Remove characters from a field
HelloWhat is the syntax to remove "" go around a field value?
Will that eliminate the 3 series of ' ' value? (as in "'' value' '")
Thank you
>
A select statement, the "regexp_replace" works perfectly.
When I try to do an update, I get an 'incorrect table name' error - with or without the apostrophes...
I couldn't get the first to work at all.
the script;
UPDATE
SET "FIELDHEADING' = regexp_replace ('FIELDHEADING', ' ^ (" "" ")(.*) (" "" ") $', '\2')
OF TB_REV_1
>
It is not at all what you're trying to reach. What is FIELDHEADING? What is a column? If so, it doesn't take much quotes in DML. See doc UPDATE: http://download.oracle.com/docs/cd/E11882_01/server.112/e10592/statements_10008.htm#i2067715
Display all such information as described in the article "How to ask questions" is the best way to get issues resolved.
The regexp_replace works as follows:
The first argument is the string to match.
The second is the regular expression, the string is compared to.
The third argument has the value will replace the first string substrings that match the regular expression.
^ - indicates the beginning of the string
$ - indicates the end of the string
. -matches any character
* - means zero or more instances of the previous item
() - items in groups.
If ' ^ ("" "")(.*) ("" "") $"matches all of the first chain - all characters - if it starts and ends with groups of 3 quotes.
\2 - is a reference back, referring to the groups in the regular expression in the order, so \2 means in this case (. *): all the characters between the quotes groups.
All correspondence to the rational expression is replaced with the 2nd element in the expression.
Takes more time to explain what to write... :-)
http://en.Wikipedia.org/wiki/Regular_expression
Tags: Database
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