"Select box" or "Drop Down Box" works only in one place at the same time

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  Hello experts.

  I received help on this a few hours ago, and it has worked very well so I closed the discussion and form.  However, now it no longer works and I don't know what I did.

  I have a form with a dropdown list and two text boxes.  The first text box is populated according to the value selected in the drop-down list, I used a simple table of the to do and it works as expected.  I had to bring textbox2 read only based on some selections in the drop-down field.  It worked very well at the beginning, but now it no longer works.  I did not any changes to the form except that I closed and since.

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  In the case of change you can't get the rawValue... So, use xfa.event.newText to get the modified text...

  Also, you have a space at the end of the value while comparing. In the code below I removed it.

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• Filling of a numeric field by selecting from a drop-down list

  Hello all;

  I went through the 38 pages on the form now to try to understand it myself. I must have missed something or this day becomes medium long.

  I am filling a numeric field that is based on what is selected in a drop-down list box.

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  if (DropDownList1.rawValue == 1) { }

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  Thank you all

  Chomp

  If it's a copy/paste of your script, you have a semicolon after the "else" and "else" should be lowercase.

  And for nested IFS, you need an "else if", so:

  If (DropDownList1.rawValue == 1) {}

  NumericField1.rawValue = 25;

  }

  Else if (DropDownList1.rawValue == 2) {}

  NumericField1.rawValue = 35;

  }

  ElseIf...

  If you have a lot of statements, you might want to look at using a statement that may be easier to read.

  {Switch (DropDownList1.RawValue)}

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  NumericField1.rawValue = 25;

  break;

  case '2 ':

  NumericField1.rawValue = 35;

  break;

  etc.

  }

• drop-down list - work with the default

  Hello

  We have drop-down list is activated option "Text entry allows the custom" (combo box). We need to display a text default value: "- choose or type--

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  Then, when the user cannot choose or type anything and exits the drop-down list, we must display '- choose or type -' again.

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  Bruce

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• Populate a drop-down list based on selected in a drop-down list in a separate table

  Good day all.

  This may seem a simple question for most, but... He had me frustrated trying to figure out.

  I'm trying to fill in a drop-down list that is based on what is selected in another drop-down list.

  Let me explain what I've done so far.

  Life cycle of Designer 8.05.2

  When I got the two drop-down lists in the same table, I've not had a problem. The code I used is

  The table name is "table1".

  if (directorate.rawValue == '1')

  {

  division.clearItems ();

  division.addItem ("select" "")

  }

  I was asked to move things and now 'division' is located in 'Table2 '.

  I know that I need the "Table1" reference, but I'm running into a syntax error. I tried the following code;

  if (Table1 Row1 directorate.rawValue == '1')

  {

  division.clearItems ();

  division.addItem ("make a choice")

  }

  if (Table1.Row1.directorate.rawValue == '1')

  {

  division.clearItems ();

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  }

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