Reg missing records for v$ archived_log

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  Any help would be greatly appreciated and I will pass this on too many other press photographers in London which are all looking forward to register for the new storm, but will probably have much less patience and perseverance than me who happens to start all
  Best regards
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  Juliette says:
  Also, I added a map for me because I was instructed to do when I tried to send an invitation ical for a participant to a photo shoot and told me: you must create an address for yourself card in the address book of Mac OS X, but I created a? This means constantly every time.
  Best regards
  Juliette

  I intend as a result tomorrow when my Storm (could actually be a couple of days, but I promise you, as soon as POSSIBLE). However, on your Mac, in the address book application follow these steps if you do not.

  (1) (to select the map that you created yourself (highlighted)

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• selection of the missing records between 2 duplicity without worrying about tables of records

  Hi all

  I have received_bills and send_bills of 2 tables.

  The SEND_BILLS table is the source table displaying all records in it.

  I need to compare two tables together and insert all the missing elements in received_items including duplicate records.

  There may be duplicate in 2 tables records.

  I wrote a query, but it does not select the duplicate records if it's all the 2 tables. When the same duplicate records are send_bills and received_bill without worrying because send_bills has 4 of them and received_bill 2, it does not select the other 2 duplicate records. And it's just what I need.

  the query is

  SELECT SEND. POINT OF REFERENCE,

  Send. PAYMENT,

  Send. CODE

  OF SEND_BILLS SEND

  WHERE THERE IS NOT (SELECT REC. DATUM, PAYMENT, REC. REC. CODE

  OF RECEIVED_BILLS REC

  WHERE REC. REFERENCE = SEND. SCRATCH CARDS

  AND REC. PAYMENT = SEND. PAYMENT

  AND REC. CODE = SEND. CODE)

  send_bills records

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	29	A3
  OCTOBER 10, 15	47	A4
  9 OCTOBER 15	19	A8
  OCTOBER 10, 15	20	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5

  received_bills records

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	29	A3
  OCTOBER 10, 15	47	A4
  OCTOBER 10, 15	19	A1

  the result of the query is:

  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	20	A1
  9 OCTOBER 15	19	A8

  So he selects all the records

  the result should be

  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	20	A1
  9 OCTOBER 15	19	A8
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1

  --------------------------------------------------------

  -The DOF for Table SEND_BILLS

  --------------------------------------------------------

  CREATE TABLE SEND_BILLS

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  --------------------------------------------------------

  -The DOF for Table RECEIVED_BILLS

  --------------------------------------------------------

  CREATE TABLE 'RECEIVED_BILLS '.

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  -Insert the script for send_bills

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5')

  -Insert invoices received from script

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 29, 'A3');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into RECEIVED_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Can someone please help me with the query so that I can also select all the missing records, including duplicates.

  Thanks in advance.

  Best regards

  Caroline

  If you should by all means use loop and then (send_bills and received_bills contain the same data as your original post):

  Select the reference, payment, code

  of (with

  Duplicator (Datum, Payment, code, CNT) as

  (select the reference, code, payment, cnt - 1).

  from (select datum, payment, code, count (one) - cnt count (two)

  (select date, payment, code, 1 one, to_number (null) two)

  of send_bills

  Union of all the

  Select datum, payment, code, to_number (null), 2 two

  of received_bills

  )

  Reference group, code

  having count (one)! = count (two)

  )

  Union of all the

  Select the reference code, payment, cnt - 1

  The duplicator

  where cnt > 0

  )

  Select the reference, payment, code

  The duplicator

  )

  DATUM	PAYMENT	CODE
  10/09/2015	19	A8
  10/10/2015	19	A1
  10/10/2015	25	A5
  10/10/2015	20	A1
  10/10/2015	19	A1
  10/10/2015	25	A5

  Concerning

  Etbin

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  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

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  phtype VARCHAR2 (10),

  Phone NUMBER

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  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

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  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

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  SQL >

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  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

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  2015-11-24 9:32 GMT + 01:00 aadeshs76610910 [email protected]>:

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  Hi all

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  Identification number,

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  Insert into a1

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  1 ABC A1

  1        ABC             0

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  DEF 2 A2

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  Thanks for your help FrankKalush...

  This one will work.

  WITH got_r_num AS

  (

  SELECT NVL (a1.id, a1.id) as id

  NVL (a1.item, a1.item) AS element

  NVL (a1.part, a1.part) IN the framework

  a1.id AS a_id

  ROW_NUMBER () OVER (PARTITION BY a1.id

  ORDER BY NULL

  ) AS r_num

  BY the a1

  )

  SELECT id

  element

  CASE

  WHEN a_id IS NOT NULL

  AND r_num = 1

  THEN part

  ELSE ' 0'

  END in the framework

  OF got_r_num

  ;