record insert question

Similar Questions

• Record insertion form wizard

  'Record insertion form wizard' Dreamweaver creates this code on my page add_products.php
  
  1 <? php require_once('.. / Connections/connStore1.php');? >
  2 <? PHP
  
  4 //Alternative for PHAkt functions.inc.php
  5 require_once('.. / includes/tNG_functions.inc.php');
  
  7 //load the classes of tNG
  8 require_once('.. / tNG/KT_tNG.inc.php');
  
  Which causes this error message:
  
  Warning: main (.. / includes/tNG_functions.inc.php): failed to open stream: no such file or directory in /home/herm1/public_html/admin/add_product.php on line 5
  
  Fatal error: main(): failed to achieve "... / includes/tNG_functions." Inc.php' (include_path ='.: / usr/lib/php: / usr/local/lib/php ') in /home/herm1/public_html/admin/add_product.php on line 5
  
  
  Dreamweaver is indicative of the add_products.php to access a folder that does not exist.
  I'm stuck.
  
  

  Hi Yes,

  You must download includes it the folder that is created when you use the
  InterAKT extensions.

  "Herman2468" wrote in message
  News:e7mmi0$IC3$1@forums. Macromedia.com...
  > 'Record insertion form wizard' Dreamweaver creates this code in my
  > add_products.php page
  >
  1 >
  2 ><>
  >
  4 > //Alternative for PHAkt functions.inc.php
  require_once('.. > 5 / includes/tNG_functions.inc.php');
  >
  load > 7 classes of tNG
  require_once('.. > 8 / tNG/KT_tNG.inc.php');
  >
  > Which causes this error message:
  >
  > Warning: main (.. / includes/tNG_functions.inc.php): failed to open stream:
  > NO.
  > file or directory in /home/herm1/public_html/admin/add_product.php on
  > line
  5 >
  >
  > Fatal error: main(): failed to realize
  > '.. / includes/tNG_functions. Inc.php'
  > (include_path ='.: / usr/lib/php: / usr/local/lib/php ') in
  > /home/herm1/public_html/admin/add_product.php on line 5
  >
  >
  > Dreamweaver says add_products.php to access a folder that is not
  > exist.
  > I'm stuck.
  >
  >
  >

• LOBs and how to retrieve the record inserted with EMPTY_BLOb()

  Hi guys
  
  
  How to retrieve the records inserted with EMPTY_BLOb() instead of NULL value.
  
  
  Best greetings
  A.G.

  There must be a better way, but these work:

  SELECT... from tableX where length (lob_column) = 0;
  SELECT... from tableX where dbms_lob.getlength (lob_column) = 0;

  Concerning
  Jonathan Lewis
  http://jonathanlewis.WordPress.com
  http://www.jlcomp.demon.co.UK

  "All experts it is a equal and opposite expert."
  Clarke

• find the most recent record inserted by using rowid

  Yes, I suspect that it is a bad idea!

  I work with an application that has been modelled incorrectly. a historical table of the status had been modeled with a primary key on a key of the company and the entry into force instead of the date of the end of the recording of the State. There is one status as possible at the same time.

  logic has been developed to insert new records of status with the dates of null terminator and then a trigger was provided that populated end dates except the one with the MAX (ROWID). so the hope is that ROWID will always get bigger.

  now, the database has been moved in environments of promotion using data pump. in our development environments, it always seems to work. but not in promotional customers environments.

  My question is: is there a setting associated with data pump that the client has used that does not respect the ROWID as it has in our development environment?

  I'm trying to determine if there is a way to continue to use the old code without immediately re-development.

  Thanks in advance for your comments.

  so the hope is that ROWID will always get bigger.

  It is an expectation that has no guarantee of being correct. He has a very good chance that a new line will have a lower value of the ROWID.

  My question is: is there a setting associated with data pump that the client has used that does not respect the ROWID as it has in our development environment?

  There is not this setting. Data pump just inserts rows into a table. Because we cannot guarantee that the next row will have a higher ROWID, then what you are looking for there is no.

  It is time to rethink this misguided approach.

  See you soon,.
  Brian

• records inserted duplicates and not inserted values

  Hi all

  create the table XXC_ORDERS (inventory_item_id customer_id number, number, budget_entity varchar2 (10), number of EXCHANGE_RATE, CURRENCY_CODE varchar2 (10));

  create table XXC_SALES1 (inventory_item_id customer_id number, number, budget_entity varchar2 (10), number of EXCHANGE_RATE, CURRENCY_CODE varchar2 (10));

  create table XXC_BUDGET (inventory_item_id customer_id number, number, budget_entity varchar2 (10), number of EXCHANGE_RATE, CURRENCY_CODE varchar2 (10));

  create table XXC_SALES_BUDGET (inventory_item_id customer_id number, number, budget_entity varchar2 (10), number of EXCHANGE_RATE, CURRENCY_CODE varchar2 (10));

  -drop table XXC_SALES_BUDGET

  insert into XXC_ORDERS

  SELECT 27962, 68329, 0.82082, 'US', '93'

  DOUBLE;

  CREATE VIEW Orders_V1 AS

  SELECT *.

  OF XXC_ORDERS;

  insert into XXC_SALES1

  SELECT 68329, 27962, '93', NULL, 'EUR '.

  DOUBLE;

  CREATE VIEW Sales_V1 AS

  SELECT *.

  OF XXC_SALES1;

  insert into XXC_BUDGET

  SELECT 68329, 27962, 'CZK', NULL, NULL

  DOUBLE;

  CREATE VIEW Budget_V1 AS

  SELECT *.

  OF XXC_BUDGET;

  DECLARE

  V_ITEM_ID number;

  number of v_cust_id;

  v_Entity varchar2 (10);

  number of v_rate;

  v_curr varchar2 (10);

  CURSOR c_1

  IS

  SELECT INVENTORY_ITEM_ID,

  CUSTOMER_ID,

  BUDGET_ENTITY,

  EXCHANGE_RATE,

  CURRENCY_CODE

  OF XXC_ORDERS

  UNION

  SELECT INVENTORY_ITEM_ID,

  CUSTOMER_ID,

  BUDGET_ENTITY,

  EXCHANGE_RATE,

  CURRENCY_CODE

  OF XXC_SALES1

  UNION

  SELECT INVENTORY_ITEM_ID,

  CUSTOMER_ID,

  BUDGET_ENTITY,

  EXCHANGE_RATE,

  CURRENCY_CODE

  OF XXC_BUDGET;

  BEGIN

  FOR c_rec IN c_1

  LOOP

  BEGIN

  SELECT INVENTORY_ITEM_ID,

  CUSTOMER_ID,

  BUDGET_ENTITY,

  EXCHANGE_RATE,

  CURRENCY_CODE

  IN v_item_id,.

  v_cust_id,

  v_Entity,

  v_rate,

  v_curr

  OF XXC_ORDERS

  WHERE INVENTORY_ITEM_ID is c_rec. INVENTORY_ITEM_ID

  AND CUSTOMER_ID = c_rec CUSTOMER_ID.

  AND BUDGET_ENTITY = c_rec. BUDGET_ENTITY;

  -AND EXCHANGE_RATE is c_rec. EXCHANGE_RATE

  -AND CURRENCY_CODE is c_rec. CURRENCY_CODE;

  EXCEPTION

  WHILE OTHERS THEN

  V_ITEM_ID: = 0;

  v_cust_id: = 0;

  v_Entity: = null;

  -v_rate: = 0;

  -v_curr: = null;

  End;

  Begin

  INSERT INTO XXC_SALES_BUDGET

  SELECT

  V_ITEM_ID,

  v_cust_id,

  v_Entity,

  v_rate,

  v_curr

  of the double

  WHERE THERE IS NO

  (SELECT 1 OF XXC_SALES_BUDGET y)

  WHERE y.budget_entity = c_rec. BUDGET_ENTITY

  AND y.customer_id = c_rec.customer_id

  AND y.inventory_item_id = c_rec.inventory_item_id

  - AND y.EXCHANGE_RATE = c_rec EXCHANGE_RATE.

  - AND y.CURRENCY_CODE = c_rec. CURRENCY_CODE

  );

  End;

  commit;

  End loop;

  End;

  (1) implementation of duplicates in the table XXC_SALES_BUDGET for the 2nd time

  (2) in my original query in the table XXC_SALES_BUDGET EXCHANGE_RATE, CURRENCY_CODE is NULL, but the test case above, it is punishable by fine

  Post edited by: added test cases 994122

  994122 wrote:

  How to avoid duplicates?

  Thanks John

  "Ostensibly you insert records with null for the column values. When you do this, it is query will be FALSE when you try to compare NULL with the NULL value because NULL = NULL is unknown (it is not true). NULL <> NULL is also unknown. You compare nulls using "IS NULL" "the #1 post . 

  
  

  I made a mistake in this conditions to not exist in INTO clause block where conditions and I added NVL on two blocks, now works well.

  AND nvl (y.currency_code, 'CCC') = nvl(c_rec.currency_code,'CCC')

  AND nvl(y.exchange_rate,1) = nvl(c_rec.exchange_rate,1)

  Question:

  in Zapex ( post #3 )

  MERGE INTO xxc_budget_history one

  USING (SELECT item_id,

  cust_id,

  DECODE (UPPER (BUDGET_ENTITY), 'ABC', '12', BUDGET_ENTITY)

  budget_entity,

  exchange_rate,

  currency_code

  OF xxc_cur_table

  WHERE item_id = 116) b

  WE (a.cust_id = b.cust_id

  AND a.BUDGET_ENTITY = b.BUDGET_ENTITY

  AND a.item_id = b.item_id)

  WHEN MATCHED

  THEN

  GAME UPDATE

  a.EXCHANGE_RATE = b.EXCHANGE_RATE, a.CURRENCY_CODE = b.CURRENCY_CODE

  WHEN NOT MATCHED

  THEN

  INSERT (EXCHANGE_RATE, CURRENCY_CODE)

  VALUES (b.EXCHANGE_RATE, b.CURRENCY_CODE);

  I tried with the above code when my table was below the values but getting even (the values are already validated)

  ITEM_ID	CUST_ID	UNITS_MONTH1	AMOUNT_MONTH1	EXCHANGE_RATE	CURRENCY_CODE	BUDGET_ENTITY
  116	836	0	0			12

  But I need to update as below with the existing values

  ITEM_ID	CUST_ID	UNITS_MONTH1	AMOUNT_MONTH1	EXCHANGE_RATE	CURRENCY_CODE	BUDGET_ENTITY
  116	836	100	110			12

  Thank you

  you do not see UNITS_MONTH1 and AMOUNT_MONTH1. How do you want to get the update? These two columns should be included in the SELECT, UPDATE and INSERT statements. Then only it will update

• Limit the records inserted with FUSION

  I created a procedure for updating a table date of termination when the user enters a date of term.  Username and ID (PK) comes from t_users and the endings are in t_terms with t_terms.user_id = t_users.id as key.  There are about 2,500 users and curently nothing in the picture of the word.

  This procedure lights are part of a dynamic of action when the page is sent on an Apex application:

  create or replace Procedure "TERM_UPDATE"

  ()p_user_id IN NUMBER

  p_term_eff_date IN DATE )

  is

  Start

  fusion en t_terms t

      using t_users u

      on (t.user_id=u.id)

  when matched then

  to update the value TERM_EFF_DATE=p_term_eff_date where useridentifier=p_user_id

  when not equal then

  integration ()user_id term_eff_date) values ()p_user_id p_term_eff_date)

  end ;

  I tried just the merge statement in SQL Workshop.  The result is an insertion of 2500 all records user to the table of endings each time that it fires.  If I run again, I get 5000 inserts.  If I understand this process, t.users_id = u.id must return nothing, triggering the insert without match.  Even when there is a match, I always get the insert.  What the hell is happening?

  The p_user_id and the p_term_eff_date are power from bind on page variables.  I put those to be bind variables when I tested the query.

  I'm under apex 4.2 on 11g.

  Thank you!

  Hello

  Thanks for posting the instructions CREATE TABLE.

  Don't forget to display instructions INSERT for you samples, a few calls to the procedure (with specific values for the arguments) and content of t_term after each call.

  What t_users role in this problem?  You get all the information to t_users; you already know the user_id to the time wherever you call the procedure.  I guess the only reason why you have to t_users to this problem is to guard against inserting a user_id not valid in t_term.  (The foreign key constraint would guard against that, too, but it would trigger an error.  You might find a little more elegant to just merge 0 line when an invalid user_id is passed to the procedure.)

  Here's a way to do it:

  create or replace procedure 'TERM_UPDATE '.

  (p_user_id in NUMBERS

  p_term_eff_date IN DATE

  )

  is

  Start

  merge into dst t_terms

  a_l'_aide_de)

  Select id as user_id

  of t_users

  where id = p_user_id

  )              src

  on (dst.user_id = src.user_id)

  When matched then

  update set TERM_EFF_DATE = p_term_eff_date

  where DECODE (TERM_EFF_DATE - if wanted

  p_term_eff_date, 1

  0

  ) = 0

  When not matched then

  Insert (dst.id, dst.user_id, dst.term_eff_date)

  values (term_id_seq. NEXTVAL, src.user_id, p_term_eff_date);

  end;

  /

  DISPLAY ERRORS

  Because t_terms.id is forced to be NON NULL, you must provide a value for the id before you can insert a new line in t_terms.  In the above procedure, I guess you have a sequence called term_id_seq for this purpose.

• How to insulate the record insertion on a block of other blocks

  Hi all

  I am facing a problem in inserting record on several blocks. Let suppose that there are three blocks A, B and C user is inserting record in the block in the user Meanwhile jumped to block B and inserting record start here and then commit those changes. Inserting record on block B is failed due to validation on block A, where user left between the two and jumped to block B and application form for incomplete registrations. However, on the block B, all elements are validated but still ask to enter data block has.

  It is possible that if the user enter the record in the current block and forms insert record in that block and validate any changes on other blocks. I tried insert_record; integrated into the insert record but did not work. An idea to get out of this situation that I would be grateful.

  Thank you.

  A form module is treated as a single unit of work or of a single transaction. Either you save all data in it or anything. If you have a logic which must be stored separately from each other, so you should design your modules accordingly, in your case, create different form-Modules for different blocks. Everything else will only cause problems and is not the way to form of work.

  Message geändert durch AndreasWeiden

• Mail after record insertion

  Hi guys, I always interim relief forms in process.php, which seizes the form fields and email, then redirects to thanks.php. I started to work with dreamweaver PHP functions and if I insert a record into MySQL, the form action becomes echo $editFormAction; and the code for process.php points, but no e-mail passes through. It ends at thanks.php so it's still going through process.php. Anyone know why it does not work? Should I send the email after the insertion of all on the same page? Thank you

  Self-confidence, insert file will present itself and DW will place of own form on the form action. The embed code is encapsulated in an IF statement that basically checks if the page loads for the first time, or if the action of the form is set to true andnthen run the embed code and redirect. You should be able to take the E-mail of the process script. PHP and place it after the code insertion and before the redirection. The form variables will be available at the time the script of the insert and the e-mail script.

• Several record insert through PROCEDURE - Urgent

  All,
  
  My requirement is, I need to call a procedure that accepts two inputs and 1 output variable. The operation of the procedure is to insert the data in two tables (head_tab and line_tab - accepts several recording). I used % rowtype to two entries i.e procedure proc (head_var head_tab % rowtype, line_var line_tab % rowtype, out_var number). The incoming doc comes from 3 application of part which sends a header record and multiple line record for the same header.
  I used the processing activity, insert row record I used for each loop for multiple record. But % rowtype is a scalar data type, it does not accept table of record to him! I'm stuck here. Can achieve us this scenario with the help of the procedure? or do I have to configure DBAdapter to insert the data directly on the table rather the procedure for this? If we can reach it through the procedure, how are we going?
  
  Thank you
  Sen

  You can mark it as Correct if it worked?

• Issue of PHP/MySQL record insert

  I work with PHP 4.4.2 MySQL Server 5.0 running on Apache 2.0.55, and I develop my website with Dreamweaver 8. That runs locally on my machine.
  
  I'm working on a real estate site that allows landlords around my area to connect to the web site and add their rental apartment or condo units in a database that students who attend my little University can surf and search. The owners register as a charge in a table 'owners' in the database and MySQL example an ID in a column "landlord_id" that obviously to guide their 'landlord_ID '.
  
  My question is: when the owner is filling out the form to add their rental units (including charges in a separate table, I called 'sites'), how can I do their 'landlord_id' (which resides in the 'owners' table) be entered in the "landlord_id" column in the table of 'sites' for each site they enter into the database?
  
  I'm trying to do this because when the landlord connects first of all, I have a table that shows all the sites they have already entered in the database and displays only their sites that they have already entered by showing only the sites that have their "landlord_id" in the site folder.
  
  Thanks a lot for your help, and if I'm confused at all, if it please reply or email me so I can clarify.

  Cade06 wrote:
  > You said that the value of the parameter name should be the username column
  > (EMAIL is), the default value as 1 (which gives me an error each time then
  > I thought that maybe you meant "col1" smell the username column that would be
  (> new EMAIL, so correct me if I was wrong to assume that),.

  Yes, you were wrong to assume. The reason why you got an error with a
  default value of 1 is because the username will be a string (no doubt
  the e-mail address). Since you are so completely at sea with this, there
  probably better to use the simple Recordset dialog box.

  You create the recordset object in whatever the page the user is sent to the
  Once connected successfully. In the simple Recordset dialog box.
  Choose a connection, and then choose the table that contains the details of
  your owners. In the columns box, select the option selected,
  and highlight the column landlord_id. In the filter section, choose
  In the first dropdown menu, EMAIL = in the next menu, then session
  Variable in the third menu drop-down. Dreamweaver shows probably
  Email in the text field, alongside of Session Variable. Replace the with
  MM_Username. Click the Test button to make sure it works. You will be
  you are prompted for a test value. Enter a valid EMAIL address and you ensure that you
  get only one result.

  When you created the recordset object, switch to Code view and find the
  line continuation (recordsetName will be everything that you call the Recordset):

  $totalRows_recordsetName = mysql_num_rows ($recordsetName);

  Insert a line just below and put it (using the real
  the name of the Recordset):

  $_SESSION ['landlord_id'] = $row_recordsetName ["landlord_id"];

  --
  David powers
  Author, "Foundation PHP for Dreamweaver 8" (friends of ED)
  Author, "Foundation PHP 5 for Flash" (friends of ED)
  http://foundationphp.com/

• Avoid duplication of record Insertion

  I'm trying to get something like that, but I think instruction Insert is not allowed in the case or Select expects something in return is why it continues to give me missing Expression. Y at - it another way to prevent duplicate insertion. I know that we can do it by running another query and then based on recoundcount or County of this distinct query, you insert records, but I don't want to do.
  
  
  SELECT THE CHECK BOX
  WHEN (SELECT COUNT (*) FROM THACARA WHERE ORG_CNY_CD = 'US' AND ORG_REG_NR = '02' AND ORG_DIS_NR = '51') > 0
  THEN ("EXSIST IN DOUBLE")
  OTHER (INSERT INTO THACARA (USR_NR, ORG_FAC_LOC_NR)
  values ('Mary', 'FLIMI'))
  TEST END AS FROM DUAL;
  
  any ideas?

  As long as you reference to DOUBLE guess is your Oracle database and DUAL is a table of 1 row.

• iOS 10 people record problem/question

  Hello

  I have a couple of "faces" in the issue of people who are coming in white, but acknowledged same 'face' of many times.  Is anyway to update it for photo comes actually?  At a few faces, I don't know that facial recognition found since it is coming from white.

  Hi JohnP007,

  Congratulations on your iPhone 7 more running iOS 10! I understand that some of your faces in the album of people pull up as a draft and you want to refresh. You can try to use the steps below to fix the faces on the thumbnails in albums.
  

  Difficulty faces and names mixed-up

  If you notice that there is a photo of someone in a collection that is poorly identified, you can remove it.

  1. Tap the person you want to remove in the album of people > select.
  2. Type Show done face to emphasize his face in every photo.
  3. Press on each photo that is not the person.
  4. Type > not this person.

  Hide people

  You can hide the people or groups that you don't want in your album of people.

  1. Open the album people and press Select.
  2. Touch the people you don't want to see.
  3. Click Hide.

  If you want to see the people that you have hidden, press on show hidden people.

  People in the Photos on your iPhone, iPad or iPod touch

  This should be corrected without delay faces. Please use the Apple Support communities to post your question. Good day.

• Record of question mark on inactivity on MBP 15 "2011

  Here's the problem, in short, I will be happy to provide you with more info soon.    I have a MBP 15 "beginning 2011 with 10.10.5 OSX, 16G of RAM, 512G SSD drive of OWS.   After about 2 weeks I started to get a folder of question mark at one point, after I start using my Mac for a while.   It seems that the MBP hangs and I have to hard reboot.  When I rebood some time I get a question mark folder but generally the 3rd reboot I can connect.

  Just FYI, disconnected know if related but about 3 weeks ago I bought an ACER 22 "external monitor, Macally keyboard and the mouse, but they all worked OK for a little everything so I don't know if this problem is related, but I still have questions, even when they all.

  < image edited by host to remove personal information >

  If a flashing question mark appears when you start your Mac - Apple Support

• New record of question mark SSHD screnn

  My Seagate SSHD should fail, so I ordered a replacement.

  In the meantime I backed up with time machine on my external hard drive in my MacBook, and then I created a bootable USB key.

  This morning, I replaced the SSHD with a new one, but I get the white screen with a folder with an exclamation mark.

  It also happened that the laptop turns off unexpectedly. Could you help me please understand what is happening?

  Thanks yo!

  The question mark appears when the drive specified in the last

  System Preferences > startup drive...

  ... is not available. Your Mac can't find the boot drive, or the drive specified is not a bootable disk (does not contain Mac OS X).

  --------

  Start with the Alt/Option key, select your key USB Bootable and install on the new SSD.

  Long-term, make sure that you enable some version of TRIM, especially if your SSD is only 8 x the size of Mac OS X or smaller.

• Strange system vs Recorded greeting question - CM3.3 (4) and VM4.0 (3) unit

  I have a client who wants their customer service number to ring on the phone during the day and immediately play a greeting with entry of the appellant on the night of the night options.

  I've set up a voicemail box that all calls get sent to, with calls during the day being transferred to a 'day of calls' which sounds an extension. I also put in place a 'night calls' manager who has a recorded welcome message that offers the possibility of the appellant. This works, except that I can't do the Manager 'night calls' play a greeting recorded, only the system greeting. I have double and triple checked the night call handler is verified to use greeting recorded to "closed". I watch the page of Port monitoring unit and see that the correct call handler is used, but he continues to play the message system.

  When I press on play on the recorded message, I can play again myself, telling me that the recording file is being found by the unit and everything has been registered correctly.

  What Miss me? I did similar configurations and never had a problem like this.

  Is there an easier way to implement the feature?

  Thanks in advance...

  Tom Siler

  Columbus, OH

  Hi Tom -.

  My first thought is to check the schedule set for the night call manager. On the profile page of your manager, if it is defined at all hours - daily, closed greeting won't be invoked. Change it to week (Mon - Fri 08:00-17:00 by default), or create a new calendar in the unit that meets your needs better.

  I hope this helps!

  Ginger