Rownum find less &; max values
Hi allI have a doubt as to ROWNUM.
Can I use rownum to find the n less values & n max values?
CREATE TABLE t1(id NUMBER(10))
SELECT ID FROM (SELECT id FROM t1 ORDER BY id ) WHERE rownum < 20.
This will give me values less 19 first?THX
Rod.
Yes, this query returns the ID values of T1 small 19.
Justin
Tags: Database
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Hi team,
I have the following query where I need to find the max value
[code]
with t as)
Select 'L1' R_nm, R_Data 'Data', 'Obj' R_Obj, r_prec 'Wd', '2' double val
Union of all the
Select 'L1', 'Data', 'Obj', 'No', '4' double
Union of all the
Select 'L2', 'Data', 'Obj', 'No', '4' double)
Select t.*, max (val) on rk (partition r_nm, r_data, r_obj) of t
[/ code]
My results should be
[code]
r_nm r_data r_obj r_prec rk val
L1 Data Obj 1 2 Wd
L1 data Obj 4 No.2
L2 Data Yes 1 1 Obj
[/ code]
Thank you
Hello
It seems that you are not interested in the MAX at all. Looks like you want to classify the lines, such as one that has the lowest value is assigned the number 1, the 2nd line with the lowest values gets 2,... and line with him gets N-th lowest value N. If is not serious if the MAX is 4, 2 or 420.
Here's a way to do it:
SELECT T.*
, RANK () OVER (PARTITION BY r_nm, r_obj)
ORDER BY val
) AS rk
T
ORDER BY r_nm, r_obj
val
;
Depending on how you want to deal with links, you can use ROW_NUMBER or DENSE_RANK instead of RANK.
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How to find the max value of scrollV in AS3?
I used the response from Ned to get my 3 fields of scrolling text set based on the value of one of them. Thanks Ned!
The other two text fields scroll to match the text box 'parent', but in the end – you get to the last scroll position - the other two do not update and 3 text fields are out of alignment. It's just at the end of the roll. The rest of the scroll values line up. I think that if I can find the scrollV max value, I can force the two others to scroll one last time when this value is reached by the text field "parent".
The textfield object has a property for this: maxScrollV.
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I have a database that is loaded and defines the customerID as 0 which is ideal when the database is not be saved and restored, etc. The question I have is that I added the possibility to users to restore a backup in the app, and now I have to do a query to select MAX (customerID) so that there is no duplicate CustomerID when you add or save items. Here is the following code, I knew that I must settle, specifically the 0 highlighted in red. I need zero to be the new customerID max value:
int SettingsStorage::load(int& lastID, GroupDataModel *model) { // number of locations loaded. QSettings settings(m_author, m_appName); int loadedCount = 0; QVariant items; // Get the last customer id first. // ID's will be generated by incrementing this number // Note values coming from settings should be cast to the // required type. lastID = settings.value(m_lastCustomerIDKey, 0).toInt(); items = m_sda->execute("SELECT * from items ORDER BY datefield"); qDebug()<< "the ID" << items; // Load all the locations from the database. foreach( const QVariant& temp, items.value
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int SettingsStorage::load(int& lastID, GroupDataModel *model) { // number of locations loaded. QSettings settings(m_author, m_appName); int loadedCount = 0; QVariant items; // Get the last customer id first. // ID's will be generated by incrementing this number // Note values coming from settings should be cast to the // required type. QVariant endID = m_sda->execute("Select MAX(customerID) from items") lastID = settings.value(m_lastCustomerIDKey, endID).toInt(); items = m_sda->execute("SELECT * from items ORDER BY datefield"); qDebug()<< "the ID" << items; // Load all the locations from the database. foreach( const QVariant& temp, items.value
() ) { Location *p; if (loadLocation(temp.value (), p)) { model->insert(p); loadedCount++; } } return loadedCount; } Any help will be loved and marked solutions.
-Thanks in advance
I was wrong about executeAndWait(). Somehow, I decided that you use the SqlConnection object, but seems his SqlDataAccess. So disregard my previous post. Keep your execute method, but you must change your code to something like this:
QVariant endID = m_sda->execute("select max(customerID) as m from items"); QVariantList vlist = endID.value
(); QVariantMap vmap = vlist.first().toMap(); lastID = vmap["m"].toInt(&ok); So I changed your SQL query slightly and added "that m" so I will have something to refer later.
Then I cast QVariantList because it is where are the results.
Then because we know its going to be the only record, I took the 1st element in the list and converted to QVariantMap.
Last step is to get the maximum.
Should work this time
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Cannot find the MAX Date value in the USER_TAB_PARTITIONS HIGH_VALUE
Hi all
I'll try to find the Max value of the date of the HIGH_VALUE from the USER_TAB_PARTITIONS, but my request has failed because the HIGH_VALUE is a LONG column.
Appreciate your valuable contributions here.
Thank you
MK.Maldini says:
I'll try to find the Max value of the date of the HIGH_VALUEYou use the PL/SQL:
SQL> select high_value 2 from user_tab_partitions 3 where table_name = 'RANGE_SALES' 4 / HIGH_VALUE ---------------------------------------------------------------------------------------------- TO_DATE(' 1998-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1998-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1998-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1999-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1999-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1999-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 1999-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 2000-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 2000-04-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 2000-07-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') TO_DATE(' 2000-10-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') HIGH_VALUE ---------------------------------------------------------------------------------------------- MAXVALUE 12 rows selected.
Now:
create or replace type DateList as table of date / declare v_DateList DateList := DateList(); v_max_high_value date; begin for v_rec in (select high_value from user_tab_partitions where table_name = 'RANGE_SALES') loop if v_rec.high_value != 'MAXVALUE' then v_DateList.extend; execute immediate 'begin :1 := ' || v_rec.high_value || '; end;' using out v_DateList(v_DateList.count); end if; end loop; select max(column_value) into v_max_high_value from table(v_DateList); dbms_output.put_line('Table RANGE_SALES max high value is ' || to_char(v_max_high_value,'MM/DD/YYYY HH24:MI:SS')); end; / Table RANGE_SALES max high value is 10/01/2000 00:00:00 PL/SQL procedure successfully completed. SQL>
SY.
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Hello
Can someone explain me why I see different values in the attached VI.
I have the array of strings, when I try to find the max value by using the Array function, I get a single value and the array of strings even when the conversion to digital, and then when I find the max value I get the different value? What I understand here?
Thank you
Repeat after me: take the max of a string array value is meaningless. He repeats it.
Repeat after me: the characters ASCII codes are NOT the same as the numeric values. He repeats it.
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Hello
I have the me_result of the table as below,
SELECT * FROM me_result;
ID ||| ELITE ||||||||||| FREQ_ITEM | COMBINED_STR | SUP
1 ||; 1; 10; 2; 3; 4; 5; 7; 8. 1 ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
2 ||; 1; 10; 2; 3; 4; 5; 7; 8. 2 ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
3 ||; 1; 10; 2; 3; 4; 5; 7; 8. 3 ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
4 ||; 1; 10; 2; 3; 4; 5; 7; 8. 4 ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
5 ||; 1; 10; 2; 3; 4; 5; 7; 8. 5 ||||||||||||||; 1; 10; 2; 3; 4; 5; 7; 8 ||| 2
6 ||; 10; 2; 3; 4; 5; 8; 9. 1 ||||||||||||||; 10; 2; 3; 4; 5; 8; 9; 1 ||| 1
7 ||; 10; 2; 3; 4; 5; 8; 9. 2 ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
8 ||; 10; 2; 3; 4; 5; 8; 9. 3 ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
9 ||; 10; 2; 3; 4; 5; 8; 9. 4 ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
10 ||; 10; 2; 3; 4; 5; 8; 9. 5 ||||||||||||||; 10; 2; 3; 4; 5; 8; 9 ||| 2
I need to find the first COMBINED_STR max for each element of the ELITE,
I mean, max value is the max REGEXP_COUNT (combined_str,' ;')))
really, I try to write down, but I had a lot of values for each ELITE and I need only the first, that
SELECT * from me_result
WHERE (ELITE, REGEXP_COUNT (combined_str,' ;')))) IN
(SELECT ELITE, MAX (REGEXP_COUNT (combined_str,' ;'))))) ME_RESULT ELITE GROUP);
I need the result to be as below.
1; 1; 10; 2; 3; 4; 5; 7; 8-1; 1; 10; 2; 3; 4; 5; 7; : p
6; 10; 2; 3; 4; 5; 8; 9 1; 10; 2; 3; 4; 5; 8; 9; 1 1
any help please,.
Published by: user11309581 on July 10, 2011 22:03Can be
with t as (select 1 ID, ';1;10;2;3;4;5;7;8' ELITE, 1 FREQ_ITEM, ';1;10;2;3;4;5;7;8' COMBINED_STR, 2 SUP from dual union all select 2 ,';1;10;2;3;4;5;7;8' ,2 ,';1;10;2;3;4;5;7;8' ,2 from dual union all select 3 ,';1;10;2;3;4;5;7;8' ,3 ,';1;10;2;3;4;5;7;8' ,2 from dual union all select 4 ,';1;10;2;3;4;5;7;8' ,4 ,';1;10;2;3;4;5;7;8' ,2 from dual union all select 5 ,';1;10;2;3;4;5;7;8' ,5 ,';1;10;2;3;4;5;7;8' ,2 from dual union all select 6 ,';10;2;3;4;5;8;9' ,1 ,';10;2;3;4;5;8;9;1' ,1 from dual union all select 7 ,';10;2;3;4;5;8;9' ,2 ,';10;2;3;4;5;8;9' ,2 from dual union all select 8 ,';10;2;3;4;5;8;9' ,3 ,';10;2;3;4;5;8;9' ,2 from dual union all select 9 ,';10;2;3;4;5;8;9' ,4 ,';10;2;3;4;5;8;9' ,2 from dual union all select 10 ,';10;2;3;4;5;8;9' ,5 ,';10;2;3;4;5;8;9' ,2 from dual ) select ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP from ( SELECT ID,ELITE,FREQ_ITEM,COMBINED_STR,SUP, ROW_NUMBER() over (PARTITION BY ELITE order by id) RN FROM t WHERE (ELITE,REGEXP_COUNT(combined_str,';')) IN (SELECT ELITE,MAX(REGEXP_COUNT(combined_str,';')) FROM t GROUP BY ELITE) ) where RN=1 order by id ID ELITE FREQ_ITEM COMBINED_STR SUP ---------------------- ----------------- ---------------------- ----------------- ---------------------- 1 ;1;10;2;3;4;5;7;8 1 ;1;10;2;3;4;5;7;8 2 6 ;10;2;3;4;5;8;9 1 ;10;2;3;4;5;8;9;1 1
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I'm trying to get the Max values and average of the single channel that has different cycles it contains. I tried to use commands such as Chnclasspeak3 and chnpeakfind, but they were not useful for me. What I need is the Max values and average of the different cycles numbers saved in the data channel.
Exampld if the string contains 5 numbers of repetitive cycles, then we must find the maximum values and the average of these 5 cycles in the single channel. Attached reference data. This is the .raw file and I have the plugin for it to use in diadem 11.1.
Kind regards
X. Ignatius
Hello, Ignatius,.
Sorry, it took some time to provide a replacement based on the script for the function. Please take a look at the attached script. I changed the script to use my function if the tiara-version is less than 12. My script function is not as fast and more stable than the implementation of tiara, but for now, it does the job
Andreas
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Find the minimum value of the table in time...
Firstly that it is not "find the min value in the table.
It is:
I have a table that changes its values at each iteration, and I want to compare the new values with previous values and make a new array with the minimum values...
In C++, it would be like this:
int main() {}
int array [8];
int min [8];
int i;
for (i = 0; i<>
min [i] = 1000000; Initialize minimum table with a high value
}
{while (1)}
Array = update_array ();
for (i = 0; i<>
If (array [i]<>
min [i] = array [i];
}
}
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}
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IM new to labview and it always confuses me a lot...
Thanks in advance.
Using the function Max & Min regular (not table Max & min as you know) with tables and a good will of employment registry change. Max Min &, as most of the digital functions, is polymorphic and works witt tables as well as scalars.
Lynn
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I want to find the minimum value from a table using the pl/sql loop
I have data format below.
1 ABC 2
1 ABC 20
1 ABC 500
1 ABC 2000
XYZ 2 250
JKL 3 300
MNP 3 350
3 KLM 400
I wrote the code below. His does not work. Please suggest.
Set serveroutput on
declare
x number: = 3;
y VARCHAR2 (3): = 'ABC ';
fmin number: = 0;
number of Fmax: = 0;
Start
for rec in (select sal from test
where id = name and x = y) loop
If rec.sal > fmin then
fmin: = rec.sal;
on the other
FMAX: = rec.sal;
fmin: = fmax.
end if;
end loop;
dbms_output.put_line (Fmax);
end;
/I want to output 2 on top of code.
Thanks in advance
Why PL/SQL? SELECT MIN (SAL) OF TEST will be more rapid and much less coding. In any case:
declare
number of v_min_sal;
Start
for v_rec in a loop (select sal from emp)
If nvl (v_min_sal, v_rec.sal + 1) > v_rec.sal
then
v_min_sal: = v_rec.sal;
end if;
end loop;
dbms_output.put_line (' lowest salaray is "' |") v_min_sal | '"');
end;
/
The lowest Salaray is "800".
PL/SQL procedure successfully completed.
SQL >
SY.
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Hi all
I have a table as below
Value name
- - - - - - - - - - - - - - - -
A1 5
A3 10
A2 7
A2 9
A1 10
What I get is the max (Value) and with the consolidation of its name
Value name
- - - - - - - - -
A2 16
Thank you
Alex
Published by: user8606416 on June 1, 2011 10:17
Published by: user8606416 on June 1, 2011 10:26Depends on how you feel on one of the links of:
SELECT name, value FROM (SELECT name, SUM(value) FROM table GROUP BY name ORDER BY 2 DESC) WHERE rownum = 1 SELECT name, SUM(value) FROM table GROUP BY name HAVING SUM(value) >= ALL (SELECT SUM(value) FROM table GROUP BY name)
among many other methods. The first takes a single arbitrary registration in the case of a tie, and the second shows all the related records.
John
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example: column 1 = 10, 2 = 20 column, column 3 = 30 > output should be 30.
I need the MAX value to sort the list by it.
That's how I tried to do:
================================
Select t1.id,
(
SELECT MAX (SUB.value)
Of
(
SELECT
CASE TO_CHAR (ROWNUM)
WHEN TO_CHAR (1) THEN (SELECT FROM myTable WHERE id = t1.id height)
WHEN TO_CHAR (2) and THEN (SELECT FROM myTable WHERE id = t1.id width)
WHEN TO_CHAR (3) THEN (SELECT FROM myTable WHERE id = t1.id depth)
END AS value
THE t1 double
CONNECT BY ROWNUM < = 3
) VOID
) AS a kind
FROM MaTable t1
sort order
================================
This would work fine if I could reach t1 in the subselect statement (...) WHERE id = t1.id...).
Unfortunately I can not get to this point to t1.id.
does anyone have advice for me?
Thank you very much!use the LARGEST
select greatest (cola, colb, colc) from table
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Any ideas? I'm sure that this is possible.MaxValue = ArrayMax (QueryName ["FieldName"]);
or Q of Q.
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3rd enter: 5-online average = 5 (you get the idea...)
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You can also use arrays to hold the data in a registry change and find the average value of the last five items.
Good luck
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