Select all values in Column1 and Column2 in Column1 without updating.

Similar Questions

• Simply select the values between min and max of a value accumulated during the day

  Hello Forum,
  
  a value is accumulated more a day and over a period of time. The next day, the value is reset and starts to build up again:
  

  with sampledata as (select to_date('09.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 23 val from dual union all
                     select to_date('09.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 29 val from dual union all
                     select to_date('09.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 30 val from dual union all
                     select to_date('09.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 45 val from dual union all
                     select to_date('09.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 60 val from dual union all
                     select to_date('09.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 75 val from dual union all
                     select to_date('09.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 95 val from dual union all
                     select to_date('09.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('09.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('09.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('09.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('09.09.2012 17:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('09.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('09.09.2012 23:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 00:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 01:03:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 02:54:11', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 03:04:08', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 04:04:19', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 05:04:20', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 06:12:02', 'dd.mm.yyyy hh24:mi:ss') ts, 14 val from dual union all
                     select to_date('10.09.2012 07:12:03', 'dd.mm.yyyy hh24:mi:ss') ts, 34 val from dual union all
                     select to_date('10.09.2012 08:12:04', 'dd.mm.yyyy hh24:mi:ss') ts, 58 val from dual union all
                     select to_date('10.09.2012 09:12:11', 'dd.mm.yyyy hh24:mi:ss') ts, 70 val from dual union all
                     select to_date('10.09.2012 10:12:12', 'dd.mm.yyyy hh24:mi:ss') ts, 120 val from dual union all
                     select to_date('10.09.2012 11:12:13', 'dd.mm.yyyy hh24:mi:ss') ts, 142 val from dual union all
                     select to_date('10.09.2012 12:21:24', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
                     select to_date('10.09.2012 13:21:26', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
                     select to_date('10.09.2012 14:21:27', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
                     select to_date('10.09.2012 15:21:30', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
                     select to_date('10.09.2012 16:21:32', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual union all
                     select to_date('10.09.2012 21:21:33', 'dd.mm.yyyy hh24:mi:ss') ts, 153 val from dual)
  select   ts, val
  from     sampledata
  order by ts asc;

  How should I change the select statement to ignore all data sets before the first minimum and duplicates after the maximum of a day to get such a result:
  

  TS     VAL
  09.09.12 06:12     23
  09.09.12 07:12     29
  09.09.12 08:12     30
  09.09.12 09:12     45
  09.09.12 10:12     60
  09.09.12 11:12     75
  09.09.12 12:21     95
  09.09.12 13:21     120
  09.09.12 14:21     142
  10.09.12 06:12     14
  10.09.12 07:12     34
  10.09.12 08:12     58
  10.09.12 09:12     70
  10.09.12 10:12     120
  10.09.12 11:12     142
  10.09.12 12:21     153

  Thank you

  Hello

  msinn wrote:
  Hello Forum,

  a value is accumulated more a day and over a period of time. The next day, the value is reset and starts to build up again:

  Thanks for posting the sample data and results. Be sure to explain how you get these results from these data. For example "for each day, I just want to show the lines after the daily low was reached. For example, on September 9, the lowest val was 23, which occurred at 6:12, so I don't want to show all lines earier to 06:12 September 9. In addition, when a val is the same as or more than the previous same day val (in order by ts), then I don't want to display the line later. For example, on 9 September, there are several consecutive lines, starting at 14:21 which all have the same val, 142. I want to only display the ealiest of this group, the line of 14:21. »

  Here's a way to do it, using analytical functions:

  WITH   got_analytics     AS
  (
       SELECT  ts, val
       ,     MIN  (val) OVER ( PARTITION BY  TRUNC (ts)
                                ORDER BY       ts  DESC
                      )      AS min_val_after
       ,     CASE
                WHEN  val = MIN (val) OVER (PARTITION BY  TRUNC (ts))
                THEN  -1    -- Impossibly low val.  See note below
                ELSE  LAG  (val) OVER ( PARTITION BY  TRUNC (ts)
                                            ORDER BY         ts
                             )
            END      AS prev_val
       FROM    sampledata
  )
  SELECT       ts
  ,       val
  FROM       got_analytics
  WHERE       val     <= min_val_after
  AND       val     >  prev_val
  ORDER BY  ts
  ;
  

  This requires that val > = 0. If you don't know a lower bound for val, and then the same basic approach still works, but it's a bit messier.

• How to create a parameterized report - select "- ALL -" for the Department and manager does not.

  I downloaded the app OEHR sample of objects and followed the steps in Oracle® Application Express Advanced Tutorials
  Version 3.2.

  The report and the settings seem to work fine except when I get 'everything' for service or manager I get no corresponding success.

  What is the way most effective to get 'everything' if the user selects all for dept and mgr - so we would like to return all records in the table.

  Snipprt region

  Enter search

  Search used Dept -SET-AdministrationMarketingPurchaseHuman resourcesExpedition to the FranceHEPublic relationsSalesExecutiveFinanceAccountingTreasuryCorporate income taxControl and creditShareholder servicesBenefitsManufacturingConstructionContractingOperationsIT supportNOCCOMPUTING helpdeskGovernment salesRetail salesRecruitmentPayroll Mgr -SET-Steven KingNeena KochharLex De HaanAlexander HunoldNancy GreenbergDen RaphaelyMatthew WeissAdam FrippPayam KauflingShanta VollmanKevin MourgosJohn RussellKaren partnersAlberto ErrazurizGerald CambraultEleni ZlotkeyMichael HartsteinShelley Higgins

  Here is the sql code that was provided as part of the turitoral.

  SELECT

  'OEHR_EMPLOYEES '. "" EMPLOYE_ID ""EMPLOYE_ID"

  'OEHR_EMPLOYEES '. "" NAME ""FIRST NAME",

  'OEHR_EMPLOYEES '. "" LAST_NAME ""NAME,"

  'OEHR_EMPLOYEES '. "" ""E-MAIL. "

  'OEHR_EMPLOYEES '. "' PHONE_NUMBER '"PHONE_NUMBER. "

  'OEHR_EMPLOYEES '. "' HIRE_DATE ' 'HIRE_DATE ',.

  'OEHR_EMPLOYEES '. "" JOB_ID ' "JOB_ID,

  'OEHR_EMPLOYEES '. "" TREATMENT ""TREATMENT. "

  'OEHR_EMPLOYEES '. "" COMMISSION_PCT ""COMMISSION_PCT. "

  'OEHR_EMPLOYEES '. "" MANAGER_ID ""MANAGER_ID. "

  'OEHR_EMPLOYEES '. "" DEPARTMENT_ID ""DEPARTMENT_ID ".

  Of

  "#OWNER # '." OEHR_EMPLOYEES' 'OEHR_EMPLOYEES '.

  WHERE

  (lower (first_name) like '%' | lower(:P1_NAME) |) '%' OR

  Lower (last_name) like '% "| Lower(:P1_NAME) | '%')

  AND department_id = decode(:P1_DEPT,'%null%',department_id,:P1_DEPT)

  AND manager_id = decode(:P1_MGR,'%null%',manager_id,:P1_MGR)

  Hello

  Use this...

  SELECT

  'OEHR_EMPLOYEES '. "" EMPLOYE_ID ""EMPLOYE_ID"

  'OEHR_EMPLOYEES '. "" NAME ""FIRST NAME",

  'OEHR_EMPLOYEES '. "" LAST_NAME ""NAME,"

  'OEHR_EMPLOYEES '. "" ""E-MAIL. "

  'OEHR_EMPLOYEES '. "' PHONE_NUMBER '"PHONE_NUMBER. "

  'OEHR_EMPLOYEES '. "' HIRE_DATE ' 'HIRE_DATE ',.

  'OEHR_EMPLOYEES '. "" JOB_ID ' "JOB_ID,

  'OEHR_EMPLOYEES '. "" TREATMENT ""TREATMENT. "

  'OEHR_EMPLOYEES '. "" COMMISSION_PCT ""COMMISSION_PCT. "

  'OEHR_EMPLOYEES '. "" MANAGER_ID ""MANAGER_ID. "

  'OEHR_EMPLOYEES '. "" DEPARTMENT_ID ""DEPARTMENT_ID ".

  Of

  "#OWNER # '." OEHR_EMPLOYEES' 'OEHR_EMPLOYEES '.

  WHERE

  (: P1_NAME IS NULL OR)

  (: P1_NAME IS NOT NULL AND)

  (

  (lower (first_name) like '%' | lower(:P1_NAME) |) '%') OR

  (lower (last_name) like '%' | lower(:P1_NAME) |) '%')

  )

  )

  ) AND

  (: P1_DEPT IS NULL or department_id =: P1_DEPT) AND

  (: P1_MGR IS NULL or manager_id =: P1_MGR)

• How to remodel a star by selecting all edges at once and how symmetrical knots?

  I'm catching up with this tutorial: http://vector.tutsplus.com/tutorials/illustration/create-an-adorable-hedgehog-with-basic-t utils in inkscape /

  But I have two problems

  First of all: I'm drawing this form: http://i1159.photobucket.com/albums/p639/Cyanide2x4/hedgehog-1_zps62feac94.png

  It is written in the article I should use the star tool, so after using the star tool I got this:

  http://i1159.Photobucket.com/albums/p639/Cyanide2x4/Star_zps484ab7ea.PNG

  Now anyway to select all edges and remodel all at once to get to this shape drawn in the article (the first photo I posted)?

  Second problem:

  I do not understand this:

  http://i1159.Photobucket.com/albums/p639/Cyanide2x4/Hedgehog-9_zpsf39f2e73.PNG

  What does mean "Nodes Tool" article?

  It is written that I have to draw a triangle using the polygon tool, then using tool nodes > nodes selected symmetric I will get this form in the photo above, but I can't find the nodes tool nor symmetrical knots option

  I use Adobe Illustrator CC

  Tutorial is made for Inkscape (another drawing software)

• Is - is no longer offers a basic remuneration for it and it's yours for as long as you want with no updates of Adobe?  All programs are now a subscription?  Is it really not possible more to pay only once and that the program without updates until what yo

  Is - is no longer offers a basic remuneration for it and it's yours for as long as you want with no updates of Adobe?  All programs are now a subscription?  Is it really not possible more to pay only once and the program without updates until you decide to improve?

  You can buy cs6, Creative Suite 6

• Display all values that bad

  I have a calendar with this SQL query to get all action items. The last condition is on the last line that pulls up all projects related to this activity of monitoring based on a value in the page. The value is stored in the field 'P133_PROJECT_CAT '.

  Select EBA_PROJ_STATUS_AIS.ID as ID,

  EBA_PROJ_STATUS_AIS. Project as project,

  EBA_PROJ_STATUS_AIS.MILESTONE_ID as MILESTONE_ID,

  EBA_PROJ_STATUS_AIS. ACTION as ACTION,

  EBA_PROJ_STATUS_AIS. End_date as end_date,

  EBA_PROJ_STATUS_AIS. ACTION_STATUS as ACTION_STATUS,

  EBA_PROJ_STATUS_AIS. CREATED as CREATION,

  EBA_PROJ_STATUS_AIS. CREATED_BY as CREATED_BY,

  EBA_PROJ_STATUS. PROJECT within the PROJECT,

  EBA_PROJ_STATUS_AIS_TYPES. AI_TYPE as AI_TYPE,

  EBA_PROJ_STATUS_MS.MILESTONE_NAME as MILESTONE_NAME,

  EBA_PROJ_STATUS.CAT_ID as CAT_ID

  of EBA_PROJ_STATUS_MS EBA_PROJ_STATUS_MS,.

  EBA_PROJ_STATUS_AIS_TYPES EBA_PROJ_STATUS_AIS_TYPES,

  EBA_PROJ_STATUS EBA_PROJ_STATUS,

  EBA_PROJ_STATUS_AIS EBA_PROJ_STATUS_AIS

  where EBA_PROJ_STATUS_AIS. PROJECT = EBA_PROJ_STATUS.ID

  and EBA_PROJ_STATUS_AIS. TYPE_ID = EBA_PROJ_STATUS_AIS_TYPES.ID

  and EBA_PROJ_STATUS_AIS.MILESTONE_ID = EBA_PROJ_STATUS_MS.ID

  and EBA_PROJ_STATUS.CAT_ID =: P133_PROJECT_CAT

  I have the setup of "P133_PROJECT_CAT" of field as a field on the page where, when a value is selected, it works very well and shows all the items/projects action for this page. However, if I select the value '- all categories -' it must pass a 0 that must be null and see all categories.

  Question: what needs this final line (and EBA_PROJ_STATUS.CAT_ID =: P133_PROJECT_CAT) look like so that "0 = all values"?

  and (EBA_PROJ_STATUS.CAT_ID =: P133_PROJECT_CAT or : P133_PROJECT_CAT = 0)

• BlackBerry Z10 how bulk delete email - not 5 or 10 by selecting all the emails one by one, but 'delete before... '. "or similar

  Hi Cimmunaute

  as you often work and as you say you have a lot of emails: how to remove the masses as delete block? on my old blackberry (except z10 newstes) I had the option "remove all front of (...)". Date"in the context menu, and could remove 1500 emails with a tap. do you know how to do this now? There is not such a function, we have to type and mark each email, even if there are 2000! crazy!

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  BB: Please urgently add functionality...! I have an imap account with approximately 200 emails a day that are just a copy of the mail of the company and need to delete hundreds every day. I can not press on and select all mails only one and then delete.

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• selecting a value in the drop-down list but page must not get recharged again.

  Hello
  I created a drop-down list. After you have selected a value from him, I can get a value in the box of text below according to updon one sql query. but the problem is that I HAV to select Page Action when the changed value parameter to the set value and redirect. Thanks to her whenever I have to select a value from the drop-down list, page get updated. Is there a way that will satisfy the requirement but page does not get new dependants.
  I use apex 4.2.
  Thank you

  You can create A dynamic Action to set the value while changing the value in the Select list (drop-down list).

  Event: change
  Selection type: item (s)
  Article (s): choose your selection list item
  Action: Execute the PL/SQL Code
  PL/SQL code:

  begin
  select colum_name into :Px_text_item_name from table where column_name=:px_select_list_name;
  end;
  

  Page elements to send: px_select_list_name
  Page referred to return: Px_text_item_name

  Its work for me without refreshing the page. Assume that, if you want to pass this value to the element in another page, then use the branch for redirection and assign the value to the element on the page of another.

  Thank you
  Lacombe

• Select literal values in the same column

  Hello
  like the practice:
  
  Select 'A', 'B', 'C' for double
  will select these values in their own column on the same line, is there a simple way to select these values in the same column on lines without first their insertion into a table?
  
  Thank you

  SQL> select 'A' x from dual union
    2  select 'B' x from dual union
    3  select 'C' x from dual ;
  
  X
  -
  A
  B
  C
  

  A bit complicated:

  SQL> select chr(ascii('A')+level-1) x
    2  from dual
    3  connect by level <=3;
  
  X
  -
  A
  B
  C
  

  Other:

  SQL> select regexp_substr('ABC','[[:alpha:]]',1,level) x
    2  from dual
    3  connect by level <= length('ABC');
  
  X
  ---
  A
  B
  C
  

  Max
  http://oracleitalia.WordPress.com

  Published by: Massimo Ruocchio, February 12, 2010 17:55
  added a second

  Published by: Massimo Ruocchio, February 12, 2010 17:58
  Added the third

• How and where to find Adobe Updater in my PC?

  Hi all!

  How and where to find Adobe Updater in my PC?

  Thank you

  Ozzy

  This is where Adobe Updater: -.

  Windows:-C:\Program Files (x 86) \Common Files\Adobe\OOBE\PDApp\UWA

  Mac:-Mac HD/Library/Application Support/Adobe/OOBE/PDApp/UWA

• How default of a multiple selection for all values setting?

  I have a setting that allows the user to select multiple values.  I want the default to use all values (which means basically just ignore this parameter in the generated SQL code).  However, I can't create named on this calculation since it accepts multiple values, and the calculation supports only the first value.  Is there a way to do what I need, without selecting all the values in the list (the LOV contains hundreds and hundreds of values so it's not a viable option).  I'm not very experienced with the discoverer and don't know all the tips/solutions workaround, if you are looking for expert advice.

  Thank you

  Hello

  You must code the parameter and the condition that he accepts the word ALL.

  For example, suppose you are working with ITEM_NUMBER and you have thousands of articles. You want the user to be able to one or more key or access all THE items.

  You must create a Boolean condition like this:

  ITEM_NUMBER IN: ITEM_PARAMETER

  OR

  UPPER(:ITEM_PARAMETER) = "ALL".

  So if the user key word ALL all all or or any variation of the word to be determined as true by the condition and all items will be selected. If the user does no key ALL, and then the other half of the condition will be applied and the element must be a valid element as contained in the list of all the elements. You can even create your parameter with a default value of all THE

  Best wishes

  Michael

• How to select all the values populated both of LOV

  Hi all.
  
  I developed a form containing fields in a table. I join these areas a LOV (which get values in the other table). Now, I have to select a value only once for each record.
  But my question is how to map all the LOV values to these fields at a time. If it is possible what exactly is the way.
  If this is not possible then what is the way to do that.
  
  Thanks in advance

  Hello!
  Try using this code.
  You will get a lot of messages, but you can discover what column could not be red:

  declare
  l_group recordgroup := find_group ( 'lov27' );
  l_result pls_integer;
  begin
  if
    show_lov --> show the lov and user selected a value
  then
    l_result := populate_group ( l_group );
    clear_record;
    for i in 1..get_group_row_count ( l_group ) loop
      message ( 'reading  personal no' );
      :bill_detail.personal_no := get_group_char_cell ( 'lov27.personal_no', i );
      message ( 'reading  name' );
      :bill_detail.name := get_group_char_cell ( 'lov27.name', i );
      message ( 'reading  desigantion' );
      :bill_detail.designation := get_group_char_cell ( 'lov27.designation', i );
      message ( 'reading  rank' );
      :bill_detail.rank := get_group_char_cell ( 'lov27.rank', i );
      message ( 'reading  basic scale' );
      :bill_detail.basic_scale := get_group_number_cell ( 'lov27.basic_scale', i );
      message ( 'reading  basic pay' );
      :bill_detail.basic_pay := get_group_number_cell ( 'lov27.basic_pay', i );
      message ( 'reading  basic pay' );
      :bill_detail.vendor_no := get_group_number_cell ( 'lov27.vendor_no', i );
      message ( 'reading  branch code' );
      :bill_detail.branch_code := get_group_number_cell ( 'lov27.branch_code', i );
      message ( 'reading  sr no' );
      :bill_detail.sr_no := get_group_number_cell ( 'lov27.sr_no', i );
      create_record;
    end loop;
  first_record;
  end if;
  end;
  

• count all values with a special WHERE clause in a select group?

  Hello
  
  I have the following table 1:
  
  code, month, value
  * 1,1,40 *.
  * 1,2,50 *.
  * 1,3,0 *.
  * 1,4,0 *.
  * 1,5,20 *.
  * 1,6,30 *.
  * 1,7,30 *.
  * 1,8,30 *.
  * 1,9,20 *.
  * 1,10,20 *.
  * 1,11,0 *.
  * 1,12,0 *.
  
  * 2,1,10 *.
  * 2,2,10 *.
  * 2,3,20 *.
  * 2,4,20 *.
  * 2,5,20 *.
  * 2,6,30 *.
  * 2,7,40 *.
  * 2,8,50 *.
  * 2,9,20 *.
  * 2,10,20 *.
  * 2,11,20 *.
  * 2,12,20 *.
  
  
  This is a table with 3 columns, first column is a code, second is the number of months, third, one is a value.
  Now, I want to select records for each code. For example, all records for the code = 1.
  I want to count how many values = 0 for this code = 1. After this count, I want to update the value with the number 0.
  
  For my example:
  Code 1, there are 4 fields with the value 0. So, I want to update all values from code 1 to 4.
  The second code = 2 there is no value = 0. So, I want to update the values of code2 to 0.
  
  This should be the result:
  code, month, value
  * 1,1,4 *.
  * 1,2,4 *.
  * 1,3,4 *.
  * 1,4,4 *.
  * 1,5,4 *.
  * 1,6,4 *.
  * 1,7,4 *.
  * 1,8,4 *.
  * 1,9,4 *.
  * 1,10,4 *.
  * 1,11,4 *.
  * 1,12,4 *.
  
  * 2,1,0 *.
  * 2,2,0 *.
  * 2,3,0 *.
  * 2,4,0 *.
  * 2,5,0 *.
  * 2,6,0 *.
  * 2,7,0 *.
  * 2,8,0 *.
  * 2,9,0 *.
  * 2,10,0 *.
  * 2,11,0 *.
  * 2,12,0 *.
  
  
  My question is:
  Is it possible in oracle to count in a select (or in an insert/update statement) all values = 0 for a group (in this example, named code) and make an update in the same statement for this group?
  
  I hope someone can give me a hint, if possible?
  
  Thank you very much.
  Best regards
  
  
  Tim

  something like that? NOT TESTED *.

  Setting a DAY Table1 a SET A.Value = (SELECT COUNT (B.ROWID) FROM Table1 B WHERE A.Code = B.Code AND B.Value = 0);

• Select all the messages and support those want to register without selecting him coming all out

  Another email I was able to select all and then click ones I wanted there without taking off select them highlighted. If I do this with Mozilla, we highlight the rest. I have over 3,000 and the need to delete without having to move the others I want to left. How can I do this?

  CTRL + A = select ALL.
  Shift + click = Select all between clicks.
  CTRL preserves the State and allows clicking on selected to deselect and vice versa.

• In clear, all the history in detail window Forum selection & search history is disabled and grayed out and I can't select the option.

  In clear, all the history in detail window Forum selection & search history is disabled and grayed out and I can't select the option.

  You are welcome