = EMP. EMPLOYEE_CODE AND B.PAY_ELEMENT_TYPE = A '
AND B.PAY_ELEMENT_CODE NOT IN ('CDF')
A.EMPLOYEE_CODE GROUP
UNION
SELECT A.EMPLOYEE_CODE, AMOUNT OF FOOD_COUPON A, PAY_ELEMENT B
WHERE EMPLOYEE_CODE = EMP. EMPLOYEE_CODE
AND B.PAY_ELEMENT_CODE = A.PAY_ELEMENT_CODE
AND B.PAY_ELEMENT_TYPE = A '
AND PERIOD = 88) D
WHERE EMPLOYEE_CODE = EMP. EMPLOYEE_CODE) AS DEDUCTIONS.
NVL ((SELECT AMOUNT OF COMPENSATION WHERE PAY_ELEMENT_CODE = 'LICENSE' AND EMPLOYEE_CODE = EMP. (EMPLOYEE_CODE), 0) AS BASIC,.
NVL ((SÉLECTIONNEZ MONTANT PAYE WHERE PAY_ELEMENT_CODE = 'HRA' AND EMPLOYEE_CODE = EMP.)) (EMPLOYEE_CODE), 0) AS HRA,.
NVL ((SELECT AMOUNT OF COMPENSATION WHERE PAY_ELEMENT_CODE = 'SP2' AND EMPLOYEE_CODE = EMP. (EMPLOYEE_CODE), 0) AS SPECIALPAY2,
NVL ((SELECT NVL(AMOUNT,0) WHERE PAY_ELEMENT_CODE = 'OA' AND EMPLOYEE_CODE = EMP COMPENSATION. (EMPLOYEE_CODE), 0) AS OTHERALLOW,
NVL ((SELECT AMOUNT OF COMPENSATION WHERE PAY_ELEMENT_CODE = 'TA' AND EMPLOYEE_CODE = EMP. (EMPLOYEE_CODE), 0) AS TRANSALLOW,
NVL ((SELECT AMOUNT OF COMPENSATION WHERE PAY_ELEMENT_CODE = 'FC' AND EMPLOYEE_CODE = EMP. (EMPLOYEE_CODE), 0) AS FOODCOUPONS
"EMPLOYEE" "EMP",.
"DEPARTMENT" "DEPT"
'DIVISION', 'DIV ',.
'LOCATION' 'LOC ',.
"LEAVE_BALANCE" 'L ',.
'PAY. '
"PRESENCES", "A".
WHERE ("EMP". "" DEPARTMENT_CODE "="DEPT ". (' "DEPARTMENT_CODE") and
("EMP". "" DIVISION_CODE "="DEPT ". (' "DIVISION_CODE") and
("EMP". "" DIVISION_CODE "="DIV ". (' "DIVISION_CODE") and
("EMP". "" LOCATION_CODE "="LOC ". (' "LOCATION_CODE") and
("EMP". "' EMPLOYEE_CODE ' = 'L '. (' "EMPLOYEE_CODE") and
("DIV". "' DIVISION_CODE ' = 'L '. (' "DIVISION_CODE") and
( "L"." EMPLOYEE_CODE"="PAYROLL. " (' "EMPLOYEE_CODE") and
("PAYROLL". "' DIVISION_CODE ' = 'L '. (' "DIVISION_CODE") and
(("EMP". ("' CURRENT_STATUS ' = 'C') AND
("PAYROLL". ("" PAY_ELEMENT_CODE "="BSC") AND
("PAYROLL". ("' PERIOD ' = 88) AND
("EMP". ' EMPLOYEE_CODE '= 'A'. (' "EMPLOYEE_CODE") AND
("A"." PERIOD "(=88))"
/

The above query returs ranks in Standard edition but get the error in XE with the same table structure and data.

Kindly help me in this regard

Delphine K

I'm not sure if it works in normal 10.2 but as I see you have leave the comparison "employee_code = emp.employee_code" inside the view on the "D" line for where condition outside the view inline (lines 49 and 69 in the reformatted below statement):

SQL> get t1
  1  SELECT "EMP"."EMPLOYEE_CODE",
  2         "EMP"."NAME",
  3         "EMP"."BIRTH_DATE",
  4         "EMP"."FH_NAME",
  5         "EMP"."JOINING_DATE",
  6         "EMP"."DESIGNATION",
  7         "EMP"."PAN_NO",
  8         "DEPT"."DESCRIPTION",
  9         "EMP"."DIVISION_CODE",
 10         "DIV"."DESCRIPTION",
 11         "LOC"."DESCRIPTION",
 12         "EMP"."PF_NO",
 13         "EMP"."ESI_NO",
 14         "EMP"."CURRENT_STATUS",
 15         "L"."CL_BALANCE",
 16         "L"."EL_BALANCE",
 17         "L"."ML_BALANCE" ,
 18         "A"."ATTENDED_DAYS",
 19         "A"."PUBLIC_HOLIDAYS",
 20         "A"."WEEKLY_HOLIDAYS",
 21         (SELECT SUM(CASE WHEN "LEAVE"."LEAVE_CODE"='CL' THEN "LEAVE"."LEAVE_DAYS" END ) CASUAL_LEAVE
 22          FROM LEAVE WHERE PERIOD=88 AND EMPLOYEE_CODE=EMP.EMPLOYEE_CODE) AS CASUAL_LEAVE,
 23         (SELECT SUM(CASE WHEN "LEAVE"."LEAVE_CODE"='EL' THEN "LEAVE"."LEAVE_DAYS" END) EARNED_LEAVE
 24          FROM LEAVE WHERE PERIOD=88 AND EMPLOYEE_CODE=EMP.EMPLOYEE_CODE) AS EARNED_LEAVE,
 25         "SICK_LEAVE",
 26         "ON_DUTY",
 27         "ESI_LEAVE",
 28         (SELECT SUM(CASE WHEN "LEAVE"."LEAVE_CODE"='LP' THEN "LEAVE"."LEAVE_DAYS" END) LOSS_OF_PAY_DAYS
 29          FROM LEAVE WHERE PERIOD=88 AND EMPLOYEE_CODE=EMP.EMPLOYEE_CODE) AS LOSS_OF_PAY_DAYS,
 30         "PAID_DAYS",
 31         "DIV"."ADDRESS2"||' '||"DIV"."ADDRESS3" AS ADDRESS,
 32         (SELECT SUM(AMOUNT)
 33          FROM (SELECT A.EMPLOYEE_CODE, SUM(A.AMOUNT) AS AMOUNT
 34             FROM   PAYROLL A,
 35                 PAY_ELEMENT B
 36             WHERE  A.PAY_ELEMENT_CODE=B.PAY_ELEMENT_CODE
 37             AND       A.PERIOD= 88 AND B.PAY_ELEMENT_TYPE='E'
 38             AND       B.PAY_ELEMENT_CODE NOT IN('FC')
 39             GROUP BY A.EMPLOYEE_CODE
 40             UNION
 41             SELECT A.EMPLOYEE_CODE, AMOUNT
 42             FROM   FOOD_COUPON A,
 43                 PAY_ELEMENT B
 44             WHERE  B.PAY_ELEMENT_CODE=A.PAY_ELEMENT_CODE
 45             AND       B.PAY_ELEMENT_TYPE='E'
 46             AND       PERIOD=88
 47            )D
 48           WHERE EMPLOYEE_CODE=EMP.EMPLOYEE_CODE
 49           and   employee_code = emp.employee_code
 50          ) AS EARNINGS,
 51         (SELECT SUM(AMOUNT)
 52          FROM (SELECT A.EMPLOYEE_CODE, SUM(A.AMOUNT) AS AMOUNT
 53             FROM   PAYROLL A,
 54                 PAY_ELEMENT B
 55             WHERE  A.PAY_ELEMENT_CODE=B.PAY_ELEMENT_CODE
 56                AND    A.PERIOD= 88
 57             AND       B.PAY_ELEMENT_TYPE='D'
 58             AND       B.PAY_ELEMENT_CODE NOT IN('FCD')
 59             GROUP BY A.EMPLOYEE_CODE
 60             UNION
 61             SELECT A.EMPLOYEE_CODE, AMOUNT
 62             FROM   FOOD_COUPON A,
 63                 PAY_ELEMENT B
 64             WHERE  B.PAY_ELEMENT_CODE=A.PAY_ELEMENT_CODE
 65             AND       B.PAY_ELEMENT_TYPE='D'
 66             AND PERIOD=88
 67            )D
 68          WHERE EMPLOYEE_CODE=EMP.EMPLOYEE_CODE
 69          and   employee_code = emp.employee_code) AS DEDUCTIONS,
 70         NVL((SELECT AMOUNT
 71           FROM     PAY
 72           WHERE     PAY_ELEMENT_CODE='BSC'
 73           AND     EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS BASIC,
 74         NVL((SELECT AMOUNT
 75           FROM     PAY
 76           WHERE     PAY_ELEMENT_CODE='HRA'
 77           AND     EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS HRA,
 78         NVL((SELECT AMOUNT
 79           FROM     PAY
 80           WHERE     PAY_ELEMENT_CODE='SP2'
 81           AND     EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS SPECIALPAY2,
 82         NVL((SELECT NVL(AMOUNT,0)
 83           FROM     PAY
 84           WHERE     PAY_ELEMENT_CODE='OA'
 85           AND     EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS OTHERALLOW,
 86         NVL((SELECT AMOUNT
 87           FROM     PAY
 88           WHERE     PAY_ELEMENT_CODE='TA'
 89           AND     EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS TRANSALLOW,
 90         NVL((SELECT AMOUNT
 91           FROM     PAY
 92           WHERE     PAY_ELEMENT_CODE='FC'
 93           AND EMPLOYEE_CODE=EMP.EMPLOYEE_CODE),0)AS FOODCOUPONS
 94  FROM  "EMPLOYEE" "EMP",
 95        "DEPARTMENT" "DEPT",
 96        "DIVISION" "DIV",
 97        "LOCATION" "LOC",
 98        "LEAVE_BALANCE" "L",
 99        "PAYROLL" ,
100        "ATTENDANCE" "A"
101  WHERE ( "EMP"."DEPARTMENT_CODE" = "DEPT"."DEPARTMENT_CODE" ) and
102        ( "EMP"."DIVISION_CODE" = "DEPT"."DIVISION_CODE" ) and
103        ( "EMP"."DIVISION_CODE" = "DIV"."DIVISION_CODE" ) and
104        ( "EMP"."LOCATION_CODE" = "LOC"."LOCATION_CODE" ) and
105        ( "EMP"."EMPLOYEE_CODE" = "L"."EMPLOYEE_CODE" ) and
106        ( "DIV"."DIVISION_CODE" = "L"."DIVISION_CODE" ) and
107        ( "L"."EMPLOYEE_CODE" = "PAYROLL"."EMPLOYEE_CODE" ) and
108        ( "PAYROLL"."DIVISION_CODE" = "L"."DIVISION_CODE" ) and
109        ( ( "EMP"."CURRENT_STATUS" = 'C' ) AND
110          ( "PAYROLL"."PAY_ELEMENT_CODE" = 'BSC' ) AND
111          ( "PAYROLL"."PERIOD" = 88) AND
112          ("EMP"."EMPLOYEE_CODE"="A"."EMPLOYEE_CODE") AND
113          ("A"."PERIOD"=88)
114*        )
115  /

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