Search table 1 d for a value

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• Search for the string in the string table and see the following value in the line

  Hi, I'm new I have LV and I do a Vi that read worksheet values and generates 2d channels of the same spreadsheet table. For the moment everything I need is a function that find specyfic string in this table and show the next value in a line. As:

  Table:

  a; b
  c; d
  f; g

  example: find the 'c '.

  VI shoud show "d".

  Concerning

  Not a bad homework problem.  Do it with pencil and paper.  Write your table and pretend you're the computer.  What you want to do (step by step)?  What questions do you have?

  Now that the translation a bit to computers.  You mentioned that the data is in an array of strings.  What structures (LabVIEW) work with tables?  [Do you know how to work with tables?  [Otherwise, review some of LabVIEW Tutorial material - see top right of the first page of the Forum].  What do you know about channels?  What questions you need to ask questions on the channels?  What do you know about string functions?

  Watch these things in some LabVIEW code, 'feed' some data and see what he does.  If it seems to do things "unexplained", you can try to look at the block diagram to run by turning the performance highlight (and if you don't know what that means, use the help of LabVIEW and see the tutorials).

  Bob Schor

• The search in a table 2d-coordinates for the point of click

  I'm doing a VI that creates a layer of 2d points on an image imported (as pictured). These points are generated by a Subvi, which simply draws points over and over again (based on the 3 selections of initial angle). All the coordinates of the points are stored in a data feed that is sent to a registry change for other future functions. Each coordinate corresponds to an electrode, labeled 0-255, goes into the lines first (although that could change, but I guess it would be easy to change). Labels are created through 2 loops (as seen in diagram 1).

  I would now like to click on a particular point and put it out in a different color, but also an indicator show me what electrode I clicked. I seem to be at a loss on how to do it! I need explore a table 2d-2 groups of the element, where she looks for the line first, then the corresponding column (or vice versa, it is not serious, but just for ease of understanding, let's say she is looking X first, where the columns first) and compare them to 2 elements (the mouse click coordinates).

  Here's what I've done so far. I need to search for the function in the following way; If find X, look no further columns and select that particular column where the X was found and begins to look for the values Y and and then stops when the value of Y is. Once the two values are found, take these out of the loops and throw them in a cluster and the function of drawing lots.

  Thank you!

  p.s. in case anyone is wondering why I have the function "in the range" in there, it's so that the user does not have to be exact pixel this allows the user to click within 2 pixels of the coordinate of the point.

  Hi Daniel!

  What do you think of this approach?

  

  We subtract just the mouse coordinates in the coordinated range 2D (Array stores the coordinates of the points on the image), the absolute value and look for the minimum. X and y the selected point index is returned in minutes or the index. You can replicate the fuction "in range" by ensuring min value is not too high.

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• Compare and get the data in the tables (see post for details)

  I have two tables TableA and TableB. I struggle to write a query to get the dates of TableB (instead of TableA dates) where TableA dates don't coincide with the tableB (beginning and end).

  Example 1: For account A1234,.

  TableA got 2 rows 1/31/2014-3/3/2014 (which corresponds to TableB row), but TableA got another rank 31/01/2014 - 31/01/2014 that corresponds with the date of TableB Begin. In this case, I'm looking for output as below,

  Use TableB start and end date and combine number two rows from TableA for this account

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  A1234	31/01/2014	03/03/2014	100.0000000000

  Example 2: For the B7777 account.

  TableA end date aligns with the end dates of TableB for this account, in this case I want out put as,.

  Use TableB start and end date and get the amount of TableA

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  B7777	05/04/2013	06/05/2013	200.0000000000

  Example 3: On behalf of D5555,.

  Even a TableA line corresponds with TableA, there are two other rows in TableA matching start date with TableA and correspondence with the end date with TableA, in this case, that I put as,.

  Use TableB start and end date and combine number three rows from TableA for this account.

  ACCOUNT	TableB_BEGIN	TableB_END	AMOUNT
  D5555	08/08/2014	10/09/2014	1100.0000000000

  Example 4: To account E6666.

  Table corresponds to a row with TableB and no additional lines in TableA, just display the data in A table

  Tables and data:

  create table TableA
  (
    Account varchar2(10) not null,
    Begin   date not null,
    End     date not null,
    Amount  number(19,10) not null
  )
  ;
  
  
  create table TableB
  (
    Account varchar2(10) not null,
    Begin   date not null,
    End     date not null,
    Amount  number(19,10) not null
  )
  ;
  
  
  TableA Data:
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('31-01-2014', 'dd-mm-yyyy'), 0.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('B7777', to_date('18-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 120.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('C6666', to_date('25-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('16-08-2014', 'dd-mm-yyyy'), 1000.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 0.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('16-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tablea (ACCOUNT, BEGIN, END, AMOUNT)
  values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  TableB Data:
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('A1234', to_date('31-01-2014', 'dd-mm-yyyy'), to_date('03-03-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('B7777', to_date('05-04-2013', 'dd-mm-yyyy'), to_date('06-05-2013', 'dd-mm-yyyy'), 200.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('C6666', to_date('06-06-2014', 'dd-mm-yyyy'), to_date('08-07-2014', 'dd-mm-yyyy'), 10.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('D5555', to_date('08-08-2014', 'dd-mm-yyyy'), to_date('10-09-2014', 'dd-mm-yyyy'), 1100.0000000000);
  
  
  insert into tableb (ACCOUNT, BEGIN, END, AMOUNT)
  values ('E6666', to_date('01-01-2014', 'dd-mm-yyyy'), to_date('01-02-2014', 'dd-mm-yyyy'), 100.0000000000);
  
  
  
  
  SELECT A.ACCOUNT,
         A.BEGIN,
         A.END,
         A.AMOUNT,
         B.ACCOUNT,
         B.BEGIN,
         B.END,
         B.AMOUNT
    FROM TABLEA A
    LEFT JOIN TABLEB B
      ON A.ACCOUNT = B.ACCOUNT
  

  Hello

  SeshuGiri wrote:

  Hi Frank,.

  Your query/solution works very well, but I forgot to mention something in the first post...

  Please insert these additional lines and try the request again.

  TableA Additional lines:

  1. Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
  2. values ('F9999', to_date (January 2, 2014 ',' dd-mm-yyyy ""), to_date (3 January 2014 ', 'dd-mm-yyyy'), 999.0000000000);
  3. Insert into TABLEA (ACCOUNT, BEGIN, END, QUANTITY)
  4. values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);

  TableB Additional lines:

  1. Insert into TABLEb (ACCOUNT, BEGIN, END, QUANTITY)
  2. values ('A1234', to_date (March 3, 2014 ',' dd-mm-yyyy ""), to_date (4 March 2014 ', 'dd-mm-yyyy'), 999.0000000000);

  Question 1:

  The table has a rows for A1234 account (i.e. the time period different than the ranks for the same account)

  one is A1234 31/01/2014-03/03/2014, A1234 03/03/2014-03/04/2014

  Your query that returns two rows for A1234 account (which is what I want), but the amount is messed up.

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	1100
  2	A1234	03/03/2014	03/04/2014	1100

  Except:

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	101
  2	A1234	03/03/2014	03/04/2014	999

  Question 2:

  In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?

  I don't get the results with additional data. I get 1099 for two lines where account = 'A1234 '.  I get 1100 as the amount on the line with the account = "D5555.  You did it other changes to data?

  Except:

  	ACCOUNT	BEGIN	END	TOTAL_AMOUNT
  1	A1234	31/01/2014	03/03/2014	101
  2	A1234	03/03/2014	03/04/2014	999

  Still, I don't see why you want to 101 for the amount of the first row.  Why not 100?

  How can you know which rows from tablea should get attached to what rows from tableb, when the account is not unique?

  Maybe you want something like this:

  SELECT a.account

  b.begin

  b.end

  SUM (a.amount) AS total_amount

  FROM tablea a

  ON a.account = b.account JOIN tableb B

  AND a.begin BETWEEN b.begin

  AND b.end

  AND a.end BETWEEN b.begin

  AND b.end

  GROUP OF a.account, b.begin, b.end

  ORDER BY a.account

  ;

  but I guess just to your needs, and guessing is not a very good or reliable way to solve problems.

  Question 2:

  In some cases TableA will have an account (F9999), but the TableB don't. I can just this line by making the Left Join right join?

  Yes, it looks that you want an outer join.  What happened when you tried?  As always, post your code, the exact results you want from the given sample data, as well as an explanation of how you get these results from these data.

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  ORA-06512: at line 2

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