Retrieve two values of column in a table
Hi I want to retrieve two values of column in a table and store the values as a single column value in another table... How to do with it?Use in this way:
Insert in tab2 (col1) select col1 | col2 from tab1;
Tags: Database
Similar Questions
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return two values of columns via Javascript
For the same purpose as:
OnClick = "$s ('P1_DEPTNO', #DEPTNO #); return false; »
to return a value from column via javascript, is it possible to return 2 values? Example:
OnClick = "$s ('P1_DEPTNO', #DEPTNO #); $s ('P1_EMP, #EMPLOYEE #); return false; »
Thank you all :)
MaxMaxime Carrier wrote:
Sorry for the wrong question form, I'm not an English speaker, so I try my best to make sentences clear.My goal is like this in this issue: Insert the value of a column in the report in a page with JavaScript element - 2?
My Apex version is: 4.0.2.00.06
My DB is: Oracle 11G
My browser: IE 7I'm trying to save two values when I click on a link in a report. I will use these values in which the declaration of another report. The content of the second report will depend on the link I clicked in the 1st. It will change dynamically without reloading the entire page.
Standard or interactive report?
Where is the defined link? Column link IR? The column link? HTML embedded in the report query?
One of the two values is not a number.
Use quotes around chains of substitution of the column as shown above.
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Retrieve the names of columns in a table.
Hi all
I want to retrieve column names of a table "test", whose values are null
For ex:
Select * from test
give the results that
column_1, column_2, column_3, column_4
111
allows to consider the case that the table has only one record.
as a result, we will have to get column_2, column_3, column_4 and more.
I tried dynamic "run immediately" the statement and tried to extract in a single execution of immediate instruction, but I wasn't able to accomplish because of several columns.
is it possible without using a pl/sql function or procedure?Check this box:
SQL> INSERT INTO my_Test values('ABCD',NULL,NULL); 1 row created. SQL> COMMIT; Commit complete. SQL> select * from my_Test; COL1 C COL3 ---------- - ---------- ABCD SQL> declare 2 CURSOR C1 IS SELECT column_name FROM all_tab_cols WHERE table_name = 'MY_TEST'; 3 v_sql VARCHAR2(10000) := NULL; 4 my_null_col_list VARCHAR2(32767) := NULL; 5 my_cnt NUMBER := 0; 6 BEGIN 7 FOR I in C1 LOOP 8 v_sql := 'SELECT COUNT(*) FROM my_test WHERE '||I.column_name ||' IS NULL'; 9 execute immediate v_sql INTO my_cnt; 10 IF (my_cnt > 0) THEN 11 my_null_col_list := my_null_Col_list||','||I.column_name; 12 END IF; 13 END LOOP; 14 my_null_col_list := SUBSTR(my_null_col_list,2); 15 dbms_output.put_line('Columns that have null values for table my_Test are:'||my_null_col_list); 16 END; 17 / Columns that have null values for table my_Test are:COL2,COL3 PL/SQL procedure successfully completed. SQL> desc my_test; Name Null? Type ----------------------------------------- -------- ---------------------------- COL1 VARCHAR2(10) COL2 VARCHAR2(1) COL3 VARCHAR2(10) SQL>
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using a Case statement to display the values of column even as table headers
I have a database that has been set up kind of tricky, in that some tables are made up of columns that are field names and one link to another table that contain the data for these field... also names there ID displays as many lines instead of as a row of data. I would like to write a query to extract that information and display it as one line for each ID.
example: table 1
ID, name, itemresponse and itemcode, Description
Dee Jones Childrens Hospital 123 SITE location
123 dee Jones, Date of appointment next NEXTAPPT 22/04/2014
123 dee Jones was on bedrest NOSHOW reason do not show
I would like to have the display of data as a record on this same patient, instead of as 3 separate registers (with the Description column in table 1
Table 2
ID, name, place, Date of the next meeting, show no reason
123 dee Jones Childrens Hospital 22/04/2014 was the bed rest
I have included the code I worked on below my question, for me to get the desired results should I use the Case statement and it's the right way to do it below?
(SELECT
PAT.ID "PATIENT ID."
PAT. FIRST | » '|| PAT. "PATIENT FIRST NAME."
PAT. "PATIENT DOB," DATE_OF_BIRTH
DS. Date 'Date of inpatients ',.
Dai. ITEM_CODE "Item Code",
Dai. DESCRIPTION "Description."
Siad. ITEM_RESPONSE,Max (CASE WHEN dai. ITEM_CODE IS "SITE" THEN DAI. Decription
ANOTHER NULL
END) AS "name of the hospital."
Max (CASE WHEN DAI.) ITEM_CODE IS 'NEXTAPPT' THEN DAI. ITEM_Description
ANOTHER NULL
END) AS 'next Appt Date. "
Max (CASE WHEN DAI.) ITEM_CODE IS "LASTDATE" THEN DAI. Description
ANOTHER NULL
END) AS 'last visit Date.
Max (CASE WHEN DAI.) ITEM_CODE IS 'NOSHOW' THEN DAI. Description
ANOTHER NULL
END) THAT "the reason has not shown".
Of
(PAT.ID "IDENTIFYING PATIENT",
PAT. FIRST | » '|| PAT. "PATIENT FIRST NAME."
PAT. "PATIENT DOB," DATE_OF_BIRTH
DS. Date 'Date of inpatients ',.
Dai. ITEM_CODE "Item Code",
Dai. DESCRIPTION "Description."
Siad. ITEM_RESPONSEOf
dm_sessions Ds,
dm_session_assessments dsa,
DAS dm_admin_sections,
dm_session_assessment_items Siad,
Dai dm_admin_items,
Po Patient_Orders,
Inventory inv,
Patients_Table PAT
dm_admin_categories CAD
where dsa.session_Id = ds.session_Id
and PAT.ID = ds. Patient_ID
and dsa.excluded_assessment =' no
and dac.category_code = 'OPEN'and dsa.section_id = das.section_id
and das.category_id = dac.category_id
and das.section_code = 'northwest'
and dai.section_id = das.section_id
and dsai.item_id = dai.item_id
and dsai.session_assessment_Id = dsa.session_assessment_Id
and dsai.excluded =' no
- and Dai.ITEM_ID = Dsai.ITEM_ID
and Dai.ITEM_CODE IN ('SITE', 'NEXTAPPT', 'LASTDATE', 'NOSHOW')
and po.patient_ID = ds.patient_ID
and in. NDC_NO = inv. NDC_NO
and inv. TDRUG_ABBREV = in. DRUG_ABBREV
PAT.ID GROUP, PAT. FIRST | » '|| PAT. LAST, PAT. DATE_OF_BIRTH, ds. Date, dai. ITEM_CODE, dai. DESCRIPTION, Siad. ITEM_RESPONSE))Hello
DATE is not a very good name for a column. Use something like EVENT_DATE, that will not be confused with a keyword from Oracle, instead.
I don't see something like this column in the CREATE TABLE statement. He will always be the same value on all lines?
Here's a way to get the results you requested:
SELECT id
first name | ' ' || LastName AS name
Date of birth
MAX (CASE WHEN item_code = "NEXTAPPT", THEN item_response END) AS next_appointment,
MAX (CASE WHEN item_code = "LASTDATE" THEN item_response END) AS last_visit_date,
MAX (CASE WHEN item_code = "SITE" THEN item_response END) AS location
FROM mytable1
GROUP BY id, firstname, lastname, dob
;
Of course, I can't test it very well until you post INSERT statements for the sample data.
I guess that 2 or more lines of the entry have the same id, then they will necessarily be first name last name, the name and date of birth, too. No doubt they are standardized in your actual tables.
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Hello
Please let me know how to query the table and get the records that are less than the other column.
ID item_id item_type
3 1 r1
2 4 r2
1 5 r3
6 5 r4
I need to get all the lines in which item_id < id
o/p
ID item_id item_type
3 1 r1
6 5 r4
SELECT ID, ITEM_ID, ITEM_TYPE
Of
WHERE ITEM_ID<>
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How can I get number of columns for all tables in a schema?
HelloCan someone help me with the code to retrieve any of the columns in each table of a master plan? I'm sorry if it sounds simple. I'm a newbie...
Thank you
Maybe:
Select table_name
count (*) col_count
of user_tab_cols
Table_name group
order of table_name;
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How to replace the value of a column in a table based on the value in the second column?
Hi, I would like to find in a table 2D for values that meet certain criteria (for example, a column< 0.98).="" based="" on="" which="" rows="" meet="" this="" criteria,="" i="" want="" to="" replace="" the="" values="" in="" a="" different="" column="" of="" the="" array="" (change="" to="" 'nan'="" so="" that="" the="" values="" will="" not="" be="" included="" in="" any="" calculations="" on="" that="" column,="" for="" example="" the="" finding="" the="" mean).="" i've="" attached="" a="" sample="" .csv="" file.="" if="" the="" values="" in="" column="" 3="" (index="" 2)="" are="" less="" than="" 0.980="" (or="" some="" other="" user="" defined="" value),="" then="" the="" value="" in="" column="" 2="" (index="" 1)="" should="" be="" replaced="" with="" nan.="" can="" someone="" help="" out="" with="" this="" search="" and="" replace="">
Thank you
Keith
(using LV 2009 SP1)
A few quick hits.
You can merge the two for loops
You have not need one of the constants 1 and 2 in the index table. They will solve automatically when you expand on the index picture, once you have wired to 0 in the column index.
It seems a lot of handling additional table spent unnecessarily.
See below. I did not try to duplicate your code to see how it actually works, but I believe that I have attached will give the same result with less steps.
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Input data match with two columns in a table
Hello
I want to find records where the input data (> 100 records) are adapted to the two columns of the table
See below
with t as
(select 1 as id, 101 as num 'ram' that pat from dual
Union
Select 2 102, 'tom' from dual
Union
Select 1 103, 'tom1' from dual
Union
Select 2 101, 'tom2' from dual
Union
Select 2 104, 'tom3' from dual
Union
Select 1 105, 'tom1' from dual
Union
Select 2 105, 'tom1' from dual
)
Select * from t
I want to find records from the 't' table where (id, num) will be (1 101, 2 102, 1, 105)
Output must be
ID num
1 101
2 102
1 105select * from t where (id, num) in ( (1,101), (2,102), (1,105) );
Or store the input in a temporary table values and use IN
select * from t where (id, num) in ( select col1,col2 from your_temp_table );
Published by: JAC on 20 may 2013 14:55
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Oracle how to multiply two columns of different tables and results
Oracle how to multiply two columns of different tables and get the result in the third column?
I want to multiply all the lines of the quantinty column in the table of quantity with the relevant lines of the table of prices price column and get the result of multiplying in the third column. What should I use procedure trigerr? OR IS IT POSSIBLE HOW TO DO IT PLEASE HELP :D
Edited by: 994229 2013-03-15 12:44/* Formatted on 3/15/2013 3:51:08 PM (QP5 v5.185.11230.41888) */ CREATE TABLE mytable1 AS (SELECT 1 id, 5 VALUE FROM DUAL UNION ALL SELECT 2, 7 FROM DUAL UNION ALL SELECT 3, 8 FROM DUAL); CREATE TABLE mytable2 AS (SELECT 1 id, 4 VALUE FROM DUAL UNION ALL SELECT 2, 12 FROM DUAL UNION ALL SELECT 10, 12 FROM DUAL); SELECT id, mytable1.VALUE, mytable2.VALUE, mytable1.VALUE * mytable2.VALUE product FROM mytable1 FULL OUTER JOIN mytable2 USING (id) ORDER BY id;
ID VALUE VALUE_1 PRODUCT 1 5 4 20 2 7 12 84 3 8 10 12
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How to set the value of a column in a table according to another column?
Hello world!
I use Apex 4.1.
My question is how can I set the value of a column in a table according to another column?
I have a table and when I insert the value in the column content, I want to change this value in the note column with the note, which is generated with pl/sql function (function of string returned if the typed value is in the range).
I tried to use javascript as
for the development of the column note to test if the value typed in the content of the column is not 1, but this code assigns the value to all the lines and I need to set only the specified line.$('input[name=f02]').live('change', function(){ if($(this).val()!='1'){ $('input[name=f03]').val("test")} });
Can someone give me a hint in any way to do this if possible?
Kind regards
drama9346You will need create a process on your page type PLSQL and develop this process "we demand" of the page. In this process, you can run the PLSQL you need. That is to say to retrieve the note value as described in your PC:
and when I insert the value in the column content, I want to change this value in the note column with the note, which is generated with pl/sql function (function of string returned if the typed value is in the range).
In this process, you must provide a return value of the call, and you can do this by using htp.p. Example:
DECLARE --putting x01 in a var to simplify l_test_var VARCHAR2(200) := apex_application.g_x01; l_return VARCHAR2(200); BEGIN -- a simplistic test IF LENGTH(l_test_var) BETWEEN 10 AND 20 THEN l_return := 'String is between 10 and 20'; END IF; --this will write l_return to the buffer, and the ajax callback will receive this htp.p(l_return); END;
And the code that I wrote above, which is javascript, would need to go where your current code is that binds to the onchange event. The result should be that, when a change is made to this element, an ajax request is made on the server. When the call is finished, it will be the value returned in the item you want.
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How to exchange the two values in the same column by using the UPDATE?
Hi all
I have a table named TEST, and it has a column called A.
and has values as follows:
A
------
10
20
30
40
50
My question is how to move '10' instead of '20' and '20' instead of '10' in the column? This permutation is only for the first two values (10, 20)
Note: Must be only in SQL, not in PLSQL.
Any advice?
Thanks in advance?Update
test
the value a = decode(a,10,20,20,10,a);Alexander gelin
http://nimishgarg.blogspot.com/ -
How to upgrade a minimum value of column column in another table?
Hi all
I created a few tables as below, and it need to update a column in a table with a minimum value of the column of another table...
Scenarios explained as follows:
NOW I WANT TO UPDATE T_30 THAT LOOKS AT BELOW:CREATE TABLE T_20 (CONTROL NUMBER(10) NOT NULL, PO NUMBER(10) NOT NULL, AMENDNO NUMBER(3) NOT NULL, FACTOR VARCHAR2(3) NOT NULL, COMMENT_X VARCHAR2(40), FLAG VARCHAR2(1)) SQL> alter table t_20 add constraint t_20_pk primary key (control, po, amendno, factor); SQL> DESC T_20; Name Null? Type -------------------------- -------- -------------- CONTROL NOT NULL NUMBER(10) PO NOT NULL NUMBER(10) AMENDNO NOT NULL NUMBER(3) FACTOR NOT NULL VARCHAR2(3) COMMENT_X VARCHAR2(40) FLAG VARCHAR2(1) Table altered. CREATE TABLE T_30 (CONTROL NUMBER(10) , PO NUMBER(10) , AMENDNO NUMBER(3) , FACTOR VARCHAR2(3) , AMOUNT NUMBER(10,2), USER_NAME VARCHAR2(4)) SQL> / Table created. SQL> INSERT INTO T_20 VALUES(101,1000,01,'MSC','NO COMMENT','Y') 2 / 1 row created. SQL> INSERT INTO T_20 VALUES(101,1000,02,'MSC','NO COMMENT','Y') 2 / 1 row created. SQL> INSERT INTO T_20 VALUES(101,1001,00,'NDP','NO COMMENT','Y') 2 / 1 row created. SQL> INSERT INTO T_20 VALUES(101,1001,01,'NDP','NO COMMENT','Y') 2 / 1 row created. SQL> INSERT INTO T_20 VALUES(102,1002,00,'ABC','NO COMMENT','Y') 2 / 1 row created. SQL> INSERT INTO T_30 VALUES(101,1000,NULL,'MSC','400','A') 2 / 1 row created. SQL> INSERT INTO T_30 VALUES(101,1000,NULL,'MSC','500','S') 2 / 1 row created. SQL> INSERT INTO T_30 VALUES(101,1001,NULL,'NDP','600','I') 2 / 1 row created. SQL> INSERT INTO T_30 VALUES(101,1001,NULL,'NDP','700','R') 2 / 1 row created. SQL> INSERT INTO T_30 VALUES(102,1002,NULL,'ABC','800','L') 2 / SQL> SELECT * FROM T_20 2 / CONTROL PO AMENDNO FACTOR COMMENT_X F ---------- ---------- ---------- -------- -------------- ---- 101 1000 1 MSC NO COMMENT Y 101 1000 2 MSC NO COMMENT Y 101 1001 0 NDP NO COMMENT Y 101 1001 1 NDP NO COMMENT Y 101 1002 0 ABC NO COMMENT Y SQL> SELECT * FROM T_30; CONTROL PO AMENDNO FAC AMOUNT USER ---------- --------- ---------- --- ---------- ---- 101 1000 null MSC 400 A 101 1000 null MSC 500 S 101 1001 null NDP 600 I 101 1001 null NDP 700 R 101 1002 null ABC 800 L
By top T_30 initially AmendNo pass is null in T_30. Now I want to update
column based on a minimum value of AMENDNO in the column T_20
best way I can explain is:
In the table T_20
For CONTROL 101-> there are two numbers with 1000 but with different Amendno like 1, 2 in.
and
In the T_30 Table for CONTROL 101-> there are two IN. with 1000 but currently null. REQUIREMENT IS NOW
THE TWO DOCUMENTS SHOULD BE UPDATED WITH MIN (AMENDNO) FOR THIS CONTROL T_20. IN THIS CASE FOR THIS CONTROL
101 MIN (AMENDNO) IS '1' (1, 2)
SO 101 RECORDS (BOTH) OF NOW T_30 SHOULD BE UPDATED WITH '1' AS AMENDNO
Once again 101 now have one another IN '1001' with two different 0.1 IN. now T_30 AmendNo should be updated with min (0.1) which is
'0'
production is expected to be lower after update:
Propose any query pls...SQL> SELECT * FROM T_30; CONTROL PO AMENDNO FAC AMOUNT USER ---------- ---------- ---------- --- --------- ---- 101 1000 1 MSC 400 A 101 1000 1 MSC 500 S 101 1001 0 NDP 600 I 101 1001 0 NDP 700 R 101 1002 0 ABC 800 L
Thanks in advance...
I'll try level better to format the pure code in the post...
Concerning
PrasanthTry this
update t_30 x set amendno = ( select amendno from ( select control, po, factor, min(amendno) amendno from t_20 ) y where x.control = y.control and x.po = y.po and x.factor = y.factor ) where exists ( select amendno from ( select control, po, factor, min(amendno) amendno from t_20 ) y where x.control = y.control and x.po = y.po and x.factor = y.factor )
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Update the value of the column based on another value of the column to another table
Hi all
I have something very confused me and need your help.
Having two tables A and B.
Table A have 2 column (+ id + and desc1)
Table B have column 2 also (+ transnum + and desc2)
Now, I want to update the column desc2 of table B identical desc1 of table was where transnum of Table B same as the id of the table has.
I use this SQL
update of a2 set a2.desc2 = a1.desc1 of a2 on a2.transnum = a1.id inner join a1
but this error occurs
Error from line 5 in order:
update of a2 set a2.desc2 = a1.desc1 of a2 on a2.transnum = a1.id inner join a1
Error in the command line: 5 column: 35
Error report:
SQL error: ORA-00933: SQL not correctly completed command
* 00933. 00000 - "command not properly ended SQL."
* Question: *.
* Action. *
Hope someone can help me. TQ for help...SQL> create table a1 (id number(2),des varchar2(10)); Table created. SQL> create table b1 (transnum number(2),des varchar2(10)); Table created. SQL> insert into a1 values (1,'maran'); 1 row created. SQL> insert into b1 values (1,'ram'); 1 row created. SQL> commit; Commit complete. SQL> update b1 set des=(select des from a1 where b1.transnum=a1.id); 1 row updated. SQL> select * from b1; TRANSNUM DES ---------- ---------- 1 maran
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How to retrieve the values of a number of column by column in pl sql
I wanted to know how can I retrieve the values of a column just in number and not the name of the column.user10989720 wrote:
I need exactly this kind of thing.I am retrieving the name of the column from all_tab_columns and under this column name can I retrieve values using any kind of query sub.
Select column_name
from all_tab_columns
where table_name = 'QUOTE_HEADERS_EXT' and
column_id = 58You're still not understanding. You need to do if you want to get the values of the table dynamically.
Either like this:
SQL> create or replace type t_colval is table of varchar2(4000); 2 / Type created. SQL> ed Wrote file afiedt.buf 1 CREATE OR REPLACE FUNCTION get_column(p_sql IN VARCHAR2, p_column_no NUMBER) RETURN t_colval PIPELINED IS 2 v_finaltxt VARCHAR2(4000); 3 v_v_val VARCHAR2(4000); 4 v_n_val NUMBER; 5 v_d_val DATE; 6 v_ret NUMBER; 7 c NUMBER; 8 d NUMBER; 9 col_cnt INTEGER; 10 f BOOLEAN; 11 rec_tab DBMS_SQL.DESC_TAB; 12 col_num NUMBER; 13 BEGIN 14 c := DBMS_SQL.OPEN_CURSOR; 15 DBMS_SQL.PARSE(c, p_sql, DBMS_SQL.NATIVE); 16 d := DBMS_SQL.EXECUTE(c); 17 DBMS_SQL.DESCRIBE_COLUMNS(c, col_cnt, rec_tab); 18 FOR j in 1..col_cnt 19 LOOP 20 CASE rec_tab(j).col_type 21 WHEN 1 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_v_val,2000); 22 WHEN 2 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_n_val); 23 WHEN 12 THEN DBMS_SQL.DEFINE_COLUMN(c,j,v_d_val); 24 ELSE 25 DBMS_SQL.DEFINE_COLUMN(c,j,v_v_val,2000); 26 END CASE; 27 END LOOP; 28 LOOP 29 v_ret := DBMS_SQL.FETCH_ROWS(c); 30 EXIT WHEN v_ret = 0; 31 v_finaltxt := NULL; 32 CASE rec_tab(p_column_no).col_type 33 WHEN 1 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_v_val); 34 WHEN 2 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_n_val); 35 v_v_val := to_char(v_n_val); 36 WHEN 12 THEN DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_d_val); 37 v_v_val := to_char(v_d_val,'DD/MM/YYYY HH24:MI:SS'); 38 ELSE 39 DBMS_SQL.COLUMN_VALUE(c,p_column_no,v_v_val); 40 END CASE; 41 PIPE ROW (v_v_val); 42 END LOOP; 43 DBMS_SQL.CLOSE_CURSOR(c); 44* END; SQL> / Function created. SQL> select * from table(get_column('select * from emp',1)); COLUMN_VALUE --------------------------------------------------------------------------------------------------------------- 7369 7499 7521 7566 7654 7698 7782 7788 7839 7844 7876 7900 7902 7934 14 rows selected. SQL> select * from table(get_column('select * from emp',2)); COLUMN_VALUE --------------------------------------------------------------------------------------------------------------- SMITH ALLEN WARD JONES MARTIN BLAKE CLARK SCOTT KING TURNER ADAMS JAMES FORD MILLER 14 rows selected. SQL>
Or like this:
SQL> create or replace type t_colval is table of varchar2(4000); 2 / Type created. SQL> ed Wrote file afiedt.buf 1 CREATE OR REPLACE FUNCTION get_column(p_table IN VARCHAR2, p_column_no NUMBER) RETURN t_colval PIPELINED IS 2 v_column_name VARCHAR2(30); 3 v_rc SYS_REFCURSOR; 4 v_val VARCHAR2(4000); 5 BEGIN 6 SELECT column_name 7 INTO v_column_name 8 FROM user_tab_columns 9 WHERE column_id = p_column_no 10 AND table_name = UPPER(p_table); 11 OPEN v_rc FOR ('SELECT '||v_column_name||' FROM '||p_table); 12 LOOP 13 FETCH v_rc INTO v_val; 14 EXIT WHEN v_rc%NOTFOUND; 15 PIPE ROW(v_val); 16 END LOOP; 17 CLOSE v_rc; 18* END; SQL> / Function created. SQL> select * from table(get_column('EMP',2)); COLUMN_VALUE ---------------------------------------------------------------------------------------------------------------- SMITH ALLEN WARD JONES MARTIN BLAKE CLARK SCOTT KING TURNER ADAMS JAMES FORD MILLER 14 rows selected. SQL>
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I have a column with two values, separated by a space, in each line. How do I create 2 new columns with the first value in one column and the second value in another column?
Add two new columns after than the original with space separated values column.
Select cell B1 and type (or copy and paste it here) the formula:
= IF (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')
shortcut for this is:
B1 = if (Len (a1) > 0, LEFT (A1, FIND ("", A1) −1), ' ')
C1 = if (Len (a1) > 0, Member SUBSTITUTE (A1, B1 & "", ""), "")
or
the formula of the C1 could also be:
= IF (Len (a1) > 0, RIGHT (A1, LEN (A1) −FIND ("", A1)), "")
Select cells B1 and C1, copy
Select cells B1 at the end of the C column, paste
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