Replace special characters in a string

Similar Questions

• Replace special characters

  Hello

  I need SQL or PL/SQL code to replace special characters such as!, @, #, $, %, ^ of the given string.

  For example, if the given string is

  "it is - test * strin #g to @ spe % ial charact!" ERS"he should replace all special characters and provide the output voltage

  It's test string with special characters

  Please enter the code

  Thank you

  You have commas in the character set block and the [[: alnum:]] is equivalent to [a-zA-Z0-9], you may want to include a space in this updated chacter block.

  Select REGEXP_REPLACE ("This is test * strin #g to @ spe % ial charact!") ERS ',' [^ [: alnum:]] *', ")

  of the double

  Output

  It's test string with blue characters

  EDIT: I do not know what will want the characters allow the OP. For example, a comma, question mark, comma, colon, apostrophe, full stop etc. are all valid in a sentence.

• Bunch of Oracle on the special characters in a string - translate?

  How to remove special characters in a string, it can contain. , (space), etc.

  SELECT TRANSLATE('123.456 (90-90)', '', '') FROM DUAL
  

  Basically I want to undress and to compare with the db value.

  WHERE TRANSLATE(TABLE.NUMCODE, '', '')  = TRANSLATE('123.456 (90-90)', '', '') 
  

  Use TRANSLATE, since you're on 9i. For example:

  TRANSLATE (your_string,'X,. #! % @$ ^ & * () _-+=', 'X')

  Removes all the s characters in ', #! % @$ ^ & * () _-+=' of your_string.

  SY.

• How to remove special characters from the string using translate() without typing all special characters?

  Hi all

  I am trying to remove special characters without the help of regular expressions.

  translate (the column name or string,'!@#$ & * (* () _) * "" :} {?}) >? /, «, » ')

  I want to eliminate this manual process to give all special characters using a chr() or ascii() function.

  Please show me the way.

  Thanks in advance

  Similar to the solution of Michael...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, i like (select level 1 c from dual connect by level<=>
  3 less
  4 Select + 32 (level-1) double connect by level<=>
  5 less
  6 select + 58 (level-1) double connect by level<=>
  7 less
  8 select + 91 (level-1) double connect by level<=>
  9 less
  10. Select 123 + (level-1) from dual connect by level<=>
  11 less
  12. Select 255 double
  13            )
  14, ts as (select level r, substr (str, level 1) c
  15 t
  16 connect by level<=>
  17             )
  18, tf as (select row_number() (order for r) r
  19                    ,ts.c
  20 TS
  21 I join on (i.c = ascii (ts.c))
  22             )
  23 select replace (sys_connect_by_path(c,'!'),'! ') Str
  24 TF
  25 where connect_by_isleaf = 1
  26 connect r = prior r + 1
  27 * start with r = 1
  SQL > /.

  STR
  -----------------------------------------------------------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

  Or something as horrible as this...

  SQL > ed
  A written file afiedt.buf

  1 with t as (select "[it comes of the #] [more amazing!") Test @# "$* & $%) assuming chain cost $ 5 000' double Str)
  2, I like (select replace (sys_connect_by_path (chr (c), 'A'), 'A') as tr)
  3 of)
  4 select c, rownum r
  5 (select 32 + (level-1) as the double connection by level c<=>
  6                         union
  7 select + 58 (level-1) double connect by level<=>
  8                         union
  9 select + 91 (level-1) double connect by level<=>
  10 the union
  11. Select 123 + (level-1) from dual connect by level<=>
  12 union
  13. Select 255 double
  14 tri 1
  15                        )
  16                  )
  17 where connect_by_isleaf = 1
  18 log r = prior r + 1
  19 start with r = 1
  20            )
  21 select translate (str, 'A' |) TR, 'A') as str
  22 * t, I
  SQL > /.

  STR
  --------------------------------------------------------------------
  Thisisthemostamazingtest¸astringcosting5000

• Find special characters in a string

  Hi all, I am using Oracle 10 g.
  
  I have a column name with special characters. How can I replace the special characters in the column with space and no space based on the special character. Please see the example below. can I use REGEXP_REPLACE?
  
  create table

  create table sample_test (
    Name    VARCHAR2(20 BYTE))

  Insert a table

   insert into sample_test values ('O''NEIL')
       insert into sample_test values ('B.E.VICTOR')
        insert into sample_test values ('WILLIAM,L')
         insert into sample_test values ('MARY-ANNE')
             insert into sample_test values ('VON_ANCKEN')
              insert into sample_test values ('BROWN;L')

  I would like the following output
  

   
  Special Character         Name         Expected Name                  Remarks      
   
  Single Quotes            O'NEIL                  ONEIL                          Remove quotes and no space        
  Dot                      B.E.VICTOR         B E VICTOR                          Replace with space        
  Comma                      WILLIAM,L         WILLIAM L                          Replace with space        
  Hyphen                      MARY-ANNE         MARY ANNE                          Replace with space        
  Underscore                VON_ANCKEN         VON ANCKEN                          Replace with space        
  Semi Colon              BROWN;L          BROWN L                          Replace with space      

  Please notify.
  
  Thank you
  Bob

  A simple solution without the use of regexp:

  -- Test Data
  with sample_test as
  (
  select 'O''NEIL' name from dual union all
  select 'B.E.VICTOR'  name from dual union all
  select'WILLIAM,L' name from dual union all
  select'MARY-ANNE' name from dual union all
  select'VON_ANCKEN' name from dual union all
  select'BROWN;L' name from dual
  )
  -- Query:
  select name old_name,
         translate(replace(name,'''',''),'.,-_;','     ') new_name
  from sample_test;
  

  Explanation:

  REPLACE deletes the quote
  TRANSLATE replaces point, comma, dash, semicolon and underscore

• Replace special characters in the FDF

  Hello

  I've looked everywhere and can't find the answer to this simple problem.  I can handle javascript in an HTML environment using free scripts, but it is not so easy in a PDF form.  I use Adobe Acrobat 9 Pro and I have a form that once completed and submitted, generates and sends a FDF file.  I use a script on the server side, called FormGenie do this and the script hate parentheses and some other characters, they break the FDF file.  Everything I want to do is set up a document level Javascript that find and replace all instances of these special characters with something license as a hyphen - or just a space.

  I tried:

  function clearText() {}
  document. FormName.FieldName.Value = filterNum (document. FormName.FieldName.value)

  function filterNum (str) {}
  re = /\$|#|~|\%|\*|\^|\(|\)|\+|\=|\[|\]|\[|\}|\{|\;|\"|\<|\>|\?| \|| \\|\!| \$/g;
  remove special characters as ' $' and ',' etc...
  return str.replace (re, "-");
  }
  }

  and

  function clearText2 (str) {}

  stringName = stringName.replace (/------$| #| ~ |------% |------* |------^ | \(|\) |--------+ |------= |------[|------] |------[{|------} |------{|------; |------"|"}]) ------< | ------> | \ ? | \|| \\|\!| \$ /g,'-');
  }

  I know that these are not good, but I have to be at least barking to the top of the tree on the right.

  Can anyone help?

  Thank you

  You create the form in Acrobat or LiveCycle Designer?

  In general, you can place a script typo in the script of the text of each filter field field hit, in the case where something replacing the user typed with something else would not cause the concern of the user. An alternative would be to be implemented a script that parses the fields just before the submission form action takes place and not to replace them.

  For example, you can use the following JavaScript typo customized for text fields created in Acrobat:

  If (! event.willCommit) {}

  Event.change = event.change.replace (/ [------$# ~ %------*------*------^ \ (\)------+=------[\]------{\};------"\<\>\?]) \ | \\\ !] /g, "-");

  }

  and it will replace these characters when the user types the data into a text field. May not include all the character you want replaced, but you should get the idea.

• Replacing special characters

  I have a page with a javascript tip which is fed with elements of a database query. Some of the results have special characters that my with the javascript syntax, in fact only 3 of them.
  
  Single quote, double quote and------.
  
  If I set & #34; in the database, it displays as a double in the ToolTip without problem, so what I want to do is to replace all occurrences of "with & #34;" and even with the others. The------should be replaced by------to view. I find it hard to do... any suggestions would be helpful... Here's my current attempt...
  
  < cfset temp = Replace (tester.loc_notes, ' "',' & #34;', 'ALL'") >
  
  Thank you

  If these quotes are displayed to the user, use " ", " or HTMLEditFormat().

  It is difficult to be more precise, unless you attach the code in question.

• How to avoid special characters in a string

  Hai.

  I want only Alphabets & numbers to appear on my channel. No other special characters except spaces. How can I do this?

  Hi Alice,.

  See the attached example.

  It will be useful.

  Mike

• How to find special characters in a string of give/sentance

  Hi all
  
  I have a task to complete with the time to give. Because I'm not very good in PL/SQL, I need you're help.
  Condition is:
  
  I must come with the SQL or PL/SQL code which should return and find the hidden or special character in the name of the data files in a database. There are nearly 400 + database are present in almost any flavor of UNIX, and I need to check the database each.
  
  As you know, the name of the data file will be like this:

   /u02/instance_name\oradata\datafile_01.dbf 

  So, it should avoid these things and only discover the special characters in the name of the data file.
  

   
  a-z , A-Z , 0-9 and \ 

  Please keep in mind that... I'll be pulled the script Oracle the Oracle 9i client that will access all the databases of Oracle 9i to 11g in a short and give me the result.
  
  Please help me to solve this problem and let me know if you need more information.

  Hello

  Mukesh says:
  Hi Frank,.

  It is an excellent service. Thanks for you response.
  I want to change the query that... I should get only the name of these data files that are special characters of detention. I don't know how to put it in that condition. :(

  Here's one way:

  SELECT  file_name
  ,       ...     -- other expressions, if you want any
  FROM    dba_data_files
  WHERE   TRANSLATE ( file_name
                    , '?0123456789.ABCDEFGHIJKLMNOPQRSTUVWXYZ\_/abcdefghijklmnopqrstuvwxyz'
                    , '?'
                    ) IS NOT NULL
  

  Among other expressions, you can put in the SELECT clause (if you wish) is a copy of the TRANSLATE function, you had in your message. That would underline exactly what characters rendering invalid file name.

• How to avoid special characters in the string box

  Hello

  is it possible that a special character can be avoided in a box of the string, as authorizing only a - z and 0-9 to enter a box in the chain

  Hi all

  Darin Laurette method is simple.

  AnkitG: You must change the code.

  Good learning for me.

  Kind regards

  Leila

  CLD

• replace special characters in sql select

  Hello

  I have a little problem with one colunm blob in a db.

  A blob contains a text with decimal characters (an application writes this colunm in HTML), for example:

  Kedves Koll & #233 g & #225; k!

  & #193; He's & #225; sfoglal & #225; sotokat k & #233; RJ & #252; k a csatolt panasz & #252; gyben (PI-1167/2014.).

  & #220; gyf & #233; ladatok

  n & #233; v: lives & #225; RIS Anetta

  How could I replace the decimal characters with ascii characters?

  Thans a lot

  set define off

  SELECT UTL_I18N. UNESCAPE_REFERENCE ('Kedves Kollegak!)

  Allasfoglalasotokat Kerjuk a. csatolt panaszugyben (PI-1167/2014.)

  Ugyfeladatok

  Nev: Anetta Vitaris') FROM dual

  UTL_I18N. UNESCAPE_REFERENCE('KEDVESKOLLéGáK!) Allasfoglal & #225

  --------------------------------------------------------------------------------

  Kedves Kollegak!

  Allasfoglalasotokat Kerjuk a. csatolt panaszugyben (PI-1167/2014.)

  Ugyfeladatok

  Nev: Vitaris Anetta

  1 selected line.

• What happened to search for and replace special characters

  I'm a recent update of FrameMaker 9 FrameMaker 11. I use several notations with nonbreaking hyphens and nonbreaking spaces. In version 9, I was able to use the hexadecimal codes in the Find/Replace dialog box and search and replace these ratings. Now in version 11, it does not find these characters. I end up getting more I want.

  For example: I want to find

  (E Vote, September 12, 2008)

  This text has a non-breaking hyphen and showing spaces are nonbreaking. When I entered the document these characters, I used the combination of keys "Esc hyphen:" for the hyphen and "Ctrl + space" for spaces.

  When I enter "(E\x15Vote\x10Sept.\x1012,\x102008)" and press the button Search, FrameMaker converts the text to "(E\+Vote\s#Sept.\s#12,\s#2008)" and refers to a "Not Found" statement. I get the error even if I copy the text and paste it into the Find/Replace dialog box. I tried with "Deal", "use wildcards" and whole-word checks both market. I can't find it.

  Honestly, I never noticed if verstion 9A made the conversion of \x15 to------+ and dialog of \x10 to \s#, in the search/replace because he always found what I was looking for.

  I hope someone can tell me how to solve this problem, because it is a feature I use all the time in FrameMaker. I use hyphens and nonbreaking spaces everywhere in my documents.

  I also reported this as a bug because that's what happens if feels like to me. I went out and updated my installation of FrameMaker, thinking that this may have been reported and already corrected.

  A sad FrameMaker user

  Chris

  I'm not sure that's what you're looking for, but you might.

  Copy your text ' E-voting, September 12, 2008'.

  Go to Find/replace

  Select text and character Formats Clipboard from the drop-down

  Click on Search.

• REGEXP_REPLACE problem with special characters in the string

  Hi guys,.
  
  I have had problems using the REGEXP_REPLACE function and I'm trying to find a solution.
  
  The closest I can get is this thread:
  
  Re: How to replace the first occurrence of a substring
  
  and that's only because the solution, I'm trying to achieve is the one suggested. I did ppost my problem there, but because it is answered, I don't have an answer.
  
  I'm doing the following:
  

  select 
    regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|',
    '^(\w|-)*\|{1}',null)
  from dual

  Basically, replace it does not work, because the first part of the string contains an asterisk. If you delete the Asterix, then replace it won't work.
  
  How can I get around this? I can't use a regular REPLACEMENT as I want to remove the first instance of A * and not all instances of the A.
  
  Help, please! I don't know what to do... probably, I mustn't start a loop through the string?
  
  Thanks in advance guys!
  
  Robin

  User_resU wrote:
  I want to remove the first instance of A * and not all instances of the A.

  To decode your regular expression, it seems that you want to remove A * | and not just A *.

  SQL> select   regexp_replace('A*|A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31
  |A1|A||_|EX|8HI01|H11|A1|A||_|OCR|H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|
  EP|||_|AA|2151|G31|A|||_|',
    2    '^(\w|-)\*\|{1}',null) reg
    3  from dual;
  
  REG
  --------------------------------------------------------------------------------
  
  A*|C11|A1|A*||_|OR|H452|C40|A|A*||_|AA|1151|G31|A1|A||_|EX|8HI01|H11|A1|A||_|OCR
  
  |H421|B11|A|||_|OR|H434|C11|A|||_|AQA|9990|E10|EP|||_|AA|2151|G31|A|||_|
  

• Replacing special characters with its actual value

  Hi all
  
  Anyone have an idea how to replace an extended character (ASCII ranging from 128 to 255 value) for its actual character set in SQL/PLSQL?
  
  For example: '½' should be replaced on a "1/2".
  '¼' should be replaced with "1/4"
  
  Ultimately if the value is "California 71 ½" then the result should be "California 71 1/2". "."
  
  Thanks for your time!
  
  Kind regards

  REPLACE the function?

  SQL> select replace('California 71 ½', '½', '1/2') from dual;
  
  REPLACE('CALIFORNIA71½','½','1
  ------------------------------
  California 71 1/2
   
  

• Replacing special characters when writing to a file

  I use the following to replace Muñoz (n with null).  It should produce as Muoz.

  This should be simple, but it does not work.  209 and 241 represent the upper and the lower case n.

  This statement is a CFFILE.  I'm generating the file but the n is still there.

  Replace (LGL_NM, Chr (209) & chr (241),'3 ', 'all')

  I also tried without success the following:

  < cfset x = ReplaceNoCase(#Object_query.) LGL_NM #, "#Chr (209) # ',' ', 'all') > '"
  < cfset LGL_NM = ReplaceNoCase (x, "#chr (241) #","", "all" "") >

  Help, please.

  Thank you!

  Bill

  
  

  
  #REReplaceNoCase (testString, "[#chr (209) ##chr (241) #]", "", "all") #.