Select the first 20 days of the month for a given date

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• find the 3rd Friday of the month at a given date

  How can 3rd Friday of the month at a given date? I can always spend the first day of the month as input
  
  for example, the effective date is 1 January 09. need to get the 3rd Saturday 16 January 09 (Jan has 5 Friday 02, 09, 16,23,30)
  
  entry date: 1 February 09, needed 20 February 09
  
  Published by: user520824 on April 1st, 2009 12:30

  How about you...

  select trunc(sysdate,'mm') + (6 - to_char(trunc(sysdate,'mm'),'d')) + 14 from dual;
  
  TRUNC(SYS
  ---------
  17-APR-09
  
  select trunc(to_date('01-JAN-09'),'mm') + (6 - to_char(trunc(to_date('01-JAN-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  16-JAN-09
  
  select trunc(to_date('01-FEB-09'),'mm') + (6 - to_char(trunc(to_date('01-FEB-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  20-FEB-09
  
  select trunc(to_date('01-MAR-09'),'mm') + (6 - to_char(trunc(to_date('01-MAR-09'),'mm'),'d')) + 14 from dual;
  
  TRUNC(TO_
  ---------
  20-MAR-09
  

• I called to cancel my subscription to the month for first adobe adobe support.  The representative told me that my membership was cancelled successfully.  But when I checked my account, it says my subscription needs to be renewed within a few days. Hoes i

  I called to cancel my subscription to the month for first adobe adobe support.  The representative told me that my membership was cancelled successfully.  But when I checked my account, it says my subscription needs to be renewed within a few days. Hoes it mean, the representative has not really cancelled my subscription?

  Hello

  You will need to contact support by calling/chat for this request.

  Contact the customer service

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  Kind regards

  Sheena

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• How to get the second Monday of each month in a given date range?

  In Oracle forms, how to get the second Monday of each month in a given date range?

  I tried below using the query WITH the Clause, but it seems that WITH Clause does not work in Oracle forms. So is there another way to do this in Oracle forms?

  WITH month_range AS

  (

  SELECT TO_DATE ('Dec 2013', 'Mon YYYY') AS first_month

  , TO_DATE ('Mar 2014', 'Mon YYYY') AS last_month

  OF the double

  )

  SELECT NEXT_DAY (6 + ADD_MONTHS (first_month

  , LEVEL - 1

  )

  , 'MONDAY '.

  ) AS second_monday

  OF month_range

  CONNECTION OF LEVEL < = 1 + MONTHS_BETWEEN (last_month, first_month)

  ;

  Thanks in advance.

  Good fishing, when the first day of the month is Thursday... So I changed the query accordingly... Try the below

  SELECT CASE WHEN TO_CHAR (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'DY') = 'game '.

  THEN NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'THU')

  Of OTHER NEXT_DAY (ADD_MONTHS (TRUNC(startdate,'MM'),(LEVEL-1)), 'Game') + 7

  END AS second_day

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

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• subscription to the month for creative cloud photoshop ended due to no money in bank account, it will b auto renewed once the money is there once again in the Bank? How to cancel it permanently?

  subscription to the month for creative cloud photoshop ended due to no money in bank account, it will b auto renewed once the money is there once again in the Bank? How to cancel it permanently?

  Liliane,

  To cancel the Member please contact our support team via: http://helpx.adobe.com/in/contact.html?step=CCSN_adobe-id-signing-in_stillNeedHelp

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  Atul_Saini

• Select the query to select the month range based on the current date.

  It's the database 10 g oracel.

  I want to choose two months of data in the table. But these two months should be based on the current date.

  For example.

  If I run the select query on July 7, 2013, then the query must ignore the current month being July 2013 and last month, which is June 2013 and it shoud select only may 2013 and April 2013.

  Can someone help me how to make this request.

  SELECT *.

  FROM my_table

  WHERE my_date > = TRUNC (ADD_MONTHS (sysdate,-3), 'MY') - first day of the month 3 months ago

  AND my_date< trunc(add_months(sysdate,-1),'mon')="" --="" first="" day="" of="" last="">

• SQL in Question actually. Select the items for all 12 months

  I am creating a notification request where I SUMMARIZED all of the amounts in the database for all 12 mount and come up with a result even if it isn't a amount totaled. I created a table called monthsInYear that has the ID (unique identifier) 1-12 and the months of Jan - Dec. I want SUM to the amount per month and arrived to the top with 12 results (one per month).

  I tried the query below, but sometimes with only 1 month and all amounts amounted to him.

  March

  484714.13

  I use:

  SELECT monthsInYear.month, IFNULL (SUM (income.amount), 0) AS amount

  OF monthsInYear

  Income ON EXTRACT(MONTH FROM income.dateAdded) = monthsInYear.monthID LEFT OUTER JOIN

  WHERE income.orgID = 10031

  AND the YEAR (income. DateAdded) = '2011'

  ORDER BY EXTRACT (MONTH FROM income.dateAdded) CSA

  Can someone tell me what I am doing wrong. I much prefer something like:

  January 3000

  February 3000

  March 4000

  April 0

  Maybe 5000

  June 6000

  July 5465

  ....

  But when I run the present, it gives me total for only the months which have in total and not 0 for those that go up as null. Any ideas?

  ....

  Also tried

  SELECT m.month, IFNULL (SUM (i.cost), 0) AS amount

  I have getExpenses LEFT OUTER JOIN monthsInYear m

  ON m.monthID = EXTRACT (MONTH FROM i.dateAdded)

  WHERE orgID = 10031

  AND YEAR (i.dateAdded) = '2011'

  GROUP BY m.month

  ORDER BY EXTRACT (MONTH FROM i.dateAdded) CSA

  There are two problems. First of all, in your join tables are reversed. A LEFT JOIN returns all the records in the left table (spending) even if there is no matching record in the table to the right. What you want, it's the opposite. If the month table should be on the left side of the JOIN:

  ...

  OF monthsInYear m LEFT JOIN getExpenses i m.monthID = EXTRACTION (i.dateAdded MONTH)

  Second, when there is no corresponding record in the expense, the column values will be null. So as soon as you use one of the fresh fields in your WHERE clause, that is to say

  WHERE i.orgID = 10031

  AND YEAR (i.dateAdded) = '2011'

  ... these missing documents are deleted, because a null value is never equal to what it is. So you are denying the outer join altogether. You must move these conditions in the JOIN clause instead:

  SELECT m.month, IFNULL (SUM (i.cost), 0) AS amount

  MonthsInyear LEFT OUTER JOIN getExpenses m I have

  ON m.monthID = EXTRACT (MONTH FROM i.dateAdded)

  AND i.orgID = 10031

  AND YEAR = 2011 (i.dateAdded)

  GROUP BY m.month

  ORDER BY m.month

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  I have the below requirement

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  On the result - 3 payment terms are the terms of payment we and the rest are Global.

  A user will select these 3 conditions of payment of the United States or the reset of the (Global) payment terms, but not all.

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• get the month and year of date type

  Hi all
  I need to get the month and year of type date.
  
  For example

  select to_date('2011-01-17', 'yyyy-mm-dd') from dual;

  Required result:

  01-2011

  Any ideas?
  
  Thanks in advance,
  Bahchevanov.

  select to_char(to_date('2011-01-17', 'yyyy-mm-dd'),'mm-yyyy') from dual;
  

  HTH

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  See the attached snipit.

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  Hello

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