Simple, but a difficult requirement for my SQL query.

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• Looking for a SQL query to retrieve callvariables + ECC to a RESULTS of SCRIPT EXECUTE (translation VRUS)

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  Omar,

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  I recommend to take a look at the following SQL query:

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  Hi all
  
  The application team uses under request and asked for recommendation for listening to this query.
  The concern was
  
  (1) how to avoid the query select sup as a query of subselects 3 is here which may degrade the performance of the query.
  (2) in any case to avoid using the JOBBERDETAILS 5 times in NVL function.
  
  
  SELECT "0". SM. SITE_ID AS "SD_SITE_NUMBER."
  SA. ADDR_L1 AS "SD_SITE_ADDRESS."
  SA. CITY_NAME AS "SD_SITE_CITY."
  SA. STATE_AC AS "SD_SITE_STATE."
  SUBSTR (SA. ZIP_CD, 0, 5) AS "SD_SITE_ZIP."
  DECODE (LENGTH (TRIM (SA. ZIP_CD)), 5, '0000', SUBSTR (SA. ZIP_CD, 6, 4)) AS "SD_SITE_ZIP4."
  SM. SITE_NAME AS "SD_NAME."
  NVL ((SELECT SM. AM_SITE DOJ_NAME. B JOBBER_BASE WHERE B.SITE_ID = SM. (SITE_ID),' ') AS "SD_NAME2."
  NVL (AM_SITE. JOBBERDETAILS (SA. (SITE_ID, 'OWNER_ADDRESS'),' ') AS "SD_MAILING_ADDRESS."
  NVL (AM_SITE. JOBBERDETAILS (SA. (SITE_ID, 'OWNER_CITY'),' ') AS "SD_MAILING_CITY."
  NVL (AM_SITE. JOBBERDETAILS (SA. (SITE_ID, 'OWNER_STATE'),' ') AS "SD_MAILING_STATE."
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  WHERE SM. SITE_ID = SA. SITE_ID AND SUPERIOR (SA. ADDR_TYPE) = 'P' AND SM. MOP_CD IS NOT NULL
  
  Can someone please help me in setting this query.
  Thanks in advance

  Follower of the Oracle says:
  Hi all

  The application team uses under request and asked for recommendation for listening to this query.
  The concern was

  (1) how to avoid the query select sup as a query of subselects 3 is here which may degrade the performance of the query.

  Use outer joins instead of scalar subqueries. See for example the recent discussion of Tom Kyte: http://asktom.oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:1594885400346999596

  (2) in any case to avoid using the JOBBERDETAILS 5 times in NVL function.

  You need to know what the function does, and replace it with a simple corresponding SQL expression. Most of the time these functions search the recursive SQL which can be very expensive. Although the functional separation is better in terms of encapsulation/maintainability ordinary SQL approach gives better performance if you have a result of great value.

  Have you checked that above two points are key issues of this query? By work without the function calls and scalar subqueries, you can check if it performs much better. If this isn't the case, you will need to investigate on what is still the main culprit.

  Kind regards
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• Need for the sql query to have several columns in a single coulumn

  Hi all
  
  I need create the query to have several columns in a single column with several lines.
  
  Select a.customer_trx_id, a.previous_customer_trx_id
  of ra_customer_trx_all one
  where a.customer_trx_id =: customer_trx_id
  
  Here, a.customer_trx_id and a.previous_customer_trx_id are in two columns. I need to put them in a single column.
  
  Say: the foregoing is output
  --------------------------------------------------------------------------------
  a.customer_trx_id a.previous_customer_trx_id
  
  --------------------------------------------------------------------------------
  123456 87654
  
  --------------------------------------------------------------------------------
  
  Need for a single column
  
  As
  
  
  --------------------------------------------------------------------------------
  123456
  87654
  
  --------------------------------------------------------------------------------
  
  Please do the needful. Please note that it is not the UNION.
  
  Thank you
  Abdul

  Hello

  You want a way to confirm that what looks like two rows is really a line?

  Here are three ways:

  (1) count the lines:

  WITH  my_original_querry     AS
  (
       select  a.customer_trx_id || CHR(13)
                        || a.previous_customer_trx_id     as id
       from      ra_customer_trx_all     a
       where      a.customer_trx_id      = 274881
  )
  SELECT     COUNT (*)
  FROM     my_original_query;
  

  (2) in SQL * Plus, have SQL * more count them for you:

  SET     FEEDBACK     1
  
  select  a.customer_trx_id || CHR(13)
                   || a.previous_customer_trx_id     as id
  from      ra_customer_trx_all     a
  where      a.customer_trx_id      = 274881;
  

  (3) implicitly count them with the ROWNUM Pseudo-column

  select  a.customer_trx_id || CHR(13)
                   || a.previous_customer_trx_id     as id
  ,     ROWNUM
  from      ra_customer_trx_all     a
  where      a.customer_trx_id      = 274881;
  

• an idea for a SQL query?

  I have a table with 2 columns. I want to choose the following lines:
  (a) one of the 2 lines where 1st row: col1, col2 Row2 =: col2, col1
  (b) all other lines where there is no equality constraint
  
  Example:
  
  Col1 Col2
  -------------------------------------
  ABC001 | BC987
  BC987 | ABC001
  CDE | PH
  BC987 | XYZ
  
  Result must be
  (a) one of the 2 first lines because col1 value in 1st row is the same as col2 value in 2nd row; and col2 value in the 1st row is the same as the value of col1 in 2nd row.
  (b) 2nd and 3rd rows (because they are unique lines)
  
  Configuration data:
  ---------------
  create table temptab (varchar2 (20) col1, col2 varchar2 (20))
  
  insert into temptab values ("ABC001", "BC987")
  
  insert into temptab values ('BC987', "ABC001")
  
  insert into temptab values ("CDE", "PH")
  
  insert into temptab values ('BC987', 'XYZ')
  
  
  
  Thank you

  Hello

  It is an example of Request Top - N .
  Assuming that col1 and col2 can be null:

  WITH     got_rnum     AS
  (
       SELECT     col1
       ,     col2
       ,     ROW_NUMBER () OVER ( PARTITION BY     LEAST (col1, col2)
                                 ,                    GREATEST (col1, col2)
                           ORDER BY        col1
                         ) AS rnum
       FROM     temptab
  )
  SELECT  col1
  ,     col2
  FROM     got_rnum
  WHERE     rnum     = 1
  ;
  

  If these columns can be NULL, it is messier, especially if there is no value (as "?") that you know does not occur in the table...

  Thanks for posting the CREATE TABLE and INSERT!

• You have no lines for the SQL query to select

  Dear Sir.

  I don't want to choose these lines in the second query, please guide me how to do.

  Request-> 1

  (SELECT ID_NO, ATTND_DATE
      FROM ATTND_REGISTER 
      WHERE ATTND_DATE BETWEEN :FD AND :TD
      ORDER BY ID_NO, ATTND_DATE
  )AT
  

  A query result.

  ID_NO	ATTND_DATE
  E1	FEBRUARY 1, 14
  E1	FEBRUARY 2, 14
  E1	3 FEBRUARY 14
  E1	4 FEBRUARY 14
  E1	FEBRUARY 5, 14
  E1	FEBRUARY 6, 14
  E1	FEBRUARY 7, 14
  E1	FEBRUARY 8, 14
  E1	FEBRUARY 9, 14
  E1	10 FEBRUARY 14
  E1	FEBRUARY 11, 14
  E1	FEBRUARY 12, 14
  E1	FEBRUARY 13, 14
  E1	14 FEBRUARY 14
  E1	15 FEBRUARY 14
  E1	16 FEBRUARY 14
  E1	17 FEBRUARY 14
  E1	18 FEBRUARY 14
  E1	19 FEBRUARY 14
  E1	20 FEBRUARY 14
  E4	FEBRUARY 1, 14
  E4	FEBRUARY 2, 14
  E4	3 FEBRUARY 14
  E4	4 FEBRUARY 14
  E4	FEBRUARY 5, 14

  Request-> 2

  : VALUE OF THE VARIABLE FD = 1 FEBRUARY 14

  : VALUE OF THE VARIABLE TD = FEBRUARY 28, 14 '
  

  SELECT A.ID_NO,B.DATES,A.EMP_NAME, A.DESG_NAME
  FROM
    (
      SELECT  ROWNUM - 1 + TO_DATE(:FD, 'DD/MM/RR') DATES
      FROM ALL_OBJECTS
      WHERE ROWNUM < TO_DATE(:TD, 'DD/MM/RR') - TO_DATE(:FD, 'DD/MM/RR') + 2
    )B,
  
  
    (
      SELECT ID_NO, INITCAP(FL_NAME) AS EMP_NAME, INITCAP(UBN.DESG_NAME(DESG_ID)) AS DESG_NAME
      FROM PERSONAL
      WHERE (STATUS = 'A')
      AND (COMPANY_CODE = :COMPANY_CODE)---COMPANY CODE=6
      AND (ID_NO = :ID_NO OR :ID_NO IS NULL)
    )A
  ORDER BY A.ID_NO,B.DATES;
  

  
  

  Solved

  I changed in the second query with using the first query.

  in Where Clause

  WHERE B.DATES | A.ID_NO NOT IN (SELECT ATTND_DATE |) NBI ID_NO. ATTND_REGISTER

  WHERE ATTND_DATE BETWEEN: FD AND: TD)

  Thank you Allah (SWT).

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  Is what we expect to be good data below:
  
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  SELECT "100000" col OF DOUBLE UNION ALL
  SELECT '1 a' collar OF DOUBLE UNION ALL
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  SELECT 'A1' collar OF DOUBLE UNION ALL
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  SELECT "/" pass OF DOUBLE UNION ALL
  SELECT '-' col OF DOUBLE UNION ALL
  SELECT ' ' collar OF DOUBLE UNION ALL
  SELECT "pass OF DOUBLE UNION ALL
  4. SELECT 5 6' collar OF DOUBLE UNION ALL
  SELECT "24.5" collar OF DOUBLE UNION ALL
  SELECT '-3' collar OF DOUBLE UNION ALL.
  SELECT 'A' collar OF DOUBLE UNION ALL
  SELECT 'F' OF DOUBLE UNION ALL cervical
  SELECT the 'Z' OF DOUBLE UNION ALL pass
  SELECT the pass 'Bye' FROM DUAL UNION ALL
  SELECT the "Hello World" OF DOUBLE UNION ALL pass
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  SELECT "+" col OF DOUBLE UNION ALL
  SELECT '_' pass OF DOUBLE UNION ALL
  SELECT '-' col OF DOUBLE UNION ALL
  SELECT ' (' col OF DOUBLE UNION ALL)
  SELECT ')' collar OF DOUBLE UNION ALL
  SELECT '&' collar OF DOUBLE UNION ALL
  SELECT ' ^' collar OF DOUBLE UNION ALL
  SELECT '%' collar OF DOUBLE UNION ALL
  SELECT the pass of "$" OF DOUBLE UNION ALL
  SELECT the pass ' # ' TO DOUBLE UNION ALL
  SELECT ' @' collar OF DOUBLE UNION ALL
  SELECT '!' collar OF DOUBLE UNION ALL
  SELECT ' ~' collar OF DOUBLE UNION ALL
  SELECT "' collar OF DOUBLE UNION ALL
  SELECT '.' pass FROM DUAL
  )
  SELECT col from Sample_data
  WHERE (translate (col, '_0123456789', '_') is not null
  or length (col) > 5
  col = 0 or
  or col is null)
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  One more thing, I also took the approach of the regular expression, but he could not understand. If anyone knows how to do with this approach, I would also appreciate learning this method as well. Below is a close because I had. Impossible to get a range to work as "between 0 and 100000", guessing because of the comparison of varchar2 and # even attempted using to_char and to_number.
  
  Select to_number (column1) from the testsql where REGEXP_LIKE (column1, ' ^ [[: digit:]] + $') ORDER BY to_number (column1) CSA;
  
  Thanks in advance for anyone to help.
  
  Nick

  Hello

  Thanks for posting the sample data in a useable form.
  It would be useful that you also posted the accurate results you wanted from this data. You want the same results as those produced by the query you posted, except that nulls should be included? If so:

  SELECT     col
  FROM     sample_data
  WHERE     CASE
           WHEN  UPPER (col) = 'NO_RP'               THEN  1
           WHEN  col IS NULL                    THEN -1
           WHEN  LTRIM (col, '0123456789') IS NOT NULL     THEN -2
           WHEN  LENGTH (col) > 5               THEN -3
                                         ELSE TO_NUMBER (col)
       END     NOT BETWEEN     1
                AND          99999
  ;
  

  The requirement that pass! = 0 gives that much more difficult. You could test easily for an integer from 1 to 5 digits, but then you must have a separate condition to make sure that the chain was not '0', '00', '000', ' 0000 'or ' 00000'.
  (Unlike Solomon, I guess that do not want to choose no-0 numbers starting by 0, such as ' 007 'or ' 02138'.)

  Using regular expressions, you may lose a few keystrokes, but you also lose a lot of clarity:

  SELECT     col
  FROM     sample_data
  WHERE     REGEXP_LIKE ( col
                , '^0{1,5}$'
                )
  OR NOT     REGEXP_LIKE ( NVL ( UPPER (col)
                   , 'BAD'
                   )
                , '^(([1-9][0-9]{0,4})|NO_RP)$'
                )
  ;
  

  Published by: Frank Kulash, December 13, 2010 21:50

  Published by: Frank Kulash, December 13, 2010 22:11
  Added regular expression solution

• puzzle of SQL query

  Hi all
  
  My version of Oracle: oracle 10G
  
  I got a puzzle and very much if you could help me with the solution (I have it solved, but mine does not seek to be the best solution), if it is here, its got 2 parts:
  
  Part 1:
  
  Source data looks like:
  AEK MANGO
  AEK MANGO
  AEK MANGO
  AEK MANGO
  AEK MANGO
  AEK APPLE
  AEK ORANGE
  AEK LICHI
  AEK LICHI
  AEK LICHI
  AEK LICHI
  AEK LICHI
  AEK LICHI
  AEK LICHI
  Abu MANGO
  Abu MANGO
  Abu APPLE
  Abu APPLE
  Abu APPLE
  Abu ORANGE
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Abu LICHI
  Melanie MANGO
  Melanie MANGO
  Rémy APPLE
  Rémy APPLE
  Rémy APPLE
  Rémy APPLE
  Rémy APPLE
  Rémy APPLE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy ORANGE
  Rémy LICHI
  Rémy LICHI
  Rémy LICHI
  Rémy LICHI
  Rémy LICHI
  Shakti MANGO
  Shakti MANGO
  Shakti MANGO
  Shakti MANGO
  Shakti MANGO
  Shakti MANGO
  Shakti APPLE
  Shakti APPLE
  Shakti APPLE
  Shakti APPLE
  Shakti ORANGE
  Shakti ORANGE
  Shakti ORANGE
  Shakti ORANGE
  Shakti ORANGE
  Shakti LICHI
  
  power required by my sql query:
  
  Orange mango apple lichi fname
  1 7 5 1 AEK
  Abu 3 8 2 1
  Rémy 6 5 2 9
  Shakti 4 1 6 5
  
  -------------------------------------------
  
  part B: is the opposite, my output above is my source and the result should be my source.
  
  Please help me.
  
  Concerning
  Rahul
  
  Published by: Mac_Freak_Rahul on January 26, 2012 06:20

  Hello

  This makes for part 1:

  Scott@my10g SQL>l
    1  with t as (
    2  select 'abhi' c1, 'MANGO' c2 from dual
    3  union all select 'abhi', 'MANGO' from dual
    4  union all select 'abhi', 'MANGO' from dual
    5  union all select 'abhi', 'MANGO' from dual
    6  union all select 'abhi', 'MANGO' from dual
    7  union all select 'abhi', 'APPLE' from dual
    8  union all select 'abhi', 'ORANGE' from dual
    9  union all select 'abhi', 'LICHI' from dual
   10  union all select 'abhi', 'LICHI' from dual
   11  union all select 'abhi', 'LICHI' from dual
   12  union all select 'abhi', 'LICHI' from dual
   13  union all select 'abhi', 'LICHI' from dual
   14  union all select 'abhi', 'LICHI' from dual
   15  union all select 'abhi', 'LICHI' from dual
   16  union all select 'abu', 'MANGO' from dual
   17  union all select 'abu', 'MANGO' from dual
   18  union all select 'abu', 'APPLE' from dual
   19  union all select 'abu', 'APPLE' from dual
   20  union all select 'abu', 'APPLE' from dual
   21  union all select 'abu', 'ORANGE' from dual
   22  union all select 'abu', 'LICHI' from dual
   23  union all select 'abu', 'LICHI' from dual
   24  union all select 'abu', 'LICHI' from dual
   25  union all select 'abu', 'LICHI' from dual
   26  union all select 'abu', 'LICHI' from dual
   27  union all select 'abu', 'LICHI' from dual
   28  union all select 'abu', 'LICHI' from dual
   29  union all select 'abu', 'LICHI' from dual
   30  union all select 'anirudh', 'MANGO' from dual
   31  union all select 'anirudh', 'MANGO' from dual
   32  union all select 'anirudh', 'APPLE' from dual
   33  union all select 'anirudh', 'APPLE' from dual
   34  union all select 'anirudh', 'APPLE' from dual
   35  union all select 'anirudh', 'APPLE' from dual
   36  union all select 'anirudh', 'APPLE' from dual
   37  union all select 'anirudh', 'APPLE' from dual
   38  union all select 'anirudh', 'ORANGE' from dual
   39  union all select 'anirudh', 'ORANGE' from dual
   40  union all select 'anirudh', 'ORANGE' from dual
   41  union all select 'anirudh', 'ORANGE' from dual
   42  union all select 'anirudh', 'ORANGE' from dual
   43  union all select 'anirudh', 'ORANGE' from dual
   44  union all select 'anirudh', 'ORANGE' from dual
   45  union all select 'anirudh', 'ORANGE' from dual
   46  union all select 'anirudh', 'ORANGE' from dual
   47  union all select 'anirudh', 'LICHI' from dual
   48  union all select 'anirudh', 'LICHI' from dual
   49  union all select 'anirudh', 'LICHI' from dual
   50  union all select 'anirudh', 'LICHI' from dual
   51  union all select 'anirudh', 'LICHI' from dual
   52  union all select 'shakti', 'MANGO' from dual
   53  union all select 'shakti', 'MANGO' from dual
   54  union all select 'shakti', 'MANGO' from dual
   55  union all select 'shakti', 'MANGO' from dual
   56  union all select 'shakti', 'MANGO' from dual
   57  union all select 'shakti', 'MANGO' from dual
   58  union all select 'shakti', 'APPLE' from dual
   59  union all select 'shakti', 'APPLE' from dual
   60  union all select 'shakti', 'APPLE' from dual
   61  union all select 'shakti', 'APPLE' from dual
   62  union all select 'shakti', 'ORANGE' from dual
   63  union all select 'shakti', 'ORANGE' from dual
   64  union all select 'shakti', 'ORANGE' from dual
   65  union all select 'shakti', 'ORANGE' from dual
   66  union all select 'shakti', 'ORANGE' from dual
   67  union all select 'shakti', 'LICHI' from dual
   68  )
   69  select
   70       c1
   71       ,max(decode(rn,1,cnt,null)) l1
   72       ,max(decode(rn,2,cnt,null)) l2
   73       ,max(decode(rn,3,cnt,null)) l3
   74       ,max(decode(rn,4,cnt,null)) l4
   75  from (
   76       select c1,cnt,row_number() over (partition by c1 order by substr(c2,1,1)) rn
   77       from (
   78            select c1,c2,count(*) cnt
   79            from t
   80            group by c1,c2
   81       )
   82  )
   83  group by c1
   84* order by c1
  Scott@my10g SQL>/
  
  C1              L1         L2         L3         L4
  ------- ---------- ---------- ---------- ----------
  abhi             1          7          5          1
  abu              3          8          2          1
  anirudh          6          5          2          9
  shakti           4          1          6          5
  

  I decided to not hardcode the four "fruits" inside the query so it would always works with anything else, as long as they do not share the initial letter.

  ---------

  This should do the part 2:

  Scott@my10g SQL>l
    1  with t as (
    2  select 'abhi' n, 1 c1, 7 c2, 5 c3, 1 c4 from dual
    3  union all select 'abu', 3, 8, 2, 1 from dual
    4  union all select 'anirudh', 6, 5, 2, 9 from dual
    5  union all select 'shakti', 4, 1, 6, 5 from dual
    6  )
    7  select *
    8  from (
    9  select t.n,
   10  case
   11  when m.column_value <= t.c1 then 'APPLE'
   12  when m.column_value <= (t.c1+t.c2) then 'LICHI'
   13  when m.column_value <= (t.c1+t.c2+t.c3) then 'MANGO'
   14  else 'ORANGE'
   15  end f
   16  from t
   17  ,table(cast(multiset(select level n from dual connect by level <= (t.c1+t.c2+t.c3+t.c4)) as sys.OdciNumberList)) m
   18  )
   19* order by n, decode(f,'MANGO',1,'APPLE',2,'ORANGE',3,'LICHI',4)
  Scott@my10g SQL>/
  
  N       F
  ------- ------
  abhi    MANGO
  abhi    MANGO
  abhi    MANGO
  abhi    MANGO
  abhi    MANGO
  abhi    APPLE
  abhi    ORANGE
  abhi    LICHI
  abhi    LICHI
  abhi    LICHI
  abhi    LICHI
  abhi    LICHI
  abhi    LICHI
  abhi    LICHI
  abu     MANGO
  abu     MANGO
  abu     APPLE
  abu     APPLE
  abu     APPLE
  abu     ORANGE
  abu     LICHI
  abu     LICHI
  abu     LICHI
  abu     LICHI
  abu     LICHI
  abu     LICHI
  abu     LICHI
  abu     LICHI
  anirudh MANGO
  anirudh MANGO
  anirudh APPLE
  anirudh APPLE
  anirudh APPLE
  anirudh APPLE
  anirudh APPLE
  anirudh APPLE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh ORANGE
  anirudh LICHI
  anirudh LICHI
  anirudh LICHI
  anirudh LICHI
  anirudh LICHI
  shakti  MANGO
  shakti  MANGO
  shakti  MANGO
  shakti  MANGO
  shakti  MANGO
  shakti  MANGO
  shakti  APPLE
  shakti  APPLE
  shakti  APPLE
  shakti  APPLE
  shakti  ORANGE
  shakti  ORANGE
  shakti  ORANGE
  shakti  ORANGE
  shakti  ORANGE
  shakti  LICHI
  
  66 rows selected.
  

  Published by: on January 26, 2012 Nicosa 15:51

• Generate the Trace file to a sql query

  Hi all
  
  I want to generate a trace for a sql query file so that I can generate a .out file corresponding I need to check the performance of an application before using it.
  Anyone can guide me please how to do this.
  I know how do to generate a trace for a concurrent program, but right now, I want to track for a simple sql query.
  
  Kind regards
  Ankur

  Hello
  Agreed. but I thought that if OP do not have access to metalink then?

  In any case I not substitute me your answer.

  Oops. Sorry I did not read the lines below.

  You can turn simple trace for this particular session.
  Oracle will generate trace files (.trc) for each session where the value of SQL_TRACE = TRUE and write them to the USER_DUMP_DEST destination. That you can use tkprof to read the generated trace file.

  Kind regards
  Taj

  Published by: Mohammed Taj on July 14, 2009 10:11