query to retrieve a next valid record

Similar Questions

• SQL query to retrieve a single record for each employee of the following table?

  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

• Query to retrieve the level 2 supervisors

  Hi all
  
  I use the following query to retrieve the people which is under the supervision of a given person_id... Is it possible to modify this query (see below) in order to get two levels of employees? something like:
  
  Supervisor 1
  Employee 1
  Employee 2
  Employee 3
  Supervisor 2
  Employee 4
  Employee 5
  Employee 6
  
  The query works if I pass the person_id 1 for example supervisor that I would get used 1 2 and 3. But if I pass an id of the person who, of higher hierarchy, I will just get supervisor 1 supervisor 2... And I need all the people (just two levels down)
  
  Select distinct *)
  Select distinct ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_assignments_x pax
  per_grade_definitions pgd
  per_people_x WP
  fnd_user fu
  per_all_people_f women's wear
  per_images pi
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where ppf.person_id = pax.person_id
  and trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  and pax.supervisor_id = papf.person_id
  and pi.parent_id (+) = ppf.person_id
  and pi.table_name (+) = "PER_PEOPLE_F".
  and pax.person_id = ppf.person_id
  and hla.location_id (+) = pax.location_id
  AND ppf.current_employee_flag = 'Y '.
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  UNION ALL
  Select ppf.first_name |' '|| PPF.last_name
  ppf.last_name
  fu.user_name
  fu.user_id
  ppf.person_id
  papf.person_id Manager
  pi.image_id
  initcap (hla.description) LOCATION
  pb.NAME pay_basis_name
  pax.grade_id
  haou.name
  employment_category
  ppos.date_start
  of per_people_x WP
  per_grade_definitions pgd
  fnd_user fu
  per_all_people_f women's wear
  HR_WORKING_PERSON_LISTS HWPL
  per_images pi
  per_assignments_x pax
  hr_locations_all hla
  per_pay_bases pb
  hr_all_organization_units haou
  per_periods_of_service OPP
  where
  trunc (sysdate) between papf.effective_start_date and papf.effective_end_date
  and fu.person_party_id = papf.party_id
  AND HWPL.owning_person_id = papf.person_id
  and hwpl.selected_person_id = ppf.person_id
  AND pi.parent_id (+) = ppf.person_id
  and ppf.current_employee_flag = 'Y '.
  and pax.person_id = ppf.person_id
  AND hla.location_id (+) = pax.location_id
  AND pb.pay_basis_id = pax.pay_basis_id
  AND haou.organization_id = pax.organization_id
  AND ppos.person_id = ppf.person_id
  AND pax.grade_id = pgd.grade_definition_id
  AND papf.person_id =: inPersonId
  ) order of last_name

  Hello Alejandro,

  You can play a little bit with one below with what you find most comfortable.

  / * multi level * /.
  Select the level
  assignment_number
  assignment_id
  Manager
  , (select full_name from per_people_x where person_id = pax.person_id)
  , sys_connect_by_path ((sélectionnez employee_number dans per_people_x où person_id = pax.person_id), '-->')
  of per_assignments_x pax
  where primary_flag = 'Y '.
  connect by prior person_id = Manager
  Start by person_id = 1523

  / * level 2 only * /.
  Select (select full_name from per_people_x where person_id = pax1.person_id)
  , (select full_name from per_people_x where person_id = pax2.person_id)
  of per_assignments_x pax1
  per_assignments_x pax2
  where pax1.supervisor_id = 1523
  and pax1.primary_flag = 'Y '.
  and pax1.person_id = pax2.supervisor_id
  and pax2.primary_flag = 'Y '.

• I need a query that selects the amount of records for each day of a table.

  I need a query that selects the amount of records for each day of a table.
  For example, the result would be:
  
  1 14 date
  Date 2-3
  
  etc.
  
  Any ideas?

  Sort:

  SELECT count ([IDCommentaire]), convert (varchar, dateAdded, 112)

  OF COMMENTSgroup by convert (varchar, dateAdded, 112)

• Query to retrieve the latest version

  Hello
  I am trying to create a query that retrieves the latetst of a product version. There are 2 tables I have mark from, we have the product number and we got the version - a varchar2 data type (60). Are versions A, B, c... etc. So, I want to give me a line for each product with its latest version of the application. It's the query I have so far
  
  
  SELECT A0. Prod_num, A0.version
  FROM (SELECT A0B. Prod_num, A0.version
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)) A0
  ranking by A0. Prod_num
  
  Returns duplicate versions and product lines.
  
  Thank you.

  Without seeing sample data...

  SELECT A0B. Prod_num,
  Max (a0.version)
  Of tb_1 A0, tb_2 A0B
  WHERE (A0.tb_1pk = A0B.tb_2pk)
  AO8.prod_num GROUP;

• Query to retrieve the number of transactions in every 1 hour for the end

  Hello
  
  Could someone help to write a query to retrieve the number of transactions in every hour for the last month.
  
  Case:
  I / P
  
  If Timestamp1
  1 01/01/2008 00:00:01
  CAS2 01/01/2008 00:01:01
  case3 01/01/2008 01:00:01
  1 01/01/2008 01:02:01
  case4 01/01/2008 01:10:01
  Service5 01/02/2008 02:00:01
  Case6 01/02/2008 02:10:01
  case7 2008-02-01 23:00:01
  .............................
  
  .............................
  case... 2008-01-31 00:24:00
  
  
  O/P
  cases of to_time of time
  2008-01-01 00:00:00 01/01/2008 01:00 2
  2008-01-01 01:00:01 01/01/2008 02:00 3
  
  .........................
  .........................
  
  etc.
  
  Any help really appreciated

  We can do this by using analytic functions

  Here's what I did:

  create table timestamp1 (date of ts)

  Select * from timestamp1
  2008-10-30 15:41:13
  2008-10-30 15:41:05
  2008-10-30 15:40:03
  2008-10-30 14:58:26
  2008-10-30 14:29:45
  2008-10-30 13:17:48
  2008-10-30 08:29:50
  2008-10-30 06:05:51
  2008-10-30 03:41:52
  2008-10-30 02:29:54

  Select distinct to_char (ts, 'hh24') frmhrs,
  TO_CHAR (ts, 'hh24') + 1 tohrs, count (ts) OVER (order by to_number (to_char (ts, 'hh24')) RANK BEFORE (1/24))
  of timestamp1
  When trunc (ts) = trunc (sysdate) - I added this just to make sure that I get for data of today
  order of frmhrs

  FRMHRS TOHRS CNT
  1-3-02
  03-4-1
  06 7 1
  1-9-08
  13 14 1
  14 15 2
  15 16 3

  You can customizeas by your need.

• analytical query to select the next record

  Hi all
  I would like to ask the two table below correspond to the output.
  1.dev_wt 2.dev_map 3. output result
  
  To help more clearance, please see this image link: http://lh6.ggpht.com/_xL6eBqjW6Yo/TEqnSvlF_FI/AAAAAAAAB0U/i2sclnnaj6g/Untitled-3.jpg
  
  1 dev_wt

  PMS_COMP     PMS_I       PMS_PERF_D   PMS_WT   PMS_CREATION_D
  BBOARD     GICEQGROSS    04/01/2001     30     04/05/2001
  BBOARD     GICST_B       04/01/2001     5      04/05/2001
  BBOARD     SBGS_B        04/01/2001     65     04/05/2001
  
  BBOARD     GICEQGROSS    04/11/2001     30     04/15/2001
  BBOARD     GICST_B       04/11/2001     5      04/15/2001
  BBOARD     SBGS_B        04/11/2001     65     04/15/2001

  2 dev_map

  GS_CODE     GS_I_CODE    GS_I_ID  MD_ID   GS_START_DT    GS_END_DT
  GICEQGROSS   CIWL        304       15     01/04/1998     31/03/2004
  GICEQGROSS   CIWL        304       2     01/04/2004      31/03/9998
  GICST_B      GICST_B     3707      15     01/04/2000     31/12/9998
  SBGS_B       SBGS_B      2231      15     01/04/1992     30/09/2003
  SBGS_B       SBGS_B      564       15     01/10/2003     31/12/9998

  I would like to match PMS_I = GS_CODE to retrieve the GS_I_CODE and analytical assistance
  
  query to search for the next record.
  Because I need to select record GICEQGROSS PMS_PERF_D date and following
  GICEQGROSS save PMS_PERF_D of dev_wt table and put the result GS_WT_FR and GS_WT_TO output.
  
  The date is in the format YYYYMMDD
  PMS_WT is divided by 100
  
  * 3. Output result *.

  GS_I_ID    PMS_COMP     GS_I_CODE     GS_WT_FR     GS_WT_TO     GS_I_CALC
  304       BBOARD        CIWL          20010401     20010410     0.3
  3707      BBOARD        GICST_B       20010401     20010410     0.05
  5209      BBOARD        SBGS_B        20010401     20010410     0.65

  PMS_COMP is of dev_wt table
  GS_I_CODE is dev_map join of tables with dev_wt
  GS_WT_FR is dev_wt GS_START_DT table
  GS_WT_TO's dev_wt record table according GS_START_DT where PMS_I = 'GICEQGROSS. '
  
  Now my challenge is to select the next record in PMS_PERF_D using the query analysis. Below
  is my query...

  SELECT GS_I_ID, PMS_COMP, GS_I_CODE, GS_WT_FR, GS_WT_TO, GS_I_CALC
  FROM dev_wt (
   SELECT lead(PMS_PERF_D) over(partition by PMS_I order by PMS_PERF_D) as GS_WT_TO        
   FROM dev_wt where PMS_I ='GICEQGROSS')
  left join dev_map on PMS_I = GS_CODE ;

  Thank you
  
  Edited by: WinZone 24 July 2010 16:46
  
  Edited by: WinZone 24 July 2010 16:50

  Hello

  This should be good:

  SELECT DISTINCT t2.gs_i_id, pms_comp, t2.gs_i_code,
                  TO_CHAR
                     (MIN (pms_perf_d) OVER (PARTITION BY pms_comp, pms_i),
                      'yyyymmdd'
                     ) gs_wt_fr,
                  TO_CHAR
                     (MAX (pms_perf_d) OVER (PARTITION BY pms_comp, pms_i) - 1,
                      'yyyymmdd'
                     ) gs_wt_to,
                  pms_wt / 100 gs_i_calc
             FROM dev_wt t1, dev_map t2
            WHERE t2.gs_code = t1.pms_i
  

  REM note even as odie: should be "2231" instead...

• SQL query to retrieve the same record because no. boxes

  Hi all

  I have a table of Bill XXINV.

  the columns are

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  1123                XXITEM2                     2                   6

  I can do a sql query so that I can retrieve the same records repeated as number INVH_BOXES.

  Select * from XXINV

  where invh_no = 1122

  output:

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  Desired output:

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  1122                XXITEM1                    1                    5

  or

  INVH_NO INVH_ITEM_CODE INVH_QTY INVH_BOXES

  1122 XXITEM1 1 1 of 5

  1122 XXITEM1 1 2 of 5

  1122 1 3 5 XXITEM1

  1122 XXITEM1 1 4 of 5

  1122 XXITEM1 1 5 of 5

  Please suggest. Like I need to print each line in a single page to stick them on boxes so that packaging.

  Kind regards

  Afzal.

  Just add INVH_ITEM_CODE to the connection by the clause.

  Select invh_no

  invh_item_code

  invh_qty

  to_char (, 'fm99') | 'from ' | TO_CHAR (invh_boxes, 'fm99') invh_boxes

  of xxinv

  where invh_no = 1122

  connect

  by level<=>

  and prior invh_item_code = invh_item_code

  and prior sys_guid() is not null

• SQL Query to retrieve records for all after the Max Dates.

  Hello everyone,

  I am trying to retrieve the record more recent, based on the date field ( nextDate ).

  Currently, there are only 4 records in the MC_Maintenance table and two in the Machine table.

  Machine table

  MC_id             EquipID          

  1                      0227

  MC_id EquipID

  2                     0228

  ---------------------------------

  MC_Maintenance table

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010     

  2                      2                      07/01/2010

  3                      1                      2010-11-06

  4                      1                      07/11/2010

  I have am trying to accomplish is,.

  the list of the two machines of the table of the Machine with the MAX (Next_maint) control the list of MC_Maintenance results

  These are the records I want to display.

  Maint_id MC_id Next_maint

  1                      2                      08/25/2010

  4                      1                      07/11/2010                 

  Here is the SQL query

  SELECT

         MC. MC_ID as ID,

  MC.complete_Date completed.

  MC.next_maint as nextDate,.

  MC.maint_notes as noted,.

  MC.facility Facility.

  M.EquipId,.

  $m.name as the name.

  M.SerialNumber SN.

  M.dept as dept.

  M.Freq as freq

  Of MC_Maintenance MC, Machine M

          where  MC. MC_ID = M.MC_ID

  '           Using MAX (nextDate)

  Any ideas would be useful.

  TJ

  I thought it was a simple group of problem?

  SELECT M.EquipID, MC.MC_ID, Max(MC.next_maint)
  FROM MC_Maintenance MC INNER JOIN Machine M ON MC.MC_ID = M.MC_ID
  GROUP BY M.EquipID, MC.MC_ID
  

• Query to retrieve records that have more than one assignment_id

  Hello
  
  I'm writing a query to extract all records in the table per_all_assignments_f that has more than one different assignment_id for each person_id. Here's the query I wrote, it retrieves the records, even if a person_id assignment_id duplicate, but I need records that have more than one assignement_id without duplicate for each person_id
  
  Select assignment_id, person_id, assignment_id
  Of per_all_assignments_f
  Having count (assignment_id) > 1
  Person_id group, assignment_id
  
  Thank you.
  PK

  Maybe something like that?

  select *
  From   per_all_assignments_f f1
  where  exists (select 1
                 from   per_all_assignments_f f2
                 where  f2.person_id = f1.person_id
                 and    f2.assignment_id != f1.assignment_id
                );
  

  Published by: SomeoneElse on May 7, 2010 14:23

  (you can add a SEPARATE from the outer query if you wish)

• SQL Query to retrieve records in a table with the same records or only one record in a table

  Hello

  Got a curious requirment to extract the Non-distincts records in a table

  Example of

  Account number	Type of account
  12345	SB
  12345	SB
  12346	CR
  12346	SB
  12347	SB
  12348	CR
  12349	SB

  Requrirement is to retrieve the records as follows

  Result must be

  Account number	Type of account
  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

  You will notice that 12346 which has two separate lines have been eliminated in the result. I tried several qeries to achieve this result, one or the other had a few mismatch. Can someone give me a request for it.

  Thanks in advance.

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE

  DE)

  SELECT ACCOUNT_NUMBER,

  ACCOUNT_TYPE,

  COUNT (*) ON CNT_ACC (ACCOUNT_NUMBER PARTITION).

  COUNT (*) ON CNT_NUM_TYP (PARTITION ACCOUNT_NUMBER, ACCOUNT_TYPE)

  FROM T1)

  WHERE CNT_ACC = CNT_NUM_TYP;

  exit;

  12345	SB
  12345	SB
  12347	SB
  12348	CR
  12349	SB

• Query to retrieve 10 records of specimen of each type

  Hello
  I have a table that has a column named TYPE. This can have values such as B, F, I, U, etc. (may be more). I need a query that returns me records of 40 10 for each sample. the cases in the sample can be all lines at random.
  
  right now, I have 4 request for each TYPE and I do a UNION ALL operation for all queries. I get the result I need, but it will scan the 4 times table and does not have good performance wise.
  Select .match_type as move_type, na.new_address_flag as is_new_address, na
  na.address_line_1_orig, na.new_street_address, na.address_line_2_orig,
  na.new_address_line2, na.apt_nbr_orig, na.new_apt_nbr, na.city_orig,
  na.new_city, na.state_orig, na.new_state, na.zip_code_orig, na.new_postal_code,
  na.zip_plus_4_orig, na.new_postal_plus_cd
  of ncoa_audit na
  When type = "B".
  and rownum < 11
  
  Can anyone please help on this.
  
  Thank you

  WITH is just one of the ways that we can generate sample data. I did it to illustrate that the query works as expected. This is known as "Subquery Factoring." See the documentation for more information.

  If you want specimen for all types of remove the list, in the WHERE clause. The query will then return for all types.

  HTH!

• Need to retrieve the last line/record in a table

  Hello
  
  I have a requirement like getting the ending balance of the last record in the table and the same insertion in the opening balance of the immediatetly created the next record.
  
  In simple terms, I need to extract a value from the last line of the recording.
  
  For example, I use the query below
  
  Select rownum emp, empno, ename
  where rownum = (select count (rownum) from emp);
  
  But, the above query does not return all of the recording.
  
  Therefore, need help on this.
  
  Kind regards
  Shivakumar has
  
  Published by: shiva March 27, 2011 22:14

  Hello
  Strictly speaking there is no such LAST or FIRST folder until that order you them.
  But check the following:

  SELECT * FROM emp MINUS
  SELECT * FROM emp WHERE rownum<=(SELECT count(empno)-1 FROM emp);
  

  Kind regards
  Lakshmi.

• Query to retrieve lines from database

  Hello
  
  I have a strange question "my oracle database contains approximately 4000 records. As it is not desirable to extract all lines at once. Is it possible for me to recover the 100 lines in a page and then the next hundred, and then the next... Not sure if we can write a PL/SQL command for this or we need to change the database to display these options. Can anyone suggest on this please?

  Hello

  This is called a Query of paging , and here's a way to do it:

  WITH     got_r_num     AS
  (
       SELECT     x.*     -- or whatever columns you need
       ,     ROW_NUMBER () OVER (ORDER BY u_key)     AS r_num
       FROM     table_x
  --     WHERE     ...     -- If you need any filtering, put it here
  )
  SELECT       *     -- or list all columns except r_num
  FROM       got_r_num
  WHERE       TRUNC (r_num / 100)     = :page_number
  ORDER BY  r_num
  ;
  

  U_key, that's what unique key determines the order. It can be a single column, or a list separated by commas of phrases, as in an ORDER BY clause. For EXAMPLE:

  ...     ,     ROW_NUMBER () OVER ( ORDER BY       UPPER (last_name)
                           ,          UPPER (first_name)
                           ,          created_date     DESC
                         )     AS r_num
  

• next n records interfaces

  am having a problem with my records next_n interface.
  
  I have a request for my index page when you click on a letter appropriate artists are displayed...
  See here
  
  http://www.musicexplained.co.uk/index.cfm
  
  the query depends on an url variable.
  
  < name cfquery = 'results' datasource = '#APPLICATION. DataSource #">"
  SELECT *.
  Of artist_art
  WHERE the bandname_art as '#url.firstletter#% '.
  < / cfquery >
  
  I am now creating a UI records next, so you can easily navigate through the artists that begin with one example, this interface is also dependent on a variable to URL... < cfset startrownext >
  However, when I click on the next button, see here
  http://www.musicexplained.co.UK/index_list_1.cfm?FirstLetter=a
  I lose the variable that feeds the index in the first place...
  
  is it all still around that?
  
  concerning
  
  
  

  Put the top of index_list_1.cfm:
  
  
  
  

  Then all your pagination links, also include the parameter firstletter again:
  
  
  First
  Next
  etc, etc.