Query to find data of each month

Hello

I have 2 tables.

(1) Order_tb

Name Null? Type
----------------------------------------- -------- ----------------------------

ORDERID NOT NULL NUMBER
NUMBER OF CUSTOMERID
ORDERDATE DATE

(2) Order_d

Name Null? Type
----------------------------------------- -------- ----------------------------

ORDERID NUMBER
PRODUCTID NOT NULL NUMBER
PRODUCTNAME VARCHAR2 (20)
NUMBER OF SELLINGPRICE

I need to find the total find the selling price for each month of the year 2012 (orderdate) total.

I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.

Thank you

Published by: RSD on February 28, 2013 09:18

Hello

RSD wrote:
I tried to use join, but I couldn't take the 2012 in particular data. Please help me on this issue.

The WHERE clause below, is what limits the results for 2012.

SELECT       TRUNC (t.orderdate, 'MONTH')     AS month
,       SUM (d.sellingprice)          AS total_sellingprice
FROM       order_tb  t
JOIN       order_d   d  ON  d.orderid  = t.orderid
WHERE       t.orderdate  >= DATE '2012-01-01'
AND       t.orderdate  <  DATE '2013-01-01'
GROUP BY  TRUNC (t.orderdate, 'MONTH')
ORDER BY  TRUNC (t.orderdate, 'MONTH')
;

I hope that answers your question.
If not, post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
Simplify the problem. For example, pretend you're only interested in the first 3 or 4 months of 2012; We will find a solution tht can easily be adapted for 12 (or any other number) of motnhs.
Explain, using specific examples, how you get these results from these data.
Always say what version of Oracle you are using (for example, 11.2.0.2.0).
See the FAQ forum {message identifier: = 9360002}

Tags: Database

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case when rownum=4 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as apr_month,
case when rownum=5 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as may_month,
case when rownum=6 then last_day(to_date(add_months(trunc(to_date('01-01-2014','DD-MM-YYYY'), 'YYYY'), level - 1), 'DD-MM-YY')) end as jun_month,
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max(case  when rownum=12 then last_day(to_date(to_char(rownum),'MM')) end) as dec_month
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    This query works fine if I'm trying to update regular days from MONDAY to SUNDAY.  What I would do is to determine if the two dates of setting, V_DATE_OUT & V_DATE_IN would fall under none of the holidays on the first table LOAD_PROFILE_TEST, and then update the lines only.  For example, V_DATE_OUT = 12/02/2013, Monday and V_DATE_IN = 06/12/2013, Friday.  The query above would update the values of the LOAD_PROF2 for PROFILE_DAY - MONDAY to FRIDAY, corresponding to the dates of 02/12/2013 and on 06/12/2013.  If, however, V_DATE_OUT = 23/12/2013, Monday and V_DATE_IN = 27/12/2013, Friday, it should update the lines corresponding to PROFILE_DAY - MONDAY 23/12/2013, THURSDAY for 26/12/2013, FRIDAY for 12 27, 2013, and REGULAR_HOLIDAY for the dates of 12 24, 2013 and 25/12/2013 since these two appear in the first table (table of holidays).  This scenario works the same way when V_DATE_OUT and/or V_DATE_IN enter the dates of 28/03/2013 and 29/03/2013.  All other dates not included in the table for special leave will be treated according to the day they fall on (from Monday to Sunday).  I hope my point is clear.  Thank you in advance.

    arms777 wrote:

    I have already given a test for the table,

    Frank pleased to display:

    "examples of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from this data."

    I do not see the second statement in the create table and insert statements. Do you expect to write us your data ourselfs?

    However I'll try it from scratch

    merge into LOAD_PROFILE_TEST t

    a_l'_aide_de)
    Select distinct
    Decode (var_date, null, theday, profile_day) profile_day
    BeO
    Select
    SUPERIOR (to_char (: V_DATE_OUT + (level 1), 'fmDAY')) theday
    ,: V_DATE_OUT + subsist (level 1)
    of the double
    connect by level<= :v_date_in="" -="" :v_date_out ="" +="">
    )
    REG_HOLIDAYS
    where
    subsist = var_date (+)

    ) g
    on (UPPER (t.PROFILE_DAY) = g.profile_day
    )
    When matched then update
    SET LOAD_PROF2 = LOAD_PROF1 +: LOAD_DIFF

    Post edited by: chris227
    Fixed: added update

  • date min for each month of list

    Hi all

    I need to select only minimal date for each month in this example query:
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select date '2011-01-05' as adate from dual union all 
select date '2011-01-06' as adate from dual union all 
select date '2011-02-01' as adate from dual union all 
select date '2011-02-02' as adate from dual union all 
select date '2011-02-03' as adate from dual union all 
select date '2011-10-03' as adate from dual union all 
select date '2011-10-04' as adate from dual union all 
select date '2011-10-05' as adate from dual
    If the result should be:
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01.02.2011
03.10.2011
    How can I make it? 
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     AS (SELECT DATE '2011-01-04' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-01-05' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-01-06' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-02-01' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-02-02' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-02-03' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-10-03' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-10-04' AS adate FROM DUAL
         UNION ALL
         SELECT DATE '2011-10-05' AS adate FROM DUAL)
SELECT TO_CHAR (MIN (adate), 'DD.MM.YYYY') adate
  FROM dates
  GROUP BY to_char(adate, 'YYYY.MM')

ADATE
--------------------
03.10.2011
01.02.2011
04.01.2011

  • Query or logic to find several days through each month.

    Dear friends,

    I need your help to solve this problem.

    We have a now where we have to pay compensation to the employees based on their number of working days.

    Say, for example, if an employee has worked since March 3, 2012-April 5, 2012.

    We have a fixed value for a month 300 dirhams. But the number of days on s March 31 and number of days in the month of April are 30.

    So by compensation daily for March day would be 300/31 and April would be 300/30.

    We are looking for a logical opr query that calcluates first right number of days in each month (per month) and then calculate as below

    Number of working days in the month of March is 31-3 + 1 = 29

    Compensation of A1 = (300 * 29) / 31

    Number of working days in the month of April is 5 (must also find logical I guess)
    Allowance for A2 = (300 * 5) / 30

    Then A1 + A2.

    (E) would be the total quota when the number of months in all.

    Please guys any help would be greatly appricated.

    R

    Just a follow-up ;-)

    Note that you can almost get what you want with standard MONTHS_BETWEEN function [url http://docs.oracle.com/cd/E11882_01/server.112/e26088/functions102.htm#i78039].
    But notice this quote from the documentation:

    >
    If date1 and date2 are the same days of the month or the last two days of the month, the result is always an integer. Otherwise the Oracle database calculates the fractional part of the result based on a month of 31 days and consider the time difference components date1 and date2.
    >

    It will always use one even if 31 days a month has fewer days.

    Then you could also implement the logic of my previous answer as your own function months_between implementation:

    create or replace function my_months_between (
   p_todate    date
 , p_fromdate  date
)
   return number
is
begin
   return ((extract(day from last_day(p_fromdate))-extract(day from p_fromdate)+1) / extract(day from last_day(p_fromdate)))
        + (months_between(trunc(p_todate-1,'MM'),trunc(p_fromdate,'MM'))-1)
        + (extract(day from p_todate-1) / extract(day from last_day(p_todate-1)));
end my_months_between;
/

    I changed it to make it "compatible" with the standard function that it calculates up to but not including the parameter to date (which is correct when you are considering dates with time included, but I guess in your case, you have just date values.)

    Then, you can compare the results of the standard months_between with the new my_months_between:
    (Note that I have call the functions with the d2 + 1 to give the desired result of inclusion and to this day in the calculation).

    SQL> with testdata as (
  2     select date '2012-03-03' as d1, date '2012-04-05' as d2 from dual union all
  3     select date '2012-02-03' as d1, date '2012-05-02' as d2 from dual union all
  4     select date '2012-03-03' as d1, date '2012-03-10' as d2 from dual union all
  5     select date '2012-03-01' as d1, date '2012-07-31' as d2 from dual union all
  6     select date '2012-02-01' as d1, date '2012-03-01' as d2 from dual union all
  7     select date '2012-01-01' as d1, date '2012-03-25' as d2 from dual
  8  )
  9  --
 10  -- end of test data --
 11  --
 12  select months_between(d2+1, d1) std_months
 13       , 300 * months_between(d2+1, d1) std_allowance
 14       , my_months_between(d2+1, d1) my_months
 15       , 300 * my_months_between(d2+1, d1) my_allowance
 16    from testdata
 17  /

STD_MONTHS STD_ALLOWANCE  MY_MONTHS MY_ALLOWANCE
---------- ------------- ---------- ------------
1.09677419    329.032258 1.10215054   330.645161
         3           900 2.99555061   898.665184
.258064516    77.4193548 .258064516   77.4193548
         5          1500          5         1500
1.03225806    309.677419 1.03225806   309.677419
2.80645161    841.935484 2.80645161   841.935484

6 rows selected.

    For a large part of the data, both give the same result, especially when the two dates are in month of 31 days.
    To work from ' 2012-03-03' to '' 2012-04-05 standard service gives too little because it uses always 31 days, while my_months_between uses 30 days of April.

    "But note working from '' 2012-02-03 to 2012 - 05 - 02. He jumped 2 days in February and has worked 2 days in May - the standard function concludes he works precisely 3 months.
    But my_months_between computes fraction 27/29 months in February, then March and April like 2 months, and then the fraction 2/31 months in May - which gives a total of 2.99555061 instead of 3 months.

    Just something to be aware of ;-)

  • Need to query to find missing months between two dates.

    A bank customer a monthly overview of databases (in the tens of millions of accounts)

    The data are sent with a line per account each month.  It is stored in a table called "ACCOUNTS_TAB".

    Fields on registration, which

    Column

    Description

    Example of format.

    * YRMTH-1

    Year and month of the snapshot

    6-character numeric, 4-digit year added to months of 2 digits, example 201301, 201311

    * AccountID

    Unique identifier for an account.

    Integer, example 100098322

    Opening balance - 1

    Initial account balance at the closing of the previous month

    $30000

    Closing balance - 1

    The account balance at the end of the month of closing

    $34200

    Class-1 relative to investments

    .....

    ...

    .....

    ......

    .....

    Many more columns, two favorites (*) columns are alone, that you will need for the query. There are no columns to tell when an account is closed, or has just opened, and not separate "master account" - you use this single table for your query that results.

    The table was in place from 200301, so many accounts have dozens of lines, if they have been open for many years and other only 1 or 2 ranks, if new.

    Write a query to give just a list of accountDs that meet the following criteria.

    1. 1) has a record for specific 201503
    2. 2) was also a record for the month specific 201602
    3. 3) missing one or several months between these two records.

    A good account which was opened from 201503 to 201602 inclusive would of course have lines for

    201503

    201504

    201505

    201506

    201507

    201508

    201509

    201510

    201511

    201512

    201601

    201602

    It's good to hardcode the month of departure (201503), end of month (201602) and the actual number of months between them (10 exclusive or 12 inclusive) as part of your query.

    Once again the account must meet all 3 criteria to be an account issue.  If only, they have a partial set of these documents but do not have the month of departure, or is not the end of the month, it is not a problem, only when they have so specified and end early and not a full between game.


    Help, please!

    Maybe this...

    -----

    -The Dataset for the test begins

    WITH dataset (ACCOUNT_NO, DATES)

    AS (SELECT 100, DOUBLE 201503

    UNION ALL

    SELECT 100, DOUBLE 201504

    UNION ALL

    SELECT 100, DOUBLE 201505

    UNION ALL

    SELECT 100, DOUBLE 201506

    UNION ALL

    SELECT 100, DOUBLE 201507

    UNION ALL

    SELECT 100, DOUBLE 201508

    UNION ALL

    SELECT 100, 201509 OF THE DOUBLE

    UNION ALL

    SELECT 100, DOUBLE 201510

    UNION ALL

    SELECT 100, 201511 OF THE DOUBLE

    UNION ALL

    SELECT 100, DOUBLE 201512

    UNION ALL

    SELECT 100, 201601 DOUBLE

    UNION ALL

    SELECT 100, DOUBLE 201602

    UNION ALL

    SELECT 200, DOUBLE 201503

    UNION ALL

    SELECT 200, DOUBLE 201504

    UNION ALL

    SELECT 200, DOUBLE 201505

    UNION ALL

    SELECT 200, DOUBLE 201506

    UNION ALL

    SELECT 200, DOUBLE 201508

    UNION ALL

    SELECT 200, DOUBLE 201509

    UNION ALL

    SELECT 200, DOUBLE 201510

    UNION ALL

    SELECT 200, DOUBLE 201511

    UNION ALL

    SELECT 200, DOUBLE 201512

    UNION ALL

    SELECT 200, 201601 DOUBLE

    UNION ALL

    SELECT 200, DOUBLE 201602

    UNION ALL

    SELECT 300, DOUBLE 201503

    UNION ALL

    SELECT 300, DOUBLE 201504

    UNION ALL

    SELECT 300, DOUBLE 201505

    UNION ALL

    SELECT 300, DOUBLE 201506

    UNION ALL

    SELECT 300, DOUBLE 201507

    UNION ALL

    SELECT 300, DOUBLE 201508

    UNION ALL

    SELECT 300, DOUBLE 201509

    UNION ALL

    SELECT 300, DOUBLE 201510

    UNION ALL

    SELECT 300, DOUBLE 201511

    UNION ALL

    SELECT 300, 201601 DOUBLE

    UNION ALL

    SELECT 300, DOUBLE 201602

    UNION ALL

    SELECT 400, DOUBLE 201504

    UNION ALL

    SELECT 400, DOUBLE 201505

    UNION ALL

    SELECT 400, DOUBLE 201506

    UNION ALL

    SELECT 400, DOUBLE 201507

    UNION ALL

    SELECT 400, 201508 DOUBLE),

    -The Dataset to test ends

    -Hand with clause begins

    ResultSet

    AS (SELECT account_no,

    CASE

    WHEN COUNT)

    CASE WHEN dates IN (201503, 201602) THEN 1 END)

    COURSES (PARTITION BY account_no) = 2

    AND (COUNT (DISTINCT SUBSTR (dates, 4)))

    COURSES (PARTITION BY account_no) = 12

    OR COUNT (DISTINCT SUBSTR (dates, 4))

    COURSES (PARTITION BY account_no)<>

    AND COUNT (DISTINCT SUBSTR (dates, 1, 4))

    (PARTITION BY account_no) > 1

    THEN

    « Y »

    ON THE OTHER

    « N »

    END

    FLG

    THE dataset---> replace with your table name

    GROUP BY account_no, dates)

    SELECT DISTINCT Account_no

    FROM THE result set

    WHERE flg = 'Y ';

    -Hand with the ends of the clause

    ACCOUNT_NO

    -----------------------

    100

    300

    200

    See you soon,.

    Manik.

  • Find the 2nd Sunday of each month in a report

    Hello

    I have the data of EMP_Name and Join_Date. I have to build a dashboard report where

    1. In the dashboard, there is a command prompt. If I select a year and a month then, the report is expected to show that the data of the respective month.
    2. This report will show the employees who joined the company only after the 2nd Sunday of each month until the end of the month.

    Inputs/suggestions, how to build it?

    Thanks in advance.

    You have a question, Yes... a SQL query... OBIEE do not mean SQL but LSQL, your query will be not really usable like this...

    You're right, it seems that when the first day of the month is a Saturday he jump 1 week...

    The correct formula for the 3rd Friday is:

    TIMESTAMPADD (SQL_TSI_DAY, (14 + 6-CASE WHEN DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE)) = 7 THEN 0 END ELSE DAYOFWEEK (TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))), TIMESTAMPADD (SQL_TSI_DAY, 1-DAYOFMONTH (CURRENT_DATE), CURRENT_DATE))

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  • How to find the first Sunday and the second Saturday of each month

    Hi all

    How to find the first Sunday and the second Saturday of each month

    Thank you

    Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production

    994122 wrote:

    Hello

    I need to pass the months parameter how to do this? like Jan, Feb etc... (one of those)

    Do you have a procedure?

    Should you output only for the months you passed in the parameter?

    The easiest way is to set the parameter as date. When you go such as p_date as DATE ' 2014-10-01', then you can

    PROCEDURE two_dates)

    p_date IN DATE

    p_first_sunday DATE

    p_second_saturday DATE

    )

    IS

    BEGIN

    p_first_sunday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-12', 'DAY'));

    p_second_saturday: = NEXT_DAY (TRUNC (p_date, 'MM') - 1, TO_CHAR (DATE ' 2014-10-11', 'DAY')) + 7;

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  • How to get the second Monday of each month in a given date range?

    In Oracle forms, how to get the second Monday of each month in a given date range?

    I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

    WITH month_range AS

    (

    SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

    , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

    OF the double

    )

    SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

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    )

    , 'MONDAY '.

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    ;

    Thanks in advance.

    Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

    SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

    THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

    Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

    END AS second_day

    FROM (SELECT SYSDATE startdate,

    SYSDATE + 300 enddate

    THE DOUBLE)

    CONNECT BY LEVEL<=>

  • start date for each week of the month

    Dear members

    How can I find double, the start date of each week of the month in a year.
    beginning of the week is the word "Monday".


    year month week day date
    ----------------------------------------------------------------------------------------
    Monday, January 3, 2011 JAN 1, 2011
    2011 2 JAN Monday, January 10, 2011
    Monday, January 17, 2011 January 3, 2011
    JAN 4 2011 on Monday, January 24, 2011
    2011 to January 5 Monday, January 31, 2011


    Thank you

    teefu

    Hello

    You can use this:

    with t as  (select to_date ('01/01/2011', 'DD/MM/YYYY') start_date from dual)
select  date_calc
from (
        select  start_date,
                (level-1)*7+trunc (start_date , 'D')+1   as date_calc
        from t
        connect by level <=53)
where trunc(date_calc,'YYYY')=trunc(start_date,'YYYY') ;

    Kind regards
    Sylvie

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