Query to see the name of the table and the name of the column...

Hi Experts,

I have an Oracle DB, I have more than 50 tables and 100,000 records. I want to get the name of the table of the record that contains "ITxtVarValue made reference to a non-existent text" text.

Is there any simple query it to find the table name and the column name for this particular file reside?

Help, please. Any help will be rewarded.

Thank you
G

Tags: Database

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Hi Oracle Experts,
I have a difficult question . Lets say that I have two table with the same name, but these two tables come from two different databases with 2 different users.
A source database and the user SCOTT
Table Column Data_Type Length PRECISION Scale Primary key Nullable Default Comment
BOOKS BOOK_ID Varchar2 4 - - 1 - - -
ISBN_10 Varchar2
13
---Yes--PRICENumber-62-Yes--
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BOOKS BOOK_ID Varchar2 20 - - 1 - - -
PRICE Number - 6 2 - Yes - -
TITLE Varchar2 50 - - - Yes - -
What I want to do:
I want to get a query script that shows which columns need to edit, add and drop depends on the source table (make the necessary changes to make the columns in the Source table columns the same target table). No need to make any changes in the database do not want the query that must run to make these changes.
EXAMPLE: I was using under query to get the query create table EMP. But seeing the column information to create the column even for the other user is difficult:)
Select dbms_metadata.get_ddl ('TABLE', 'EMP') of double

Erhan_toronto wrote:

Is it possible to see the result like this:

ALTER table Target_table change BOOK_ID Varchar2 (4);

ALTER table Target_table add ISBN_10 Varchar2 (13), null;

ALTER table drop TITLE Target_table;

There are two simple ways to do so.

1. use free sql Oracle development tools

http://www.Oracle.com/technetwork/developer-tools/SQL-Developer/downloads/index.html

Simply select 'Tools - Diff of the database' and go through the menus

Here is an article from Oracle by Jeff Smith that shows how do

http://www.Oracle.com/technetwork/issue-archive/2012/12-Sep/o52sqldev-1735911.html

>

Quickly copy, compare and synchronize databases with Oracle SQL Developer.

>

2 use the DBMS_METADATA_DIFF package - see the commercial doc

http://docs.Oracle.com/CD/E11882_01/server.112/e22490/metadata_api.htm#BABIDHGE

>

Using the DBMS_METADATA_DIFF API to compare the metadata of the object

>

If you look at step 14 of this article, you will see the result of the use of COMPARE_ALTER:

>

14. compare the results by using the navigation API DBMS_METADATA_DIFF:

SQL > SELECT dbms_metadata_diff.compare_alter ('TABLE', 'TAB1', 'TAB2') FROM dual;
ALTER TABLE 'SCOTT '. "' TAB1 ' ADD ("MGR"NUMBER (4,0))
ALTER TABLE 'SCOTT '. "' TAB1 ' DROP ("JOB")
ALTER TABLE 'SCOTT '. "' TAB1 ' CHANGE ('ENAME' VARCHAR2 (20))
ALTER TABLE 'SCOTT '. "' TAB1 ' ADD A KEY ('EMPNO') PRIMARY AID INDEX
PCTFREE, INITRANS 10 2 STORAGE (INITIAL 16384 MINEXTENTS THEN 16384 1)
MAXEXTENTS 505 PCTINCREASE 50 FREELISTS 1 FREELIST GROUPS 1 USER_TABLES
(VALEUR PAR DÉFAUT) ACTIVATE ALTER TABLE "SCOTT" TAB1"AND RENAME"TAB2 ".

1 selected line.

>

How to list the columns for a view

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But my problem is how to issue a query that returns the columns for a view?
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USER_TAB_COLUMNS stores the metadata for both views.

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Select the request match the columns diagonally
Hello

Here are the instructions struncture and table insert
```
create table emp_trans values (empno number , emptran_no number, prev_amount number, current_amount number)

insert into emp_trans values(102,109,0,20);
insert into emp_trans values(102,119,10,20);
insert into emp_trans values(102,129,20,30);
insert into emp_trans values(102,139,30,0);

insert into emp_trans  values(201,101,0,20);
insert into emp_trans values(201,110,20,30);
insert into emp_trans values(201,120,0,30);
insert into emp_trans values(201,130,30,20);
insert into emp_trans values(201,140,0,20);
```
In the chart, we see some mappings as follows

Data based empno.
We have 2 employees with empno 201 and 102. Each empno has different emptrans_no. Are not necessarily in a sequence.
We have to select the Recordset where prev_amount column matches the values in column current_amount for
the previous record for each individual empno.

until the next basic select statement can be considered
```
select * from emp_trans  order by empno , emptran_no
```
for ex:

the column values of prev_amount of emptran_no 129 EMP No 102 with values of 20 matches with the column of current_amount have 20
with emptran_no 119.

empno 201 with emptran_no 110, we can see the column of prev_amount having the value put 20 mapped to havig 20 current_account column values
of emptran_no previous 101 for the same 201 empno.

something like we need to see the values of mathced diagonally.

Any help on this request, most welcome.

Kind regards
Hello
Sri says:
Hello

Here are the instructions struncture and table insert
```
create table emp_trans values (empno number , emptran_no number, prev_amount number, current_amount number) ...
```
Thanks for posting the CREATE TABLE and INSERT. Please test 9and, if necessary, correct) them before posting. You do not want the word 'values' above.

In the chart, we see some mappings as follows

Data based empno.
We have 2 employees with empno 201 and 102. Each empno has different emptrans_no. Are not necessarily in a sequence.
We have to select the Recordset where prev_amount column matches the values in column current_amount for
the previous record for each individual empno.

Means "the previous record? Is the line with the same empno and the next emptran_no below? The combination (empno, emptran_no) is unique?
>
until the next basic select statement can be considered
```
select * from emp_trans  order by empno , emptran_no
```
for ex:

the column values of prev_amount of emptran_no 129 EMP No 102 with values of 20 matches with the column of current_amount have 20
with emptran_no 119.

empno 201 with emptran_no 110, we can see the column of prev_amount having the value put 20 mapped to havig 20 current_account column values
of emptran_no previous 101 for the same 201 empno.

something like we need to see the values of mathced diagonally.

Any help on this request, most welcome.

Kind regards
Always show the desired results from the given sample data. It is fine to describe the results, but describe them after (not instead of) displaying.
Is that what you want?
```
`    EMPNO EMPTRAN_NO PREV_AMOUNT CURRENT_AMOUNT
---------- ---------- ----------- --------------
       102        129          20             30
       102        139          30              0
       201        110          20             30
       201        130          30             20
```
Here's a way to get these results:
```
WITH   got_prev_current_amount     AS
(
     SELECT     empno, emptran_no, prev_amount, current_amount
     ,     LAG (current_amount) OVER ( PARTITION BY  empno
                                      ORDER BY         emptran_no
                           )        AS prev_current_amount
     FROM    emp_trans
)
SELECT       empno, emptran_no, prev_amount, current_amount
FROM       got_prev_current_amount
WHERE       prev_amount     = prev_current_amount
ORDER BY  empno, emptran_no
;
```

Change the order of the columns does not cause any data found error report
Hello. I have a weird problem (and I'm new to APEX). I have a subregion of report that shows the details of a master record based on the ID of the parent area. When I have everything first to change SQL for the query and apply the changes page works fine. When I go back and change the region > attributes report and use the arrows to change the order of the columns the region then returns:

error report:
ORA-01403: no data found

I tried to change the query so that the columns found in the desired order and who has also not returned no data error. If I go back to my original query (which had 2 fewer columns) the page works again. Then I change to the new query (2 addtl columns), and then it works again, until I have change the order of the columns again. Don't know if it would be serious or not, but one of the columns is a 2 columns of the table concat.

Any ideas would be appreciated, because I'm out of them.

Thank you!

use: Apex 4.0
DB: 10g Exp
"807428," Hi

using 4.0 or 4.0.1? Can you reproduce the same problem on apex.oracle.com as well?

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-----------
My Blog: http://www.inside-oracle-apex.com
APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
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User ColumnSetContainer for the width of the columns preferences

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I want to set the width of the column columnsetContainers (datagrid) at run time and save it.
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Thanks for the confirmation.

Table	Column	Data_Type	Length	PRECISION	Scale	Primary key	Nullable	Default	Comment
BOOKS	BOOK_ID	Varchar2	4	-	-	1	-	-	-
	ISBN_10	Varchar2	13

Table	Column	Data_Type	Length	PRECISION	Scale	Primary key	Nullable	Default	Comment
BOOKS	BOOK_ID	Varchar2	20	-	-	1	-	-	-
	PRICE	Number	-	6	2	-	Yes	-	-
	TITLE	Varchar2	50	-	-	-	Yes	-	-

Creating a unique index frame on a one-to-many table and search

Hello

I was properly put in place of the full text index on multiple columns on the same table (using the MULTI_COLUMN_DATASTORE preferences), but now I have a situation with a table of one-to-many data collection (with a CF of a lookup table), and I need to get columns through two of these tables. Code example below, several of my chatter after the code block:

CREATE TABLE SUBMISSION
( SUBMISSION_ID             NUMBER(10)          NOT NULL,
  SUBMISSION_NAME           VARCHAR2(100)       NOT NULL
);
 
CREATE TABLE ADVISOR_TYPE
( ADVISOR_TYPE_ID           NUMBER(10)          NOT NULL,
  ADVISOR_TYPE_NAME         VARCHAR2(50)        NOT NULL
);
  
CREATE TABLE SUBMISSION_ADVISORS
( SUBMISSION_ADVISORS_ID    NUMBER(10)          NOT NULL,
  SUBMISSION_ID             NUMBER(10)          NOT NULL,
  ADVISOR_TYPE_ID           NUMBER(10)          NOT NULL,
  FIRST_NAME                VARCHAR(50)         NULL,
  LAST_NAME                 VARCHAR(50)         NULL,
  SUFFIX                    VARCHAR(20)         NULL
);

INSERT INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME) VALUES (1, 'Some Research Paper');
INSERT INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME) VALUES (2, 'Thesis on 17th Century Weather Patterns');
INSERT INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME) VALUES (3, 'Statistical Analysis on Sunny Days in March');

INSERT INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME) VALUES (1, 'Department Chair');
INSERT INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME) VALUES (2, 'Department Co-Chair');
INSERT INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME) VALUES (3, 'Professor');
INSERT INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME) VALUES (4, 'Associate Professor');
INSERT INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME) VALUES (5, 'Scientist');

INSERT INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX) VALUES (1,1,2,'John', 'Doe', 'PhD');
INSERT INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX) VALUES (2,1,2,'Jane', 'Doe', 'PhD');
INSERT INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX) VALUES (3,2,3,'Johan', 'Smith', NULL);
INSERT INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX) VALUES (4,2,4,'Magnus', 'Jackson', 'MS');
INSERT INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX) VALUES (5,3,5,'Williard', 'Forsberg', 'AMS');
 
COMMIT;

I want to be able to create a text index to group these fields:

SUBMISSION_ADVISORS. FIRST NAME
SUBMISSION_ADVISORS. LAST_NAME
SUBMISSION_ADVISORS. SUFFIX
ADVISOR_TYPE. ADVISOR_TYPE_NAME

I looked at DETAIL_DATASTORE and USER_DATASTORE, but examples of Oracle Docs for DETAIL_DATASTORE leave me a little confused. It seems that this should be fairly simple.

Ideally, I try to avoid creating new columns and keeping a minimum shutter adjustments. But I'm open to any suggestion. Thanks for your time and your thoughts.

-Jamie

I would create a procedure that creates a virtual with labels document, what is the multi_column_datatstore behind the scenes. Then I would like to use this procedure in a user_datastore, so the result is the same for several tables as a multi_column_datastore for a table. I would use auto_section_group or another type of Group of sections, so that you can search from WITHIN as with the multi_column_datastore. Please see the demo below.

SCOTT@orcl_11gR2> -- tables and data that you provided:
SCOTT@orcl_11gR2> CREATE TABLE SUBMISSION
  2  ( SUBMISSION_ID           NUMBER(10)          NOT NULL,
  3    SUBMISSION_NAME           VARCHAR2(100)          NOT NULL
  4  )
  5  /

Table created.

SCOTT@orcl_11gR2> CREATE TABLE ADVISOR_TYPE
  2  ( ADVISOR_TYPE_ID           NUMBER(10)          NOT NULL,
  3    ADVISOR_TYPE_NAME      VARCHAR2(50)          NOT NULL
  4  )
  5  /

Table created.

SCOTT@orcl_11gR2> CREATE TABLE SUBMISSION_ADVISORS
  2  ( SUBMISSION_ADVISORS_ID      NUMBER(10)          NOT NULL,
  3    SUBMISSION_ID           NUMBER(10)          NOT NULL,
  4    ADVISOR_TYPE_ID           NUMBER(10)          NOT NULL,
  5    FIRST_NAME           VARCHAR(50)          NULL,
  6    LAST_NAME           VARCHAR(50)          NULL,
  7    SUFFIX                VARCHAR(20)          NULL
  8  )
  9  /

Table created.

SCOTT@orcl_11gR2> INSERT ALL
  2  INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME)
  3    VALUES (1, 'Some Research Paper')
  4  INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME)
  5    VALUES (2, 'Thesis on 17th Century Weather Patterns')
  6  INTO SUBMISSION (SUBMISSION_ID, SUBMISSION_NAME)
  7    VALUES (3, 'Statistical Analysis on Sunny Days in March')
  8  SELECT * FROM DUAL
  9  /

3 rows created.

SCOTT@orcl_11gR2> INSERT ALL
  2  INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME)
  3    VALUES (1, 'Department Chair')
  4  INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME)
  5    VALUES (2, 'Department Co-Chair')
  6  INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME)
  7    VALUES (3, 'Professor')
  8  INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME)
  9    VALUES (4, 'Associate Professor')
 10  INTO ADVISOR_TYPE (ADVISOR_TYPE_ID, ADVISOR_TYPE_NAME)
 11    VALUES (5, 'Scientist')
 12  SELECT * FROM DUAL
 13  /

5 rows created.

SCOTT@orcl_11gR2> INSERT ALL
  2  INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX)
  3    VALUES (1,1,2,'John', 'Doe', 'PhD')
  4  INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX)
  5    VALUES (2,1,2,'Jane', 'Doe', 'PhD')
  6  INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX)
  7    VALUES (3,2,3,'Johan', 'Smith', NULL)
  8  INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX)
  9    VALUES (4,2,4,'Magnus', 'Jackson', 'MS')
 10  INTO SUBMISSION_ADVISORS (SUBMISSION_ADVISORS_ID, SUBMISSION_ID, ADVISOR_TYPE_ID, FIRST_NAME, LAST_NAME, SUFFIX)
 11    VALUES (5,3,5,'Williard', 'Forsberg', 'AMS')
 12  SELECT * FROM DUAL
 13  /

5 rows created.

SCOTT@orcl_11gR2> -- constraints presumed based on your description:
SCOTT@orcl_11gR2> ALTER TABLE submission ADD CONSTRAINT submission_id_pk
  2    PRIMARY KEY (submission_id)
  3  /

Table altered.

SCOTT@orcl_11gR2> ALTER TABLE advisor_type ADD CONSTRAINT advisor_type_id_pk
  2    PRIMARY KEY (advisor_type_id)
  3  /

Table altered.

SCOTT@orcl_11gR2> ALTER TABLE submission_advisors ADD CONSTRAINT submission_advisors_id_pk
  2    PRIMARY KEY (submission_advisors_id)
  3  /

Table altered.

SCOTT@orcl_11gR2> ALTER TABLE submission_advisors ADD CONSTRAINT submission_id_fk
  2    FOREIGN KEY (submission_id) REFERENCES submission (submission_id)
  3  /

Table altered.

SCOTT@orcl_11gR2> ALTER TABLE submission_advisors ADD CONSTRAINT advisor_type_id_fk
  2    FOREIGN KEY (advisor_type_id) REFERENCES advisor_type (advisor_type_id)
  3  /

Table altered.

SCOTT@orcl_11gR2> -- resulting data:
SCOTT@orcl_11gR2> COLUMN submission_name FORMAT A45
SCOTT@orcl_11gR2> COLUMN advisor      FORMAT A40
SCOTT@orcl_11gR2> SELECT s.submission_name,
  2           a.advisor_type_name || ' ' ||
  3           sa.first_name || ' ' ||
  4           sa.last_name || ' ' ||
  5           sa.suffix AS advisor
  6  FROM   submission_advisors sa,
  7           submission s,
  8           advisor_type a
  9  WHERE  sa.advisor_type_id = a.advisor_type_id
 10  AND    sa.submission_id = s.submission_id
 11  /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Some Research Paper                           Department Co-Chair John Doe PhD
Some Research Paper                           Department Co-Chair Jane Doe PhD
Thesis on 17th Century Weather Patterns       Professor Johan Smith
Thesis on 17th Century Weather Patterns       Associate Professor Magnus Jackson MS
Statistical Analysis on Sunny Days in March   Scientist Williard Forsberg AMS

5 rows selected.

SCOTT@orcl_11gR2> -- procedure to create virtual documents:
SCOTT@orcl_11gR2> CREATE OR REPLACE PROCEDURE submission_advisors_proc
  2    (p_rowid IN           ROWID,
  3       p_clob     IN OUT NOCOPY CLOB)
  4  AS
  5  BEGIN
  6    FOR r1 IN
  7        (SELECT *
  8         FROM      submission_advisors
  9         WHERE  ROWID = p_rowid)
 10    LOOP
 11        IF r1.first_name IS NOT NULL THEN
 12          DBMS_LOB.WRITEAPPEND (p_clob, 12, '');
 13          DBMS_LOB.WRITEAPPEND (p_clob, LENGTH (r1.first_name), r1.first_name);
 14          DBMS_LOB.WRITEAPPEND (p_clob, 13, '');
 15        END IF;
 16        IF r1.last_name IS NOT NULL THEN
 17          DBMS_LOB.WRITEAPPEND (p_clob, 11, '');
 18          DBMS_LOB.WRITEAPPEND (p_clob, LENGTH (r1.last_name), r1.last_name);
 19          DBMS_LOB.WRITEAPPEND (p_clob, 12, '');
 20        END IF;
 21        IF r1.suffix IS NOT NULL THEN
 22          DBMS_LOB.WRITEAPPEND (p_clob, 8, '');
 23          DBMS_LOB.WRITEAPPEND (p_clob, LENGTH (r1.suffix), r1.suffix);
 24          DBMS_LOB.WRITEAPPEND (p_clob, 9, '');
 25        END IF;
 26        FOR r2 IN
 27          (SELECT *
 28           FROM   submission
 29           WHERE  submission_id = r1.submission_id)
 30        LOOP
 31          DBMS_LOB.WRITEAPPEND (p_clob, 17, '');
 32          DBMS_LOB.WRITEAPPEND (p_clob, LENGTH (r2.submission_name), r2.submission_name);
 33          DBMS_LOB.WRITEAPPEND (p_clob, 18, '');
 34        END LOOP;
 35        FOR r3 IN
 36          (SELECT *
 37           FROM   advisor_type
 38           WHERE  advisor_type_id = r1.advisor_type_id)
 39        LOOP
 40          DBMS_LOB.WRITEAPPEND (p_clob, 19, '');
 41          DBMS_LOB.WRITEAPPEND (p_clob, LENGTH (r3.advisor_type_name), r3.advisor_type_name);
 42          DBMS_LOB.WRITEAPPEND (p_clob, 20, '');
 43        END LOOP;
 44    END LOOP;
 45  END submission_advisors_proc;
 46  /

Procedure created.

SCOTT@orcl_11gR2> SHOW ERRORS
No errors.
SCOTT@orcl_11gR2> -- examples of virtual documents that procedure creates:
SCOTT@orcl_11gR2> DECLARE
  2    v_clob  CLOB := EMPTY_CLOB();
  3  BEGIN
  4    FOR r IN
  5        (SELECT ROWID rid FROM submission_advisors)
  6    LOOP
  7        DBMS_LOB.CREATETEMPORARY (v_clob, TRUE);
  8        submission_advisors_proc (r.rid, v_clob);
  9        DBMS_OUTPUT.PUT_LINE (v_clob);
 10        DBMS_LOB.FREETEMPORARY (v_clob);
 11    END LOOP;
 12  END;
 13  /
JohnDoePhDSome
Research PaperDepartment Co-Chair
JaneDoePhDSome
Research PaperDepartment Co-Chair
JohanSmithThesis on 17th Century
Weather PatternsProfessor
MagnusJacksonMSThe
sis on 17th Century Weather PatternsAssociate
Professor
WilliardForsbergAMS


Statistical Analysis on Sunny Days in
MarchScientist

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> -- user_datastore that uses procedure:
SCOTT@orcl_11gR2> BEGIN
  2    CTX_DDL.CREATE_PREFERENCE ('sa_datastore', 'USER_DATASTORE');
  3    CTX_DDL.SET_ATTRIBUTE ('sa_datastore', 'PROCEDURE', 'submission_advisors_proc');
  4  END;
  5  /

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> -- index (on optional extra column) that uses user_datastore and section group:
SCOTT@orcl_11gR2> ALTER TABLE submission_advisors ADD (any_column VARCHAR2(1))
  2  /

Table altered.

SCOTT@orcl_11gR2> CREATE INDEX submission_advisors_idx
  2  ON submission_advisors (any_column)
  3  INDEXTYPE IS CTXSYS.CONTEXT
  4  PARAMETERS
  5    ('DATASTORE     sa_datastore
  6        SECTION GROUP     CTXSYS.AUTO_SECTION_GROUP')
  7  /

Index created.

SCOTT@orcl_11gR2> -- what is tokenized, indexed, and searchable:
SCOTT@orcl_11gR2> SELECT token_text FROM dr$submission_advisors_idx$i
  2  /

TOKEN_TEXT
----------------------------------------------------------------
17TH
ADVISOR_TYPE_NAME
AMS
ANALYSIS
ASSOCIATE
CENTURY
CHAIR
CO
DAYS
DEPARTMENT
DOE
FIRST_NAME
FORSBERG
JACKSON
JANE
JOHAN
JOHN
LAST_NAME
MAGNUS
MARCH
PAPER
PATTERNS
PHD
PROFESSOR
RESEARCH
SCIENTIST
SMITH
STATISTICAL
SUBMISSION_NAME
SUFFIX
SUNNY
THESIS
WEATHER
WILLIARD

34 rows selected.

SCOTT@orcl_11gR2> -- sample searches across all data:
SCOTT@orcl_11gR2> VARIABLE search_string VARCHAR2(100)
SCOTT@orcl_11gR2> EXEC :search_string := 'professor'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> SELECT s.submission_name,
  2           a.advisor_type_name || ' ' ||
  3           sa.first_name || ' ' ||
  4           sa.last_name || ' ' ||
  5           sa.suffix AS advisor
  6  FROM   submission_advisors sa,
  7           submission s,
  8           advisor_type a
  9  WHERE  CONTAINS (sa.any_column, :search_string) > 0
 10  AND    sa.advisor_type_id = a.advisor_type_id
 11  AND    sa.submission_id = s.submission_id
 12  /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Thesis on 17th Century Weather Patterns       Professor Johan Smith
Thesis on 17th Century Weather Patterns       Associate Professor Magnus Jackson MS

2 rows selected.

SCOTT@orcl_11gR2> EXEC :search_string := 'doe'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Some Research Paper                           Department Co-Chair John Doe PhD
Some Research Paper                           Department Co-Chair Jane Doe PhD

2 rows selected.

SCOTT@orcl_11gR2> EXEC :search_string := 'paper'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Some Research Paper                           Department Co-Chair John Doe PhD
Some Research Paper                           Department Co-Chair Jane Doe PhD

2 rows selected.

SCOTT@orcl_11gR2> -- sample searches within specific columns:
SCOTT@orcl_11gR2> EXEC :search_string := 'chair'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> SELECT s.submission_name,
  2           a.advisor_type_name || ' ' ||
  3           sa.first_name || ' ' ||
  4           sa.last_name || ' ' ||
  5           sa.suffix AS advisor
  6  FROM   submission_advisors sa,
  7           submission s,
  8           advisor_type a
  9  WHERE  CONTAINS (sa.any_column, :search_string || ' WITHIN advisor_type_name') > 0
 10  AND    sa.advisor_type_id = a.advisor_type_id
 11  AND    sa.submission_id = s.submission_id
 12  /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Some Research Paper                           Department Co-Chair John Doe PhD
Some Research Paper                           Department Co-Chair Jane Doe PhD

2 rows selected.

SCOTT@orcl_11gR2> EXEC :search_string := 'phd'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> SELECT s.submission_name,
  2           a.advisor_type_name || ' ' ||
  3           sa.first_name || ' ' ||
  4           sa.last_name || ' ' ||
  5           sa.suffix AS advisor
  6  FROM   submission_advisors sa,
  7           submission s,
  8           advisor_type a
  9  WHERE  CONTAINS (sa.any_column, :search_string || ' WITHIN suffix') > 0
 10  AND    sa.advisor_type_id = a.advisor_type_id
 11  AND    sa.submission_id = s.submission_id
 12  /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Some Research Paper                           Department Co-Chair John Doe PhD
Some Research Paper                           Department Co-Chair Jane Doe PhD

2 rows selected.

SCOTT@orcl_11gR2> EXEC :search_string := 'weather'

PL/SQL procedure successfully completed.

SCOTT@orcl_11gR2> SELECT s.submission_name,
  2           a.advisor_type_name || ' ' ||
  3           sa.first_name || ' ' ||
  4           sa.last_name || ' ' ||
  5           sa.suffix AS advisor
  6  FROM   submission_advisors sa,
  7           submission s,
  8           advisor_type a
  9  WHERE  CONTAINS (sa.any_column, :search_string || ' WITHIN submission_name') > 0
 10  AND    sa.advisor_type_id = a.advisor_type_id
 11  AND    sa.submission_id = s.submission_id
 12  /

SUBMISSION_NAME                               ADVISOR
--------------------------------------------- ----------------------------------------
Thesis on 17th Century Weather Patterns       Professor Johan Smith
Thesis on 17th Century Weather Patterns       Associate Professor Magnus Jackson MS

2 rows selected.

 
            
            
		     Name of the table to see the forecast in the backend SQL query 
			 Hello




Forecast is released on ASIC of Dematra,


I have the name of the table to see the forecast published in Demantra


How to confirm that the same forecasts are published in CPSA also


What is the name of Table to see forecasts, forecasts			 Data published in the CAWC Demantra forecasts will be stored in the following MSD_DP_SCN_ENTRIES_DENORM table
first get the scenario_id of the msd_dp_ascp_scenarios_v of table using scenario_id check if the forecast is filled in msd_dp_scn_entries_denorm
Published by: user11986840 on August 13, 2012 03:15
		    
            
            
		     How to see the lock on the table and query? 
			 Hi all
How do we see the lock on the table and query?




Thank you
Rafi			 Yes Rafi,
It works fine at my end... see below:
Opening of Session 1 with scott/tiger and:
setting a day emp set ename = 'xx' where empno = 7499;
Opening of Session 2 with scott/tiger and:
setting a day emp set ename = 'xx' where empno = 7499;

> This session is locked by a superior.

Open 3 Session with pw/sys as sysdba and:
SQL> set serveroutput on
SQL> BEGIN
  2  dbms_output.enable(1000000);
  3  for do_loop in (select session_id, a.object_id, xidsqn, oracle_username, b.owner owner,
  4  b.object_name object_name, b.object_type object_type
  5  FROM v$locked_object a, dba_objects b
  6  WHERE xidsqn != 0
  7  and b.object_id = a.object_id)
  8  loop
  9  dbms_output.put_line('.');
 10  dbms_output.put_line('Blocking Session : '||do_loop.session_id);
 11  dbms_output.put_line('Object (Owner/Name): '||do_loop.owner||'.'||do_loop.object_name);
 12  dbms_output.put_line('Object Type : '||do_loop.object_type);
 13  for next_loop in (select sid from v$lock
 14  where id2 = do_loop.xidsqn
 15  and sid != do_loop.session_id)
 16  LOOP
 17  dbms_output.put_line('Sessions being blocked : '||next_loop.sid);
 18  end loop;
 19  end loop;
 20  END;
 21  /
.
Blocking Session : 139
Object (Owner/Name): SCOTT.EMP
Object Type : TABLE
Sessions being blocked : 134

PL/SQL procedure successfully completed.

HTH
Girish Sharma

 
		 
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