Requirements of SQL VWorkspace 8.6.1
I was going through the hardware and software requirements for vw 8.6.1 and he said: vworkspace management database can be hosted on SQL 2012 +. We have not the ability to upgrade the SQL Server at this time. Is it possible to host it on SQL 2008 R2? Someone has it already tried?
A few other questions:
The role of broker can be installed on the Windows Server 2012 R2 kernel? (Basic without the GUI edition)
VWorkspace service of catalyst for Hyper-v supports Hyper-V server? (Basic without the GUI edition)
in our environment, we use 8.6.1 with SQL 2008 r2 without problems.
Tags: Dell Tech
Similar Questions
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I have a table and passes as below:
START DATE TOTAL NUMBER OF DAYS
11/10/2011 15:00 1
15/10/2011-05:00 1
2011-12-22 10:00 1
22/12/2011 11:00 2
30/12/2011-10:00 1
01/01/2012 01:00 1
01/01/2012 10:00 1
01/01/2012 16:00 2
02/01/2012 14:00 1
03/01/2012-15:00 1
04/01/2012-15:00 2
04/01/2012 18:00 1
I need to ask where the values in the table above
must return values as below:
I tried many ways, but not able to find the solution.
Kindly help me in this regard.
START DATE TOTAL NUMBER OF DAYS
11/10/2011 15:00 1
15/10/2011-05:00 1
22/12/2011 11:00 2
30/12/2011-10:00 1
01/01/2012 16:00 2
02/01/2012 14:00 1
03/01/2012-15:00 1
04/01/2012-15:00 2
the ultimate goal is to summarize the TOTAL number of DAYS column all the numbers in the second table... All jobs must be treated in the same query. I can't use the coding of java to process what my requirement should be included in the query that already exists.
Published by: 915175 on February 16, 2012 23:02select trunc(start_date), max(start_date), max(total_days) from tablename group by trunc(start_date);
Please check below is on my local site with you Test data:
SQL> SQL> with tablename as 2 ( 3 select to_date('10/11/2011 15:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 4 select to_date('10/15/2011 5:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 5 select to_date('12/22/2011 10:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 6 select to_date('12/22/2011 11:00' , 'mm/dd/yyyy hh24:mi') start_date, 2 total_days from dual union all 7 select to_date('12/30/2011 10:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 8 select to_date('1/1/2012 1:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 9 select to_date('1/1/2012 10:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 10 select to_date('1/1/2012 16:00' , 'mm/dd/yyyy hh24:mi') start_date, 2 total_days from dual union all 11 select to_date('1/2/2012 14:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 12 select to_date('1/3/2012 15:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual union all 13 select to_date('1/4/2012 15:00' , 'mm/dd/yyyy hh24:mi') start_date, 2 total_days from dual union all 14 select to_date('1/4/2012 18:00' , 'mm/dd/yyyy hh24:mi') start_date, 1 total_days from dual 15 ) 16 select TO_CHAR(max(start_date),'MM/DD/YYYY HH24:MI') start_date , max(total_days) total_days from tablename 17 group by trunc(start_date); START_DATE TOTAL_DAYS ---------------- ---------- 10/15/2011 05:00 1 01/03/2012 15:00 1 12/30/2011 10:00 1 01/01/2012 16:00 2 10/11/2011 15:00 1 12/22/2011 11:00 2 01/04/2012 18:00 2 01/02/2012 14:00 1 8 rows selected. SQL>
Kind regards
Lifexisxnotxsoxbeautiful...Update: added test done to my database...
Edited by: lifexisxnotxsoxbeautiful Vithalani, on February 16, 2012 23:18
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License is required for Sql Loader?
I find that Sql Loader could save a lot of time for me in bulk insertion.
But I do not know if the license is required for use in the development of commercial software.
Or is there an API that can provide similar features of Sql Loader?I think sqlloader is a standard utility and it is included in the price of SE.
You can see the details at http://www.oracle.com/technetwork/database/database10g/overview/twp-general-10gdb-product-family-132973.pdf
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Hello friends,
.
I am trying to query a record of two Emp and Dept tables, I would like to know where employee works (location is stored in)
the Dept table) and would like to employee knowledge belongs to what manager Id stored in the Emp table.
The query below don't give me the desired output. Please suggest me something.
SELECT
E1. EMPNO,
E1. ENAME,
E1. EMPLOYMENT,
E1. SAL,
E1. DEPTNO,
TO_CHAR (E1. HIREDATE, 'DD-MM-YYYY') HIRE_DATE,.
D.LOC,
E1. ENAME Manager
EMP E1, E2 EMP, DEPT. D
WHERE E1. DEPTNO = D.DEPTNO
AND E2. MGR = E1. EMPNO;
HadNext time ask similar questions in the sql forum
SQL and PL/SQLAnswer to your question is
(based on the assumption MGR_NO column exists and is Manager empno)
SELECT E1. EMPNO,
E1. ENAME,
E1. EMPLOYMENT,
E1. SAL,
E1. DEPTNO,
TO_CHAR (E1. HIREDATE, 'DD-MM-YYYY') HIRE_DATE,.
D.LOC,
E2. ENAME Manager
EMP E1, E2 EMP, DEPT. D
WHERE E1. DEPTNO = D.DEPTNO AND E2. EMPNO = E1. MGR_NO; -
Calendar holiday table logic required in sql instead of pl sql
My fn_test function calculates the date of-1. And if it's a holiday according to the temp_calendar of the table, and then call it recursively the fn_test again to-1. In this case until I get a holiday, no date.
I've implemented as follows:
But I can have a single SQL do which is more effective?
Drop table temp_calendar;
Create table temp_calendar)
Identification number,
date of vacation);
Insert into temp_calendar values (1, "January 5, 2012'");
Insert into temp_calendar values (1, ' 6 January 2012');
Insert into temp_calendar values (1, 10 January 2012 ');
Insert into temp_calendar values (1, ' 2 February 2012');
Insert into temp_calendar values (1, 11 February 2012 ');
Commit;
FUNCTION to CREATE or REPLACE fn_test (in_date IN DATE)
DATE OF RETURN
IS
v_pr_day DATE;
BEGIN
v_pr_day: = in_date-1;
BY Calendar_Dates (holiday SELECT FROM temp_calendar)
LOOP
IF (v_pr_day = Calendar_Dates.holiday)
THEN
v_pr_day: = fn_test (v_pr_day);
END IF;
END LOOP;
RETURN TRUNC (v_pr_day);
END fn_test;
/
Select double fn_test('8-JAN-2012'); -Returns Jan. 7 as no holiday in the temp_calendar table.
But select double fn_test('7-JAN-2012'); -Returns Jan 6 4 and 5 is holidays in the temp_calendar table.
Thank you...Hello
It could do:
create or replace FUNCTION fn_test (in_date IN DATE) return date is l_ret date; begin select startdt-1 into l_ret from ( select min(holiday) startdt, max(holiday) enddt from ( select id, holiday, holiday-(row_number() over (order by holiday)) grp from temp_calendar ) group by grp ) v where in_date-1 between startdt and enddt; return l_ret; exception when no_data_found then return in_date-1; end fn_test; /
Test:
[11.2] Scott @ My11g > l 1 declare 2 l_date1 date := to_date('8-JAN-2012','dd-Mon-yyyy'); 3 l_date2 date := to_date('7-JAN-2012','dd-Mon-yyyy'); 4 begin 5 null; 6 dbms_output.put_line(l_date1 ||' => '||fn_test(l_date1)); 7 dbms_output.put_line(l_date2 ||' => '||fn_test(l_date2)); 8* end; [11.2] Scott @ My11g > / 08/01/2012 00:00:00 => 07/01/2012 00:00:00 07/01/2012 00:00:00 => 04/01/2012 00:00:00 PL/SQL procedure successfully completed. Elapsed: 00:00:00.02
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Hi all
I used the SUM on the Partition by for a select query. But, I need to restrict this SUM for a reception.
I have 10 recipes, then this function should calculate only for reception only. But in my case it's in summary for all receipts.
can anyone suggest me how to use function for this group?
Kind regards
Suresh ReddySuresh Reddy wrote:
But, if I need to re group the TAX lines then what we should do?
You must explain in more detail. You can use separate columns or partition in reception, tax:
SQL> select deptno, 2 job, 3 ename, 4 sal, 5 sum(sal) over(partition by deptno) total_dept_sal, 6 sum(sal) over(partition by job) total_job_sal, 7 sum(sal) over(partition by deptno,job) total_dept_job_sal 8 from emp 9 order by deptno, 10 job 11 / DEPTNO JOB ENAME SAL TOTAL_DEPT_SAL TOTAL_JOB_SAL TOTAL_DEPT_JOB_SAL ---------- --------- ---------- ---------- -------------- ------------- ------------------ 10 CLERK MILLER 1300 8750 4150 1300 10 MANAGER CLARK 2450 8750 8275 2450 10 PRESIDENT KING 5000 8750 5000 5000 20 ANALYST SCOTT 3000 10875 6000 6000 20 ANALYST FORD 3000 10875 6000 6000 20 CLERK ADAMS 1100 10875 4150 1900 20 CLERK SMITH 800 10875 4150 1900 20 MANAGER JONES 2975 10875 8275 2975 30 CLERK JAMES 950 9400 4150 950 30 MANAGER BLAKE 2850 9400 8275 2850 30 SALESMAN TURNER 1500 9400 5600 5600 DEPTNO JOB ENAME SAL TOTAL_DEPT_SAL TOTAL_JOB_SAL TOTAL_DEPT_JOB_SAL ---------- --------- ---------- ---------- -------------- ------------- ------------------ 30 SALESMAN MARTIN 1250 9400 5600 5600 30 SALESMAN WARD 1250 9400 5600 5600 30 SALESMAN ALLEN 1600 9400 5600 5600 14 rows selected. SQL>
SY.
-
I have three tables listed below
FORMAT - Columns are format_id, format_desc
VIDEO_FORMAT - areVIDEO_FORMAT_ID of columns, COST VIDEO_ID, FORMAT_ID,
RENTAL - Coulmns are RENTAL_ID, DATE_OUT, DATE_DUE, DATE_IN, DELIVERY_STATUS, LATE_FEE, CUSTOMER_ID, VIDEO_FORMAT_ID
I need to find the customer list id, format description and cost of the video format for customers who have rented a video.
I wrote the request
Select rental r format f, video_format, r.customer_id, f.format_desc, vf.cost vf where f.format_id in (select video_format format_id) and r.video_format_id = vf.video_format_id
This isn't to get accurate results. Help, please.Would know what kind of results you get, but I think that I can see.
Try:
Select r.customer_id, f.format_desc, vf.cost
rental r, f format, video_format vf
where vf.format_id = f.format_id
and r.video_format_id = vf.video_format_idCan't be sure without a little more information so that will set you. But I do not know why you went with trying to get a relationship using an IN with a subquery. It will be useful.
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Hi all
I need to display the number 100000 under 1,00,000.00
Any help is appreciated...API> SELECT TO_CHAR(100000,'FM999,999,999,990.90') 2 FROM DUAL; TO_CHAR(100000,'FM9 ------------------- 100,000.00
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SQL Server 2008 R2 CPU and RAM requirement for HFM/FDM
Summary of the problem
---------------------------------------------------
Requirement of SQL Server 2008 R2 for HFM/FDM
Description of the problem
---------------------------------------------------
We install a new EPM 11.1.2.3 - HFM and FDM on one server that hosts the services of the Foundation and FR. Our question is on the CPU and Ram needed on the SQL Server. We have 2 users with 4 GB of data, but we have to get the good performance of SQL server.
Please provide me with a white paper link or just tell me what it takes.
Thanks in advance.
4 CPUS and 16 GB of RAM should be more than enough to support your needs
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Unable to kenza link to download the Patch MS02-061 for SQL Server 2000
original title: can not download Patch MS02-061
Hello
I know this is an old patch but our new VPN software was listed as a patch that is required if SQL Server 2000 is installed. I get out the site and I am unable to download. Telling me that it can't find it when I click on the link:
http://support.Microsoft.com/default.aspx?scid=kb;en-us;316333&SD=Tech
It is on the page: http://www.microsoft.com/technet/security/bulletin/ms02-061.mspx
This is supposed to be the patch that replaces MS02-039.
Thank you!
RyanVisit the Microsoft Solution Center and antivirus security for resources and tools to keep your PC safe and healthy. If you have problems with the installation of the update itself, visit the Microsoft Update Support for resources and tools to keep your PC updated with the latest updates.
You will find appropriate support for SQL Server in this forum: http://social.msdn.microsoft.com/forums/en-US/sqlsetupandupgrade/threads
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I'm using Mircosoft XP Pro & in an automatic update the following Module was noted as required - Microsoft SQL Server 2005 Express Edition Service Pack 4 (KB2463332) - but it will not be installed.
I get a code error 0 x 534
What should I do to fix this?
Hi EricFien,-Are the other updates, complete the installation successfully without any problem?Try it out below mentioned methods in order and control which of them helps you to fix the problem:Method 1: Try to download the standalone update package and install it manually.Download it from the link given below:Method 2: There is a similar question to SQL Server Forums which includes possible steps to solve this problem and contributed to many users to solve the problem.Do the same reference in the link given below and check if it also helps you: -
SQL Express LocalDB Path missing until reboot
We have just upgraded one of our Installer components required for SQL Express LocalDB 2014 (SP1) since the 2012 version.
The problem is that LocalDB installer does not update the path environment variable, so when the main installer try subsequently call slqlocaldb it fails because it cannot find the executable file.
The path variable does not seem to be updated after a reboot, but the LocalDB installer does not prompt for this (and anyway it would be a pain).
Everyone knows this? Is a workaround to enable the change of the path without a reboot?
This issue is beyond the scope of this site (for consumers) and to be sure, you get the best (and fastest) reply, we have to ask either on Technet (for IT Pro) or MSDN (for developers)
If you give us a link to the new thread we can point to some resources it -
SQL help on records in the range of dates in a month
Hello
I have a simple requirement on Sql.
I have two records in the table of the absence-
Absence1 January 6, 2015 at 10 January 2015, 5 days
Absecne2 January 21, 2015 to 31 January 2015, 11 days
I need to write a Sql to get all the records separate date, as under-
January 5, 2015, 1 January 2015 days 5 days
January 6, 2015 at 10 January 2015 5 days of absence
January 20, 2015, 11 January 2015 10 days working days
January 21, 2015 to 31 January 2015, 11 days of absence
Could be for any month, I just have absences stored in a table and will pass the dates of beginning and end of the month.
I can write this in Pl/Sql, but wanted to see if it's possible in Sql.
TIA
Vignesh
Here's a way to do it.
with the days as
(select mstart + lv mdate
Of
(select mstart to_date('201501','yyyymm')-1, lv)
of the double
cross join
(select level lv
of the double
connect by level<=>=>
)
)
)
abs as
(select 1 anum, to_date ('20150106', 'YYYYMMDD') date_from, to_date ('20150110', 'YYYYMMDD') date_to, 5 days_abs of all double union)
Select option 2, 5 days_abs of the double to_date ('20150121', 'YYYYMMDD') from_date, to_date ('20150131', 'YYYYMMDD')
)
--
Select min (mdate) date_from, max (mdate) date_to, max (day_type) day_type
Of
(select mdate, where anum is null then 'working days' else 'Absence' end day_type, max (rn) on rn (order by mdate))
Of
(select mdate, anum, case when row_number() over (order by mdate) = 1 or nvl(anum,0) <> (nvl(anum,0)) (order of mdate) lag then row_number() (any order by mdate) end rn)
Of
(select mdate, anum)
days d
join left abs one on d.mdate between a.date_from and a.date_to
)
)
)
Group by rn
date_from order;
-
Developer SQL 4 - issue House Java JDK
Hello
I just installed SQL Developer 4 (I have the Version 3.2.20.09 race) and when tried to start at the first time, asking its JDK.
My cell phone has Java (JRE) after that, I tried to give all 3 trails but its not accepting.
Help, please
j2re1.4.2_16
jre6
jre7
Concerning
Nanan
To add to the comments of Jeff, remember the Java installation wizard gives you the ability to No installation/update of the public JRE. So when installing the latest JDK required by SQL Developer, just install the public JRE associated.
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Merger of SQL in writeback OBIEE 11 g
Hello
I have a requirement to insert again record of OBIEE 11 g report and the table has (TKT_ID) primary key defined in the table. I can't insert null check in the DB table. Not be able to achieve my requirement using SQL INSERT/UPDATE statements.
I tried with the merger of the SQL statement, but I am unable to reach the requirement. Here's my query.
MERGE INTO A_WB HAS
USING (SELECT * FROM A_WB where TKT_ID = '12343') B
ON (A.TKT_ID = B.TKT_ID)
WHEN MATCHED THEN
UPDATE SET OUT_CAUSE = "VZ".
WHEN NOT MATCHED THEN
INSERT (TKT_ID, OUT_CAUSE, CUSTOMER_ID) VALUES ('12343',' OTHER', ' 21')
Please correct me if I missed something...
Thank you
Prasanna
SET VARIABLE DISABLE_CACHE_HIT = 1; has solved my problem and get the updated records to date.
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