remove items from a table on a user defined range

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• remove items from the table

  Hi all

  If I have the table as

  var my_Arr:Array = new Array ("a", "b", "c");

  and I have a button to use a random element of the array of ths, y at - it no to remove this element if I press the button once again I don't think the last item?

  could someone help me...?

  thnx

  Wael
  

  
  

  var someArray:Array = [1,2,3,4,5,6,7,8,9];

  someArray.shift (); remove the first value (1)

  someArray.pop (); remove final value (9)

  If you type: untableau. then comes a list of possibilities and you can see that makes each of them, e.g. .reverse probably reverse the table e.g. 9, 8, 7... etc.

• remove items from the table and resize the matrix

  Hello, I'm new to Labview so I'm struggling with ideas. I have the following matrix

  A = [1 2 3 4

  5 6 7 8

  9 10 11 12

  13 14 15 16]

  I want to get only follows resized in a matrix with items 6, 7, 10 and 11, that is

  B = [6 7

  10 11]

  I appreciate your help

  On the table-online matrix palette, there is a function to get a submatrix.

• It is usually safe to remove items from the user / local/temp file? I want to free up space.

  Original title: local/temp folder files

  It is usually safe to remove items from the user / local/temp file?  I want to free up space.

  Clean the system (compensation to all temp/tmp folders and included all the content offline, the tif browser, delete the cookies of compensation.)

  Do a disk cleanup. Click the Start button. in the search box, type Disk Cleanup, and then in the list of results, click Disk Cleanup.

  Delete your temp files where a large number of software malware installers cache and or CCleaner for a more thorough cleaning.

  Download the basic version (slim) via

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  The basic version (slim) does not contain the toolbar disgusted

  Cleaning DO NOT USE ANY Advanced options. DO NOT TOUCH THE REGISTRY OR TOOLS. At least not for now.
  Reset

  UTC/GMT is 04:20 on Thursday, January 5, 2012

• On my iPad, I would like to remove items from the iBook

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  You can remove books/PDFS downloaded/synchronized to the iBooks via the button in the top right of the shelf

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• Windows Live Movie Maker 2011 - how to remove items from the recent projects list

  Windows Live Movie Maker 2011

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  How to remove items from the numbered list of recent projects?  What are the (thumb)

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  Hello

  The question you have posted is related to Windows Live Movie Maker and would be better suited in the Windows Live Solution Center. Please visit the link below to find a community that will provide the best support.

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  Microsoft Answers Support Engineer

• Removing items from Launcher: deleted Web "Bookmark" but miniature rest Launcher?

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  Why are there not something simple to remove items from the Launcher?  Which of the following you can remove and how?

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• remove items from a collection

  Hi all

  I have a record type, and I want to delete items, if second and third attribute of the current record is the same as an attribute of second and third the previous record. Here is an example:

  declare
    type t_serv is record (
      a varchar2(10),
      b varchar2(10),
      c number(5),
      d number(5)
    );
    
    type t_serv_tab is table of t_serv;
    x t_serv_tab;
  begin
    x := new t_serv_tab();
    x.extend;
    
    x(x.last).a := 'DSL';
    x(x.last).b := 'ADSL';
    x(x.last).c := 100;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'ADSL';
    x(x.last).c := null;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'IPTV';
    x(x.last).b := 'N/A';
    x(x.last).c := null;
    x(x.last).d := null;
    
    x.extend;
    x(x.last).a := 'CABLE';
    x(x.last).b := 'CATV_FTTH';
    x(x.last).c := 50;
    x(x.last).d := null;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'VDSL';
    x(x.last).c := 100;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'VDSL';
    x(x.last).c := 100;
    x(x.last).d := null;
    
  -- in this case, elements from 2nd and 6th position are deleted, as they have similar "a" and "b" attributes as the previous record's "a" and "b"
    for i in x.first..x.last loop
      if i>1 then -- if I don't put this, I got an Subscript outside limit error
        if x(i).a = x(i-1).a and x(i).b = x(i-1).b then
          x.delete(i);
        end if;
      end if;
    end loop;
    
    -- print the final collection (should have 4 elements)
    for j in x.first..x.last loop
      dbms_output.put_line(x(j).a||', '||x(j).b||', '||x(j).c||', '||x(j).d);
    end loop;
  end;
  

  The problem is that I'm me ORA - 01403 No. data found error. And I understand why, because the last loop, loops within all the elements, but the 2nd and 6th items from the collection are deleted before.

  How can I solve this problem and to print the 4 remaining items?

  Thank you!

  The collections are rare objects, so unless you know collection has no deficiencies you should not use the LOOP for first time (before deletion) you know collection has no gaps, so you can use the FOR LOOP. However, since you remove elements, previous element of SEO via i - 1 is false, because I have element - 1 can be deleted. You must save the last element not removed. Now your impression share must assume at least an element has been removed and the collection is sparse (present gaps). Therefore, you must use LOOP, no LOOPS and use methods NEXT and LAST to iterate over the collection:

  declare

  type t_serv is (record

  a varchar2 (10),

  b varchar2 (10),

  c number (5),

  d number (5)

  );

  type t_serv_tab is table of the t_serv;

  x t_serv_tab;

  number of prev_i;

  Start

  x: = new t_serv_tab();

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = "ADSL"

  x (x.last) .c: = 100;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = "ADSL"

  x (x.last) .c: = null;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = 'IPTV ';

  x (x.last) .b: = "n/a";

  x (x.last) .c: = null;

  x (x.last) .d: = null;

  x.extend;

  x (x.last) .to: = "CABLE."

  x (x.last) .b: = "CATV_FTTH";

  x (x.last) .c: = 50;

  x (x.last) .d: = null;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = 'VDSL.

  x (x.last) .c: = 100;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = 'VDSL.

  x (x.last) .c: = 100;

  x (x.last) .d: = null;

  prev_i: = 1;

  I'm looping 2.x.last

  If x (i) (prev_i) .to .to = x and x (i) .b = x (prev_i) .b

  then

  x.Delete (i);

  on the other

  prev_i: = i;

  end if;

  end loop;

  -print the final collection (must have 4 elements)

  prev_i: = x.first;

  loop

  dbms_output.put_line (x (prev_i) .to | ',' | x (prev_i) .b | ',' | x (prev_i) .c | ',' | x (prev_i) .d);

  When the output prev_i = x.last;

  prev_i: = x.next (prev_i);

  end loop;

  end;

  /

  Scott@pdb1orcl12 > /.
  DSL, ADSL, 100, 20
  IPTV, N/A,
  CABLE, CATV_FTTH, 50.
  ADSL, VDSL, 100, 20

  PL/SQL procedure successfully completed.

  Scott@pdb1orcl12 >

  SY.

• How do I remove items from launch pad

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• Remove items from Menu in RH 8 Microsoft HTML layout

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• Removing items from Array Collection

  Hello. I have a collection of table that consists of the elements defined in the PlayListEntry class. I want to delete all items that have the property value select is set to false. That's what I came up with, it works fine, but only removes half of the items at once. I think it's because when you delete and point with removeitemat() it shifts the indexes of the items. How can I get around this?
  
  Code
  
  private function removeitems (): void {}
  
  for each {(var ple:PlayListEntry in songCollection)
  If (ple ['select']! = true) {}
  songCollection.removeItemAt (songCollection.getItemIndex (ple));
  
  }
  }
  }

  Here is a sample application that I wrote which allows to get what you are looking for.

  http://www.Adobe.com/2006/mxml"layout ="absolute">

  
  

  Import mx.collections.ArrayCollection;

  [Bindable] private var medalsAC:ArrayCollection = new ArrayCollection([)
  {Country: "USA", gold: 35, Silver: 39, Bronze: 29, select: true},
  {Country: "China", gold: 32, money: 17, Bronze: 14, select: true},
  {Country: "Russia", gold: 27, money: 27, Bronze: 38, select: true},
  {Country: "USA2", gold: 35, Silver: 39, Bronze: 29, select: false},
  {Country: "2" China, gold: 32, money: 17, Bronze: 14, select: false},
  {Country: "Syria2", gold: 27, money: 27, Bronze: 38, select: false},
  {Country: "3", gold: 35 Silver: 39, Bronze: 29, select: true},
  {Country: "China3", gold: 32, money: 17, Bronze: 14, select: true},
  {Country: "Russia3", gold: 27, money: 27, Bronze: 38, select: true}
  ]);

  private void filterItems (): void {}
  for (var i: Number = 0; i< medalsac.length;="">
  If (medalsAC . Select == false) {}
  => Remove item
  medalsAC.removeItemAt (i);
  -Online discount collection if see you s new change.
  medalsAC.refresh ();
  -Online start at the beginning and keep looking
  i = 0;
  }
  }
  }
  ]]>
  

  
  
  
  
  
  
  
  
  
  
  

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