Reg months start date

Similar Questions

• start date for each week of the month

  Dear members
  
  How can I find double, the start date of each week of the month in a year.
  beginning of the week is the word "Monday".
  
  
  year month week day date
  ----------------------------------------------------------------------------------------
  Monday, January 3, 2011 JAN 1, 2011
  2011 2 JAN Monday, January 10, 2011
  Monday, January 17, 2011 January 3, 2011
  JAN 4 2011 on Monday, January 24, 2011
  2011 to January 5 Monday, January 31, 2011
  
  
  Thank you
  
  teefu

  Hello

  You can use this:

  with t as  (select to_date ('01/01/2011', 'DD/MM/YYYY') start_date from dual)
  select  date_calc
  from (
          select  start_date,
                  (level-1)*7+trunc (start_date , 'D')+1   as date_calc
          from t
          connect by level <=53)
  where trunc(date_calc,'YYYY')=trunc(start_date,'YYYY') ;
  

  Kind regards
  Sylvie

• specify the start date of subscription plan?

  How can I specify the start date for a subscription to a plan (as the land line + mobile for the plan of Britain)? I would like to be covered for the month of September. I have to wait until September 1 before you subscribe and pay?

  Thank you

  Rob

  RobIreland wrote:

  I have to wait until September 1 before you subscribe and pay?

  Hello and welcome to the Skype community.

  Yes, you do.

  TIME ZONE - US EAST. LOCATION - PHILADELPHIA, PA, USA.
  
  I recommend that you always run the latest version of Skype: Windows & Mac
  
  If my advice helped to solve your problem, please mark it as a solution to help others.
  Please note that I usually do not respond to unsolicited private Messages. Thank you.

• Receive every month between date Range

  Hi all

  I said you want to display the month and year for the date range. IE Start date: 01-11-12, end Date: 31/05/13

  SELECT COUNT(T1.CUST_NM) AS COUNT, TO_CHAR(T1.CREATE_DT,'MON-YY') AS MONTH, SUM(T3.DISBURSEMENT_LIMIT) AS TOTAL
    FROM CUSTOMER T1, 
   ACCOUNT T2, LOAN_ACCOUNT T3, CREDIT_APPL T4, PORTFOLIO T5 WHERE  T1.CUST_ID = T2.CUST_ID  AND T2.ACCT_ID = T3.ACCT_ID  AND T3.APPL_ID = T4.APPL_ID  AND 
   T4.PORTFOLIO_ID = T5.PORTFOLIO_ID
  and t1.CREATE_DT between to_date('01-01-10','DD-MM-YY') and  to_date('30-12-10','DD-MM-YY') 
   GROUP BY TO_CHAR(T1.CREATE_DT,'MON-YY')
  
  
  
  

  
  

  Exit SQL:

  County	Month-year	Total
  8	JAN-10	15300
  6	FEB-10	4245000
  11	AUG-10	144500
  6	DEC-10	15500

  Now SQL returns matching records to date. But the requirement is to display the name of the month, the number and total 0 if there is no data found.

  Power required:

  County	Month-year	Total
  8	Jan	15300
  1	Feb-10	118750
  0	March-10	0
  0	Apr-10	0
  0	May - 10	0
  0	Jun - 10	0
  0	Jul-10	0
  11	Aug-10	144500
  0	Seven.-10	0
  0	Oct-10	0
  0	Nov - 10	0
  6	Dec - 10	15500

  Please suggest me SQL to archive the above of the requirement.

  Thanks and greetings

  Saami

  Try this

  with t

  as

  (

  Select count (t1.cust_nm) as County

  to_char(t1.create_dt,'mon-yy') per month

  , sum (t3.disbursement_limit) total

  the t1 client

  in t2

  loan_account t3

  credit_appl t4

  the t5 portfolio

  where t1.cust_id = t2.cust_id

  and t2.acct_id = t3.acct_id

  and t3.appl_id = t4.appl_id

  and t4.portfolio_id = t5.portfolio_id

  and t1.create_dt between to_date ('01-01-10', ' dd-mm-yy')

  and to_date ('30-12-10', ' dd-mm-yy')

  Group

  by to_char(t1.create_dt,'mon-yy')

  )

  t1

  as

  (

  Select to_char (add_months (to_date('01-01-10','dd-mm-yy'), level-1), 'Mon - yy') month_list

  of the double

  connect

  by add_months (to_date('01-01-10','dd-mm-yy'), level-1)<= >

  )

  Select nvl (t.count, 0) as County

  t1.month_list per month

  , nvl (t.total, 0), as total

  from t1

  left

  Join t

  on t1. month_list = t.month

• editing a start date of information from another table

  Hello all;
  
  I have the sample data below
  

  create table t1
  (
         id varchar2(200),
         begin_date date,
         ending_date date
  );
  create table t2
  (
     id varchar2(200),
     period_number number(30),
     period varchar2(200) 
  );
  insert into t1
    (id, begin_date, ending_date)
  values
    ('A', sysdate, to_date('01/02/2020', 'MM/DD/YYYY'));
  insert into t1
    (id, begin_date, ending_date)
  values
    ('B', sysdate, to_date('03/31/2011', 'MM/DD/YYYY') );
  insert into t1
    (id, begin_date, ending_date)
  values
    ('C', sysdate, to_date('01/20/2011', 'MM/DD/YYYY')); 
  
  insert into t2
    (id, period_number, period)
  values
    ('A', 2, 'Years');
  insert into t2
    (id, period_number, period)
  values
    ('B', 3, 'Months');
  insert into t2
    (id, period_number, period)
  values
    ('C', 4, 'Days');

  So what I'm trying to do is basically update the start date in t1, using the information from table t2
  for example, A
  start date should be start date = 01/02/2020-2 years = 01/02/2018
  for C
  start date should be start date = 20/01/2011 - 4 = 01/16/2011

  Thanks for the sample data, it makes life easier.

  Something like this:

  SQL> UPDATE t1
    2  SET begin_date = (SELECT CASE WHEN t2.period = 'Years' THEN ADD_MONTHS(t1.ending_date, t2.period_number * -12)
    3                                WHEN t2.period = 'Months' THEN ADD_MONTHS(t1.ending_date, t2.period_number * -1)
    4                                ELSE t1.ending_date - t2.period_number END
    5                    FROM t2
    6                    WHERE t1.id = t2.id)
    7  WHERE EXISTS (SELECT 1 FROM t2
    8                WHERE t1.id = t2.id);
  
  3 rows updated.
  
  SQL> SELECT * FROM t1;
  
  ID         BEGIN_DATE  ENDING_DATE
  ---------- ----------- -----------
  A          02-JAN-2018 02-JAN-2020
  B          31-DEC-2010 31-MAR-2011
  C          16-JAN-2011 20-JAN-2011
  

  If t2 is unique, you could also do it as an editable join view using a structure of similar cases.

  John

• Use the project start Date and duration to calculate the end Date of project

  I'm trying to calculate the end date of the project in a report using the project end Date and time entered on the opportunity.
  For example, if the start date of the project filled an opportunity is 31/01/2009 and the length (integer) is entered on the opportunity is 5, the project end date is in the report must be 30/06/2009.
  
  I'm trying to TIMESTAMPADD forumaul allows you to add the duration (number of months) to the project start date
  This Fx works TIMESTAMPADD (SQL_TSI_MONTH, 12, '-used Custom Attributes ".) DATE_40)
  But if I try to replace the number twelve by the length (integer field) I get an error when you try to save: TIMESTAMPADD (SQL_TSI_MONTH, "-opportunity Custom Metrics".) S_INT_0, '-used custom attributes. DATE_40)
  
  Any ideas on how I can get this to work would be greatly appreciated.

  Hi, try this. It might solve your prioblem TIMESTAMPADD (SQL_TSI_MONTH, CAST (YOUR FIELD AS INTEGER), account. (' "Last modified")

  -John CRMIT

• Pavilion 15 p158sa: Incorrect warranty start date

  Like so many others on this forum, my new laptop HP Pavilion has bad warranty start date.

  The laptop was purchased only on 11 January 2015. However, the warranty start date is 11/10/2014.

  Of course, I'd like it corrected.

  Until someone asks. Yes I can prove it.

  Thanks in advance

  James

  Hi @Jtsnr ,

  I brought your question to the attention of a team within HP. They are likely to ask for information from you to get your information or product serial number. Please search for a private message from a contact HP identified. Also, remember not to publicly display (numbers series and information).

  If you are unfamiliar with the operation of the function of the Forum, private messages you can learn it all here.

  Kind regards
  George

• view the log by using the time field a date of last year start date

  As the new year begins, I notice that if I try to do a 'show log beginning December 28 00:00:00 ' to get all the logs that surrounds an event of last week, I get no results. Most likely because the router's view I want newspapers beginning December 28, 2016, who has not yet arrived.  This command must be modified to use the * last * appearance of the starting date, not the date of beginning of this calendar year.

  This has been fixed in 5.2.3 and 5.3.0 increase CSCud91074

  Thank you

  Sam

• Specific database srom growth monthly from date

  
  Hi all

  Database: Oracle database 11g Enterprise 11.2.0.4

  Can someone help me get the growth monthlywise of database specific date

  Ex: Start Date: April 10, 2015

  Growth (Size) until 10 may 2015

  Next Growth (size) 10 June 2015

  What is your (DBA_HIST_WR_CONTROL) AWR retention period?

  If it is 7 days, then you have to extend that, or take regular steps or perhaps OEM there somewhere.

• Identify the Start Date, based on other summary values.

  I am runing:

  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 64 bit Production
  PL/SQL Release 11.2.0.1.0 - Production

  CORE11.2.0.1.0 Production

  AMT for Linux: Version 11.2.0.1.0 - Production

  NLSRTL Version 11.2.0.1.0 - Production

  Here are the general dateset that I try.

  with dateset as)
  Select 1 worker, 8 totalhours, 27 April 15 ' work date, 1 installation, 35 production of all the double union
  Select 1, 8, April 26, 15 ', 1, 35 of all the double union
  Select 1, 0, 25 April 15 ', 1, 0 of all the double union
  Select 1, 0, 24 April 15 ', 1, 0 of all the double union
  Select 1, 6, 23 April 15 ', 1, 20 of all the double union
  Select 1, 7, April 22, 15 ', 1, 27 union double all the
  Select 2, 4, April 24, 15 ', 1, 15 union double all the
  Select 2, 4, April 27, 15 ', 1, 15 union double all the
  Select 2, 4, April 22, 15 ', 1, 15 union double all the
  Select 3, 6, 26 April 15 ', 2, 32 union double all the
  Select 3, 6, April 25, 15 ', 2, 32 union double all the
  Select 3, 6, 24 April 15 ', 2, 32 union double all the
  Select 3, 6, 22 April 15 ', 2, 32 union double all the
  Select 3, 6, 23 April 15 ', 2, 32 double
  )

  Select
  *
  of dateset

  I'm trying to get a date range or have the identified dates for the first harvest of the end date and then have hours max per each day added up to at least 15 hours and find the total production to examine these days that are.

  So, if I choose the end date of April 25, 15 ', then I identified the maximum working hours at the facility. So because no work was allocated to the 25 for installation 1, 24 is the actual start date, in a plant worker 2 3 had 6 hours work, if installation date of end is the 25 hours max of 6. Noticed that the installation has 24, 23 and 22 total hours bing 17 (always meets the requirements of 15 hours), while the installation of 2 has 18 hours 25, 24, 23 (requirement for hours 15 min)

  This is the prison of result data group.

  with datasettwo like)
  Select 4 maxhours, 24 April 15 ' work date, 1 installation, 15 totalproduction of all the double union
  Select 6, April 23, 15 ', 1, 20 of all the double union
  Select 7, April 22, 15 ', 1, 27 union double all the
  Select 6, April 25, 15 ', 2, 32 union double all the
  Select 6, April 24, 15 ', 2, 32 union double all the
  Select 6, April 23, 15 ', 2, 32 double
  )

  Select
  *
  of datasettwo
  order by
  installation
  date desc

  so, how would I go about konwing when start work Date date has been reached because the total number of hours has been reached or excited the limit.

  All thoughts.

  With the help of everyone, thank you,

  It's the rough solution I was looking for, could probably be cleaner.

  I apologize for the confusion.

  so, for April 27, the total production for that day for installation 1 is 50 units and 8 hours max.

  and if the end date is sent to the 24

  April 22 is the total output of 32 units and hours max of 6 for this day.

  with dateset as)
  Select 1 worker, 8 totalhours, 27 April 15 ' work date, 1 installation, 35 production of all the double union
  Select 1, 8, April 26, 15 ', 1, 35 of all the double union
  Select 1, 0, 25 April 15 ', 1, 0 of all the double union
  Select 1, 0, 24 April 15 ', 1, 0 of all the double union
  Select 1, 6, 23 April 15 ', 1, 20 of all the double union
  Select 1, 7, April 22, 15 ', 1, 27 union double all the
  Select 2, 4, April 24, 15 ', 1, 15 union double all the
  Select 2, 4, April 27, 15 ', 1, 15 union double all the
  Select 2, 4, April 22, 15 ', 1, 15 union double all the
  Select 3, 6, 26 April 15 ', 2, 32 union double all the
  Select 3, 6, April 25, 15 ', 2, 32 union double all the
  Select 3, 6, 24 April 15 ', 2, 32 union double all the
  Select 3, 6, 22 April 15 ', 2, 32 union double all the
  Select 3, 6, April 27, 15 ', 2, 32 double
  )

  Select
  installation
  date of work
  totalproductionperday
  maxhoursperday
  sum (maxhoursperday) on totalhours (installation partition)

  from (select distinct)
  installation
  date of work
  maxhoursperday
  totalproductionperday
  , case when sum (maxhoursperday) over (partition by order of ease by date desc)
  -sum (maxhoursperday) over (partition by establishment, work date)<>
  then 'Y '.
  another "n".
  end to_include
         
  (select
  installation
  date of work
  max (totalhours) maxhoursperday
  sum (production) totalproductionperday
                 
  of dateset
                   
  where date of work<= to_date(:enddate,="" 'dd-mon-rr')="" --="" end="" date="">
                 
  Group
  installation
  date of work
  )
  )

  where to_include like 'Y '.

  order by
  installation
  date desc

• Start date of change for the employee

  I have an employee whose departure date was entered incorrectly. The system will not start date change which indicates that allocation changes exist between the old and the new dates.

  This is what the data looks like:

  Employee has been shown as hired August 1, 2014.

  An assignment was made for 1 - August to August 2, 2014.

  A second tour there on 3 August 2014 and the end date is 31-Dec-4712

  The start date must be changed in August 16, 2014.

  Two assignments seem to be a data entry error.

  Is there a way to accomplish this change? Since the two assignments are in error, there is not need to exist.

  Any help is appreciated.
  

  Datetrack on August 1, 2014 and go to the screen for the assignment. Use the remove menu icon and a popup asking if you want to delete all future changes...

  Once you remove the future recordings, you will have a unique assignment record.

  Navigate to the file and replace the most recent start date August 16, 2014.

  Hope that helps.

• When purchasing a subscription, if I know that I used to use the product until a certain date in the future, am I able to set up a future subscription start date as a way to not lose all day in the duration of my subscription?

  When purchasing a subscription, if I know that I used to use the product until a certain date in the future, am I able to set up a future subscription start date as a way to not lose all day in the duration of my subscription?

  Not according to the terms and conditions

  Adobe - General conditions of subscription

  Service starts as soon as your first payment is processed.

  Subscribe when you are ready to use it.

• How can I install my month Acrobat Pro XI to the version of the subscription month starting on another computer? All I can get is a trial version that requires a serial number...

  How can I install my month Acrobat Pro XI to the version of the subscription month starting on another computer? All I can get is a trial version that requires a serial number... when I go to download from my account it is still asking me to pay again?

  Hello

  There is no serial number associated with the subscription.

  Please check the help below document:

  Applications creative Cloud back in test mode after an update until 2015 for CC

  Kind regards

  Sheena

• If you upgrade or change your plan, resets the start date?

  See the question above. I want to know if I upgrade/switch a plan, the start date of the subscription will be based on my initial contract or a new one?

  Not the start date is not reset. The payment date remains the same, the amount of charge are adjusted accordingly.

  Concerning

  Stéphane

• Determine if the end date is after the start date

  I have 2 date fields in a form.  When I click the button submit, that I'm trying to ensure that the end date is after the start date.

  Here is the code I use:

  var sDate = Date.parse (BackgroundInformation.Background.CheckingDateStart.rawValue);

  var eDate = Date.parse (BackgroundInformation.Background.CheckingDateEnd.rawValue);

  xfa.host.messageBox ("Start Date:"+ BackgroundInformation.Background.CheckingDateStart.rawValue ");

  xfa.host.messageBox ("eDate: sDate" + eDate + ":" + sDate);

  if(sDate > eDate)

  	{
  	valid = false;
  	fieldName += "Start Date is greater than the end Date."
  	}

  The message box displays the start date 2014-10-30 but sDate is Nan.

  I tried:

  var eDate = new Date (BackgroundInformation.Background.CheckingDateEnd.rawValue);

  sDate var = new Date (BackgroundInformation.Background.CheckingDateStart.rawValue);

  and when I display sDate says 'Invalid Date '.

  Any ideas?

  It should work...

  var sDate = BackgroundInformation.Background.CheckingDateStart.value.date.value;

  var eDate = BackgroundInformation.Background.CheckingDateEnd.value.date.value;

  xfa.host.messageBox ("eDate: sDate" + eDate + ":" + sDate);

  if(sDate > eDate)

  	{
  	valid = false;
  	fieldName += "Start Date is greater than the end Date."
  	}