Select from another table, when the query returns no result
HelloI have a question where I'm supposed to retrieve the address of an account id-based billing. However, the table of billing may not have an address. There is a table of addresses that always has an address for an account. If the billing address exists, it should be used, so I can't use the address table. Is it possible in a select statement to query to the billing address and if it does not exist, use the address table.
SELECT * FROM accounts a, b billings WHERE a.accountid = b.accountid
Any help will be greatly appreciated.
Thank you.
user10407139 wrote:
HelloI have a question where I'm supposed to retrieve the address of an account id-based billing. However, the table of billing may not have an address. There is a table of addresses that always has an address for an account. If the billing address exists, it should be used, so I can't use the address table. Is it possible in a select statement to query to the billing address and if it does not exist, use the address table.
SELECT * FROM accounts a, b billings WHERE a.accountid = b.accountid
Any help will be greatly appreciated.
I think you need to explain more clearly if
-you only have a couple of "billing" columns which is empty and in this case, you want to use the columns from the table 'accounts '.
- or you have a join with another table that doesn't return data, for example a foreign key "address_id" "billing" is zero and therefore the join to other tables 'address' will return all the data
In the first case, you have already been provided with some examples here, how to use NVL or similar functions to achieve, even if the first post first evaluates the information of 'accounts' and if it is white using information from "billing". According to your description you need the other way around. The second post a subquery recursive useless in my opinion.
In the latter case, you should probably use an "outer" join so that the data in your table "bills" are returned, even if the join to another table is not at all the lines.
SELECT
NVL(AD1.ADDRESS_ATTR1, AD2.ADDRESS_ATTR1) as ADDRESS_ATTR1,
NVL(AD1.ADDRESS_ATTR2, AD2.ADDRESS_ATTR2) as ADDRESS_ATTR2,
NVL(AD1.ADDRESS_STREET, AD2.ADDRESS_STREET) as ADDRESS_STREET,
...
FROM accounts a
INNER JOIN billings b
ON a.accountid = b.accountid
LEFT OUTER JOIN address ad1
ON b.address_id = ad1.address_id
INNER JOIN address ad2
ON a.address_id = ad2.address_id;
In this way you pick up the address stored in the "invoices" table, if it existed, otherwise you pick up the address assigned to the "accounts" table I used an inner for the second address join join because you said that the account always has an assigned address.
Kind regards
Randolf
Oracle related blog stuff:
http://Oracle-Randolf.blogspot.com/
SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676 /.
http://sourceforge.NET/projects/SQLT-pp/
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