Restarting Lightroom - how * and * recorded preferences (and start with the specified catalog)

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  I accidentally deleted my copy of Lightroom 5. How can I re install and activate it with the disk? Any help would be greatly appreciated.

  You can download the latest version here:

  Updates

  If you perform the installation on the same computer is perhaps not necessary to re-enter your serial number. But it would be a good idea to have your number of series available if necessary.

• How to record entries of UI with the data measured in a TDM file?

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• media, stops and starts with the cursor movement on the screen

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  Hello Craig Barnett.

  Thank you to contact the community Microsoft and we will be happy to help you with your concern.

  According to the description, it seems that you are having problems with online videos don't play do not.

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• Understanding "CONNECT BY" and "START WITH".

  OK, I'm trying to update the rows with values determined by lines joined in a recursive relationship of unknown depth. I am told that "CONNECT BY" and "START WITH" can be useful in this, but I don't see how to get the value I'm looking for.
  
  In my case, there are 3 values in my table.
  ID
  ID of the parent
  Invoice
  
  On some lines, the Bill is null. For records, you get the ID of the invoice by searching for the invoice of the parent folder. I'm trying to update the table so that all THE rows in the table have an ID of invoice.
  
  Here is an example of table and the lines.
  

  CREATE TABLE DISTRIBUTION (
  ID            INT,
  INV_NUM       INT,
  PARENT_ID     INT
  )
  
  INSERT INTO DISTRIBUTION 1, 111, NULL;
  INSERT INTO DISTRIBUTION 2, 112, NULL;
  INSERT INTO DISTRIBUTION 3, NULL, 2;
  INSERT INTO DISTRIBUTION 4, 113, NULL;
  INSERT INTO DISTRIBUTION 5, NULL, 4;
  INSERT INTO DISTRIBUTION 6, NULL, 5;
  INSERT INTO DISTRIBUTION 7, NULL, 6;

  What I would do is update the inv_num column in the table so that a select statement * would look like this...
  

  ID        INV_NUM    PARENT_ID
  -----     -------------     ---------------
  1            111           null
  2            112           null
  3            112              2
  4            113           null
  5            113              4
  6            113              5
  7            113              6

  You can provide any help would be greatly appreciated.

  Hello

  Thank you post the CREATE TABLE and INSERT instructions, but please make sure that they work.
  None of the INSERT statements; I think you meant something like the statements shown after the query.

  Here's a way to get the desired results:

  UPDATE  distribution     m
  SET     inv_num = ( SELECT  inv_num
                FROM    distribution
                WHERE   CONNECT_BY_ISLEAF     = 1
                START WITH     id          = m.id
                CONNECT BY     id          = PRIOR parent_id
                         AND     PRIOR inv_num     IS NULL
                 )
  WHERE   inv_num       IS NULL
  ;
  

  This statement is Bottom-Up of subqueries, where we START WITH the lines that need to update, and process to the top of the tree, until you get to an ancestor who was an inv_num.
  In your sample data, only the roots (the lines that have no parents) have inv_num. In this case, it might be a little easier (but only a little) to make a request from top to bottom , where we START WITH the roots and low process in the tree to find their subordinates.
  If we add some data examples where a nonroot has inv_num:

  INSERT INTO DISTRIBUTION (id, inv_num, parent_id) VALUES ( 91, 910,   1);
  INSERT INTO DISTRIBUTION (id, inv_num, parent_id) VALUES ( 92, NULL, 91);
  

  What results would you like?
  Using the UPDATE statement above, id = 92 would get his inv_nuym of the closest ancestor (in the case of thios, parent) who had an inv_num:

  .       ID    INV_NUM  PARENT_ID
  ---------- ---------- ----------
           1        111
          91        910          1
          92        910         91
           2        112
           3        112          2
           4        113
           5        113          4
           6        113          5
           7        113          6
  

  Either the row with id = 92 gets inv_num = 910, no 111.

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  The servers are windows 2008 r2. Don't know if it matters.

  I'm not exactly an expert at the express request...

  Hi DJake,

  DJake wrote:

  I have a server/database Application Express 4.1.1 running and a server/database Application Express 4.2.0 running. Is it risky to try to upgrade them both to the latest version and start using the universal or complex theme?  Is how easy it to do? Recommended?

  The servers are windows 2008 r2. Don't know if it matters.

  I'm not exactly an expert at the express request...

  Please read the documentation of the requirement for Oracle APEX 5. Ensure that your environment meets these requirements. Upgrade your oracle database or other software if necessary components and then you can go right 4.1/4.2 to 5.0 update according to the above-discussed upgrade strategies in the above discussions.

  Reference: https://docs.oracle.com/cd/E59726_01/install.50/e39144/pre_require.htm#HTMIG376

  You should go for upgrade of the Oracle APEX of 4.1 to 5.x. Regression test your applications to remove if any errors introduced by upgrade. The kickoff of a new project to migrate your applications to universal theme.

  Reference:

  • Re: upgrading to 5.0 - best practices
  • Re: APEX late upgrade
  • https://www.YouTube.com/watch?v=o8S4bg4Vo0A

  Kind regards

  Kiran

• If I want to open the Web site in a second tab and press Ctrl + T and start typing the title of the website or the URL, why Firefox 4 insists on moving to the first tab? Is it possible to disable this option?

  I regularly need to open the same Web site in two tabs, to be able to view the changes between the first and the second opening tabs. In Firefox 3.x I could press Ctrl + T and start typing the URL or Web site title, which would be part by Firefox. This allowed me to open quickly the same website in a second tab Firefox 4 does not, on the contrary, he wants me to switch to the existing tab. This isn't what I need.

  Of course, it is possible to open the Web site in a second tab through for example a bookmark, but it takes more time and effort. It would be great if I could select the Firefox behavior in this situation.

  If you have already opened this page in another tab and then you get a switch to tab appears in the location bar menu drop-down.

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• How and what is the keyboard shortcut for layer duplicated in a new tab? Thank you!

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