question about group by function

Similar Questions

• A question about the analytical function used with the GROUP BY clause in SHORT

  Hi all
  
  I created the following table named myenterprise
  

  CITY       STOREID    MONTH_NAME TOTAL_SALES            
  ---------- ---------- ---------- ---------------------- 
  paris      id1        January    1000                   
  paris      id1        March      7000                   
  paris      id1        April      2000                   
  paris      id2        November   2000                   
  paris      id3        January    5000                   
  london     id4        Janaury    3000                   
  london     id4        August     6000                   
  london     id5        September  500                    
  london     id5        November   1000

  If I want to find which is the total sales by city? I'll run the following query

  SELECT city, SUM(total_sales) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  that works very well and produces the expected result, i.e.

  CITY       TOTAL_SALES_PER_CITY   
  ---------- ---------------------- 
  london     10500                  
  paris      17000            

  Now in one of my books SQL (Mastering Oracle SQL) I found another method by using the SUM, but this time as an analytic function. Here's what the method of the book suggests as an alternative to the problem:

  SELECT city, 
         SUM(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  I know that the analytic functions are executed after the GROUP BY clause has been transformed completely and Unlike regular aggregate functions, they return their result for each line belonging to the partitions specified in the partition clause (if there is a defined partition clause).
  
  Now my problem is that I do not understand what we have to use two functions SUM? If we only use one only, i.e.

  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY;

  This generates the following error:

  Error starting at line 2 in command:
  SELECT city, 
         SUM(total_sales) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
  FROM myenterprise
  GROUP BY city
  ORDER BY city, TOTAL_SALES_PER_CITY
  Error at Command Line:2 Column:11
  Error report:
  SQL Error: ORA-00979: not a GROUP BY expression
  00979. 00000 -  "not a GROUP BY expression"
  *Cause:    
  *Action:

  The error is generated for the line 2 column 11 which is, for the expression SUM (total_sales), well it's true that total_sales does not appear in the GROUP BY clause, but this should not be a problem, it has been used in an analytical function, so it is evaluated after the GROUP BY clause.
  
  So here's my question:
  
  Why use SUM (SUM (total_sales)) instead of SUM (total_sales)?
  
  
  Thanks in advance!
  :)
  
  
  
  
  
  In case you are interested, that's my definition of the table:

  DROP TABLE myenterprise;
  CREATE TABLE myenterprise(
  city VARCHAR2(10), 
  storeid VARCHAR2(10),
  month_name VARCHAR2(10),
  total_sales NUMBER);
  
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'January', 1000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'March', 7000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id1', 'April', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id2', 'November', 2000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('paris', 'id3', 'January', 5000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'Janaury', 3000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id4', 'August', 6000);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'September', 500);
  INSERT INTO myenterprise(city, storeid, month_name, total_sales)
    VALUES ('london', 'id5', 'November', 1000);

  Edited by: dariyoosh on April 9, 2009 04:51

  It is clear that thet Analytics is reduntant here...
  You can even use AVG or any analytic function...

  SQL> SELECT city,
    2         avg(SUM(total_sales)) OVER (PARTITION BY city) AS TOTAL_SALES_PER_CITY
    3  FROM myenterprise
    4  GROUP BY city
    5  ORDER BY city, TOTAL_SALES_PER_CITY;
  
  CITY       TOTAL_SALES_PER_CITY
  ---------- --------------------
  london                    10500
  paris                     17000
  

• Question about Group by

  Hello friends,
  
  I have a table called APPLICATIONS (INQUIRY_ID, CALLING_DATE, ASSIGN_TO_AGENT)
  
  I need to create a report to show the number of requests received by Agent as follows:
  

  Assign_to_agent , number_of_daily_inquiries, total_inquiries_number
  
  X               ,         4                 , 150
  Y               ,         8                 , 200
  ..........
  ....

  I used this query that does not work:
  

  select assign_to_agent   ,
   count (inquiry_id) , 
   (select count ( inquiry_id)   as "total_inquiries_number"
   from inquiries   where trunc ( calling_date,'DD' )= trunc ( sysdate, 'DD')  ) as "number_of_daily_inquiries"
  from inquiries  group by assign_to_agent

  I hope that my question was clear.
  
  Kind regards
  Water
  
  Published by: cold_water on 25 Sep 2012 10:23

  Hi cold_water,

  Maybe it is not necessary to query two times table. Something like

  select   i.assign_to_agent,
           count (
             case
               when trunc ( i.calling_date, 'DD') = trunc ( sysdate, 'DD') then
                 i.inquiry_id
             end ) as "number_of_daily_inquiries",
           count (i.inquiry_id) as "total_inquiries_number"
  from     inquiries i
  group by i.assign_to_agent;
  

  Concerning
  Peter

• Question about GROUP BY and HAVING

  Good afternoon
  
  I have the following query, which returns the desired result (a set of students who follow the CS112 or CS114 but not both). I wanted to 'condense' it in a single SELECT statement (if that's possible - DDL of execution of the instruction is provided at the end of this post):
  

  --
  -- is this select distinct * and its associated where clause absolutely
  -- necessary to obtain the result ?
  --
  
  select distinct *
    from (
          select s.sno,
                 s.sname,
                 s.age,
                 sum(case when t.cno in ('CS112', 'CS114')
                          then 1
                          else 0
                     end)
                   over (partition by s.sno) as takes_either_or_both
            from student s join take t
                             on (s.sno = t.sno)
         )
    where takes_either_or_both = 1
  ;

  The following text seemed reasonable, but unfortunately without success:
  

  /*
    Window functions not allowed here (in Having Clause)
  
  select max(s.sno),
         max(s.sname),
         max(s.age),
         sum(case when t.cno in ('CS112', 'CS114')
                  then 1
                  else 0
             end)
           over (partition by s.sno) as takes_either_or_both
    from student s join take t
                     on (s.sno = t.sno)
   group by s.sno
  having sum(case when t.cno in ('CS112', 'CS114')
                  then 1
                  else 0
             end)
           over (partition by s.sno) = 1
  ;
  
  */
  
  /*
  
  Invalid identifier in Having clause
  
  select s.sno,
         s.sname,
         s.age,
         sum(case when t.cno in ('CS112', 'CS114')
                  then 1
                  else 0
             end)
           over (partition by s.sno) as takes_either_or_both
    from student s join take t
                     on (s.sno = t.sno)
   group by s.sno, s.sname, s.age
  having takes_either_or_both = 1
  ;

  I tried a document that completely defines the order in which the clauses are executed. I found bits and pieces here and there but not complete something. I realize that my race with problems like this is due to my lack of understanding of the sequence and scope of the clauses that make a statement. For this reason, I can't even say if it is possible to write the query above using a single select statement. Forgive my little frustration...
  
  Thank you for your help,
  
  John.
  
  DDL follows.
  

          /* drop any preexisting tables */
  
          drop table student;
          drop table courses;
          drop table take;
  
          /* table of students */
  
          create table student
          ( sno integer,
            sname varchar(10),
            age integer
          );
  
          /* table of courses */
  
          create table courses
          ( cno varchar(5),
            title varchar(10),
            credits integer
          );
  
          /* table of students and the courses they take */
  
          create table take
          ( sno integer,
            cno varchar(5)
          );
  
          insert into student values (1,'AARON',20);
          insert into student values (2,'CHUCK',21);
          insert into student values (3,'DOUG',20);
          insert into student values (4,'MAGGIE',19);
          insert into student values (5,'STEVE',22);
          insert into student values (6,'JING',18);
          insert into student values (7,'BRIAN',21);
          insert into student values (8,'KAY',20);
          insert into student values (9,'GILLIAN',20);
          insert into student values (10,'CHAD',21);
  
          insert into courses values ('CS112','PHYSICS',4);
          insert into courses values ('CS113','CALCULUS',4);
          insert into courses values ('CS114','HISTORY',4);
  
          insert into take values (1,'CS112');
          insert into take values (1,'CS113');
          insert into take values (1,'CS114');
          insert into take values (2,'CS112');
          insert into take values (3,'CS112');
          insert into take values (3,'CS114');
          insert into take values (4,'CS112');
          insert into take values (4,'CS113');
          insert into take values (5,'CS113');
          insert into take values (6,'CS113');
          insert into take values (6,'CS114');

  Hi, John,.

  Just use the SUM aggregate function.

  --
          select s.sno,
                 s.sname,
                 s.age,
                 sum(case when t.cno in ('CS112', 'CS114')
                          then 1
                          else 0
                     end) as takes_either_or_both
            from student s join take t
                             on (s.sno = t.sno)
         GROUP BY  s.sno,
                  s.sname,
                s.age
         HAVING  sum(case when t.cno in ('CS112', 'CS114')
                          then 1
                          else 0
                     end)  = 1;
  

  Analytical functions are calculated after the WHERE - HAVING clause are applied. Use the results of an analytic function in a WHERE or HAVING clause, you need to calculate it in a subquery, and then you can use it in a WHERE - or the HAVING of a query clause Super.

• Question about GROUP BY and double aggregation for example MAX (AVG (val))

  Good evening/morning,
  
  I am struggling with what is probably a simple problem.
  
  The objective of the exercise is to display the highest average earnings and his Department (with the EMP table).
  
  Easy to get the maximum average wage:
  

  select max(avg(sal)) as max_avg_sal
    from emp
   group by deptno;

  I could not figure out how to change this query to get the deptno associated AVG. max. Gave up on changing this query and came to this:
  

  select deptno,
         avg_sal as max_avg_sal
    from (
          select deptno,
                 avg(sal) as avg_sal
            from emp
           group by deptno
           --
           -- order causes 1st row to have the max(avg(sal))
           -- this will be exploited in the where of the outer query
           --
           order by avg_sal desc                                             
         )
   --
   -- get only the first row since that one has the values we want
   --
   where rownum <= 1;

  This works, but feels pretty disappointing compared to the simplicity of the first query (which I couldn't the deptno on.) That is the request more simple with that I could come.
  
  The QUESTION is:
  
  The query above is really the way simpler and easier to get the maximum average and its associated department number? If it isn't, I'm more interested in your simplest solution. :)
  
  Could someone to laugh at one of the alternatives that I came up with a "simpler": solution
  

  with x as
    (
     select deptno,
            avg(sal) as avg_sal
       from emp
      group by deptno
    ),
    max_avg_sal as
    (
     select max(avg_sal)                  as asmax
       from x
    ),
    deptno_max as
    (
     select deptno                        as dnmax
       from x where avg_sal = (select asmax from max_avg_sal)
    )
  select (select asmax from max_avg_sal) as max_avg_sal,
         (select dnmax from deptno_max)  as deptno_max
    from dual;

  The road to hell is simple, it is paved from selects < chuckle >,.
  
  Thank you for helping,
  
  John.

  Hello
  Try this

  SELECT MAX(AVG(sal)) AS max_avg_sal,
         MAX(DEPTNO) KEEP (DENSE_RANK FIRST ORDER BY AVG(SAL) DESC )  DEPTNO
  FROM scott.emp
  GROUP BY deptno
  

  Kind regards
  Anthony Alix

• Question about grouping.

  Hello
  
  I have a problem with my data as I want, I have 2 tables: orders & Modifiedorders,.
  the Modifiedorders holds the orderid and some information on how the order is changed, sometimes orderid
  in the Modifiedorders table can repeat if the changed data are of different types, such as changing the quantity or the price...
  
  Now what I want is to make a report that displays data from the Orders table and when there is
  record (s) in the table modifiedorders that it should appear on the left, for example, but without repeating the orderid.
  
  What I tried creating a query of outerjoin between 2 tables and using the wizard I created a report with the style of left group and had Orderid as the grouping field, but again orderid. What should I do?
  
  Thanks in advance...

  What I tried creating a query of outerjoin between 2 tables and using the wizard I created a report with the style of left group and had Orderid as the grouping field, but again orderid. What should I do?

  You have made the right choice. Reuse the reports Wizard.

  What is your question?

• BB10 simulator: questions about the clock function

  I don't know, but I have the notion that under the Simulator for BB10 the clock() function returns a value of timer resolution of the host and not the right pair

  And since

  #define CLOCKS_PER_SEC 1000000

  during the conversion of the clock in seconds it will be least bad results under windows. Because Windows there

  #define CLOCKS_PER_SEC 1000

  I want to keep constant 60 FPS and I have a code like:

  const int FRAMES_PER_SECOND = 60;
  const int SKIP_TICKS = 1000 / FRAMES_PER_SECOND;

  int GetTickCount (void)
  {
  Return MathUtils::dti ((double) clock () / CLOCKS_PER_SEC);
  }

  and the game loop is:

  int t_prev = GetTickCount();

  mbGameRunning = true;
  While (mbGameRunning)
  {
  int t = GetTickCount();

  If ((t-t_prev) > SKIP_TICKS)
  Tick();

  Draw();

  EventLoop();

  t_prev = t;
  }

  Am I missing something?

  The clock() function only increments while your program is managed by the operating system. When the operating system switches to another task, "clock" your program stops running.

  You must use:

  clock_gettime(), which is the system clock that is still running.

• questions about group by weeks

  Hello experts

  I have data similar to what follows below

  create the table t_one

  (

  sale number (30),

  date of date_req,

  req_desc varchar (1000)

  )

  insert into t_one values (30, to_date (March 7, 2014, ' DD/MM/YYYY'), 'boston')

  insert into t_one values (to_date 40, (March 9, 2014, "MM/DD/YYYY '"), "New York")

  insert into t_one values (10, to_date (March 14, 2014, ' DD/MM/YYYY'), 'boston')

  insert into t_one values (to_date 20, (March 16, 2014, "MM/DD/YYYY '"), "New York")

  required output

  Week total_sales

  Week 1-70

  Week 2 30

  Please note, the first week will start at 07/03/2014 in the system, that is why it is week 1 and a week is from (Friday - Sunday). That is because the execution is either on Friday or Saturday or Sunday. I have problems with this because I can't think of a good way to group my weeks together.

  any help is appreciated.

  Thank you

  Hello

  Here's one way:

  WITH got_week_num AS

  (

  Req_desc sale, SELECT

  , FLOOR ((date_req-TO_DATE (7 mars 2014 ", «MM/DD/YYYY»)))

  / 7

  ) + 1 AS week_num

  FROM t_one

  )

  SELECT 'week ' | week_num WEEK

  SUM (sales) AS total_sales

  OF got_week_num

  GROUP BY week_num

  ORDER BY week_num

  ;

  This will work with dates before March 7, 2014, also.  The week before week 1 (that is, the beginning of the week on February 28, 2014) week is 0; the week before this (from February 21) is week - 1 and so on.

• Qosmio G30-201: Question about video in function

  New, proud owner of this superb piece of equipment!

  I'm stuck on one thing - I can't seem to be able play disk or configure anything in which is the 'video-enter' registration. Manual describes how to connect to a VCR bridge, but once connected I cannot view anything on entering the port. Nothing in the WMSE, nothing in the creator of Invervideo, nothing in the control panel to activate.

  Any ideas out there?

  Appreciate any help.
  Thank you
  Andy

  Hello Andy

  Who, IN the port that you are using?

  By the way: http://forums.computers.toshiba-europe.com/forums/thread.jspa?threadID=18960

  Maybe using.

• Question about the CAST function

  Hi all
  
  I have two tables that have the same columns and the different type of data. I have to create a Union to see all these paintings, but want to change the data type of number (6) in the view. I couldn't do. Could someone please help me out here.
  
  Thanks in advance!
  
  
  SQL > desc t1;
  Name Null? Type
  ----------------------------------------------------------------- -------- ------------
  COL1 NUMBER (3)
  
  SQL > desc t2;
  Name Null? Type
  ----------------------------------------------------------------- -------- ------------
  COL1 NUMBER (6)
  
  SQL > create or replace view t12
  2 as
  3 select cast (col1 as col1 number (6)) from t1
  4 Union all the
  5 Select cast (col1 as number (6)) t2 col1;
  
  Created view.
  
  SQL > desc t12
  Name Null? Type
  ----------------------------------------------------------------- -------- -------------
  COL1 NUMBER
  
  
  SQL > create or replace view t12
  2 as
  3 select cast (col1 as col1 number (6)) from t1
  4 Union all the
  5. Select col1 in t2;
  
  SQL > desc t12
  Name Null? Type
  ----------------------------------------------------------------- -------- --------------
  COL1 NUMBER
  
  
  SQL > create or replace view t12
  2 as
  3 select cast (col1 as col1 varchar2 (6)) from t1
  4 Union all the
  5 Select cast (col1 as varchar2 (6)) t2 col1;
  
  Created view.
  
  SQL > desc t12
  Name Null? Type
  ----------------------------------------------------------------- -------- -----------------------
  COL1 VARCHAR2 (6)

  Hello

  As others have mentioned, no doubt regardless of whether the column is a NUMBER (6) or the NUMBER without limitation.

  In case it matters, however, you can get the desired results by masking the UNION within a subquery:

  CREATE OR REPLACE VIEW t12
  AS
  SELECT     CAST (col1 AS NUMBER(6))  AS col1
  FROM     (            SELECT   col1     FROM t1
       UNION ALL  SELECT   col1     FROM t2
       );
  

• Question about DISCHARGE (expr, 1016) function

  Hello
  
  I have a question about the DUMP function, specifically the DUMP (expr, 1016). What character set is the function of report? The only logical answer seems to me the characters of data. The http://download.oracle.com/docs/cd/E11882_01/server.112/e17118/functions055.htm#SQLRF00635 docs it says: "by default, the return value contains no character set information. To retrieve the name of character of expr, add 1000 to all the values of previous format. "For example, a return_fmt of 1008 returns the result in octal * and provides the character set name of expr.*.
  
  I ask this question because a client complains that there a database with database EE8MSWIN1250 (obtained from DATABASE_PROPERTIES) characters and when I asked him to run a SELECT that could empty the contents of a column, he gave me this result:
  

  select dump(some_col, 1016) from some_table;
  
  Typ=1 Len=8 CharacterSet=AL32UTF8: c5,bd,c5,a0,54,45,53,54

  Now I can't imagine how the data can be stored in the AL32UTF8 character set if the characters of the database are EE8MSWIN1250. This scenario is still possible? I tried in vain to reproduce on my test database.
  
  I don't know if the column is defined with the characters of database or the national database characterset, but even if it was a NVARCHAR2, the dump function could not return AL32UTF8 since he is not a national character set.
  
  If anyone has an explanation, I will be very grateful.
  
  Thanks in advance and best regards,
  Swear

  1. to help with the confusion about the DUMP function: index realizes that the DUMP function can be performed in the remote database. Oracle tries to push as many functions as possible and semantically correct on the remote site. Therefore, it sends the statement of simple table on the remote site after stripping the DB link. In this case, the DUMP function sees the character set of the remote database and creates the resulting string of information. This string of AL32UTF8 to EE8MSWIN1250, as described in the note, but as all the characters in the string of information are pure ASCII, some codes are actually changed.

  Things get more interesting if you start to combine the tables of local and remote databases. For example, the following query is will normally return the character of local database defined for the two columns:

  select dump(xx,1016),dump(yy,1016) from (select x.dummy xx, y.dummy yy from dual x, dual@dblink y);
  

  This is because the first dual@dblink is transported to the local site and the join is performed here with application of DUMP.

  The following query returns the set for two columns of characters in remote database:

  select dump(xx,1016),dump(yy,1016) from (select x.dummy xx, y.dummy yy from dual@dblink x, dual@dblink y);
  

  This is because all the tables are remote and the entire query is sent to the remote database and y.

  The following query returns the remote character set thus:

  select dump(xx,1016),dump(yy,1016) from (select /*+driving_site(y)*/ x.dummy xx, y.dummy yy from dual x, dual@dblink y);
  

  Here, the DRIVING_SITE hint asks the database to perform the join in the database of the table, for example dual@dblink.

  2. to answer your question:

  Your understanding of the way of conversion is generally correct, but conclusions are not quite correct. In the scenario [client EE8ISO8859P2, EE8MSWIN1250 local database, remote database AL32UTF8], Eastern and Central European characters will work correctly, but the other characters to the remote database will not be (for example, French, Greek, Chinese). It is, I think, quite clear and is usually not a major problem, as usually only compatible languages EE8 are interesting for an EE8ISO8859P2 customer. However, in the scenario [customer AL32UTF8, EE8MSWIN1250 local database, remote database AL32UTF8], the problem becomes more visible. Having a taking customer support Unicode, you can recover some data French or Greeks of the remote database but you will fail as all of these characters will be "killed" by the conversion of distance at the local level (link DB conversion).

  EE8ISO8859P2 is also for the same group of languages, such as EE8MSWIN1250, indeed, but it lacks some interesting characters. The most important of them is the symbol of the Euro. Others are "' quotes, long dashes, TM symbol, and a few other less frequently used punctuation. Therefore, always define a database as EE8MSWIN1250, even if you run some clients (Unix) with EE8ISO8859P2. Do not run Windows with EE8ISO8859P2 clients, except for purposes of loading/generation of special file.

  -Sergiusz

• Question about to_date() function?

  Hello
  I have a question about the to_date() function.
  I am aware that for the to_date() function, we should give the format of the input string.
  My current settings for the NLS_DATE_FORMAT parameter in the NLS_SESSION_PARAMETERS table is "DD-MON-YY."
  Then, when I give

  SELECT TO_DATE('15-DEC-2008','DD/MM/YY') it should error out because the format is not same as the format of the input string('DD-MON-YY').

  But this isn't any error out.why?
  Also please tell me if the format of SYSDATE is taken NLS_SESSION_PARAMETERS table or another table.

  Please take a look at Unexpected result with to_date

• A question about the insertion of the localTimeStamp returned the value into a timestamp with time zone column

  Hello

  Oracle version: Enterprise Edition Release 12.1.0.1.0 - 64 bit

  OS: CentOS 4.6 X86_64                  

  I have a question about the localTimeStamp function. According to the documentation for this function is
  the same thing as current_TimeStamp except that the returned value does not include the time zone.

  Consider the following example:

  SQL > create table tmptab (colval timestamp with time zone not null);

  Table created.

  SQL > insert into tmptab (colval) values (localTimeStamp);

  1 line of creation.

  SQL > select t1.colval, tmptab from t1;

  COLVAL

  ---------------------------------------------------------------------------

  24 JANUARY 14 09.45.42.253732 H + 01:00

  SQL >

  Why introduce the foregoing did not fail? the data type of the column in my table colval expects a timestamp with time zone

  during each which inserts as I understand (correct me if I'm wrong) is not provided by the localTimeStamp function.

  Could someone kindly tell me what I misunderstood?

  Thanks in advance,

  dariyoosh wrote:

  Hello

  Oracle version: Enterprise Edition Release 12.1.0.1.0 - 64 bit

  OS: CentOS 4.6 X86_64                  

  I have a question about the localTimeStamp function. According to the documentation for this function is
  the same thing as current_TimeStamp except that the returned value does not include the time zone.

  Consider the following example:

  SQL > create table tmptab (colval timestamp with time zone not null);

  Table created.

  SQL > insert into tmptab (colval) values (localTimeStamp);

  1 line of creation.

  SQL > select t1.colval, tmptab from t1;

  COLVAL

  ---------------------------------------------------------------------------

  24 JANUARY 14 09.45.42.253732 H + 01:00

  SQL >

  Why introduce the foregoing did not fail? the data type of the column in my table colval expects a timestamp with time zone

  during each which inserts as I understand (correct me if I'm wrong) is not provided by the localTimeStamp function.

  Could someone kindly tell me what I misunderstood?

  Thanks in advance,

  Then, when you do

  create table t (neck DATE);

  Insert into t (to_date ('1st January 2014', ' mon-dd-yyyy "");)

  Are you surprised that it works? After all a DATE column contains a time component, you do not provide: but he

  works and gives you 00:00:00 as the component "hour".

  Similarly, the timezone component is being developed to automatically with, I think, time zone of your system.

• Ask questions about the functionality of EA8500 MU-MIMO

  Dear Linksys

  I bought EA8500, and it arrived today.

  I have two questions about the functionality of MU-MIMO of EA8500 AP.

  1. I want to compare the performance between SU-MIMO and MU-MIMO, but there is no option to control this feature in the router admin page. Is that one of the possible ways?

  2 EA8500 supports 1733 Mbps wireless speed, but it resembles the speed of 1 Gbps ethernet cable.

  This router supports really speed 1 Gbps ethernet? or y at - it an option to support more throughput as the aggregation of links?

  Thank you

  Hi, hyeonu. For your first query, it is not possible because there is no option to disable the feature of MU-MIMO on your Linksys EA8500 router. In addition, with regard to your second, you can get a higher throughput of 1 Gbps since this is the maximum capacity of your ethernet connection.

• I have a question about the functionality of Oracle Identity Manager...?

  Hi friends
  I have a question about the features of Oracle Identity Manager.
  Here's my question:
  Self-management is possible network passwords (reset / unlock) with Oracle Identity Manager 9.1.0.2
  
  Very grateful.

  What Kevin suggested this means that you are managing accounts and their password by IOM. If your condition is the same then follow:

  Re: error during password reset using the self-service portal