Select days in the future

Similar Questions

• How can I get a list of jobs that are planned for the days of the future

  How can I get a list of jobs that are planned for the days of the future?

  In a previous article, I found a query that lists the scheduled tasks that are already running. Can I get a similar request for the future days which is compiled?

  Hi sreedevir,

  SELECT jobmst.jobmst_prntname, jobmst.jobmst_name, jobrun.*

  FROM jobrun JOIN jobmst ON jobmst.jobmst_id = jobrun.jobmst_id -joining tables jobmst and jobrun

  WHERE jobrun_proddt > = dateadd (dd, 1, datediff (dd, getdate())) 0, -future dates

  AND jobmst.jobmst_type = 2 -given jobs (and not groups)

  ORDER BY 1, 2 -Sort by name of the parent, then by task name

  Feel free to make any changes to your reporting needs

  ARO

  The Derrick

• Set a date of two days in the future

  Hi all

  This code works very well to set a value if there is no value in the form. MEETING (so I can insert the value in my db with sql):

  < cfset isMEETINGNull = iif (len (trim (form. (False (MEETING)) EQ 0, true) >

  How can I set the value to a date of two days from now if it is empty (instead of the null value because it is at the moment, seomthing like that?)

  < cfset isMEETINGNull = DateFormat (DateAdd ("d", + 2, now(), ' MM/DD/YYYY') >

  Thank you!

  Message has been changed due to the possible response from google search

  Here is another suggestion. It includes a validation.

  The value to store in the database is then meetingDate.

• Thunderbird is save messages sent with a date 3 days in the future, what is with that?

  I noticed this morning that an email I sent from another computer yesterday, 05/28/15, in the afternoon around 16:00 sitting in my inbox sends file dated 05/31/15. Today 29/05/15. What's new? I'm under TB 31.7.0 in Windows 7.

  have you checked the date information, time and time zone of the computer that you used to send the mail?

• Selection field of the day of the week as the appointment screen

  Hello

  I am developing a screen exactly similar to the ' screen new appointment "in the calendar application. But I can't find any appropriate UI component to expand the field of selection of the day of the week.

  In the 'new appointment screen of origin', this field of choice in week appears when you select "weekly" in the choicefield "recidivism". There are 7 characters, one for each day of week & you can select / deselect a day of week by pressing the space bar.

  Now, can someone please give me an idea on how to develop this field?

  Thank you.

  Hello

  Add HorizontalFieldManager and add ButtonFields on measurement (method overload f.e paint.).

  ButtonFieldListener is added to the custom field button.

  If selected the day of the week (given by the manufacturer) paint "BOLD", and another not.

  Kind regards

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• When purchasing a subscription, if I know that I used to use the product until a certain date in the future, am I able to set up a future subscription start date as a way to not lose all day in the duration of my subscription?

  When purchasing a subscription, if I know that I used to use the product until a certain date in the future, am I able to set up a future subscription start date as a way to not lose all day in the duration of my subscription?

  Not according to the terms and conditions

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• by selecting specific days of the week for the date range?

  I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
  every week, since the beginning of the dates. Table is simple and has two columns. Each line is separate from a Date
  There is no duplicate of Date, it is counted for every day of the year.
  
  column 1: number of clients, count (customer_id)
  column 2: Date
  
  Need help with the best way to achieve this.
  
  Not sure if it is even possible to select a date in the name of the day?
  
  Basically, I want to select every Wednesday and Thursday of each week and compare the counts during the week, the week during
  week for the whole week see if charges go upwards or downwards, to get trends, thank you!

  Hello

  Kodiak_Seattle wrote:
  I have a table with a number of clients for about a year, but I want to only select Wednesday and Thursday of
  every week, since the beginning of the dates. Table is simple and has two columns. Each line is separate from a Date
  There is no duplicate of Date, it is counted for every day of the year.

  column 1: number of clients, count (customer_id)
  column 2: Date

  Need help with the best way to achieve this.

  Not sure if it is even possible to select a date in the name of the day?

  Sorry, we don't know what you want.

  To see if a date given (dt) is a Wednesday or Thursday, you can use:

  WHERE   TO_CHAR ( dt
            , 'DY'
            , 'NLS_DATE_LANGUAGE=ENGLISH'     -- If necessary
            )  IN ('WED', 'THU')
  

  I hope that answers your question.
  If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and also publish outcomes from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).
  See the FAQ forum {message identifier: = 9360002}

• Select the first 20 days of the month for a given date

  Hi gurus,
  
  Please let me know to select the first 20 dates for a date supplied by using a parameter.
  
  For ex -.
  
  Suppose I provided a date by using a parameter - January 13, 2012
  
  The query should return me - 01-Jan-2012, January 2, 2012... January 20, 2012
  
  or if I get home on 23 March 2012
  
  The query should return me - 01-Mar-2012, March 2, 2012... 20 March 2012
  
  Thanks in advance.

  Hello

  Here's one way:

  VARIABLE  target_date     VARCHAR2 (11)
  EXEC     :target_date := '13-Jan-2012';
  
  SELECT      TO_DATE ( SUBSTR (:target_date, 4)
              , 'Mon-YYYY'
             ) + LEVEL - 1     AS a_date
  FROM     dual
  CONNECT BY     LEVEL     <= 20
  ;
  

  Note that this does not take account the part of: target_date that represents the day of the month. When you use TO_DATE without giving a date of the month, it defaults to the 1st of the month.

• Select SQL - last day of the month, a year from now

  Hello
  How do we get the last day of the month, a year from now.
  
  For example-sysdate-12/2/2009
  Result - 31/12/2009
  
  Thank you

  Hello

  SELECT  LAST_DAY ( ADD_MONTHS ( SYSDATE
                                , 12
              )           )
  FROM    dual;
  

  Remember, all DATEs, including the results of this query, include the hours minutes and seconds.
  The hours, the minutes and the seconds returned by the above expression are the same as SYSDATE: If you run it at 15:43:30 today, it returns 15:43:30 on December 31, 2010. This can be important if you want to use an expression like this as the cut-off point in a WHERE clause.

• Select the last value for each day of the table

  Hello!
  
  I have a table that contains several measures for each day. I need two queries on this table, and I'm not sure how to write them.
  
  The table stores the rows (sample data)
  

  *DateCol1                 Value       Database*
  27.09.2009 12:00:00       100           DB1
  27.09.2009 20:00:00       150           DB1
  27.09.2009 12:00:00       1000          DB2
  27.09.2009 20:00:00       1100          DB2
  28.09.2009 12:00:00       200           DB1
  28.09.2009 20:00:00       220           DB1
  28.09.2009 12:00:00       1500          DB2
  28.09.2009 20:00:00       2000          DB2

  Explanation of the data in the sample table:
  We measure the size of the data files belonging to each database to one or more times a day. The value column indicates the size of the files of database for each database at some point (date in DateCol1 European model).
  
  
  What I need:
  Query 1:
  The query must return to the last action for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009        150          DB1
  27.09.2009       1100          DB2
  28.09.2009        220          DB1
  28.09.2009       2000          DB2

  Query 2:
  The query should return the average measurement for each day and the database. Like this:

  *DateCol1       Value      Database*
  27.09.2009       125          DB1
  27.09.2009      1050          DB2
  28.09.2009       210          DB1
  28.09.2009      1750          DB2

  Could someone please help me to write these two queries?
  
  Please let me know if you need further information.
  
  Published by: user7066552 on September 29, 2009 10:17
  
  Published by: user7066552 on September 29, 2009 10:17

  Why two queries when it suffice ;)

  SQL> select dt
    2       , db
    3       , val
    4       , avg_val
    5    from (
    6  select dt
    7       , val
    8       , db
    9       , row_number () over (partition by db, trunc (dt)
   10                                 order by dt desc
   11                            ) rn
   12       , avg (val) over (partition by db, trunc (dt)) avg_val
   13    from test)
   14   where rn = 1
   15  order by dt
   16  /
  
  DT        DB           VAL    AVG_VAL
  --------- ----- ---------- ----------
  27-SEP-09 DB2         1100       1050
  27-SEP-09 DB1          150        125
  28-SEP-09 DB2         2000       1750
  28-SEP-09 DB1          220        210
  

• Yahoo mail and yahoo Web sites not be loading not on safari April 10, 2916. How to get around this problem? Œuvres of chrome! What is the future of mac?

  Yahoo mail and yahoo Web sites not to load not on safari as of April 10, 2016. How to get around this problem? Œuvres of chrome! What is the future of mac?

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• My wrt400n worked very well, but since those days, as the internet continues to drop.

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  How about if you change the settings of the router wireless. Change the width of the channel at 20 Mhz and select 9 as the standard channel under the 2.4 Ghz settings. For 2.4 GHz wireless security settings, you must set the security settings wireless personal WPA2 and AES as the encryption. BTW, you have problems in your laptop only, or with computers portable mutiple because if you don't have a laptop then you must try to update drivers wireless card from your cell phone.

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  Hello

  Would you please ask the same questions more then once in these Forums.

  What you're doing is confusing in these Forums, as nobody else knows what advice are envisaged for you in other responses.

  Other questions, it seems you have an HP computer.

  Here is the information of HP for Vista from recovery to factory settings:

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  http://h10025.www1.HP.com/ewfrf/wc/document?DocName=c00809678&LC=en&DLC=en&cc=us&product=18703

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  4. When the HP Recovery Manager window appears, click Advanced options , System Recovery , and then click Next to open the Recovery Manager.
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  If you are having problems using the HP recovery process, you will need to contact HP, because this is Recovery process HP, not Microsoft.

  Details of HP:

  http://WWW8.HP.com/us/en/contact-HP/contact.html

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  http://h30434.www3.HP.com/

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• Cancellation: "do not show this message in the future".

  A Tech support guy selected "do not show this message in the future" on the page uninstall programs...  Well... I didn't do this to him.

  How to reverse the "selection" do not show this message in the future? '"

  Thank you

  Well found the answer.  Posting it here in case anyone else is curious

  1. type regedit into the dialog box RUN and press ENTER. Now goto:

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