Removing items from system preferences

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• remove items from a collection

  Hi all

  I have a record type, and I want to delete items, if second and third attribute of the current record is the same as an attribute of second and third the previous record. Here is an example:

  declare
    type t_serv is record (
      a varchar2(10),
      b varchar2(10),
      c number(5),
      d number(5)
    );
    
    type t_serv_tab is table of t_serv;
    x t_serv_tab;
  begin
    x := new t_serv_tab();
    x.extend;
    
    x(x.last).a := 'DSL';
    x(x.last).b := 'ADSL';
    x(x.last).c := 100;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'ADSL';
    x(x.last).c := null;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'IPTV';
    x(x.last).b := 'N/A';
    x(x.last).c := null;
    x(x.last).d := null;
    
    x.extend;
    x(x.last).a := 'CABLE';
    x(x.last).b := 'CATV_FTTH';
    x(x.last).c := 50;
    x(x.last).d := null;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'VDSL';
    x(x.last).c := 100;
    x(x.last).d := 20;
    
    x.extend;
    x(x.last).a := 'DSL';
    x(x.last).b := 'VDSL';
    x(x.last).c := 100;
    x(x.last).d := null;
    
  -- in this case, elements from 2nd and 6th position are deleted, as they have similar "a" and "b" attributes as the previous record's "a" and "b"
    for i in x.first..x.last loop
      if i>1 then -- if I don't put this, I got an Subscript outside limit error
        if x(i).a = x(i-1).a and x(i).b = x(i-1).b then
          x.delete(i);
        end if;
      end if;
    end loop;
    
    -- print the final collection (should have 4 elements)
    for j in x.first..x.last loop
      dbms_output.put_line(x(j).a||', '||x(j).b||', '||x(j).c||', '||x(j).d);
    end loop;
  end;
  

  The problem is that I'm me ORA - 01403 No. data found error. And I understand why, because the last loop, loops within all the elements, but the 2nd and 6th items from the collection are deleted before.

  How can I solve this problem and to print the 4 remaining items?

  Thank you!

  The collections are rare objects, so unless you know collection has no deficiencies you should not use the LOOP for first time (before deletion) you know collection has no gaps, so you can use the FOR LOOP. However, since you remove elements, previous element of SEO via i - 1 is false, because I have element - 1 can be deleted. You must save the last element not removed. Now your impression share must assume at least an element has been removed and the collection is sparse (present gaps). Therefore, you must use LOOP, no LOOPS and use methods NEXT and LAST to iterate over the collection:

  declare

  type t_serv is (record

  a varchar2 (10),

  b varchar2 (10),

  c number (5),

  d number (5)

  );

  type t_serv_tab is table of the t_serv;

  x t_serv_tab;

  number of prev_i;

  Start

  x: = new t_serv_tab();

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = "ADSL"

  x (x.last) .c: = 100;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = "ADSL"

  x (x.last) .c: = null;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = 'IPTV ';

  x (x.last) .b: = "n/a";

  x (x.last) .c: = null;

  x (x.last) .d: = null;

  x.extend;

  x (x.last) .to: = "CABLE."

  x (x.last) .b: = "CATV_FTTH";

  x (x.last) .c: = 50;

  x (x.last) .d: = null;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = 'VDSL.

  x (x.last) .c: = 100;

  x (x.last) .d: = 20;

  x.extend;

  x (x.last) .to: = "READ";

  x (x.last) .b: = 'VDSL.

  x (x.last) .c: = 100;

  x (x.last) .d: = null;

  prev_i: = 1;

  I'm looping 2.x.last

  If x (i) (prev_i) .to .to = x and x (i) .b = x (prev_i) .b

  then

  x.Delete (i);

  on the other

  prev_i: = i;

  end if;

  end loop;

  -print the final collection (must have 4 elements)

  prev_i: = x.first;

  loop

  dbms_output.put_line (x (prev_i) .to | ',' | x (prev_i) .b | ',' | x (prev_i) .c | ',' | x (prev_i) .d);

  When the output prev_i = x.last;

  prev_i: = x.next (prev_i);

  end loop;

  end;

  /

  Scott@pdb1orcl12 > /.
  DSL, ADSL, 100, 20
  IPTV, N/A,
  CABLE, CATV_FTTH, 50.
  ADSL, VDSL, 100, 20

  PL/SQL procedure successfully completed.

  Scott@pdb1orcl12 >

  SY.

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