Resource and resource type definituion table names

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• vCAC vCO plugin - get vCACCAFECsResourceType for resource type internal 'IaaS VC VirtualMachine' in the workflow?

  HI -.

  I'm in vCO using the 6.0.1 plugin vCO for vCAC, trying to create a resource vCAC action ADS face a VC:VirtualMachine. When I manually register my process of action in the UI vCAC, he finds the parameter of VC:VirtualMachine and maps to a resource type 'IaaS VC VirtualMachine', and action shows and works against the VMS selected in the user interface elements vCAC.

  Now, in a workflow to create the action for the resource, I try to use createResourceActionFromWorkflow() from the package com.vmware.library.vcaccafe.asd.resourceaction , which requires a vCACCAFECsResourceType (i.e. VCACCAFE:CustomResource) object. I would like to point to the same resource type "Infrastructure.Virtual" that uses the vCAC UI, but I can't seem to find in a safe way.

  If I get a VCACCAFE:ResourceAction created previously and look at his getInputParameter () .getResourceType () in a workflow, I can see an object that looks like:

  [2014-08-11 16:14:50.094] [I] type.id = eaba1f37-6154-4 ch. 17-94ae-ea419cb9e14e

  [2014-08-11 16:14:50.095] [I] type.name = IaaS VC VirtualMachine

  [2014-08-11 16:14:50.095] [I] type.externalTypeId = Infrastructure.Virtual

  [2014-08-11 16:14:50.095] [I] type.vcoType = VC:VirtualMachine

  [2014-08-11 16:14:50.095] [I] type.vcoId = null

  [2014-08-11 16:14:50.095] [I] type.providerId = asd.external

  [2014-08-11 16:14:50.096] [I] type.tenantId = _internal

  and if I make a new vCACCAFECsResourceType() and manually set the values (especially the id) in this object and use it in createResourceActionFromWorkflow(), it works. But he feels unsure and hardcode the type.id in my workflow - is that work on the other vCAC installs?

  Also, I was to get the corresponding vCACCAFEResourceType via:

  
  

  vCACCAFEHost.createAdvancedDesignerClient () .getAdvancedDesignerCsResourceTypeService () .getResourceType ('_internal', 'Infrastructure.Virtual');

  but it's a different object class and I do not see how to get the vCACCAFECsResourceTypecorrespondent.

  I also tried to do a com.vmware.library.vcaccafe.asd.customresources.createCustomResourceFromInventoryType ("VC:VirtualMachine"), then using this vCACCAFECsResourceType to create the resource action. It creates and publishes very well, but the action never shows in the vCAC UI (using the same rights as when using Infrastructure.Virtual).

  Any ideas? Thank you

  Greg

  This turns out to be just a question in 6.0.

  When I switched to 6.1, the entries in the 'Resources mappings' tab in the show of the interface user upward into the folder "ASD Custom Resources" in the inventory of the vCACCAFEHost and vCACCAFEEntitiesFinder.findCustomResources (host), returns with the mapped to 'VC:VirtualMachine' have good guid. This same method in 6.0 returns an empty array.

• table names the interface and interface modules of oracle programs

  Hi all
  I need urgent and specific information on the names of the tables of the interface and the following oracle R12 modules interface programs, or either ther are custom made. Any specific link by referring to information of desire would be much appreciated.
  In addition, I need a clear and simple definition and the purpose of the tables of the interface and the program interface and what other names are known in the industry.
  
  Data object, Oracle Module
  Chart of accounts, General Ledger Oracle
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  Main provider, Oracle Payables
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  Master client, Oracle to receive
  
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  Master asset, active Oracle
  
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  Routings, Oracle discrete manufacturing
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  Pending purchase orders, purchase of the Oracle
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  Price list, Oracle order management

  Salvation;

  His metalink note you need connection with valid CSI number metalink (support ID customer) can notice via using the note number.

  Please see:

  Oracle EBS based tables and Interface
  Oracle EBS based tables and Interface

  Respect of
  HELIOS

• I don't find the default resource Type in my console OAM.

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  This may be due to an incomplete installation of OAM. I would say to install and configure OAM even once.

• Always downloaded files like "attachment.ashx" instead of the file name and file type they actually are.

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  Hi Linda,.

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• How to query a resource Type definition?

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  Using framework HA to protect applications third, is posible define the types of resources with the command:

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  I can't find the command.

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  crsctl status type ora.network.type f

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• What is the difference between the type of table and view?

  Hello world.

  What is the difference between the type of view and table that we can set using SQL statement such as: "tab type is table of...» » ?

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  An array type is a construction of PL/SQL.

  Both are documented:

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• Remove the resource type that is already mapped.

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• Record and Types of Table definition

  Is there a good tutorial out there somewhere that provides good examples on how to define and work with recording and Types of Table? How to define and work with a complete file or table rather than just a variable?
  
  For instance - I would like to create a cursor of records in a table, to loop through each record to examine the values of variables and in some cases, insert these entire records in another table.
  
  Thanks in advance for your suggestions.

  Oracle documentation is excellent (lots of living examples can you cutNpaste) starting point.

  http://download.Oracle.com/docs/CD/B10501_01/AppDev.920/a96624/05_colls.htm

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• Possibility to change the BA, TABLE name for a report, and then keep putting in the form

  Hi all
  
  I have a report from a custom folder of BA1 xx_test1... Now, I want to modify the workbook to use the custom file BA2 xx_test2.
  The custom folders have the same exact columns.
  
  Is it possible because I dione a lot of formatting and donot want to redo everything again. ?
  
  Thank you
  VJ

  Hi Vj
  Let me explain a few things about Discovererw workbooks.

  All the code needed to run than a workbook is embedded in the workbook. There is no record of SQL that you can go change the code. Discoverer incorporates the name of the file and identify as well as the name of any joint used. You can change the name of a folder without causing any problem as long as you do not modify the identifier as well. When the workbook opens then he will still find the folder. You should save the workbook again at this time so that the appropriate folder name is saved too.

  Interestingly, the corporate domain names are not included in the workbook. If the Finder can locate records is any accessible business while the workbook is open.

  So here's what I'd do:

  1. get the new SQL for the custom folder and replace the SQL in your existing folder

  2. rename the folder in the name you want to use. DO NOT modify the identifier and DO NOT change the names of all the joints.

  3 try to open your workbooks. They will find the file and continue working

  With regard to a new BA, here's my recommendation.

  1. create a master BA for all folders

  2 use folders to manage in the Admin tool, I'd share any files with this master BA - then you have an area for maintenance

  3. create a new empty BA

  4 use folders to manage again, sharing folders, you need the new BA - the joints will get too shared

  5 using the tools | Security, grant users access to this new BA and remove access to any former

  That's all. The workbooks will find records in the new BA and continue as before.

  I'm really sorry about planning. This is an option you should use really. It sounds like your business might need a discoverer health check, to make sure that you use it properly. Have a look here: http://ascbi.com/consulting.htm

  I hope my answers above help
  Best wishes
  Michael

• IOM table name

  Hello
  
  
  I put in service resource AD, and I want to check the AD in the IOM database process form data.
  
  Please help me find the name of the table.
  
  Thank you

  You can see the table name in AD Process Definition in Console Design.

  If you have installed the connector OOTB AD, it would be UD_ADUSER.

• How to find all the table names in all modules in EBS R12?

  How to find all the table names of all the modules in EBS R12?

  In addition, you can go to http://etrm.oracle.com, you select the version of the EBS, select "FND Data" or "S/n data", select the Type of the object TABLE and you will get all the tables of EBS in module.

• fill a field from the sum and the other two table group

  I have a table named dgpercentagedatachart that has a field
  called totalcecrating which must be completed

  dgpercentagedatachart is my target table

  To fill in this field, I will use two existing tables

  Table 1 = rental service

  Table 2 = meter

  I need the SUM of the KW of field in table 2 GROUPBY feederid in table 1

  Table 1 and table 2 common field is the objectid tbl1 and servicelocationid
  for tbl 2, so this is will be the join I will use

  It of what I have so far in my query, but are unable to complete
  correctly. I need help!

  Insert into dgpercentagedatachart (totalcecrating)

  using servicelocation (objectid)

  Sum (kW)

  innerjoin servicelocation meter

  on meter.servicelocationid = servicelocaid.objectid

  GROUP BY servicelocation.feederid;

  Here is my table DG % (target)

  name of the field type Nullable

  TOTALCECRATING NUMBER (38.0) Yes

  FEEDERID NVARCHAR2 (255 CHAR) Yes

  NUMBER (38.8) PERCENTAGE Yes

  LOWESTFEEDERRATING NUMBER (38.0) Yes

  OBJECTID NUMBER (38.0) No.

  DG % DATACHART

  DATA

  FEEDERID TOTALCECRATING

  X 33

  X 33

  X 121

  X 122

  ServiceLocation table (table 1)

  fieldName nullable datatype

  OBJECTID NUMBER (38.0) No.

  Yes FEEDERID VARCHAR2 (20 BYTES)

  Data

  OBJECTID FEEDERID

  61897 X 33

  61898 X 33

  61899 X 33

  61900 X 33

  B521 141287

  Counter table (table2)

  fieldName Nullable Datatype

  Yes NUMBER (38.8) KW

  OBJECTID NUMBER (38.0) No.

  ID ServiceLocation source KW

  PV 0 162756

  194720 PV 1.01

  106697 PV 1.2

  195975 PV 1.2

  133967 PV 1.5

  105461 PV 1.6

  365278 PV 1.62

  Hello

  2685870 wrote:

  That's what I received your reply:

  Select sum (m.kw), servicelocation.feederid

  of servicelocation sl, meter m

  where to meter servicelocation inner join

  on meter.servicelocationid = servicelocation.objectid

  Servicelocation.feederid group;

  ...

  You are mixing up in two different ways to do joins.

  ANSI join syntax uses the keyword JOIN between table names and the join conditions, after the keyword, all in the FROM clause, like this:

  OF sevicelocation sl

  JOIN meter m ON m.servicelocattionid = sl.objectid

  The old Oracle syntax has commas between the names of tables in the FROM clause and the join conditions go in a WHERE clause.  JOIN keywords and THEY are not used.  For example:

  OF serviceloation sl

  meter m

  WHERE m.servicelocattionid = sl.objectid

  Do not use both in the same query.  Use one or the other consistently.  (I recommend the ANSI rating.)

• There are two select statement, which are as follows: 1) select project id, the name of ppm.pm_projects project_name and request_id 2) select id, name from request_type_name to kcrt_request_details. There is a column called entity that allows you to store

  There are two select statement, which are as follows: 1) select project id, the name of ppm.pm_projects project_name and request_id 2) select id, name from request_type_name to kcrt_request_details. There is a column called entity that can store a value i.e. project or request. I want to write a select statement containing a condition that is if the entity name is project and then run the select statement 1 otherwise, if the name of the entity's request, then run the select statement 2. All this must be written in a select statement. Can someone help me how to write this select statement type.

  Hello

  Hello

  2726057 wrote:

  ... There is a column called entity that can store a value i.e. project or request. ...

  In which table is this column?  Assuming that it is in a table called entity_table, you can do something like this:

  SELECT project AS id

  project name AS the name

  OF ppm.pm_projects

  WHEN THERE IS)

  SELECT 1

  Of entity_table

  Entity WHERE = "Project".

  )

  UNION ALL

  SELECT request_id ID

  request_type_name AS name

  OF kcrt_request_details

  WHEN THERE IS)

  SELECT 1

  Of entity_table

  Entity WHERE = 'ask '.

  )

  ;

  This does not have anything on the number of lines is entity_table, or what are the values in the column of the entity.  In other words, the query works in all cases.  If any line in entity_table entity = 'Project', then the pm_projects data will be included in the result set.  If any line in entity_table entity = 'Request', kcrt_request_details data will be included.

  I hope that answers your question.

  If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

• Curl call to start the workflow with the Type of table / Composite

  Hello I'm trying to start a workflow with an array type / Composite.

  I'm using curl to make the call and post fields look like this when you send just a string:

  {

  "settings":

  [

  {

  'value ':

  {

  "chain": {"value": "test"}

  },

  "type": "string",.

  "name':"vm. "

  "scope": "local".

  }

  ]

  }

  How would he format if I had a type of table / Composite?

  The composite type has the format of the Type / size and String / number

  Well, I don't know like what your workflow, but here is what looks like my quick test workflow:

  

  MESSAGE: https://YOUR-VCO-SERVER;8281/vco/api/workflows/475a3967-2c29-4140-a63f-ec1822ec330b/executions/

  Headers:

  Content-Type: application/json

  Accept: application/json

  And here is the json work to get into the body:

  {
      "parameters": [
          {
              "value": {
                  "array": {
                      "elements": [
                          {
                              "composite": {
                                  "type": "CompositeType(Type:string,size:number):drives",
                                  "property": [
                                      {
                                          "id": "Type",
                                          "value": {
                                              "string": {
                                                  "value": "NTFS"
                                              }
                                          }
                                      },
                                      {
                                          "id": "size",
                                          "value": {
                                              "number": {
                                                  "value": 20
                                              }
                                          }
                                      }
                                  ]
                              }
                          },
                          {
                              "composite": {
                                  "type": "CompositeType(Type:string,size:number):drives",
                                  "property": [
                                      {
                                          "id": "Type",
                                          "value": {
                                              "string": {
                                                  "value": "ext3"
                                              }
                                          }
                                      },
                                      {
                                          "id": "size",
                                          "value": {
                                              "number": {
                                                  "value": 25
                                              }
                                          }
                                      }
                                  ]
                              }
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                      ]
                  }
              },
              "type": "Array/CompositeType(Type:string,size:number):drives",
              "name": "drives",
              "scope": "local"
          }
      ]
  }
  

  I've included the workflow here as well.

  Just a simple script:

  System.debug("Drives:");
  for each (drive in drives){
    System.debug("================");
    System.debug("Type: "+drive.Type);
    System.debug("Size: "+drive.size);
  }
  

  My results: