Removal of duplicate records: (please respond to it ::))

Similar Questions

• Delete several duplicate records

  Hi all
  My table has multiple records, and I want to keep only the first record in the table. Can someone help me on this. I tried following things:
  SELECT * FROM the tab
  WHERE ROWID in (SELECT MAX (ROWID) <>
  IN tab B
  WHERE B.col1 = A.col1
  AND B.col2 = A.col2
  )
  This remove the last duplicate record.
  I also tried
  SELECT * FROM the tab
  WHERE ROWID > (SELECT MIN (ROWID)
  IN tab B
  WHERE B.col1 = A.col1
  AND B.col2 = A.col2
  )
  This was removed and the first record to some places, but it has worked in some places. I am not able to understand why it was wrong in some places.
  I'm working on Oracle 10 g
  Please suggest.
  
  Thank you.

  Duplicate records mean reproduce according to specific columns (in your example, col1 and col2).
  If you want the trial to be held, you must determine all first according to what, if you mean the first entered record (which is not safe, and you should rely on an explicit column).
  You can use

  SELECT *
    FROM tab A
   WHERE ROWID NOT IN (SELECT MIN (ROWID)
                         FROM tab B
                        WHERE B.col1 = A.col1 AND B.col2 = A.col2)
  

  or use a column

  SELECT *
    FROM tab A
   WHERE col3 NOT IN (SELECT MIN (col3)
                         FROM tab B
                        WHERE B.col1 = A.col1 AND B.col2 = A.col2)
  

  Saad,

• How to store the original and to remove some duplicate songs in iTunes on a PC Win7, which took place after iTunes to scan for music during a re - install?

  How to store the original and to remove some duplicate songs in iTunes on a PC Win7, which took place after iTunes to scan for music during a re - install?

  I recently had to format my hard drive and reinstall iTunes 12.3.2.35 on my Win7 PC. As part of the re - install iTunes, I clicked on the button scan for music.  This has created duplicates several of my songs.  I deleted then the duplicate songs from iTunes, but when I went to play a few songs a pop-up said "the song would not be because the original could not be found.  You want to locate? "When I tried to locate the song it is not found, but when I pulled the songs out of the trash they could be found.

  How can I keep the original and remove any duplicate songs in iTunes on PC Win7 which took place after iTunes to scan for music during a re - install?

  iTunes can create duplicates if the same content is added several times from outside the media folder when it is about to make copies of everything that is added to the library, or is added from an external drive that hosts the press kit that was disconnected during the launch of iTunes.

  Official notice of Apple on the duplicates is here: find and remove duplicates in your iTunes library. This is a manual process and article fails to explain some of the potential pitfalls such as the lost coast and membership of playlist, or sometimes the same file can be represented by multiple entries in the library as well as a removal and recycling the file will break all the others.

  Use MAJ > display > show items to reproduce exactly to display the duplicates because it is normally a selection more useful. You must manually select all but one of each group to remove. Sort the list by Date added can make easier select appropriate tracks, but it works better when executed immediately after the dupes were created.  If you have several entries in iTunes connected to a same file on the disk hard then don't not send to trash.

  Use my DeDuper script (Windows only) If you are not sure, do not want to do it by hand, or want to maintain ratings, play counts and playlist membership. See this background thread , this post for detailed instructions and Please take note of the warning to back up your library before deduping.

  (If you don't see the menu bar press ALT to temporarily view or CTRL + B to keep displayed.)

  The latest version of the script can put away the dead links as long as there is at least a double live to merge his stats and membership of the playlist and must deal wisely when the same file has been added through multiple paths.

  TT2

• Remove boot run record vain NTSTATUS = 0 xC0000001

  Hello

  I have this message to the slieshow of my laptop but it started anyway! Remove boot run record vain NTSTATUS = 0 xC0000001's grave this? And that do pay message of what he's got rain? My EST 7 64 windows O.S

  Hello

   
   
  Please select your language from the drop-down menu above to post your question in the language of your choice. The forum in which you've posted is for English only. If you can't find your language above, support for additional international sites options are by following the link below:
   
   
  http://support.Microsoft.com/common/international.aspx
   
   
  I hope this helps.

• I have to remove the duplicate files, but having problems by selecting more than one file in the player at the time.

  I have to remove the duplicate files, but having problems by selecting more than one file in the player at the time. How can I select multiple files at the same time so I can just delete them. I used to be able to do this in previous versions of Media Player, but this function seems now blocked or unavailable. The problem is this: through previous use of media player, it plays all my multimedia files several times whenever a device support has been added. He would try to save the files on my main drive, but since there is not enough room this would save the files somewhere else. This happened several times, I suppose, because when I upgraded my computer and a media scan was conducted he found duplicates of all my media various times of at least 6-8. I've consolidated since my plates on 3-disc multi to, but have now records duplicated hundreds and thousands of duplicate media files. Previous versions of Media Player would allow me to select all files and then delete them both of the reader, but also from my hard drive. So now I'm stuck with more than 300 GB of duplicate media I have to search line by line through all my hard drives to find each duplicate both, unless I can get media player to do what it can. Any help in this area would be appreciated.

  Hello

  1. did you of recent changes on the computer?

  2. is Windows media player files in double creation during playback of music files?

  To delete duplicate entries, click on another feature tab in the drive (for example the current playback), and then click library.
  
  If this does not remove duplicates from your library, you can use the Add to library dialog box to search computer to analyze a file on your computer the duplicate entries not valid-pointing. The player will remove invalid entries in your library that point to files that no longer exist in the folder.

  Complete the steps above for files that are stored in the hard disks.

  Method 1: Use the add to Library dialog box search for computers

  (a) start Windows Media Player.
  
  (b) press F3 on your keyboard to open Add to the library of the find computers dialog box.

  (c) click the Browse button to locate the folder on your computer so that your library contains invalid entries. Specify the location of the folder in the box look in.

  If you are not sure what duplicate in your library entry is not valid, you can add a path column to display in your library. Specify the folder on your computer that corresponds to the path not valid file displayed in your library.
  
  (d) click on the Search button.

  The player will search for digital media files and playlists in the folder that you specify and remove invalid entries in your library that point to files that no longer exist in the folder. If not valid in double entries point to other folders on your computer, repeat this procedure, specify a different folder every time.

  If only a small number of duplicate entries exist, you can delete those invalid manually by right-clicking on the invalid entry, and then clicking Delete .
  
  For large double-number of entries in your library (or if all your library is duplicated), it might be better to create a new library and delete the files.

  Method 2:

  After you remove the duplicate entries, run the troubleshooting of Windows Media Library settings to solve this problem.

  Open the troubleshooter in Windows Media Library

  http://Windows.Microsoft.com/en-us/Windows7/open-the-Windows-Media-Player-library-Troubleshooter

  Let us know the results.

  I hope this helps.

• Matching records between 2 tables with duplicate records

  Hi all

  I need help in what follows.

  I have 2 tables Received_bills and Send_bills.

  -------------------------------------------------------

  -The DOF for Table SEND_BILLS

  --------------------------------------------------------

  CREATE TABLE SEND_BILLS

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  --------------------------------------------------------

  -The DOF for Table RECEIVED_BILLS

  --------------------------------------------------------

  CREATE TABLE 'RECEIVED_BILLS '.

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE),

  VARCHAR2 (5 BYTE) 'STATUS' )  ;

  INSERTION of REM in RECEIVED_BILLS

  TOGETHER TO DEFINE

  Insert. RECEIVED_BILLS (DATUM, PAYMENT, CODE, STATE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'SUCCESS');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 'A5', 'SUCCESS', 25);

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4', 'FAILED');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'FAILED');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'SUCCESS');

  INSERTION of REM in SEND_BILLS

  TOGETHER TO DEFINE

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  I match all records of send_bills and received_bills with a status of 'SUCCESS' There is no single column in the table.

  Correspondence held payment of columns, the code and the scratch cards, but it may also duplicate records. But even if there are duplicates, I also need those records in the query results

  the query I wrote is this:

  SELECT SEND.*

  REC received_bills, send_bills send

  WHERE send.datum = rec.datum

  AND send.payment = rec.payment

  AND send.code = rec.code

  AND 'rec.status =' SUCCESS

  ;

  The query results give me this

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5

  The result of the correct application would be

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	19	A1

  The select statement that I need I want to use a loop to insert records in another table.

  Can someone help me please?

  Thanks in advance.

  Best regards

  Caroline

  Hi, Caroline.

  Caroline wrote:

  Hi all

  I need help in what follows.

  I have 2 tables Received_bills and Send_bills.

  -------------------------------------------------------

  -The DOF for Table SEND_BILLS

  --------------------------------------------------------

  CREATE TABLE SEND_BILLS

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE)

  )  ;

  --------------------------------------------------------

  -The DOF for Table RECEIVED_BILLS

  --------------------------------------------------------

  CREATE TABLE 'RECEIVED_BILLS '.

  (DATE OF "DATUM",

  NUMBER OF "PAYMENT."

  'CODE' VARCHAR2 (5 BYTE),

  VARCHAR2 (5 BYTE) 'STATUS');

  INSERTION of REM in RECEIVED_BILLS

  TOGETHER TO DEFINE

  Insert. RECEIVED_BILLS (DATUM, PAYMENT, CODE, STATE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'SUCCESS');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 'A5', 'SUCCESS', 25);

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4', 'FAILED');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'FAILED');

  Insert into RECEIVED_BILLS (PAYMENT, CODE, DATE, STATUS) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1', 'SUCCESS');

  INSERTION of REM in SEND_BILLS

  TOGETHER TO DEFINE

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 47, 'A4');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('09-OCT-15','DD-MON-RR'), 19, 'A8');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 20, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 19, 'A1');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  Insert into SEND_BILLS (DATUM, CODE) values (to_date('10-OCT-15','DD-MON-RR'), 25, 'A5');

  I match all records of send_bills and received_bills with a status of 'SUCCESS' There is no single column in the table.

  Correspondence held payment of columns, the code and the scratch cards, but it may also duplicate records. But even if there are duplicates, I also need those records in the query results

  the query I wrote is this:

  SELECT SEND.*

  REC received_bills, send_bills send

  WHERE send.datum = rec.datum

  AND send.payment = rec.payment

  AND send.code = rec.code

  AND 'rec.status =' SUCCESS

  ;

  The query results give me this

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5

  The result of the correct application would be

  OCTOBER 10, 15	19	A1
  OCTOBER 10, 15	25	A5
  OCTOBER 10, 15	19	A1

  The select statement that I need I want to use a loop to insert records in another table.

  Can someone help me please?

  Thanks in advance.

  Best regards

  Caroline

  Want to get answers that work?  Then make sure that the CREATE TABLE and INSERT statements you post too much work.  Test (and, if necessary, correct) your statements before committing.  You have a stray "." in the first INSERT statement for received_bills and receikved_bills.status is defined as VARCHAR2 (5), but all values are 6 characters long.

  There are 5 lines in send_bills that are similar to the

  10 OCTOBER 2015 19 A1

  Why do you want that 2 rows like this in the output, not 1 or 3, or 4 or 5?  Is it because there are 2 matching rows in received_bills?  If so, you can do something like this:

  WITH rec AS

  (

  SELECT the reference, payment, code

  , ROW_NUMBER () OVER (PARTITION BY datum, payment, code)

  ORDER BY NULL

  ) AS r_num

  OF received_bills

  Situation WHERE = 'SUCCESS'

  )

  send AS

  (

  SELECT the reference, payment, code

  , ROW_NUMBER () OVER (PARTITION BY datum, payment, code)

  ORDER BY NULL

  ) AS r_num

  OF send_bills

  )

  SELECT send.datum, send.payment, send.code

  REC, send

  WHERE send.datum = rec.datum

  AND send.payment = rec.payment

  AND send.code = rec.code

  AND send.r_num = rec.r_num

  ;

  Note that the main request is very similar to the query you posted, but the last condition has changed.

  If you need to insert these lines in another table, you can use this query in an INSERT statement. There is no need of a loop, or for any PL/SQL.

• Check duplicate record all by preventing insertion

  Hello

  I have a scenario where I need to insert records from 20 000 to 30 000 daily in a table that has data in millions.

  Keep inserting a record in duplicate and in the event of any duplicate record, this issue need to be logged in another table.

  I used FORALL except SAVE to allow loading of all records not not duplicate. But with this approach, I am unable to know which record was duplicate or problems in the insertion.

  Also I can't use triggers to connect each record before insertion because I only need the duplicate records. Also, trigger will slow down performance.

  Guide kindly on what approach I should follow to do this (which are also good performance as data are huge).

  Kind regards

  Karki

  Logging error clause does not support dyrect path operations, you must remove the Add indicator to use.

  This is because the logging of errors using autonomous transaction.

  create table test_tomkt_raw
  (c1 varchar2(20),
  c2  varchar2(20),
  c3  varchar2(20));
  
  Table created
  
  Executed in 0,015 seconds
  create table test_mkt
  (c1 varchar2(20),
  c2  varchar2(20),
  c3  varchar2(20));
  
  Table created
  
  Executed in 0,031 seconds
  create table test_mkt_log
  (c1 varchar2(20),
  c2  varchar2(20),
  c3  varchar2(20));
  
  Table created
  
  Executed in 0,078 seconds
  insert into test_tomkt_raw VALUES( 'A','B','C');
  
  1 row inserted
  
  Executed in 0,015 seconds
  insert into test_tomkt_raw VALUES( 'A','B','C');
  
  1 row inserted
  
  Executed in 0 seconds
  insert into test_tomkt_raw VALUES( 'D','E','F');
  
  1 row inserted
  
  Executed in 0 seconds
  insert into test_tomkt_raw VALUES( 'R','BD','AC');
  
  1 row inserted
  
  Executed in 0 seconds
  insert into test_tomkt_raw VALUES( 'AQ','SB','AC');
  
  1 row inserted
  
  Executed in 0,016 seconds
  insert into test_tomkt_raw VALUES( 'AA','BA','CA');
  
  1 row inserted
  
  Executed in 0 seconds
  insert into test_tomkt_raw VALUES( 'A','B','C');
  
  1 row inserted
  
  Executed in 0 seconds
  insert into test_tomkt_raw VALUES( 'D','E','F');
  
  1 row inserted
  
  Executed in 0,016 seconds
  ALTER TABLE test_mkt
  ADD PRIMARY KEY (C1,C2,C3);
  
  Table altered
  
  Executed in 0,015 seconds
  BEGIN
    DBMS_ERRLOG.CREATE_ERROR_LOG('test_mkt');
  END;
  /
  
  PL/SQL procedure successfully completed
  
  Executed in 0,031 seconds
  INSERT /* APPEND */
  INTO TEST_MKT
  SELECT * FROM  TEST_TOMKT_RAW
  LOG ERRORS INTO ERR$_TEST_MKT ('TEST_01') --> This can be a variable on your code to identify this operation
  REJECT LIMIT UNLIMITED
  ;
  
  5 rows inserted
  
  Executed in 0,063 seconds
  INSERT INTO test_mkt_log
  SELECT er.c1, er.c2, er.c3
  FROM  ERR$_TEST_MKT er
  WHERE  er.ora_err_tag$ = 'TEST_01'--> This can be a variable on your code
  AND    er.ora_err_number$ = 1 --> Unique constraint violated
  ;
  
  3 rows inserted
  
  Executed in 0 seconds
  SELECT *
  FROM  TEST_MKT
  ;
  
  C1                  C2                  C3
  -------------------- -------------------- --------------------
  A                    B                    C
  AA                  BA                  CA
  AQ                  SB                  AC
  D                    E                    F
  R                    BD                  AC
  
  Executed in 0,062 seconds
  SELECT *
  FROM  TEST_MKT_LOG
  ;
  
  C1                  C2                  C3
  -------------------- -------------------- --------------------
  A                    B                    C
  A                    B                    C
  D                    E                    F
  
  Executed in 0,047 seconds
  DROP TABLE  test_tomkt_raw;
  
  Table dropped
  
  Executed in 0,032 seconds
  DROP TABLE  test_mkt;
  
  Table dropped
  
  Executed in 0,094 seconds
  DROP TABLE  err$_test_mkt;
  
  Table dropped
  
  Executed in 0,078 seconds
  DROP TABLE  test_mkt_log;
  
  Table dropped
  
  Executed in 0,047 seconds
  

• How to remove all duplicate in my PHOTO collection

  Having a little problem, after I gathered all my photos in my hard drives many duplicates of photos in my albums, that I need to clean it. Under SEARCH in the help at the top bar on the left there is a Visual search to find duplicate photos, but how do you remove them? Can someone help me please in this case? Thank you

  Hi Mr.Ed.,.

  Could you please confirm whether the name of the image are the same or if the images looks like same.

  Please visit the following link: find and remove the duplicate Images in Lightroom | Lightroom training Laura shoe, tutorials and tips

  Kind regards

  Tanuj

• ROW_NUMBER and duplicate records

  Hello
  
  Tried to delete duplicate records. The code below works, but would remove all, rather than simply the > #1 records:
  
  (SELECT academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number, rowid that RID, row_number() over (partition of)
  academic_period, load_week, sub_academic_period, person_uid, course_number,
  order of course_reference_number of academic_period, load_week, sub_academic_period,
  person_uid, course_number, course_reference_number)
  Of THE cea
  WHERE (academic_period, load_week, sub_academic_period, person_uid, course_number,)
  IN course_reference_number)
  (SELECT academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number
  Of THE cea
  GROUP of academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number
  HAVING COUNT (*) > 1))
  
  
  If I try to put 'rn' and rn > 1, I get ora-00933: Sql not correctly completed command
  
  SELECT academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number, rowid that RID, row_number() over (partition of)
  academic_period, load_week, sub_academic_period, person_uid, course_number,
  order of course_reference_number of academic_period, load_week, sub_academic_period,
  person_uid, course_number, course_reference_number): the nurse
  Of THE cea
  WHERE (academic_period, load_week, sub_academic_period, person_uid, course_number,)
  IN course_reference_number)
  (SELECT academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number
  Of THE cea
  GROUP of academic_period, load_week, sub_academic_period, person_uid, course_number,
  course_reference_number
  After HAVING COUNT (*) > 1)
  and rn > 1
  
  I tried to remove as"rn" and make "rn" and "rn", which gave me an error of syntax also. The '' rn > 1 and '' clause gets an error of syntax also. I gone through a bunch of different Web sites. All of this indicates the syntax I am using will work. However, any query I run into a TOAD, always error when I include the 'rn > 1.
  
  Any ideas? Thank you!
  
  Victoria

  You mix two ways to identify duplicates.

  One way is HAVING:

  SELECT academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number
  FROM cea
  GROUP BY academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number
  HAVING COUNT(*) > 1)
  

  That tells you just what combinations of your group are more than once.

  Another way is to analytical functions:

  select *
  from (
    SELECT academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number
           count(*) over (partition by academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number) cnt
    FROM cea
  )
  where cnt > 1
  

  This will all return duplicate records - if some combinations has three duplicates, then this will return all three lines.

  If you use the ROW_NUMBER() place COUNT() analytical analytical function, you get this:

  select *
  from (
    SELECT academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number
           row_number() over (partition by academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number) rn
    FROM cea
  )
  where rn > 1
  

  All of these files without duplicates will get rn = 1. Those with duplicates gets rn = 1, rn = 2... If rn > 1 Gets all "unnecessary" records - the ones you want to remove.

  If a deletion might look like:

  delete cea
  where rowid in (
    select rid
    from (
      SELECT ROWID as rid,
             row_number() over (partition by academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number) rn
      FROM cea
    )
    where rn > 1
  )
  

  Or if you want to manually inspect before you delete ;-):

  select *
  from cea
  where rowid in (
    select rid
    from (
      SELECT ROWID as rid,
             row_number() over (partition by academic_period, load_week, sub_academic_period, person_uid, course_number, course_reference_number) rn
      FROM cea
    )
    where rn > 1
  )
  

  In another answer, you can find a way to remove duplicates with HAVING.
  The point is that do you it either with or with ROW_NUMBER() - not both HAVING ;-)

• How to delete duplicate records

  Suppose I have a table with N columns and K TAB (K < N) for which I should not have duplicated (in other words, the K column can be a key primary candidated)
  Can you give me a SQL query to delete duplicate records of TAB for columns K?
  Thank you very much!

  remove the tab where rowid not in (select min (rowid) of the TAB group by k)

• remove the duplicate

  Hi all
  
  I have a table like
  
  tbl1
  ----
  Identification number
  name varchar2
  I have some duplicate records
  
  for ex:
  
  ID
  --
  1
  1
  2
  2
  2
  
  
  I need the sample script to delete some records until my unique id
  as
  
  ID
  --
  1
  2
  
  
  Help, please

  RowID is useful :D

  delete from table
  where RowID not in(select min(RowID) from table
                     group by id);
  

• "Compression" duplicate records over time

  Hi, I've been fighting with a problem for a while now and don't know how to solve. I have data that looks like this:
  
  
  Code1... Code2... Start_Dt... End_Dt
  A.......... A......... 1/1/2000...12/31/2000
  A.......... A......... 1/1/2001...12/31/2001
  A.......... B......... 1/1/2002...12/31/2002
  A.......... B......... 1/1/2003...12/31/2003
  A.......... A......... 1/1/2004...12/31/2004
  A.......... A......... 1/1/2005...12/31/2005
  A.......... A......... 1/1/2006...12/31/2006
  
  What I would do in the data store is 'compress' duplicate records, so that the final result should look like this:
  
  Code1... Code2... Start_Dt... End_Dt
  A.......... A......... 1/1/2000...12/31/2001
  A.......... A......... 1/1/2002...12/31/2003
  A.......... B......... 1/1/2004...12/31/2006
  
  I can't figure a way to do it. I can just say:
  
  Select code1, code2, min (start_dt), max (end_dt)
  
  because I get A codes / has, from 01/01/2000 through 12/31/2006 - is not just, they have changed between the two.
  
  Does anyone know of a way to do this (base mode GAME please... not to write PL/SQL and do a rank at a time).
  
  Thanks in advance,
  Scott

  Hi Scott,.
  Try this SQL

  select a_code,b_code,group_id,min(start_date,max(end_date) from
  (select q.*,sum(change_flag) over (partition by a_code,b_code) group_id
          from
          (SELECT a_code,
                  b_code,
                  start_date,
                  end_date,
                  CASE
                  WHEN a_code = lag(a_code,1) over (partition by a_code,b_code ORDER BY start_date)
                     AND b_code = lag(b_code,1) over (partition by a_code,b_code ORDER BY start_date)
                  THEN 0 ELSE 1 END change_flag
                  FROM stp_test) q
  ) q2 group a_code,b_code,group_id
  

  Kind regards
  Oleg

  Edited by: oleg2 09/22/2009 06:30 - Add Group by at the end

• remove the last record from the plsql table

  TYPE r_LOOPElement IS RECORD (TermID   NUMBER 
                                        );
  
  TYPE t_LOOPType IS TABLE OF r_LOOPElement INDEX BY BINARY_INTEGER;
  i_CustomerLoop      t_LOOPType ;
  
  i_CustomerLoop(1).TermID=1;
  i_CustomerLoop(2).TermID=2;
  i_CustomerLoop(3).TermID=3;

  Under certain conditions, I need to remove the last record from i_CustomerLoop
  
  whichi s the best way to do it. because I sometimes get duplicates for TermID in this plsql table.

  Hello

  See [removing items from Collection (DELETE method) | http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28370/collections.htm#CJAFGFIG]

  Kind regards

• I have an ebookbrowse toolbar icon right next to my home screen icon. I can't understand how do to remove/uninstall it. Please notify.

  I accidentally visited the site to browse e-books, and apparently the site installed her own boyfriend of toolbar in firefox. I can't understand how to remove it. Help, please

  See also:

  • http://KB.mozillazine.org/Uninstalling_add-ons
  • http://KB.mozillazine.org/Uninstalling_toolbars

• I do understand the benefit of "Options" tab utilities and want to remove it. How, please?

  I do understand the benefit of "Options" tab utilities and want to remove it. How, please? I tried this feature because the tab 'Fox' was no longer available with the 5.0 update.

  I loved tab 'Fox '. A click and go on a site added you to 'top sites' before. The update 5.0, this feature is no longer available. It was a disappointment. There is a similar feature "add on" that is, as tab 'Fox' compatible with 5.0. If yes I would like to know about it. Or better yet... make it usable with Firefox 5.0 ' Fox' tab if upgrades cancel features previously downloaded that work really... What's the point?

  Please click the button solved it next to the answer that solved your problem of Firefox support, it appears when you are connected, so this thread is marked as resolved to help other users who may have this same problem.