SDO_NN cannot be assessed without using the index
HelloI'll try to find more close neighbours of a point using two tables (grafo_ped_links & haltestellen) and I fail miserably quiet.
Select h.desc_i, grafo_ped_links h.numpal g, haltestellen h where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
*
ERROR on line 1:
ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
But I am able to find the nearest neighbor on individual tables (singularly) without any problem. I'm even able to find a WITHIN_DISTANCE using two tables (below the sql statement).
Select h.numpal from grafo_ped_links g, haltestellen h where SDO_WITHIN_DISTANCE (h.geometry, g.geometry, 'DISTANCE = 0.5 UNIT = KM') = 'TRUE' and g.start_node_id = 355;
NUMPAL
----------
5122
5103
5102
5120
5100
5301
5302
5303
I even dropped the indexes of the two tables and recreated them again. I read somewhere that the problem could be due to a lack of advice, so I tried the following and I still get the same error.
Select / * + LEADING (g) INDEX (h haltestellen_ridx) * / h.desc_i, h.numpal
of grafo_ped_links g, h haltestellen
where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
Select / * + INDEX (h haltestellen_ridx) NO_INDEX (g grafo_ped_links_ridx) * / h.desc_i, h.numpal
of grafo_ped_links g, h haltestellen
where (g.geometry, h.geometry) sdo_nn = 'true' and g.start_node_id = 355 and rownum < = 5
Select / * + USE_NL (h, g) VALUE * / h.desc_i, h.numpal
of grafo_ped_links g, h haltestellen
where sdo_nn (g.geometry, h.geometry, 'sdo_num_res = 5', 1) = 'true' and g.start_node_id = 355 and rownum < = 5
Anyone can please, show me the way, or give a hint. I use oracle spatial 11g.
Thank you!
Cook
Published by: user611283 on December 30, 2009 06:11
It should be 'TRUE '.
Select h.desc_i, grafo_ped_links h.numpal g, haltestellen h where (h.geometry, g.geometry) sdo_nn = 'TRUE' and g.start_node_id = 355 and rownum<=>=>
Tags: Database
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SDO_NN cannot be assessed without using the index when put inside subquery
Hi all
I met a problem when you use the function sdo_nn to find the nearest neighbor. Here is my scenario:
_ I have 2 customer and store tables.
Customer table _ a client_ID and a 2D sdo_geom point
_ Store table has store_ID and a 2D polygon sdo_geom.
In the beginning, I have this query to find the nearest store to each customer as below:
Select s.STORE_ID, c.CLIENT_ID
store customer, s c
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_It works as expected when it returns a table showing the nearest store each customer.
_Now I want to count the number of customers who have the same nearest store:
Select / * + INDEX (store store_spatial_idx, client_spatial_idx client) * / count (nearest_store. CLIENT_ID)
from (select s.STORE_ID, c.CLIENT_ID
store customer, s c
where sdo_nn (s.MYPOLYGON, c.MYPOINT, 'sdo_num_res = 1', 1) = "TRUE") nearest_store
Group of nearest_store. STORE_ID;
This query generates the following error:
Error report-
SQL error: ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 9
13249 00000 - '%s '.
I'm pretty new to spatial databases and hope get help to go further. Thank you in advance!
Hello Pinball,
Oracle space tends to be a quite complex with many variables and moving parts. We chatted about the group to a sort of FAQ or guidelines to help people like you submit questions that actually answers. First of all, you really have to tell us the version of Oracle you are using. Particularly the problems involving the optimizer, version down to the exact defined patch number is a good idea. Secondly, you took the time to submit the question so I guess you want a response. If you really want to see the answer and then providing an example is one of the most important things that you can do. I'm going to do here for you, but in general people on this forum come and go and are often pushed into lurkitude, so if you want the coax to provide you with an example of work is the key.
DROP TABLE store1 PURGE; CREATE TABLE store1( store_id INTEGER NOT NULL ,shape MDSYS.SDO_GEOMETRY ,PRIMARY KEY(store_id) ); DROP TABLE client2 PURGE; CREATE TABLE client2( client_id INTEGER NOT NULL ,shape MDSYS.SDO_GEOMETRY ,PRIMARY KEY(client_id) ); CREATE OR REPLACE PROCEDURE seeder( p_client_count IN NUMBER ,p_store_count IN NUMBER ) AS sdo_foo MDSYS.SDO_GEOMETRY; int_counter NUMBER; FUNCTION random_point RETURN MDSYS.SDO_GEOMETRY AS num_x1 NUMBER; num_y1 NUMBER; BEGIN num_x1 := dbms_random.value(-179,179); num_y1 := dbms_random.value(-89,89); RETURN MDSYS.SDO_GEOMETRY( 2001 ,8265 ,MDSYS.SDO_POINT_TYPE( num_x1 ,num_y1 ,NULL ) ,NULL ,NULL ); END random_point; BEGIN int_counter := 1; FOR i IN 1 .. p_client_count LOOP -- Create a client point sdo_foo := random_point(); INSERT INTO client2 VALUES ( int_counter ,sdo_foo ); int_counter := int_counter + 1; END LOOP; int_counter := 1; FOR i IN 1 .. p_store_count LOOP -- Create a store polygon of some kind sdo_foo := MDSYS.SDO_GEOM.SDO_ARC_DENSIFY( MDSYS.SDO_GEOM.SDO_BUFFER( random_point() ,5000 ,0.05 ) ,0.05 ,'arc_tolerance=0.05' ); INSERT INTO store1 VALUES ( int_counter ,sdo_foo ); int_counter := int_counter + 1; END LOOP; COMMIT; END seeder; / BEGIN seeder(10000,200); END; / BEGIN INSERT INTO user_sdo_geom_metadata( table_name ,column_name ,diminfo ,srid ) VALUES ( 'STORE1' ,'SHAPE' ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05)) ,8265 ); COMMIT; EXCEPTION WHEN OTHERS THEN NULL; END; / BEGIN INSERT INTO user_sdo_geom_metadata( table_name ,column_name ,diminfo ,srid ) VALUES ( 'CLIENT2' ,'SHAPE' ,MDSYS.SDO_DIM_ARRAY(MDSYS.SDO_DIM_ELEMENT('X',-180,180,.05),MDSYS.SDO_DIM_ELEMENT('Y',-90,90,.05)) ,8265 ); COMMIT; EXCEPTION WHEN OTHERS THEN NULL; END; / CREATE INDEX store1_spx ON store1 (shape) INDEXTYPE IS MDSYS.SPATIAL_INDEX NOPARALLEL; CREATE INDEX client2_spx ON client2 (shape) INDEXTYPE IS MDSYS.SPATIAL_INDEX NOPARALLEL; /* Works as expected */ SELECT s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE'; /* No worky? Works for me */ SELECT ns.store_id ,COUNT(ns.client_id) FROM ( SELECT s.store_id ,c.client_id FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE' ) ns GROUP BY ns.store_id ORDER BY ns.store_id;
So I wrote this about 12 c (12.1.0.2.0) and everything works fine for me. Then I moved back from 11 GR 2 (11.2.0.4.0) and of course, there are questions. So I guess that you don't use flavor of 11g. So at this point we can look at the docs and see for 11g, have you often need to specify which table is the head and that is the one that has the spatial index to use.
http://docs.Oracle.com/CD/E11882_01/AppDev.112/e11830/sdo_operat.htm#SPATL1032Its rather interesting that the optimizer of 12 c knows what you want, when I had to squint myself at your request and to play a little with the refining. Note that SDO_NN is sensitive, because the geometry of the main table should come second in the operator. I did not know that on the top of my head.
SELECT /*+ LEADING(c) INDEX(s store1_spx) */ s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE'; SELECT ns.store_id ,COUNT(ns.client_id) FROM ( SELECT /*+ LEADING(c) INDEX(s store1_spx) */ s.store_id ,c.client_id ,MDSYS.SDO_NN_DISTANCE(1) FROM store1 s ,client2 c WHERE MDSYS.SDO_NN( s.shape ,c.shape ,'sdo_num_res=1' ,1 ) = 'TRUE' ) ns GROUP BY ns.store_id ORDER BY ns.store_id;
So I think that is your answer. Give it a shot and see if this fits the Bill. Of course, moving to 12 c would be useful for such things. It would be interesting to collect more examples of this kind of space thing where 12 c is the answer. Also, would be nice if we could mark somehow this discussion as applying only to 11g and earlier versions.
See you soon,.
Paul
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SDO_NN giving ORA-13249: SDO_NN cannot be assessed without using the index
Hi people,
I do not understand why the SDO_NN gives ORA-13249 in circumstances.
SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and title like '%' and rownum < 10;
TITLE
--------------------------------------------------------------------------------
MultiPoint_305199
LineString_691779
MultiPolygon_180478
MultiPolygon_358113
MultiPolygon_53008
MultiPolygon_249905
MultiPolygon_204076
MultiPolygon_636994
MultiPoint_464514
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SQL > SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10;
SELECT SlavaTest WHERE SDO_NN s s.title (s.geometry, SDO_GEOMETRY (2001, 4326, SDO_POINT (14.0, 49.0, NULL), null, null)) = 'TRUE' and timestamp > = to_timestamp (January 6, 2011 ', ' dd/mm/yyyy') and rownum < 10
*
ERROR on line 1:
ORA-13249: SDO_NN cannot be assessed without using the index
ORA-06512: at the 'MDSYS. MD", line 1723
ORA-06512: at the 'MDSYS. MDERR", line 17
ORA-06512: at the 'MDSYS. PRVT_IDX', line 49
The spatial index is created with:
CREATE the INDEX SlavaTest_geometry_idx_spatial ON SlavaTest (geometry) INDEXTYPE IS mdsys.spatial_index;
'Title' and 'timestamp' columns have an index.
Note the query comes from Hibernate and I can't change it's arbitrary.Slava2 wrote:
What this means - there is a bug in Oracle?Well, it could probably be considered a, but [url http://docs.oracle.com/cd/E11882_01/appdev.112/e11830/sdo_operat.htm#i78067] documentation on SDO_NN warns you:
Documentation says:
However, if the column in the WHERE clause predicate specifies a non-space column in the table for geometry1 with an associated index, make sure that this index is not used by specifying the NO_INDEX indicator for this index.See you soon,.
Stefan -
Using the index to extract data without filter predicate
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| 0 | SELECT STATEMENT | 485K | 2372K | 1528 (1) | 00:00:19 |
| 1. TABLE ACCESS FULL | T1 | 485K | 2372K | 1528 (1) | 00:00:19 |
--------------------------------------------------------------------------
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----------------------------------------------------------
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Execution plan
----------------------------------------------------------
Hash value of plan: 3555700789
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-------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | 485K | 2372K | 242 (3) | 00:00:03 |
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---------------------------------------------------
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Statistics
----------------------------------------------------------
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5684 bytes received via SQL * Net from client
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SQLsql-
drop table t1 purge;
create table t1 tablespace users in select * from dba_objects;
Insert into t1 (select * from t1);
commit;
Insert into t1 (select * from t1);
commit;
Insert into t1 (select * from t1);
commit;
create index oid_ix on t1 (object_id) tablespace users;
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In my case, the Table and the Index looks like this way:
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TABLE_NAME, NUM_ROWS BLOCKS AVG_SPACE
=======================================
485984 6944 T1 0
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INDEX_NAME BLEVEL LEAF_BLOCKS DISTINCT_KEYS NUM_ROWS
===================================================
2 1074 60745 485960 OID_IX
Elapsed time: 00:00:00.07
The table contains 7 times more than the index blocks!
any answer welcome
Best regards
Published by: guenterp on August 12, 2010 14:44The column is not defined as NOT NULL, then there may be values that are not in the index (because the index does not include null values). The useless predicate implies NOT NULL, then the index may be used.
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Trying to assess the benefits of the addition of index of multiple values, a quick question on the index of multiple values:
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ValueExtractor salExtractor = new PofExtractor (Integer.class, 2);
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cache.addIndex (mExtractor, false, null);
But how can I use the extractor to create multivalued filter queries for employees in the Department of human resources with greater than 35000 salary? Any ideas are much appreciated.
Thank youD wrote:
Hi guys,.Trying to assess the benefits of the addition of index of multiple values, a quick question on the index of multiple values:
Here's my content from the cache:
Key (EmpID), value [employee (age int, double salary, Department of String)]
(1, new employee (25, 35000.0, "Admin"));
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(8, new employee (36, 35000.0, "HR"));
(9, new employee (46, 45000.0, "Admin"));
(10, new employee (48, 47000.0, "HR"));If I still want to find all employees in the 'Human resources' Department and whose salary is more than 35000.
Eventually, I would like to do the following:
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cache.addIndex (salExtractor, false, null);
cache.addIndex (depExtractor, false, null);EqualsFilter departmentFilter = new EqualsFilter (depExtractor, 'HR');
GreaterFilter salFilter = new GreaterFilter (salExtractor, 35000);
Filter allFilter = new AllFilter (new filter [] {departmentFilter, salFilter});
Employees value = cache.entrySet (allFilter));For my usecase above how can I use the indexing of multiple values to the same query?
ValueExtractor salExtractor = new PofExtractor (Integer.class, 2);
ValueExtractor depExtractor = new PofExtractor (String.class, 3);
MultiExtractor mExtractor is new MultiExtractor (new ValueExtractor [] {salExtractor, depExtractor});.
cache.addIndex (mExtractor, false, null);But how can I use the extractor to create multivalued filter queries for employees in the Department of human resources with greater than 35000 salary? Any ideas are much appreciated.
Thank you
I remember, values multiple index refers to a different concept: a multivalued index means that you can retrieve a collection of values of similar role of an attribute on which you can do Contains, ContainsAll filtering, and ContainsAny.
In this case to fully the lever consistency of querying capabilities, you would
- either add a sorted index with a custom comparator that compares the tables containing a salary and a Department on a first salary so the base of the Department and add a filter custom which is able to take advantage of the index for the request for the salary and also able to filter on the element of the array of index service
-Add two independent indices (a sorted index of wages and a unsorted for the Department), in which case you can leverage all existing (GreaterThanFilter, EqualsFilter and AndFilter) codeBest regards
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