REGEXP_COUNT on the string containing * or /.

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  If (test.) IndexOf("\\") > = 0) seems to knock on a string that is 'ss\\ss', but I have a feeling that is incorrect. I think it's really just test for 1 backslash.

  AS3 and don't let you do if (test.indexOf("\") > = 0), as the single backslash escapes the rest of your code.

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  {if(s.IndexOf("\\\")>-1})

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  There is that a single backslash

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  Hello, I created an application to read data from a serial port device. The problem is that the device, at startup, displays a block of text that contain characters describing the device. Shortly after, he displays a command prompt "command:" it's when I want my VI to enter the command to start to take action.

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• How to convert the Ascii string containing hex to hex string info?

  Dear all,

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  Bio,.

  This should do what you want.

• Check that a string contains data only numbers

  Hello

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  (3) using the 'Decimal string to Number.vi' with an offset of 1, the result is a number.

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  You can use a regular expression to match the pattern.

  

• REGEXP_REPLACE problem with special characters in the string

  Hi guys,.
  
  I have had problems using the REGEXP_REPLACE function and I'm trying to find a solution.
  
  The closest I can get is this thread:
  
  Re: How to replace the first occurrence of a substring
  
  and that's only because the solution, I'm trying to achieve is the one suggested. I did ppost my problem there, but because it is answered, I don't have an answer.
  
  I'm doing the following:
  

  select 
    regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|',
    '^(\w|-)*\|{1}',null)
  from dual

  Basically, replace it does not work, because the first part of the string contains an asterisk. If you delete the Asterix, then replace it won't work.
  
  How can I get around this? I can't use a regular REPLACEMENT as I want to remove the first instance of A * and not all instances of the A.
  
  Help, please! I don't know what to do... probably, I mustn't start a loop through the string?
  
  Thanks in advance guys!
  
  Robin

  User_resU wrote:
  I want to remove the first instance of A * and not all instances of the A.

  To decode your regular expression, it seems that you want to remove A * | and not just A *.

  SQL> select   regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31
  |A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|
  EP|||_|AA|2151|G31|A|||_|',
    2    '^(\w|-)\*\|{1}',null) reg
    3  from dual;
  
  REG
  --------------------------------------------------------------------------------
  
  A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR
  
  |H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|
  

• Bug: Find/replace does not work if the statement contains the string is too long

  Hello

  in my sequence, I press Ctrl + F to open the Find dialog box and enter a string. All the checkboxes are checked 'Elements for search' and ' limit the search to "is not enabled.

  Now comes the finding it is only announcing the discovery in the main sequence.

  Other places in a sous-suite that are part of a labview vi action setting is not in the list. Also if I open the sequence and I'm looking at this place.

  If I create a comment in the subsequence containing the searchstring, then it is.

  When I open the properties of the action of labview and open the parameter that contains the string and click on check for errors, and then close all and supplementary search then the value lies.

  Is it possible that the variable is too long setting? It's about 200 characters and one thing very nested SationGlobals and the table and the TestSockets. Search string Dees is finally an arrayindex in this grand statement.

  It seems that this is the problem.

  Is this a known bug?

  Solved.

  There was an empty character at the end of the search string...

• Is there a way to parse a string containing % (percentage symbols) using the function 'analysis of the chain?

  I am communication in series with a mirror device and the syntax of the input string contains this text: "% hr ="

  I was not able to find a way to say to the function that the percentage here is not a format specifier. Is it possible, or should I just try to use a different function?

  Thank you.

  Use %% in your format string for what he knows to use the percent literally.  So % RH = %f

  

  EDIT: Darin has one here in front of me.  It seems to be-% and % both work.

• Order findstr/l/s/m print the file names of all the files in the directories and subdirectories despite any string contained

  Hello

  I'm looking for a file via the findstr command. After that I opened the command as Administrator window, I get:

  Findstr/l/s/m 'a string containing the words. " *

  Then, the command window displays all the files in the directory and its subdirectories. I think that I see which file is searched for the chain in real time.

  I expected to see only the name of the file/s if the string was found in it.

  What I am doing wrong? or why is this malcfunctionaning?

  I got directions for ordering findstr here: https://technet.microsoft.com/en-us/library/bb490907.aspx

  Thank you

  I think you want the /c parameter instead a / l.  As written, your search string is interpreted as a list of strings: 'a', 'string', 'with' and 'words '.  Any file that contains an 'a' will be a return match.  The parameter/l keeps your strings to be interpreted as regular expressions.

  If you need exactly match to the entire chain, type:

  Findstr /s/m/c: "a string containing the words." *

  Under the direction of add: It is not clear, but you can have several settings/c , to search for more than one exact string at a time.  For example:

  / s/m/c: 'a string' findstr / c: "a Word." *

  Research is 'a string' or 'a word' exactly.

• Check if a string contains "text" in a box, and only if it does not, add it to the chain.

  I have some comboboxes. I want a text field to add a channel to itself, that contains the text selected in each combobox. I got it with this:

  var a = this.getField ("CoBi_text");

  for (i = 1; i < 16; i ++) {}

  var t = (this.getField("CoB_"+i).valueAsString);

  Si (t ! = « ») {}

  a.Value += t + ',';   }   }

  But what adds text even though I select the same option in any of the combobox control. How can I include a conditional don't skip the increment if "the text is already in the string?  I tried this:

  If ((t! = «») & & (a.value.indexOf ("t") < 0)) {}

  a.Value += t + ',' ;}

  But it causes the chain add the text first, don't increment not any text more after that.

  PS. This text field will be hidden and later used on another condition (if it contains 'a specific text'), some other triggering actions.
  So the ',' (comma) is probably not necessary, but I think that it should not be in the way of a proper search indexOf (right?)

  Thank you.

  eHRM, nevermind. I got it.

  the "t" inside indexOf should not "s...".

  var a = this.getField ("CoBi_text");

  for (i = 1; i<16;i++)>

  var t = (this.getField("CoB_"+i).valueAsString);

  If ((t! = «») & (a.value.indexOf (t))<0) )="">

  a.Value += t + ',' ;}

  Now, he adds "text", but not more than once for each different text on each drop-down list.

  There is always the question of the modification of a selected item in a combobox control, how do I remove the old text from the text box but I think than any forced recalculation should be enough.

  Thank you for taking the time to respond and for the link!

• How to get a paragraph that contains the string selected in FDK?

  Hello
  
  I am writing a program that extracts content of the paragraph that contains a selection string. This program runs in the interaction point menu. When the user click on the menu item. The process as follows:
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  Hi thai,

  Paragraph ID is returned as part of the structure of F_TextRangeT, as the Member "objId". Let's say you have:

  F_TextRangeT tr;

  ... then:

  TR = F_ApiFind (...);

  On an action to search with success, "tr" will contain the pgfId of the paragraph. I'm assuming you're looking for a string that is entirely contained in a paragraph, in which case two ways contains the ID of the paragraph:

  tr.beg.objId

  TR.end objId

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  F_TextItemsT ti;

  F_TextRangeT tr;

  F_ObjHandleT docId.

  ...

  TR = F_ApiFind (...);

  TR. Beg.offset = 0;

  TR.end.Offset = FV_OBJ_END_OFFSET;

  TI = F_ApiGetTextForRange (docId, & b, FTI_String);

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  2 - the message I get (translated from french to English):

  

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