Need to query to find missing months between two dates.

Similar Questions

• Need help on the list of months between two Dates

  Hi all
  
  I have a table which has startdate and enddate and need a select to list all the months between these two dates for each given ID.
  I did some tests and could not figure out how to get the startdate and enddate table (instead of hard coding) tests in the select statement.
  
  Could someone please help on this (Oracle 11 g 2),
  Thanks in advance!
  
  
  

  create table testing(
  id          number,
  start_date  date,
  end_date    date);
  insert into testing values(100, to_date('05-FEB-2011', 'DD-MON-YYYY'), to_date('28-MAY-2011', 'DD-MON-YYYY'));
  insert into testing values(200, to_date('20-JUN-2011', 'DD-MON-YYYY'), to_date('28-DEC-2011', 'DD-MON-YYYY'));
  commit;
  
  select * from testing;
  
          ID START_DAT END_DATE
  ---------- --------- ---------
         100 05-FEB-11 28-MAY-11
         200 20-JUN-11 28-DEC-11
  
  Elapsed: 00:00:00.01
  
  *for testing.id = 100:*
  select to_char(add_months(to_date('05-FEB-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
   from (select level l
         from dual
      connect by level <= months_between(trunc(to_date('28-MAY-2011', 'DD-MON-YYYY'), 'MONTH'),
                                         trunc(to_date('05-FEB-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
  
  DATES
  -----------------
  2011-Feb
  2011-Mar
  2011-Apr
  2011-May
  
  Elapsed: 00:00:00.01
  
  *for testing.id = 200:*
  select to_char(add_months(to_date('20-JUN-2011', 'DD-MON-YYYY'), l - 1), 'YYYY-Mon') Dates
   from (select level l
         from dual
      connect by level <= months_between(trunc(to_date('28-DEC-2011', 'DD-MON-YYYY'), 'MONTH'),
                                         trunc(to_date('20-JUN-2011', 'DD-MON-YYYY'), 'MONTH')) + 1);
  
  DATES
  -----------------
  2011-Jun
  2011-Jul
  2011-Aug
  2011-Sep
  2011-Oct
  2011-Nov
  2011-Dec
  
  7 rows selected.

  SQL> select * from testing
    2  /
  
          ID START_DAT END_DATE
  ---------- --------- ---------
         100 05-FEB-11 28-MAY-11
         200 20-JUN-11 28-DEC-11
  
  SQL> select  id,
    2          to_char(add_months(start_date,column_value - 1),'YYYY-Mon') dates
    3    from  testing,
    4          table(
    5                cast(
    6                     multiset(
    7                              select  level
    8                                from  dual
    9                                connect by add_months(trunc(start_date,'MM'),level - 1) <= end_date
   10                             )
   11                     as sys.OdciNumberList
   12                    )
   13               )
   14    order by id,
   15             column_value
   16  /
  
          ID DATES
  ---------- --------
         100 2011-Feb
         100 2011-Mar
         100 2011-Apr
         100 2011-May
         200 2011-Jun
         200 2011-Jul
         200 2011-Aug
         200 2011-Sep
         200 2011-Oct
         200 2011-Nov
         200 2011-Dec
  
  11 rows selected.
  
  SQL> 
  

  SY.

• get all the date of end of months between two dates

  Hi all, I'll try to find together the date of end of months between two dates.
  I have the following data in a table
  
  WITH AS's Data1
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, "TEST2" lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, "TEST3" lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, "TEST4" lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, "TEST5" lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, "TEST6" lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual
  
  )
  
  I would like to write an application that gives you all the end date for months between two dates
  for example, if you give the date 9/1/4 and 5/6/9, the output should be
  

  DT          LNAME
  -------------------
  4/30/2009   TEST

  IF I give you the dates 01/04/09 AND 01/06/09, THEN output should be

  DT          LNAME
  -------------------
  4/30/2009   TEST
  5/31/2009   TEST7

  as you can see, I want all the end dates of months between two dates by giving the output.
  
  If I give you 06/05/09 and 05/06/09, and then does so no output because there is no end of month between these two dates.
  Similarly, if I give you 30/04/09 and 30/04/09 then output should be 30/04/09 because it is an end of month date
  
  anyone can help to write a query. Thank you very much

  Jin
  Not sure if you need subquery, analytical functions for this.
  According to me, which should solve your purpose.

  WITH data1 AS
  (
  SELECT To_Date('4/30/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual UNION ALL
  SELECT To_Date('5/01/2009','mm/dd/yyyy') dt, 'TEST2' lname FROM dual UNION all
  SELECT To_Date('5/02/2009','mm/dd/yyyy') dt, 'TEST3' lname FROM dual UNION all
  SELECT To_Date('5/03/2009','mm/dd/yyyy') dt, 'TEST4' lname FROM dual UNION all
  SELECT To_Date('5/04/2009','mm/dd/yyyy') dt, 'TEST5' lname FROM dual UNION all
  SELECT To_Date('5/05/2009','mm/dd/yyyy') dt, 'TEST6' lname FROM dual UNION ALL
  SELECT To_Date('5/31/2009','mm/dd/yyyy') dt, 'TEST7' lname FROM dual UNION all
  SELECT To_Date('6/01/2009','mm/dd/yyyy') dt, 'TEST' lname FROM dual 
  
  )
  select distinct last_day(dt) dt,lname
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
  

  also, i have another request. how would i do this without using the data i provided. lets say,
   i tell you, give me alll the months end between two dates using dual in the from clause of a query.
  how would you do this in a query or pl/sql? thanks again
  

  Can be like that

  with data1 as(
  select &start_date+level-1 dt from dual
  connect by level <= &end_date-&start_date+1)
  select distinct last_day(dt)
    from data1
   where dt between &start_date and &end_date
     and last_day(dt) <= &end_date
   order by last_day(dt)
  

  See you soon!
  Bobin

  Published by: Buga added query for updated the need

• Display the months between two dates

  Hello:
  I need all the months between two dates. I entered two dates as January 15, 2001 and 2011-mar-03. I want the result as below.
  
  JANUARY 15, 2011 - JANUARY 31, 2011
  February 1, 2011 - February 28, 2011
  MARCH 1, 2011 - MARCH 3, 2011
  
  I held this result of sql query in oracle. Could you please suggest me?
  Thanks in advance.
  Abhishek

  SELECT     GREATEST(st, ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1))) dt,
             LEAST(ed, LAST_DAY(ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1)))) ld
        FROM (SELECT DATE '2011-01-15' AS st, DATE '2011-03-03' AS ed
                FROM DUAL)
  CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(ed, 'MONTH'), TRUNC(st, 'MONTH')) + 1
    ORDER BY 1;
  
  DT                       LD
  ------------------------ ------------------------
  15.01.2011 00:00:00      31.01.2011 00:00:00
  01.02.2011 00:00:00      28.02.2011 00:00:00
  01.03.2011 00:00:00      03.03.2011 00:00:00
  

  HTH, Urs

• Months between two dates

  Hello

  I have two dates. start date and end date.

  I want to extract months between two dates

  months should be as

  JAN

  FEB

  MAR

  for example.

  Start - 1-jan-2014

  date of end - 31 - dec - 2014

  How can I do this?

  Thanks and greetings

  CORINE

  You should always use the function MONTHS_BETWEEN...

  for example

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5. Select to_char (add_months (start_date, rownum-1), 'My') by month
  6 t
  7 * connect by rownum<=>
  SQL > /.

  LUN
  ---
  Jan
  Feb
  Mar
  Apr
  May
  Jun
  Jul
  Aug
  Ms
  Oct
  Nov
  Dec

  12 selected lines.

  And if you want that they display, separated by commas...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
  2  --
  3 end of test data
  4  --
  5 Select listagg (to_char (add_months (start_date, rownum-1), 'My'), ',') group by month (order by rownum)
  6 t
  7 * connect by rownum<=>
  SQL > /.

  MONTH
  -----------------------------------------------------------------------------------------------------------------
  Jan, Feb, Mar, Apr, may, June, July, August, Sept, Oct, Nov, Dec

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• How to display each month between the date range

  I want a query that gives me the number of months between two dates given for example, if I going January 1, 2009 and April 1, 2009 then I should get on February 1, 2009 and March 1, 2009 in my trips
  
  Thank you very much

  Srix wrote:
  Thanks for the request

  It is not working do not when the effective date is differs from that in a year i.e start date January 1, 2009 and end date February 1, 2009, that it does not give u then required result

  I don't know what you mean? The dates are in the same year.

• Calculate business hours between two dates in a cursor

  Hello, its me again (?).
  
  Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

  with t (start_date
         ,end_date
         )
  as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                         to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
      from dual
     )
  , hrs (dt) as
    (select start_date
     from   t
     union all
     select dt +1/24/60
     from   hrs
     where  hrs.dt < (select end_date-1/24/60 from t)
    )
  select count(*)/60
  from hrs
  where to_char(dt,'dy') not in ('sat','sun')
  and  to_number(to_char(dt,'hh24')) not between 18 and 23
  and  to_number(to_char(dt,'hh24')) not between 0 and 8
  /

  The logic above, I'm up here:

  FOR c_record IN c_1 LOOP
  //For each record, check if the two dates meet the criteria and then raise the counters accordingly
  select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
  SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;
  
  IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE 
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END
      IF;
  
  IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
    vContOk :=vContOk + 0;
    vContBad := vContBad+1;
    vContOt   := vContOt+1;
  ELSE
    vContOk :=vContOk +1;
    vContBad := vContBad+0;
    vContOt   := vContOt+1;
  END IF;
  
  END LOOP;

  I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
  However, I can't find a way to use this connection even in this case
  
  Could you help me?
  Thank you!
  
  Greetings,
  NACEUR

  N wrote:
  I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

  CREATE OR REPLACE
    FUNCTION get_bus_minutes_between(
                                     p_start_date DATE,
                                     p_end_date DATE
                                    )
      RETURN NUMBER
      IS
          v_return NUMBER;
      BEGIN
          with t as (
                     select  case level
                               when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                               else trunc(p_start_date) + level - 15 / 24
                             end start_dt,
                             case connect_by_isleaf
                               when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                               else trunc(p_start_date) + level - 8 / 24
                             end end_dt
                       from  dual
                       connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                    )
          select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
            into  v_return
            from  t
            where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
          RETURN v_return;
  END;
  /
  

  For example:

  SQL> select get_bus_minutes_between(
    2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
    3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
    4                                ) work_minutes
    5    from dual
    6  /
  
  WORK_MINUTES
  ------------
           261
  
  SQL> 
  

  SY.

• Select the mountains between two dates

  Hi all
  How can I select all months between two dates. For example, if two dates are say 2008-05-25 and 2009-07-15, then I need following output
  
  May-2008
  June-2008
  July-2008
  August-2008
  September-2008
  October-2008
  November-2008
  December-2008
  January-2009
  February-2009
  March-2009
  April-2008
  May-2009
  -June 2009
  July-2009
  
  Thank you
  Sujnan

  Try this one

  SQL>  SELECT TO_CHAR(add_months(TRUNC(to_date('25/05/2008','DD/MM/YYYY'),'MM') ,(level-1)),'fmMonth-YYYY')
    2     FROM dual
    3    CONNECT BY level <= months_between(to_date('15/07/2009','DD/MM/YYYY'),to_date('25/05/2008','DD/MM/YYYY')) + 2;
  
  TO_CHAR(ADD_MO
  --------------
  May-2008
  June-2008
  July-2008
  August-2008
  September-2008
  October-2008
  November-2008
  December-2008
  January-2009
  February-2009
  March-2009
  
  TO_CHAR(ADD_MO
  --------------
  April-2009
  May-2009
  June-2009
  July-2009
  
  15 rows selected.
  
  SQL> 
  

• find the difference in days between two dates

  Hello world
  
  I'm trying to find out the difference in days between two dates and the execution of the query that I'm passing
  
  SELECT TO_char(sysdate, 'dd/mm/yyyy') - TO_char('15/11/2011', 'dd/mm/yyyy') DAYS FROM DUAL
  
  the error I get is
  
  ORA-01722: invalid number
  01722 00000 - "invalid number."
  * Cause:
  * Action:
  
  Could someone please help.
  
  Thanks in advance

  user10636796 wrote:
  Hello world

  Thanks a lot for all the replies. I am trying to apply it in a statement to my table like this

  SELECT trunc (sysdate) - TO_char (date_last_recommended, ' dd/mm/yyyy') DAYS OF recommendation;

  SELECT trunc (sysdate) - TRUNC (date_last_recommended) DAYS OF recommendation;

• Get the number of months between the dates.

  Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?

  876056 wrote:
  Hi I need to get the exact number of months between the dates. So if I'm Sysdate - to_date(31-JAN-2011) I should get something like 8.4 months. Months_between function doesn't quite give me what I need. Is it possible that I can do this?

  I don't see how you get 8.4 months. The counted months are February, March, April, may, June, July, August and, as of today, 9 and change the days of September. Unless I forgot the lessons of counting, I learned in kndergarten is 7 full months and a bit.

  Maybe you want something like:

  SQL> select months_between(Sysdate, to_date('01-JAN-2011', 'dd-mon-yyyy')) mb,
    2         (Sysdate - to_date('01-JAN-2011', 'dd-mon-yyyy'))/30 div30
    3  from dual;
  
          MB      DIV30
  ---------- ----------
  8.27800142 8.38726813
  

  If you get the form date a table, you can use trunc (date_column, 'mm') at the date of the first day of the month.

  John

• difference between two dates in the year/month/day in Obiee

  Hi gurus,

  I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.

  I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output

  SQL > select end_date, start_date,

  trunc (months_between (end_date, start_date) / 12) years.

  months of mod (trunc (months_between (end_date, start_date)), 12).

  End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days

  t

  Thanks in advance

  SK

  Search for this

  "TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

  or else

  To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

  Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

  Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

• How to calculate the number of days/weeks/months between 2 dates?

  Hello
  
  I would like to know how to calculate the number of days/weeks/months between 2 dates in OBIEE 11 g, for example, I have 26/05/2013 and 19/05/2013, then I want to get 7 days.
  
  Thank you!
  Jamie

  Hi Jamie,

  Through this links...

  http://www.bravesoft.com/blog/?p=682
  http://twobiee.blogspot.in/2012/01/working-with-date-differences.html

  Mark as correct it allows u...
  Thank you...