Calendar holiday table logic required in sql instead of pl sql

My fn_test function calculates the date of-1. And if it's a holiday according to the temp_calendar of the table, and then call it recursively the fn_test again to-1. In this case until I get a holiday, no date.
I've implemented as follows:

But I can have a single SQL do which is more effective?

Drop table temp_calendar;
Create table temp_calendar)
Identification number,
date of vacation);

Insert into temp_calendar values (1, "January 5, 2012'");
Insert into temp_calendar values (1, ' 6 January 2012');
Insert into temp_calendar values (1, 10 January 2012 ');
Insert into temp_calendar values (1, ' 2 February 2012');
Insert into temp_calendar values (1, 11 February 2012 ');
Commit;

FUNCTION to CREATE or REPLACE fn_test (in_date IN DATE)
DATE OF RETURN
IS
v_pr_day DATE;
BEGIN
v_pr_day: = in_date-1;
BY Calendar_Dates (holiday SELECT FROM temp_calendar)
LOOP
IF (v_pr_day = Calendar_Dates.holiday)
THEN
v_pr_day: = fn_test (v_pr_day);
END IF;
END LOOP;
RETURN TRUNC (v_pr_day);
END fn_test;
/

Select double fn_test('8-JAN-2012'); -Returns Jan. 7 as no holiday in the temp_calendar table.
But select double fn_test('7-JAN-2012'); -Returns Jan 6 4 and 5 is holidays in the temp_calendar table.

Thank you...

Hello

It could do:

create or replace FUNCTION fn_test (in_date IN DATE)
return date
is
        l_ret date;
begin
        select startdt-1
        into l_ret
        from (
                select min(holiday) startdt, max(holiday) enddt
                from (
                        select id, holiday, holiday-(row_number() over (order by holiday)) grp
                        from temp_calendar
                )
                group by grp
        ) v
        where in_date-1 between startdt and enddt;
        return l_ret;
exception when no_data_found then
        return in_date-1;
end fn_test;
/

Test:

[11.2] Scott @ My11g > l
  1  declare
  2  l_date1 date := to_date('8-JAN-2012','dd-Mon-yyyy');
  3  l_date2 date := to_date('7-JAN-2012','dd-Mon-yyyy');
  4  begin
  5  null;
  6  dbms_output.put_line(l_date1 ||' => '||fn_test(l_date1));
  7  dbms_output.put_line(l_date2 ||' => '||fn_test(l_date2));
  8* end;
[11.2] Scott @ My11g > /
08/01/2012 00:00:00 => 07/01/2012 00:00:00
07/01/2012 00:00:00 => 04/01/2012 00:00:00

PL/SQL procedure successfully completed.

Elapsed: 00:00:00.02

Tags: Database

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. . .
SELECT COUNT(*) AS rowsNum
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Indeed, oracle considers "I.tbname" as an unknown table name (although he refers to by its exact name).

SQL> @script.sql

                                FROM I.tbname;
                                       *
ERROR at line 99:
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How can I solve this problem? I mean, how to use a variable (in my example, I.tbname) as the table name in the FROM clause to query a table instead of explicitly write the name of the table?

Thanks in advance,
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By the following:

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Max
[My Italian blog Oracle | http://oracleitalia.wordpress.com/2010/01/10/crittografia-in-plsql-utilizzando-dbms_crypto/]

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Hi yankyhater,

Windows Vista does not feature of holidays in windows calendar. There are third party online software that can help you accomplish the task above.

Link below may interest you
Create a family calendar with Windows Vista
http://www.Microsoft.com/athome/organization/vistacalendar.aspx

I hope this helps!

Halima S - Microsoft technical support.
Visit our Microsoft answers feedback Forum and let us know what you think.

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Don't forget to mark it as "answered". It will help others with a similar problem, and it will save time for people answering questions on this forum.

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select trunc(start_date), max(start_date), max(total_days) from tablename
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Please check below is on my local site with you Test data:

SQL>
SQL> with tablename as
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 10  select to_date('1/1/2012 16:00' , 'mm/dd/yyyy hh24:mi') start_date,  2 total_days from dual union all
 11  select to_date('1/2/2012 14:00' , 'mm/dd/yyyy hh24:mi') start_date,  1 total_days from dual union all
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 14  select to_date('1/4/2012 18:00' , 'mm/dd/yyyy hh24:mi') start_date,  1 total_days from dual
 15  )
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 17  group by trunc(start_date);

START_DATE       TOTAL_DAYS
---------------- ----------
10/15/2011 05:00          1
01/03/2012 15:00          1
12/30/2011 10:00          1
01/01/2012 16:00          2
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8 rows selected.

SQL>

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Update: added test done to my database...

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