Replicate EQL in a group with several pools
I wonder how and if you even go about it.
I'm replying to a group of elders without in our disaster recovery site which have speeds of 10 k - 7.2 k disks. Yes I know its DR, but I split the san 3-10 k in a pool and 2-7 k san in a pool.
How to reproduce 1 prod to 10 k of the pool and 2 Volume to the pool 7 k?
Whenever I looked there delegation of space I could not understand how to remove specifically 1 pool or in the other, and if it would still be selectable during replication.
So is this possible WITHOUT cut it pools in their own groups.
Anyone?
Hello, Tsz109...
With PS Series firmware v8 and later versions, you can assign space for delegates in several pools, and the whole storage space can be used in the replication group. Delegate space can be assigned in one, some, or all the pools. Prior to firmware, delegated PS Series v8 space was restricted to a storage pool for a particular replication partner. Also, in the PS firmware v8 series and later, you can configure a mapping between primary and secondary pools for original replica set placement.
See the following for more information:
en.Community.Dell.com/.../19861448
Please let me know if I can provide additional information.
Have a great day.
Tags: Dell Products
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Welcome to the Forums - you are right to worry about this situation - check on http://www.yellow-bricks.com/2010/02/22/the-resource-pool-priority-pie-paradox/ for description - but don't worry Duncan also has a solution - http://www.yellow-bricks.com/2010/02/24/custom-shares-on-a-resource-pools-scripted/
If you find this or any other answer useful please consider awarding points marking the answer correct or useful
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Unable to create cache with several tables group
Hello
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Script, I used is:
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of the TEST. ROOT1)
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Hello
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Jah,
For assistance, please ask for help in the appropriate Microsoft TechNet Windows Server Forum.
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ASA EzVPN with several remote subnets
Hello world
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Access by the network directly connected on the 5505 to the central site works very well.
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I guess I need to specify that some sort of acl's to be able to do that.
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(--LAN--)-5520---5505-(--LAN1--)-ROUTER-(--LAN2--)-(WAN)-
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Client:
vpnclient Server 10.x.x.x
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Server:
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allow to NEM
allow password-storage
tunnel-group EzVPN type ipsec-ra
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Group Policy - by default-EzVPN
IPSec-attributes tunnel-group EzVPN
pre-shared key *.
user user1 password *.
I hope you can help
Best regards
Jarle
Unfortunately, it is not supported on the platform of the SAA. With EasyVPN on the SAA, only the connected networks can be advertised. To accomplish what you want to do, you need to configure a static IPSec tunnel and announce local networks via ACL interesting traffic. You can also use an IOS device that does not have the capabilities of "multiple subnet" with EasyVPN.
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Dear all!
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Create different group with VPN remote access
Hello world
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ASA Version 8.0 (2)
!
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: endWhat you need to configure is to imitate the configuration on the tunnel-group and group strategy and to configure access to specific network you need.
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vpn-vidrul group policy internal
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How to subtract a grunge texture of a layer with several objects?
Hi all
I've been struggling with this for hours. Would be very grateful for help.
I'm trying to apply a vintage texture to some vector illustrations.
In the screenshot, the work I created is in the layer of "work." I tried to simplify the work as much as possible by using the union, merge, expand, etc. I wanted to do a piece of work, but that seems so simple that I can get it.
When I try to perform a subtraction on the layer 'work' with the layer of 'texture', basically everything disappears.
I suspect that it does not work as expected because the layer of my work is always composed of several objects and not a unified object.
Vintage texture superimposed on the work looks good, but I need this subtraction in vector because I intend to get it printed on a shirt in one color, so I can't get the holes filled with color.
Any help would be greatly appreciated.
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How can I activate art in a single compound path?
First of all, to unite all paths with the first button in the Pathfinder palette. Then choose object > compound path > make (or press Command-8).
But don't do it this way. Use an opacity mask.
If I use the grunge texture as an opacity mask, do I still to transform the art into a single compound path first or I can do to a layer with several objects as if it were now?
No, you have not; You can keep a complete editibility of your design. You need to just design group firstly, why the opacity mask applies to all this.
Opacity masks are easier to use if you uncheck "Clip" after their creation. Then, all parts of the mask that is black will be transparent; each part that is white will be opaque, and the things which are shades of gray will be partially transparent. Just like in Photoshop. Right now, your grunge texture is white, so you would need to change to black after making your opacity mask.
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{kViewRsrcType,
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};
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*/
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"", / / Substitute the form menu path ' hand: Foo "If you want your palette in the second menu item to place
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c_Panel
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{
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{
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My previous post was that this panelMgr-> GetPanelFromWidgetID (kMyPanelWidgetID) does not find the Panel when it is called in the initializer.
I'm now deep - search the trees from the GetRootPaletteNode paletteRef, using PaletteRefUtils methods. For kTabPanelContainerType, I used panelMgr-> GetPanelFromPaletteContainer() to check the ID of widget, fortunately callers already works. For other types, I just go down the children.
Three steps more to move the paletteRef found in a new floating window:
columnRef = PaletteRefUtils::NewFloatingTabGroupContainerPalette(); kTabPaneType
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I drew a map of the country with several layers and sous-calques, including the streets, cities, railroads...
Now, I want to create a template for my colleagues in After Effects.
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When I do, I get the first two layers correctly, others just in a merged publication.
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Illustrator imports only the first level of the layers. If you have groups or paths below you must release layer groups. The layers will then be stacked in the order in the form of layers. Then you need to move them to the top.
The procedure is to select a layer in the layer Illustrator Panel, then without selecting any which specific element in the layer click on the menu in the upper right corner and select release to layers. All an elements in this layer will be transformed into layers. Now, select all, and drag them to the top above the original layer. This will leave the empty original layer and put all the elements in new layers.
Here is a tutorial I made there are a bunch of years and who uses this technique to transform a mixture in a morphing.
Morphing with Adobe Illustrator. I hope this helps.
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I am posting this as a follow-up question to:
[8i] grouping with tricky conditions
This is a repeat of my version information:
Still stuck on an old database a little longer, and I'm trying out some information...
BANNER
--------------------------------------------------------------------------------
Oracle8i Enterprise Edition Release 8.1.7.2.0 - Production
PL/SQL Release 8.1.7.2.0 - Production
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AMT for HP - UX: 8.1.7.2.0 - Production Version
NLSRTL Version 3.4.1.0.0 - Production
Now for the sample data. I took an order of my real data set and cut a few columns to illustrate how the previous solution didn't find work. My real DataSet still has thousands of orders, similar to this one.
Instead of grouping all sequential steps with 'OUTPR' station, I am gathering all the sequential steps with "S9%" station, then here is the solution changed to this:CREATE TABLE test_data ( item_id CHAR(25) , ord_id CHAR(10) , step_id CHAR(4) , station CHAR(5) , act_hrs NUMBER(11,8) , q_comp NUMBER(13,4) , q_scrap NUMBER(13,4) ); INSERT INTO test_data VALUES ('abc-123','0001715683','0005','S509',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0010','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0020','A501',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0026','S011',0.58,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0030','S970',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0040','S970',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0050','S003',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0055','S600',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0060','Z108',6.94,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0070','Z108',7,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0080','Z310',4.02,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0085','Z409',2.17,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0090','S500',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0095','S502',1.63,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0110','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0112','S011',0.15,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0117','S903',0,10,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0118','S900',0,9,1); INSERT INTO test_data VALUES ('abc-123','0001715683','0119','S950',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0120','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0140','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0145','S950',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0150','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0160','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0170','S900',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0220','S902',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0230','S906',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0240','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0250','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0260','S006',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0270','S012',0.95,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0280','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0285','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0290','Z426',1.78,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0300','Z426',2.07,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0305','Z426',1.23,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0310','Z402',3.97,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0315','Z308',8.09,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0410','Z409',4.83,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0430','S500',3.6,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0435','S502',0.43,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0450','S002',0.35,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0460','S001',1,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0470','Z000',2.6,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0476','S011',1,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0478','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0480','S903',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0490','S003',1.2,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0500','S500',1.37,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0530','B000',0.28,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0536','S011',0.65,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0538','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0540','S923',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0560','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0565','S001',0.85,0,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0570','S012',2.15,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0575','S509',0,0,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0580','B000',3.78,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0590','S011',0.27,9,0); INSERT INTO test_data VALUES ('abc-123','0001715683','0600','S510',0,9,0);
If just run the subquery to calculate grp_id, you can see that it sometimes affects the same number of group in two stages that are not side by side. For example, the two step 285 and 480 are they assigned group 32...SELECT item_id , ord_id , MIN (step_id) AS step_id , station , SUM (act_hrs) AS act_hrs , MIN (q_comp) AS q_comp , SUM (q_scrap) AS q_scrap FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station LIKE 'S9%' THEN NULL ELSE step_id END ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station LIKE 'S9%' THEN NULL ELSE step_id END ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , step_id ;
I don't know if it's because my orders have many more steps that the orders of the sample I provided, or what...
I tried this version too (by replacing all the names of the stations "S9%" by "OUTPR"):
and it shows the same problem.INSERT INTO test_data VALUES ('abc-123','0009999999','0005','S509',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0010','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0020','A501',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0026','S011',0.58,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0030','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0040','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0050','S003',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0055','S600',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0060','Z108',6.94,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0070','Z108',7,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0080','Z310',4.02,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0085','Z409',2.17,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0090','S500',0.85,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0095','S502',1.63,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0110','S006',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0112','S011',0.15,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0117','OUTPR',0,10,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0118','OUTPR',0,9,1); INSERT INTO test_data VALUES ('abc-123','0009999999','0119','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0120','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0140','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0145','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0150','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0160','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0170','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0220','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0230','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0240','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0250','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0260','S006',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0270','S012',0.95,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0280','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0285','Z417',0.68,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0290','Z426',1.78,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0300','Z426',2.07,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0305','Z426',1.23,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0310','Z402',3.97,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0315','Z308',8.09,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0410','Z409',4.83,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0430','S500',3.6,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0435','S502',0.43,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0450','S002',0.35,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0460','S001',1,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0470','Z000',2.6,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0476','S011',1,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0478','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0480','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0490','S003',1.2,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0500','S500',1.37,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0530','B000',0.28,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0536','S011',0.65,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0538','S510',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0540','OUTPR',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0560','S003',0,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0565','S001',0.85,0,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0570','S012',2.15,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0575','S509',0,0,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0580','B000',3.78,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0590','S011',0.27,9,0); INSERT INTO test_data VALUES ('abc-123','0009999999','0600','S510',0,9,0); SELECT item_id , ord_id , MIN (step_id) AS step_id , station , SUM (act_hrs) AS act_hrs , MIN (q_comp) AS q_comp , SUM (q_scrap) AS q_scrap FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station = 'OUTPR' THEN NULL ELSE step_id END ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id , CASE WHEN station = 'OUTPR' THEN NULL ELSE step_id END ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , step_id ;
Help?Hello
I'm glad that you understood the problem.
Here's a little explanation of the approach of the fixed difference. I can refer to this page later, so I will explain some things you obviously already understand, but I jump you will find helpful.
Your problem has additional feature that, according to the station, some lines can never combine in large groups. For now, we will greatly simplify the problem. In view of the CREATE TABLE statement, you have posted and these data:INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0010', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0011', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0012', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0140', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0170', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0175', 'Z417'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0200', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0205', 'S906');Let's say that we want this output:
` FIRST LAST _STEP _STEP ITEM_ID ORD_ID _ID _ID STATION CNT ------- ---------- ----- ----- ------- ---- abc-123 0001715683 0010 0010 Z417 1 abc-123 0001715683 0011 0140 S906 3 abc-123 0001715683 0170 0175 Z417 2 abc-123 0001715683 0200 0205 S906 2Where each line of output represents a contiguous set of rows with the same item_id, ord_id and station. "Contguous" is determined by step_id: lines with "0200" = step_id = step_id "0205' are contiguous in this example of data because there is no step_ids between '0200' and '0205". "
The expected results include the step_id highest and lowest in the group, and the total number of original lines of the group.GROUP BY (usually) collapses the results of a query within lines. A production line can be 1, 2, 3, or any number of lines in the original. This is obviously a problem of GROUP BY: we sometimes want several lines in the original can be combined in a line of output.
GROUP BY guess, just by looking at a row, you can tell which group it belongs. Looking at all the 2 lines, you can always know whether or not they belong to the same group. This isn't quite the case in this issue. For example, these lines
INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0140', 'S906'); INSERT INTO test_data (item_id, ord_id, step_id, station) VALUES ('abc-123', '0001715683', '0200', 'S906');These 2 rows belong to the same group or not? We cannot tell. Looking at just 2 lines, what we can say is that they pourraient belonging to the same group, since they have the same item_id, ord_id and station. It is true that members of same groups will always be the same item_id, the ord_id and train station; If one of these columns differ from one line to the other, we can be sure that they belong to different groups, but if they are identical, we cannot be certain that they are in the same group, because item_id, ord_id and station only tell part of the story. A group is not just a bunch or rows that have the same item_id, ord_id and station: a group is defined as a sequence of adjacent to lines that have these columns in common. Before we can make the GROUP BY, we need to use the analytical functions to see two lines are in the same contiguous streak. Once we know that, we can store this data in a new column (which I called grp_id), and then GROUP BY all 4 columns: item_id, ord_id, station and grp_id.
First of all, let's recognize a basic difference in 3 columns in the table that will be included in the GROUP BY clause: item_id, ord_id and station.
Item_id and ord_id always identify separate worlds. There is never any point comparing lines with separate item_ids or ord_ids to the other. Different item_ids never interact; different ord_ids have nothing to do with each other. We'll call item_id and ord_id column 'separate world '. Separate planet do not touch each other.
The station is different. Sometimes, it makes sense to compare lines with different stations. For example, this problem is based on questions such as "these adjacent lines have the same station or not? We will call a "separate country" column of the station. There is certainly a difference between separate countries, but countries affect each other.The most intuitive way to identify groups of contiguous lines with the same station is to use a LAG or LEAD to look at adjacent lines. You can certainly do the job, but it happens to be a better way, using ROW_NUMBER.
Help the ROW_NUMBER, we can take the irregular you are ordering step_id and turn it into a dial of nice, regular, as shown in the column of r_num1 below:` R_ R_ GRP ITEM_ID ORD_ID STEP STATION NUM1 S906 Z417 NUM2 _ID ------- ---------- ---- ------- ---- ---- ---- ---- --- abc-123 0001715683 0010 Z417 1 1 1 0 abc-123 0001715683 0011 S906 2 1 1 1 abc-123 0001715683 0012 S906 3 2 2 1 abc-123 0001715683 0140 S906 4 3 3 1 abc-123 0001715683 0170 Z417 5 2 2 3 abc-123 0001715683 0175 Z417 6 3 3 3 abc-123 0001715683 0200 S906 7 4 4 3 abc-123 0001715683 0205 S906 8 5 5 3We could also assign consecutive integers to the lines in each station, as shown in the two columns, I called S906 and Z417.
Notice how the r_num1 increases by 1 for each line to another.
When there is a trail of several rows of S906 consectuive (for example, step_ids ' 0011 'by '0140'), the number of s906 increases by 1 each line to another. Therefore, during the duration of a streak, the difference between r_num1 and s906 will be constant. For 3 lines of the first series, this difference is being 1. Another series of S906s contiguous started step_id = '0200 '. the difference between r_num1 and s906 for this whole series is set to 3. This difference is what I called grp_id.
There is little meaning for real numbers, and, as you have noticed, streaks for different stations can have as by chance the same grp_id. (it does not happen to be examples of that in this game of small sample data.) However, two rows have the same grp_id and station if and only if they belong to the same streak.Here is the query that produced the result immediately before:
SELECT item_id , ord_id , step_id , station , r_num1 , CASE WHEN station = 'S906' THEN r_num2 END AS s906 , CASE WHEN station = 'Z417' THEN r_num2 END AS Z417 , r_num2 , grp_id FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS grp_id , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) AS r_num1 , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS r_num2 FROM test_data ) -- End in-line view to compute grp_id ORDER BY item_id , ord_id , step_id ;Here are a few things to note:
All analytical ORDER BY clauses are the same. In most of the problems, there will be only an ording regime that matters.
Analytical PARTITION BY clauses include the columns of 'distinct from the planet', item_id and ord_id.
The analytical PARTITION BY clauses also among the column 'split the country', station.To get the results we want in the end, we add a GROUP BY clause from the main query. Yet once, this includes the columns of the 'separate world', column 'split the country', and the column 'fixed the difference', grp_id.
Eliminating columns that have been includied just to make the output easier to understand, we get:SELECT item_id , ord_id , MIN (step_id) AS first_step_id , MAX (step_id) AS last_step_id , station , COUNT (*) AS cnt FROM ( -- Begin in-line view to compute grp_id SELECT test_data.* , ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id ORDER BY step_id ) - ROW_NUMBER () OVER ( PARTITION BY item_id, ord_id, station ORDER BY step_id ) AS grp_id FROM test_data ) -- End in-line view to compute grp_id GROUP BY item_id , ord_id , station , grp_id ORDER BY item_id , ord_id , first_step_id ;This prioduces the output displayed much earlier in this message.
This example shows the fixed difference indicated. Specific problem you is complicated a little what you should use an expression BOX based on station rather than the station iteself.
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